Answer:
The price elasticity of demand is -10
Step-by-step explanation:
Given
[tex]p_1,p_2 = 50,40[/tex]
[tex]q_1,q_2 = 400,500[/tex]
Solving (a): The coefficient of price elasticity of demand (k)
This is calculated as:
[tex]k = \frac{\triangle q}{\triangle p}[/tex]
So, we have:
[tex]k = \frac{500 - 400}{40 - 50}[/tex]
[tex]k = \frac{100}{-10}[/tex]
[tex]k = -10[/tex]
Because |k| > 0, then we can conclude that the company made a wise decision.
Assume that x and y are both differentiable functions of t. Find dx/dt when x=11 and dy/dt=-4 for the equation xy=99 .
Differentiating both sides of
xy = 99
with respect to t yields
x dy/dt + y dx/dt = 0
When x = 11, we have
11y = 99 ==> y = 9
and we're given that dy/dt = -4 at this point, which means
11 (-4) + 9 dx/dt = 0 ==> dx/dt = 44/9
I do not understand this and could use help it needs the work shown
Answer:
a = 9
Step-by-step explanation:
The given trinomial is :
[tex]x^2-6x+\_\_\__[/tex]
let the blank is a.
So, we need to find the value of a so that it results in a perfect square trinomial.
We know that, [tex](m-n)^2=m^2-2mn+n^2[/tex]
So,
[tex]x^2-6x+a=x^2-2(1)(3)+3^2\\=(x-3)^2[/tex]
So, the value of a is 9. If a is 9, then only it would be a perfect square trinomial.
Suppose that the manufacturer of a gas clothes dryer has found that, when the unit price is p dollars, the revenue R (in dollars) is R(P) = - 8p^2 + 24,000p. What unit
price should be established for the dryer to maximize revenue? What is the maximum revenue?
The unit price that should be established to maximize revenue is $|
(Simplify your answer.)
Here we have a problem of maximization and quadratic equations.
The unit prize that maximizes the revenue is $1,500, and the maximum revenue is $18,000.
We know that the revenue equation is:
R(P) = - 8p^2 + 24,000p
Where the variable p is the price.
Now we want to find the value of p that maximizes the revenue.
To do it, we can see that the revenue equation is a quadratic equation with a negative leading coefficient.
This means that the arms of the graph will go downwards, then the maximum point of the graph will be at the vertex.
Remember that for an equation like:
y = a*x^2 + b*x+ c
The x-value of the vertex is at:
x = -b/(2*a)
Then for the equation:
R(P) = - 8p^2 + 24,000p
The vertex is at:
p = -(24,000)/(2*-8) = 1,500
The value of p that maximizes the revenue is p = $1,500
To get the maximum revenue, we need to evaluate the revenue equation in that p value.
R(1,500) = - 8*(1,500)^2 + 24,000*1,500 = 18,000
And the revenue equation is in dollars, then the maximum revenue is 18,000 dollars.
If you want to learn more, you can read:
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p = 1500 $ the unit price
R(p) = 18000000 $ maximum revenue
We will use two different procedures to calculate the maximum revenue.
That is equivalent to solve the problem and after that to test the solution
The first one is:
R(p) = - 8*p² + 24000*p
we realize that R(p) is a quadratic function ( a parabola) of the form:
y = a*x² + b*x + c ( c = 0 in this case)
We also know that as the coefficient of p² is negative the parabola opens downwards then the vertex is a maximum value for R(p), and the x coordinate of p is:
x = p = - b/2*a then by substitution
p = - ( 24000)/ 2 ( - 8)
p = 1500 $ and for that value of p
R(p) = - 8 ( 1500)² + 24000* (1500) = - 18000000 + 36000000
R(p) = 18000000 $
The second procedure is solving with the help of derivatives.
