Which angle is the vertical angle toBEC

Options :

A.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded below the line

B.The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded above the line.

C. The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded below the line.

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Answer:

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Step-by-step explanation:

The equation y > 3x – 8

Interpreting as a linear relation :

y > ax + b

Where, a = slope ; b = intercept

a = 3 ; that is a slope value of 3

b = -8 ; that is an intercept value of - 8

Since the inequality is >, a dashed line is used (dashed like is used for > and <) ; since we a have a greater than sign, the graph will be shaded above the dashed line.

Answer: The answer is D on edu 2021

Step-by-step explanation:

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Answer:

sin(x)

Step-by-step explanation:

sec x tanx(1 - sin^2 x)

1 - sin^2 x = cos^2 x

sec(x)tan(x)cos^2(x)

[tex]\frac{1}{cos(x)}[/tex] * [tex]\frac{sin(x)}{cos(x)}[/tex] * cos^2(x)

[tex]\frac{sin(x)cos^2(x)}{cos^2(x)}[/tex]

sin(x)

Answer: hello your question was poorly written but i was able to the get missing parts online which enabled me resolve your question

answer:

a) a = 0.1096

b) 1.89 watts

Step-by-step explanation:

Std of output voltage = 0.25 volt

H0 : μ = 5 volts

Ha : μ ≠ 5 volts

n = 16

a) Acceptance region = 4.9 ≤ X ≤ 5.1  

Determine the value of a

value of a = 0.0548 + 0.0548

                 = 0.1096

attached below is the reaming solution

note : a is a type 1 error

b) power of test

True mean output voltage = 5.1 volts

P = - 1.89 watts

power cant be negative hence the power of the test  = 1.89 watts

Answer:

$1.50

Step-by-step explanation:

so its

4.5 ÷ 3

which

1.5

Answer:

(in the image)

Step-by-step explanation:

I'm not sure I understood your question completely but I hope this helps.

Answer:

A

Step-by-step explanation:

Number of suitcases on a plane is discrete because you can only have an integer amount. You can't have a fraction of a suitcase on a plane.

Recall that variation of parameters is used to solve second-order ODEs of the form

y''(t) + p(t) y'(t) + q(t) y(t) = f(t)

so the first thing you need to do is divide both sides of your equation by t :

y'' + (2t - 1)/t y' - 2/t y = 7t

You're looking for a solution of the form

[tex]y=y_1u_1+y_2u_2[/tex]

where

[tex]u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]

[tex]u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]

and W denotes the Wronskian determinant.

Compute the Wronskian:

[tex]W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}[/tex]

Then

[tex]u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t[/tex]

[tex]u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}[/tex]

The general solution to the ODE is

[tex]y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}[/tex]

which simplifies somewhat to

[tex]\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}[/tex]

Answer:

Jon Applebe withdrew 37.15% of the amount he initially deposited.

Step-by-step explanation:

Given that Jon Applebee deposited $ 619 in his savings account, and I have later withdrew $ 230, to determine the integer that represents the amount Jon Applebee deposited the following calculation must be performed:

619 = 100

230 = X

230 x 100/619 = X

23,000 / 619 = X

37.15 = X

Therefore, Jon Applebe withdrew 37.15% of the amount he initially deposited.

The answer is (a)..........

Answer:

[tex] { - 3}^{2} + (4 + 7)(2) \\ = - 9 + 22 \\ = 13[/tex]

Answer:

hello there here is your answer

51 is your next term.

Step-by-step explanation:

you are subtracting 9 from each number

95-9= 86

86-9=78

78-9=65

65-9=60

60-9=51

so on and so on

Hope this help

have a good day

bye

Step-by-step explanation:

[tex]here \: is \: your \: solution: - \\ \\ given \: number \: = 95.86.78.71.65.60 \\ \\ = > 95 - 9 = 86 \\ \\ = > 86 - 8 = 78 \\ \\ = > 78 - 7 = 71 \\ \\ = > 71 - 6 = 65 \\ \\ = > 65 - 5 = 60 \\ \\ \: now \: follow \: the \: sequence \: \\ \\ subtract \: 4 \: from \: 60 \\ \\ = > 60 - 4 = 56 \\ \\ = > \: \: 56 \: \:( ANSWER✓✓✓)[/tex]

