Which best describes what forms in nuclea fission?
O two smaller, more stable nuclei
O two larger, less stable nuclei
• one smaller, less stable nucleus
one larger, more stable nucleus

Answer: the answer is 12/13

Answer:

2 feet

Step-by-step explanation:

Displacement at 0 seconds is 0 feet.

Displacement at 2 seconds is 2 feet because it took them 2 seconds to walk 2 feet.

Answer:

(a): The conditional pmf of Y when X = 1

[tex]p_{Y|X}(0|1) = 0.2353[/tex]

[tex]p_{Y|X}(1|1) = 0.5882[/tex]

[tex]p_{Y|X}(2|1) = 0.1765[/tex]

(b): The conditional pmf of Y when X = 2

[tex]p_{Y|X}(0|2) = 0.0962[/tex]

[tex]p_{Y|X}(1|2) = 0.2692[/tex]

[tex]p_{Y|X}(2|2) = 0.6346[/tex]

(c): From (b) calculate P(Y<=1 | X =2)

[tex]P(Y\le1 | X =2) = 0.3654[/tex]

(d): The conditional pmf of X when Y = 2

[tex]p_{X|Y}(0|2) = 0.025[/tex]

[tex]p_{X|Y}(1|2) = 0.150[/tex]

[tex]p_{X|Y}(2|2) = 0.825[/tex]

Step-by-step explanation:

Given

The above table

Solving (a): The conditional pmf of Y when X = 1

This implies that we calculate

[tex]p_{Y|X}(0|1), p_{Y|X}(1|1), p_{Y|X}(2|1)[/tex]

So, we have:

[tex]p_{Y|X}(0|1) = \frac{p(y = 0\ n\ x = 1)}{p(x = 1)}[/tex]

Reading the data from the given table, the equation becomes

[tex]p_{Y|X}(0|1) = \frac{0.08}{0.08+0.20+0.06}[/tex]

[tex]p_{Y|X}(0|1) = \frac{0.08}{0.34}[/tex]

[tex]p_{Y|X}(0|1) = 0.2353[/tex]

Using the format of the above formula for the rest, we have:

[tex]p_{Y|X}(1|1) = \frac{0.20}{0.34}[/tex]

[tex]p_{Y|X}(1|1) = 0.5882[/tex]

[tex]p_{Y|X}(2|1) = \frac{0.06}{0.34}[/tex]

[tex]p_{Y|X}(2|1) = 0.1765[/tex]

Solving (b): The conditional pmf of Y when X = 2

This implies that we calculate

[tex]p_{Y|X}(0|2), p_{Y|X}(1|2), p_{Y|X}(2|2)[/tex]

So, we have:

[tex]p_{Y|X}(0|2) = \frac{p(y = 0\ n\ x = 2)}{p(x = 2)}[/tex]

Reading the data from the given table, the equation becomes

[tex]p_{Y|X}(0|2) = \frac{0.05}{0.05+0.14+0.33}[/tex]

[tex]p_{Y|X}(0|2) = \frac{0.05}{0.52}[/tex]

[tex]p_{Y|X}(0|2) = 0.0962[/tex]

Using the format of the above formula for the rest, we have:

[tex]p_{Y|X}(1|2) = \frac{0.14}{0.52}[/tex]

[tex]p_{Y|X}(1|2) = 0.2692[/tex]

[tex]p_{Y|X}(2|2) = \frac{0.33}{0.52}[/tex]

[tex]p_{Y|X}(2|2) = 0.6346[/tex]

Solving (c): From (b) calculate P(Y<=1 | X =2)

To do this, where Y = 0 or 1

So, we have:

[tex]P(Y\le1 | X =2) = P_{Y|X}(0|2) + P_{Y|X}(1|2)[/tex]

[tex]P(Y\le1 | X =2) = 0.0962 + 0.2692[/tex]

[tex]P(Y\le1 | X =2) = 0.3654[/tex]

Solving (d): The conditional pmf of X when Y = 2

This implies that we calculate

[tex]p_{X|Y}(0|2), p_{X|Y}(1|2), p_{X|Y}(2|2)[/tex]