R(p) = - 8*p² + 24000*p
Tacking derivatives on both sides of the equation we get:
R´(p) = -16p + 24000
If R´(p) = 0 then -16p + 24000 = 0
p = 24000/ 16 p = 1500
if we check for the second derivative
R´´(p) = -16 -16 < 0 therefore there is a maximum value for R(p) when p = 1500, and that value is:
By substitution in R(p)
R(p) = -8 *(1500)² + 24000* 1500
R(p) = - 18000000 + 36000000
R(p) = 18000000 $
Try this 33-33+33×33÷0
Answer:
the answer is
Step-by-step explanation:
1089 first divide then multiply both numbers after that substract the numbers
Answer:
the answer is error
hope it helps
give ABCD is a trapizod , Ab = 13, CD= 14, BC = 15, and AD = 20 what is the area
Step-by-step explanation:
A=140sq. units
Step-by-step explanation:
ABCD
A=13
B=15
C=14
D=20
C=14×14
=196sqr.units
A rectangluar swimming pool 25 feet long, 15 feet wide, and 7 feet deep is filled with water to a depth of 6 feet. The weight density of water is 62.4 lb ft 3 lb/ft^3. Calculate the work required to pump all of the water out over the top.
___________ ft-lb
9514 1404 393
Answer:
491,400 ft·lb
Step-by-step explanation:
The mass of the water is ...
M = Vρ = LWHρ = (25 ft)(15 ft)(7 ft)(62.4 lb/ft³) = 163,800 lb
The average depth is 3 ft, so the work required is equivalent to that required to raise this mass 3 ft.
W = (3 ft)(163,800 lb) = 491,400 ft·lb
D. Rom has just given an insurance company $35,000. In return, he will receive an annuity of $3,700 for 20 years. At what
rate of return must the insurance company invest this $35,000 in order to make the annual payments?
Answer:
0.53%
Step-by-step explanation:
hope it is well understood
Based on the Nielsen ratings, the local Fox affiliate claims its 10:00 PM newscast reaches 31% of the viewing audience in the area. In a survey of 100 viewers, 26% indicated that they watch the late evening news on this local Fox station. What is the null hypothesis
Answer:
The null hypothesis is [tex]H_0: p = 0.31[/tex]
Step-by-step explanation:
Based on the Nielsen ratings, the local Fox affiliate claims its 10:00 PM newscast reaches 31% of the viewing audience in the area.
From the claim, we get the expected proportion, that is, the value tested at the null hypothesis. Thus, at the null hypothesis, we test if the proportion is of 31%, that is:
[tex]H_0: p = 0.31[/tex]
5/root 7 - root 3 +1/root 7+ root 3
[tex]\\ \sf\longmapsto \frac{5}{ \sqrt{7} - \sqrt{3} } + \frac{1}{ \sqrt{7} + \sqrt{3} } \\ \\ \sf\longmapsto \frac{5( \sqrt{7} + \sqrt{3} ) + 1 (\sqrt{7} - \sqrt{3} )}{( \sqrt{7} - \sqrt{3} )( \sqrt{7} + \sqrt{3} )} \\ \\ \sf\longmapsto \frac{5 \sqrt{7} + 5 \sqrt{3} + \sqrt{7} - \sqrt{3} }{( { \sqrt{7} )}^{2} - ( \sqrt{3}) {}^{2} } \\ \\ \sf\longmapsto \frac{5 \sqrt{7} + \sqrt{7} + 5 \sqrt{3} - \sqrt{3} }{7 - 3} \\ \\ \sf\longmapsto \frac{6 \sqrt{7} + 4 \sqrt{3} }{4} [/tex]
find the HCF of 72,108 and 180
Answer:
36 is the answer
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
72: 2×2×2×3×3
108: 2×2×3×3×3
180: 2×2×3×3×5
here, common factors are 2,2,3 and 3 ..
so.. HCF: 2×2×3×3
•°•HCF=36 ..
A rational expression is _______ for those values of the variable(s) that make the denominator zero.
9514 1404 393
Answer:
undefined
Step-by-step explanation:
A rational expression is undefined when its denominator is zero.
A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean life of 83 months with a variance of 81. If the claim is true, what is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors? Round your answer to four decimal places.
Answer:
0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The production manager claims they have a mean life of 83 months with a variance of 81.
This means that [tex]\mu = 83, \sigma = \sqrt{81} = 9[/tex]
Sample of 146:
This means that [tex]n = 146, s = \frac{9}{\sqrt{146}}[/tex]
What is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors?