Answer: [tex]\$1.45[/tex]; [tex]\$3.6[/tex]

Step-by-step explanation:

Given

A dozen roses in a gift box costs $21

Similarly, 20 roses in a gift box costs $32.6

Suppose the price of single rose and gift box is [tex]x[/tex] and [tex]y[/tex]

[tex]\therefore 12x+y=21\quad \ldots(i)\\\Rightarrow 20x+y=32.6\quad \ldots(ii)[/tex]

Solving (i) and (ii) ,  we get

[tex]x=\$1.45;y=\$3.6[/tex]

Thus, the price of the one rose is [tex]\$1.45[/tex] and the price of gift box is [tex]\$3.6[/tex]

Answer:

1.45 and 3.5

Step-by-step explanation:

Answer:

Slope = [tex]\frac{4}{3}[/tex]

Equation of the line → [tex]y=\frac{4}{3}x[/tex]

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = [tex]\frac{4-0}{3-0}[/tex]

m = [tex]\frac{4}{3}[/tex]

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

[tex]y=\frac{4}{3}x[/tex]

Answer:

ΔEFG ~ ΔRPQ - Angle Angle Angle Theorem

ΔEFG ~ ΔRFQ - Side Side Side Proportional Theorem

Step-by-step explanation:

First set : using triangle sum theory to find missing angle. Letters should match congruent angles when creating statement.

Second set :

[tex]\frac{EG}{RQ}[/tex] = [tex]\frac{10}{12}[/tex] =  [tex]\frac{5}{6}[/tex]

[tex]\frac{EF}{RF}[/tex] =  [tex]\frac{15}{18}[/tex] =  [tex]\frac{5}{6}[/tex]

[tex]\frac{FG}{FQ}[/tex] =  [tex]\frac{20}{24}[/tex] =  [tex]\frac{5}{6}[/tex]

Answer:

Step-by-step explanation:

It’s G

Answer:

(A - B) - C = { 1 , 4 , 6 , 7 }

Step-by-step explanation:

A = { 1 , 2 , 3 , 4 , 5 }

B = { 4 , 5 , 6 , 7 }

A - B = { 1 , 2, 3 ,6 , 7 }

C = { 2 , 3 , 4 }

(A - B) - C = { 1 , 4 , 6 , 7 }

===========================================================

Explanation:

We have these two functions

which represent the amounts for his friend and William in that order. Strangely your teacher mentions William first, but then swaps the order when listing the exponential function as the first. This might be slightly confusing.

The table of values is shown below. We have t represent the number of years and t starts at 0.5. It increments by 0.1

The f(t) and g(t) columns represent the outputs for those mentioned values of t. For example, if t = 0.5 years (aka 6 months) then f(t) = 12.48 and that indicates his friend has 12,480 dollars in the account.

I've added a fourth column labeled |f - g| which represents the absolute value of the difference of the f and g columns. If f = g, then f-g = 0. The goal is to see if we get 0 in this column or try to get as close as possible. This occurs when we get 0.09 when t = 1.0

So we don't exactly get f(t) and g(t) perfectly equal, but they get very close when t = 1.0

It turns out that the more accurate solution is roughly t = 0.9925 which is close enough. I used a graphing calculator to find this approximate solution.

It takes about a year for the two accounts to have the same approximate amount of money.

Answer:

B

Step-by-step explanation:

Answer:

a. 18.34 s b. 327.92 m

Step-by-step explanation:

a. How long before the police car catches the speeder who continued traveling at 40 miles/hour

The acceleration of the car a in 10 s from 0 to 55 mi/h is a = (v - u)/t where u = initial velocity = 0 m/s, v = final velocity = 55 mi/h = 55 × 1609 m/3600 s = 24.58 m/s and t = time = 10 s.

So, a =  (v - u)/t =  (24.58 m/s - 0 m/s)/10 s = 24.58 m/s ÷ 10 s = 2.458 m/s².