So, we have:

[tex]p_{X|Y}(0|2) = \frac{p(x = 0\ n\ y = 2)}{p(y = 2)}[/tex]

Reading the data from the given table, the equation becomes

[tex]p_{X|Y}(0|2) = \frac{0.01}{0.01+0.06+0.33}[/tex]

[tex]p_{X|Y}(0|2) = \frac{0.01}{0.40}[/tex]

[tex]p_{X|Y}(0|2) = 0.025[/tex]

Using the format of the above formula for the rest, we have:

[tex]p_{X|Y}(1|2) = \frac{0.06}{0.40}[/tex]

[tex]p_{X|Y}(1|2) = 0.150[/tex]

[tex]p_{X|Y}(2|2) = \frac{0.33}{0.40}[/tex]

[tex]p_{X|Y}(2|2) = 0.825[/tex]

Answer: [tex]t\in [\dfrac{1}{4},2][/tex]

Step-by-step explanation:

Given

Inequality is [tex]4t^2\leq9t-2[/tex]

Taking variables one side

[tex]\Rightarrow 4t^2-9t+2\leq0\\\Rightarrow 4t^2-8t-t+2\leq0\\\Rightarrow 4t(t-2)-1(t-2)\leq0\\\Rightarrow (4t-1)(t-2)\leq0[/tex]

Using wavy curve method

[tex]t\in [\dfrac{1}{4},2][/tex]

Answer:

To find the surface area of a cuboid we can also label the length, width and the height of the prism and use the formula SA=2LW+2LH+2HW to find the area of a cuboid

Answer:

202 cm²

Step-by-step explanation:

The opposite faces of a cuboid are congruent , then

SA = top/bottom + front/ back + sides , that is

SA = 2(9 × 4) + 2(9 × 5) + 2(4 × 5)

     = 2(36) + 2(45) + 2(20)

     = 72 + 90 + 40

    = 202 cm²

9514 1404 393

Answer:

  29.4 m/s

Step-by-step explanation:

Speed is proportional to time, so we have ...

  speed / time = s/3 = 49/5

  s = 3/5(49) = 29.4

The speed of the object is 29.4 m/s after 3 seconds.

Answer:

median

Step-by-step explanation:

Q is at the midpoint of RS and so PQ is a median

A median is a segment from a vertex to the midpoint of the opposite side.

We want to define what type of line is PQ (the line that passes through points P and Q) by looking at the given image, one can easily see that the line PQ is a median, now let's explain why.

First, let's analyze the image:

In the image, we can see that P is one vertex of the triangle, and Q is the midpoint of the segment RS (you can see that RQ = 4 and QS = 4) , where R and S are the other two vertexes of the triangle.

Particularly, we can define a median of a triangle as the line that passes through the midpoint of one side of the triangle and by the vertex that does not belong to that side.

With that definition, we can see that PQ is a median because Q is the midpoint of one side of the triangle and P is the vertex that does not belong to that side.

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Answer:

[tex]m = \frac{1}{12}[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (36,6)[/tex]

[tex]f(x) = \sqrt x[/tex] ----- the equation of the curve

Required

The slope of f(x)

The slope (m) is calculated using:

[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]

[tex](x,y) = (36,6)[/tex] implies that:

[tex]a = 36; f(a) = 6[/tex]

So, we have:

[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]

[tex]m = \lim_{h \to 0} \frac{f(36 + h) - 6}{h}[/tex]

If [tex]f(x) = \sqrt x[/tex]; then:

[tex]f(36 + h) = \sqrt{36 + h}[/tex]

So, we have:

[tex]m = \lim_{h \to 0} \frac{\sqrt{36 + h} - 6}{h}[/tex]

Multiply by: [tex]\sqrt{36 + h} + 6[/tex]

[tex]m = \lim_{h \to 0} \frac{(\sqrt{36 + h} - 6)(\sqrt{36 + h} + 6)}{h(\sqrt{36 + h} + 6)}[/tex]