This is 1 subtracted by the p-value of Z when X = 81.2. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{81.2 - 83}{\frac{9}{\sqrt{146}}}[/tex]
[tex]Z = -2.42[/tex]
[tex]Z = -2.42[/tex] has a p-value of 0.0078.
1 - 0.0078 = 0.9922.
0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the sample mean?
Choose the correct answer below.
A. 15.0 mm
B. 52.5 mm
C. 7.5 mm
D. Somewhere between 45mm and 60mm, but the exact value cannot be determined without more information.
Answer:
I cannot understand this question
Step-by-step explanation:
I don't know what is in the question
The amount of soda a dispensing machine pours into a 12 ounce can of soda follows a normal distribution with a standard deviation of 0.08 ounce. Every car that has more than 12.20 ounces of soda poured into it causes a spill and the can needs to go through a special cleaning process before it can be sold. What is the mean amount of soda the machine should dispense if the company wants to limit the percentage that need to be cleaned because of spillage to 3%
Answer:
x = 12.15 oz
Step-by-step explanation:
z = 1.8808
1.8808 = (x - 12)/.08
The consumer price index (CPI), issued by the U.S. Bureau of Labor Statistics, provides a means of determining the purchasing power of the U.S. dollar from one year to the next. Using the period from 1982 to 1984 as a measure of 100.0, the CPI figures for selected years from 2002 to 2016 are shown here. Year Consumer Price Index 2002 179.9 2004 188.9 2006 201.6 2008 215.3 2010 218.1 2012 229.6 2014 236.7 2016 240.0 E. To use the CPI to predict a price in a particular year, we can set up a proportion and compare it with a known price in another year, as follows. price in year A index in year A price in year B index in year B
Translate and solve: five less than z is 4
z -5 =4
neutralize the left -5 by adding 5 on both sides
z -5 (+5) = 4 (+5)
z = 9
PLEASEEEE HELP
In the diagram, AABC-ADEC What is the value of x?
Similar triangles are proportional, meaning one will be a factor larger or smaller than the other. This factor will be the same for all of the sides. So, we can say that one corresponding pair of sides is equal to another corresponding pair of sides.
BA / ED = AC / CD
42 / 6 = (64 - x) / (x)
6(64 - x) = 42(x)
384 - 6x = 42x
384 = 48x
x = 8
Hope this helps!
If x+y=8 and xy =15 find the value of x³+y³.
Answer:
152Step-by-step explanation:
let x= 5 and y= 3x + y = 85 + 3 = 8xy = 155 × 3 = 15x³ + y³ = ?5³ + 3³ = ?125 + 27 = 152[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
Bianca is planting trees along her driveway, and she has 55 sycamores and 55 palm trees to plant in one row. What is the probability that she randomly plants the trees so that all 55 sycamores are next to each other and all 55 palm trees are next to each other
Answer:
0.0079 = 0.79% probability that she randomly plants the trees so that all 5 sycamores are next to each other and all 5 palm trees are next to each other.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The trees are arranged, so, to find the number of outcomes, the arrangements formula is used.
Arrangements formula:
The number of possible arrangements of n elements is given by:
[tex]A_n = n![/tex]
Desired outcomes:
5 sycamores(5! possible ways) and then the 5 palm trees(5! possible ways)
5 palm trees(5! possible ways) then the 5 sycamores(5! possible ways).
[tex]D = 2*5!*5![/tex]
Total outcomes:
Arrangements of 10 plants, so:
[tex]T = 10![/tex]
What is the probability that she randomly plants the trees so that all 5 sycamores are next to each other and all 5 palm trees are next to each other?
[tex]p = \frac{D}{T} = \frac{2*5!*5!}{10!} = 0.0079[/tex]
0.0079 = 0.79% probability that she randomly plants the trees so that all 5 sycamores are next to each other and all 5 palm trees are next to each other.
Find x on this special right triangle
Answer:
the ans is 45⁰ BC it is a right angle
Step-by-step explanation:
Is this a trigonometry ratio
Use the following conversions to answer the question.
60 seconds = 1 minute
60 minutes = 1 hour
24 hours = 1 day
How many minutes are there in a week?