The distance moved by the police car in 10 s is gotten from

s = ut + 1/2at² where u = initial velocity of police car = 0 m/s, a = acceleration = 2.458 m/s² and t = time = 10 s.

s = 0 m/s × 10 s + 1/2 × 2.458 m/s² (10)²

s = 0 m + 1/2 × 2.458 m/s² × 100 s²

s = 122.9 m

The distance moved when the police car is driving at 55 mi/h is s' = 24.58 t where t = driving time after attaining 55 mi/h

The total distance moved by the police car is thus S = s + s' = 122.9 + 24.58t

The total distance moved by the speeder is S' = 40t' mi = (40 × 1609 m/3600 s)t' =  17.88t' m where t' = time taken for police to catch up with speeder.

Since both distances are the same,

S' = S

17.88t' = 122.9 + 24.58t

Also, the time  taken for the police car to catch up with the speeder, t' = time taken for car to accelerate to 55 mi/h + rest of time taken for police car to catch up with speed, t

t' = 10 + t

So, substituting t' into the equation, we have

17.88t' = 122.9 + 24.58t

17.88(10 + t) = 122.9 + 24.58t

178.8 + 17.88t = 122.9 + 24.58t

17.88t - 24.58t = 122.9 - 178.8

-6.7t = -55.9

t = -55.9/-6.7

t = 8.34 s

So, t' = 10 + t

t' = 10 + 8.34

t' = 18.34 s

So, it will take 18.34 s before the police car catches the speeder who continued traveling at 40 miles/hour

b. how far before the police car catches the speeder who continued traveling at 40 miles/hour

Since the distance moved by the police car also equals the distance moved by the speeder, how far the police car will move before he catches the speeder is given by S' = 17.88t' = 17.88 × 18.34 s = 327.92 m

Answer:

13/17

Step-by-step explanation:

Answer:

0.015 = 1.5% probability that the mean monitor life would be greater than 83.8 months in a sample of 71 monitors

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean life of 82 months with a standard deviation of 7 months.

This means that [tex]\mu = 82, \sigma = 7[/tex]

Sample of 71

This means that [tex]n = 71, s = \frac{7}{\sqrt{71}}[/tex]

What is the probability that the mean monitor life would be greater than 83.8 months?

1 subtracted by the p-value of Z when X = 83.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{83.8 - 82}{\frac{7}{\sqrt{71}}}[/tex]

[tex]Z = 2.17[/tex]

[tex]Z = 2.17[/tex] has a p-value of 0.985.

1 - 0.985 = 0.015

0.015 = 1.5% probability that the mean monitor life would be greater than 83.8 months in a sample of 71 monitors

Answer:

x is down and up and y is up then down

Step-by-step explanation:

I think

Answer:

Slope is undefined. Line parallel to y-axis.

Step-by-step explanation:

By Analytic Geometry, we can determine the slope of a line by knowing two distinct lines and using the definition of secant line:

[tex]m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] (1)

Where:

[tex](x_{1}, y_{1})[/tex] - Coordinates of the initial point.

[tex](x_{2}, y_{2})[/tex] - Coordinates of the final point.

[tex]m[/tex] - Slope.

If we know that [tex](x_{1}, y_{1}) = (17, -13)[/tex] and [tex](x_{2}, y_{2}) = (17, 8)[/tex], then the slope of the line is:

[tex]m = \frac{8-(-13)}{17-17}[/tex]

[tex]m = \frac{21}{0}[/tex]

The slope is undefined, which means that line is parallel to y-axis.

Answer:

eh width = 103.5 inches

Step-by-step explanation:

x = width

Length = (x/2 - 5 )*6

so 384=x+3x-30

414=4x

x=414/4=103.5 inches

I believe your answer is D.) $900

204 + 96 = 300

300 x 3 = 900

I hope this is correct and helps!

Answer:

36 introverts

Step-by-step explanation:

Total number of adults in the survey = 120

Ratio of introverts to extroverts = 3:7

Number of introverts = ratio number of introverts / ratio total × 120

Ratio number of introverts = 3

Ratio total = 3 + 7 = 10

Number of introverts = 3/10 × 120

= 36

Answer:

See explanation

Step-by-step explanation:

Given

[tex]M \to[/tex] randomly selecting a male

[tex]B \to[/tex] randomly selecting someone with blue eyes

Solving (a): Interpret P(M|B)

The above implies conditional probability

The interpretation is: the probability of selecting a male provided that a person with blue eyes has been selected

Solving (b): is (a) the same as P(B|M)

No, they are not the same.

The interpretation of P(B|M) is: the probability of selecting a person with blue eyes provided that a male has been selected