Expand the numerator

[tex]m = \lim_{h \to 0} \frac{36 + h - 36}{h(\sqrt{36 + h} + 6)}[/tex]

Collect like terms

[tex]m = \lim_{h \to 0} \frac{36 - 36+ h }{h(\sqrt{36 + h} + 6)}[/tex]

[tex]m = \lim_{h \to 0} \frac{h }{h(\sqrt{36 + h} + 6)}[/tex]

Cancel out h

[tex]m = \lim_{h \to 0} \frac{1}{\sqrt{36 + h} + 6}[/tex]

[tex]h \to 0[/tex] implies that we substitute 0 for h;

So, we have:

[tex]m = \frac{1}{\sqrt{36 + 0} + 6}[/tex]

[tex]m = \frac{1}{\sqrt{36} + 6}[/tex]

[tex]m = \frac{1}{6 + 6}[/tex]

[tex]m = \frac{1}{12}[/tex]

Hence, the slope is 1/12

Answer:

[tex]{ \tt{rate \: of \: change \: in \: A = 9}}[/tex]

Rate of change in function A is two times than that in function B

Answer:

(a)So, there are 2 kings in red- one of hearts and the other of diamonds. Therefore, the probability of selecting a red king from a deck of cards= 2/52 or 1/26.

(b) There are 6 red face cards in a 52-card deck (so 46 other cards). PROBABILITIES compare the number of favorable outcomes to the total number of possible outcomes: The PROBABILITY of getting a red face card is 6/52 = 3/26.

The odds in favor of getting a red king will be 1/26. And the odds against getting a red king will be 25/26.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

You are dealt one card from a 52-card deck.

Total events = 52

The odds in favor of getting a red king will be

Favorable events = 2

Then the probability will be

P = 2/52

P = 1/26

The odds against getting a red king will be

q = 1 – P

q = 1 – 1/26

q = 25/26

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Answer:

1/108

Step-by-step explanation:

each denominator triples, so just triple 36.

Answer:

1/108

Step-by-step explanation:

This is a geometric sequence, where each number is 3 times the previous. Normally you would use the actual formula, however you're just asked to pick up on a pattern so just multiplying the second number by 3 works.

Hi!

√80 = √(16 • 5) = √(4² • 5) = 4√5

I think you are asked to find the value of the first derivative of f(x) at π/4. Given

[tex]f(x) = \dfrac{\sin(4x)-\cos(x)}{\tan(x)}[/tex]

use the quotient to differentiate and you get

[tex]f'(x) = \dfrac{\tan(x)(4\cos(4x)+\sin(x))-(\sin(4x)-\cos(x))\sec^2(x)}{\tan^2(x)}[/tex]

Then at x = π/4, you have

tan(π/4) = 1

cos(4•π/4) = cos(π) = -1

sin(π/4) = 1/√2

sin(4•π/4) = sin(π) = 0

cos(π/4) = 1/√2

sec(π/4) = √2

==>   f ' (π/4) = (1•(-4 + 1/√2) - (0 - 1/√2)•(√2)²) / 1² = -4 + 1/√2 + √2

Answer:

108 square metres

Step-by-step explanation:

A=√d square - l square

here

A = area

d= diagonal

l= length

Answer:

The p-value of the test is 0.015 < 0.05, which means that there is sufficient evidence at the 0.05 level to support the company's claim.

Step-by-step explanation:

The company's promotional literature claimed that more than 47% do not fail in the first 1000 hours of their use.

At the null hypothesis, we test if the proportion is of 47% or less, that is:

[tex]H_0: p \leq 0.47[/tex]

At the alternative hypothesis, we test if the proportion is of more than 47%, that is:

[tex]H_1: p > 0.47[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.47 is tested at the null hypothesis:

This means that [tex]\mu = 0.47, \sigma = \sqrt{0.47*0.53}[/tex]

A sample of 1300 computer chips revealed that 50% of the chips do not fail in the first 1000 hours of their use.