A. 420
B. 1,400
C. 10,080
D. 604,800
Answer:
C. 10,080
Step-by-step explanation:
We can multiply to find how many minutes there are in 1 day.
24 * 60 = 1,440
Now, we can multiply that value by 7 to find out how many minutes there are in 1 week.
1,440 * 7 = 10,080
Best of Luck!
Which of the following will result in a rational answer? multiplying pi by a fraction. adding the square root of a non perfect square to a whole number. adding the square root of a perfect square to pi. multiplying a fraction by a repeating decimal.
Correct option is "multiplying a fraction by a repeating decimal."
Explanation:
Since multiplying a fraction is a rational and repeating decimal is also rational, therefore, it's result is also rational.
Hope it helps you... pls mark brainliest if it helped you
Suppose that the probability that a person will develop hypertension over a life time is 60%. Of 13 graduating students from the same college are selected at random. find the mean number of the students who develop hypertension over a life time
Answer:
The mean number of the students who develop hypertension over a life time is 7.8.
Step-by-step explanation:
For each person, there are only two possible outcomes, either they will develop hypertension, or they will not. The probability of a person developing hypertension is independent of any other person, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
Suppose that the probability that a person will develop hypertension over a life time is 60%.
This means that [tex]p = 0.6[/tex]
13 graduating students from the same college are selected at random.
This means that [tex]n = 13[/tex]
Find the mean number of the students who develop hypertension over a life time
[tex]E(X) = np = 13*0.6 = 7.8[/tex]
The mean number of the students who develop hypertension over a life time is 7.8.
Solve for x
(x-5) ²+5 =49
Answer:
x = 5±2 sqrt(11)
Step-by-step explanation:
(x-5) ²+5 =49
Subtract 5 from each side
(x-5) ²+5-5 =49-5
(x-5) ² =44
Take the square root of each side
sqrt((x-5) ²) =±sqrt(44)
sqrt((x-5) ²) =±sqrt(4*11)
x-5 = ±2 sqrt(11)
Add 5 to each side
x-5+5 = 5±2 sqrt(11)
x = 5±2 sqrt(11)
Answer:
[tex]\left(x-5\right)^2+5=49[/tex]
Subtract 5 from both sides
[tex]\left(x-5\right)^2+5-5=49-5[/tex]
[tex]\left(x-5\right)^2=44[/tex]
[tex]x-5=\sqrt{44}[/tex]
[tex]44=2^{2} \times11[/tex]
[tex]x-5=\sqrt{11} \sqrt{2^{2} }[/tex]
Radical rule:- [tex]\sqrt[n]{a^{n} } =a[/tex]
[tex]x-5=2\sqrt{11}[/tex]
Add 5 to both sides
[tex]x=2\sqrt{11}+5[/tex]
-------
[tex]x-5=-2\sqrt{11}[/tex]
Add 5 to both sides
[tex]x-5=-2\sqrt{11}[/tex]
Ans: [tex]x=2\sqrt{11}+5,\:x=-2\sqrt{11}+5[/tex]
OAmalOHopeO
Make a substitution to express the integrand as a rational function and then evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.)
2 sec^2(t)/tan^2(t) + 14 tan(t) + 48 dt
Complete the square in the denominator to get
tan²(t ) + 14 tan(t ) + 48 = tan²(t ) + 14 tan(t ) + 49 - 1
… = (tan(t ) + 7)² - 1
Substitute u = tan(t ) + 7 and du = sec²(t ) dt. Then the integral becomes
[tex]\displaystyle \int \frac{2\sec^2(t)}{\tan^2(t)+14\tan(t)+48} \,\mathrm dt = 2 \int \frac{\mathrm du}{u^2-1}[/tex]
Separate the integrand into partial fractions:
[tex]\dfrac1{u^2-1} = \dfrac12 \left(\dfrac1{u-1}-\dfrac1{u+1}\right)[/tex]
Then we get
[tex]\displaystyle \int \frac{2\sec^2(t)}{\tan^2(t)+14\tan(t)+48} \,\mathrm dt = \int \left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm du \\\\ =\ln|u-1|-\ln|u+1| + C \\\\ = \ln\left|\frac{u-1}{u+1}\right|+C \\\\ = \boxed{\ln\left|\frac{\tan(t)+6}{\tan(t)+8}\right|+C}[/tex]
The temperature in Kansas City varies greatly some days. One day in January, the temperature was 16 degrees but then the temperature decreased by 23 degrees by midnight. What was the temperature at midnight?
Answer:
-7 degrees
Step-by-step explanation:
the temperature was 16 degrees then was the decrease by 23 degrees so subtract 23 from 16 and the answer is -7
Which of the following is an example of a sample that would NOT be random?
A. Going through the list and choosing the first 25 names on the list.
B. Writing each student’s name on a card and then drawing out 25 names without looking.
C. Choosing one student at random from the list and going through the list and choosing every fifth student until she has 25 names.
D. Separating the students on the list into boys and girls and choosing a sample from each group that is proportional to the size of the group.
Answer: D
"Separating the students on the list into boys and girls and choosing a sample from each group that is proportional to the size of the group."
Step-by-step explanation:
You are sampling an equal amount of boys and girls since your getting an equal sample of each gender. (Not random)
The option that is not a random sample is:
Separating the students on the list into boys and girls and choosing a sample from each group that is proportional to the size of the group.
Option D is the correct answer.
What is random sampling?It is the way of choosing a number of required items from a population given.
Each item has an equal probability of being chosen.
We have,
We will see which option is a sample that is not random.
A. Going through the list and choosing the first 25 names on the list.
Going through the list means every name has an equal chance of getting chosen.
This is a random sample.
B. Writing each student’s name on a card and then drawing out 25 names without looking.
Since we are drawing out 25 names without looking, all the students' names have an equal chance of getting drawn.
This is a random sample.
C. Choosing one student at random from the list and going through the list and choosing every fifth student until she has 25 names.
Choosing one student at random means every student has an equal chance of getting chosen.
This is a random sampling.
D. Separating the students on the list into boys and girls and choosing a sample from each group that is proportional to the size of the group.
The students are separated into boys and girls and the sample is chosen from each group so we are selecting the sample from the separated group.
This can not be a random sampling.
Thus,
The option that is not a random sample is:
Separating the students on the list into boys and girls and choosing a sample from each group that is proportional to the size of the group.
Option D is the correct answer.
Learn more about random sampling here:
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The length of a rectangle is five times the width if the area of the rectangle is 180 in.² then find the length and the width
Let breadth be x
Length=5x
ATQ
[tex]\\ \sf \longmapsto Area=Length\times breadth[/tex]
[tex]\\ \sf \longmapsto 5x(x)=180[/tex]
[tex]\\ \sf \longmapsto 5x^2=180[/tex]
[tex]\\ \sf \longmapsto x^2=\dfrac{180}{5}[/tex]
[tex]\\ \sf \longmapsto x^2=36[/tex]
[tex]\\ \sf \longmapsto x=\sqrt{36}[/tex]
[tex]\\ \sf \longmapsto x=6in[/tex]
Width=6inLength=6×5=30inWrite each decimal as a fraction or mixed number in simplest form.
1 3/8
3/2
Step One: 1 3/8, transform the number into a improper fraction:
To have a mixed number in to a improper fraction, you need to use addition and multiplication. For 1 3/8, We first multiply the denominator (8, also know to be the bottom number of the fraction) to the whole number (1). 8x1= 8NOTE: The original denominator (8) will be use for are improper, again playing as the denominator, we only multiply the denominator for the numerator (which is the top number of a fraction).After multiplying, we'll add are product with the numerator (3) for the process. 8+3= 12 Now we have both numerator and denominator for 1 3/8, we can create the improper fraction. 12 as the numerator and 8 as the denominator. 12/8We still need to simplify the number. To that, we need the biggest whole number, or rather I call it the lowest number, that can be divide both in 12 and 8. 4 can be divide by both number so: 12/4= 3 and 8/4=2Now 3 is are simplify numerator and 2 is are simplify denominator.Find the value of x.
Answer:
[tex]here \: the \: two \: sides \: are \: equal \: so \: \\ the \: triangle \: is \: issosceles \\ then \: x = 40 \\ thank \: you[/tex]