This means that [tex]n = 1300, X = 0.5[/tex]

Value of the statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.5 - 0.47}{\frac{\sqrt{0.47*0.53}}{\sqrt{1300}}}[/tex]

[tex]z = 2.17[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.5, which is 1 subtracted by the p-value of z = 2.17.

Looking at the z-table, z = 2.17 has a p-value of 0.9850

1 - 0.985 = 0.015

The p-value of the test is 0.015 < 0.05, which means that there is sufficient evidence at the 0.05 level to support the company's claim.

Answer:

121 unit^2.

Step-by-step explanation:

The area = height/2 * ( sum of the opposite parallel  lines)

= h/2(BC + AD

h = BF = 14 - 3 = 11 units.

BC   = 13 - 5 = 8 units.

AD = 16 - 2 = 14 units.

Area = (11/2)(8 + 14)

= 5.5 * 22

= 121 unit^2.

Answer:

121

Step-by-step explanation:

Common difference: 6

First term: 7

Second term: 13

Third term: 19

Fourth term: 25

Fifth term: 31

I hope this is correct and helps!

Answer to the following question is as follows;

Number of term in AP (N) = 10

Step-by-step explanation:

Given:

Sum of arithmetic progression (Sn) = 340

First term of AP (a) = 7

Common difference of AP (d) = 6

Find;

Number of term in AP (N)

Computation:

Sn = [n/2][2a + (n-1)d]

340 = [n/2][2(7) + (n-1)6]

340 = [n/2][14 + 6n - 6]

680 = n[6n + 8]

6n² + 8n - 680

Using Quadratic Formula

n = 10

Number of term in AP (N) = 10

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Answer:

129469.3194

342000

212530.6806

Step-by-step explanation:

Going to assume that the 8% is a nominal, montly rate

which means the effective monthly rate is .08/12= .006667

using the annuity immediate formula...

a.)

[tex]950(\frac{1-(1+.006667)^{-30*12}}{.006667})=129469.3194[/tex]

b.) we would pay 950*30*12= 342000

c.) the amount in interest would be 342000-129469.3194=212530.6806

a) The loan one can afford is $1,29,460.2

b) The total amount of money paid to the loan company over the life of the loan is $342,000.

c)  $212539.8 of the total amount paid is interest.

To determine the answers to these questions, we'll need to use the formula for calculating a fixed monthly mortgage payment:

[tex]M = \frac{P \times r \times (1 + r)^n}{((1 + r)^n - 1)}[/tex]

where:

M is the monthly payment,

P is the principal loan amount,

r is the monthly interest rate (annual interest rate divided by 12),

and n is the total number of payments (number of years multiplied by 12).

Given:

Monthly payment (M) = $950

Loan term = 30 years

Interest rate = 8% per year

a) How big of a loan can you afford?

Let's calculate the principal loan amount (P):

First, we need to convert the annual interest rate to a monthly interest rate:

r = 0.08 / 12

= 0.00667

n = 30 years × 12 months

n= 360

Using the formula and plugging in the values we have:

[tex]950 = \frac{P \times 0.00667 \times (1 + 0.00667)^{360}}{((1 + 0.00667)^{360} - 1)}[/tex]

[tex]950 = \frac{P \times 0.00667 \times 10.948}{10.948 - 1}[/tex]

[tex]950=\frac{P \times 0.07302316}{9.948}[/tex]

[tex]950\times9.948 = 0.0730P[/tex]

Divide by 0.073:

Now we can solve for P:

[tex]P=\frac{9450.6}{0.0730}[/tex]

[tex]P = 1,29,460.2[/tex]

Therefore, you can afford a loan amount of $1,29,460.2

b) The total amount paid to the loan company can be calculated by multiplying the monthly payment by the total number of payments:

Total amount = Monthly payment × Total number of payments

Total amount =[tex]$950 \times 360[/tex]

Total amount = [tex]342,000[/tex]

Therefore, the total amount of money paid to the loan company over the life of the loan is $342,000.

c) To find out how much of the total amount paid is interest, we can subtract the principal loan amount from the total amount:

Interest = Total amount - Principal loan amount

Interest = [tex]342,000 - 129460.2[/tex]

=$212539.8

Therefore, $212539.8 of the total amount paid is interest.

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Actual data table :

X __ y

2 15

6 13

7 9

8 8

12 5

Answer:

0.953

Step-by-step explanation:

The question isnt well formatted :

The actual data:

X __ y

2 15

6 13

7 9

8 8

12 5

Using a correlation Coefficient calculator, the correlation Coefficient obtained by fitting the data is 0.953 which depicts a strong linear correlation between the x and y variable. This shows that the value of y increases with a corresponding increase in x values and vice versa.

step by step explanation:

[tex]\mathfrak{x}^{2}+{y}^{2}+16=0[/tex]

=[x2+16=0x26]

=[2x{y}^2{16}~0]

=[4×{y}^0{16}]

=[32x{y}^x]

Answer:

A and b Are in quadrant 2. F and D are in quadrant 1. F is in quadrant 3 and C is in quadrant 4

Step-by-step explanation:

each quadrant is in the boxes and the question is asking what is each  coordinate is in what quadrant

Answer:

D

Step-by-step explanation:

There 2 ways to interpret this problem.

From the info given:

These two triangles are congruent by SSS and congruent triangles have congruent or equal side lengths so the answer have to be 1.

If the triangles are similar, the side lengths form a proportion of that

[tex] \frac{3}{3} = \frac{3}{3} [/tex]

So the ratio or scale factor is 1.

The scale factor in the figure is 1.

A scale factor in math is the ratio between corresponding measurements of an object and a representation of that object.

Given that two triangles, LMN and OPQ, we need to find the scale factor,

We can see triangles are congruent, and we know that

Two triangles are congruent, by the SSS congruence criterion, if they are similar and the scale factor happens to be 1,

Hence, the scale factor in the figure is 1.

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Answer:

x= - 1

Step-by-step explanation:

Answer:

5 yd

Step-by-step explanation:

Formula to find area of a square is a² where each side is a,

So, a²=25

or, a=√25

or, a=±5

since a side can't be negative, so a = 5 yd

Answered by GAUTHMATH

Answer:

22608 mm³/s

Step-by-step explanation:

Applying chain rule,

dV/dt = (dV/dr)(dr/dt)............... Equation 1

Where dV/dr = rate at which the volume is increasing

But,

V = 4πr³/3

Therefore,

dV/dr = 4πr²............... Equation 2

Substitute equation 2 into equation 1

dV/dt = 4πr²(dr/dt).............. Equation 3

From the question,

Given: dr/dt = 2 mm/s, r = 60/2 = 30 mm

Consatant: π = 3.14

Substitute these values into equation 3

dV/dt = 4×3.14×30²×2

dV/dt = 22608 mm³/s

Answer:

[tex]\frac{y^{6} }{ x^{2} }[/tex]

Step-by-step explanation:

[tex]y^{6} x^{-2}[/tex]

Answer and Step-by-step explanation:

When there is a set of values within parenthesis, and an exponents on the values and on the parenthesis, you multiply the outer exponent with the inner exponent.

When a value has a negative exponent, the value that has the negative exponent will become a fraction and go to the denominator of the fraction (or go immediately to the denominator), or if it is already a fraction, goes to the denominator. If the value that has the negative exponent is in the denominator, the value will go to the numerator. In both instances, the negative exponent will then change to positive.

First, we need to simplify the expression inside the parenthesis.

[tex]y^{\frac{3}{2} } x^{-\frac{1}{2} } --> \frac{y^{\frac{3}{2} } }{x^{\frac{1}{2}} }[/tex]

Now we multiply the 4 to the exponents.

[tex]\frac{y^{\frac{3}{2} *\frac{x4}{1} } }{x^{\frac{1}{2}}*\frac{4}{1} } = \frac{y^{\frac{12}{2}} }{x^{\frac{4}{2}}} = \frac{y^6}{x^2}[/tex]

[tex]\frac{y^6}{x^2}[/tex] is the answer.

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