Answer:
CH3—CH2—O—CH2—CH3 is the compound of glycol.
Answer:
HOH2C―CH2―CH2―CH2OH is glycol
Explanation:
Los 4 números cuánticos del oxígeno
if slowing down is the response to seeing a blinking yellow light is it conditioned or unconditioned?
Answer:
Conditioned
Explanation:
Naturally, you do not slow down when you see a yellow light. That response is learned, therefore it is a conditioned response.
what are the six chemicals in production of liquid soaps
1. Sodium triphosphate ·
2. Sodium hydroxide ·
3. potassium hydroxide
4. Sodium Lauryl Sulfate · 5.Hydroxyethylcellulose ·
6. Sodium carbonate
need help w the questions in the pic! thankyouu
Answer: Here are the answers
Explanation:
7a) Calcium Chloride +water+carbon dioxide
b)Calcium Oxide +Carbon dioxide
8a) zinc + carbon monoxide
b) Aluminum + Carbon dioxide
c) Lead + carbon dioxide
Balancing equations
1. __Na + __Oz -> __Na2O
Answer:
Balancing equations
1
[tex]4Na + O_{2} -> 2Na_{2}O[/tex]
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen atoms and 2 oxygen atoms
Answer:
What period is the atom in?
1.
What group is the atom in?
What is the name of this atom?
What other atom would have similar
properties to the atom?
Will this atom conduct electricity well
Explanation:
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen
and 2 oxygen atoms
An empirical research method in which data are gathered from observations of phenomena, hypothesis are formulated and tested, and conclusions are drawn that validate or modify the original hypothesis is known as the: Group of answer choices Gotham theory Scientific Method Niels-Bohr hypothesis Entropy theory
Answer:
Scientific Method
Explanation:
Science is empirical in nature. The entire purpose of science is to discover new knowledge.
The empirical research method in science all begins with gathering observations from phenomena. After that, the researcher formulates appropriate hypothesis which are rigorously tested.
The conclusions drawn from testing the original hypothesis validate or modify the original hypothesis.
The table shows four reactions.
Reactions
Reaction Equation
1 C3H8 + 5O₂ → 3CO₂ + 4H₂O
2 C₂H4 + H₂ → C₂H6
3 AgNO3 + NaCl - AgCl + NaNO3
4 2Fe + O₂ → 2Feo
Which of the above reactions is an example of combustion of an organic substance?
a) 1
b) 2
c) 3
d) 4
Answer:its B
Explanation:
i have done this before! and i got 100 so i hope you got all the other questions right!
The table shows four reactions. The reaction That is an example of combustion of an organic substance is C₂H₄ + H₂ → C₂H₆. The correct option is b) 2.
What are combustion reactions?Combustion reactions are those reactions in which the reactant reacts with oxygen and produces heat and light. An example is the burning of wood, it happens in the presence of oxygen.
Organic compounds are those compounds that are made by carbons. They are made by carbon-carbon or carbon-hydrogen bonds. They are naturally present in nature.
C₂H₄ + H₂ → C₂H₆
The equation above shows the reaction between methane and hydrogen, which is forming ethane in the presence of oxygen.
Thus, the correct option is b) 2. C₂H₄ + H₂ → C₂H₆.
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What is the balance equation for
_AI+_Pb(NO3)2—__Pb+__Ca(NO3)2
Answer:
2 Al + 3 Pb(NO3)2 > 2 Al(NO3)3 + 3 Pb
Explanation:
describe the formation of ionic bonds in potassium chloride compound (5 marks)
Answer:
When the two atoms are in contact, potassium readily transfers its outer electron to chlorine which readily accepts it, resulting in both atoms achieving a state of eight outermost electrons. With this electron transfer, the ionic bond in KCl is formed.
an experiment was carried out and H2SO4 was collected resulting in a 92.0% yield. What mass of H2SO4 was collected from the experiment?
Answer:
The mass of H2SO4 collected is 92.0g assuming the theoretical yield of H2SO4 is 100g
Explanation:
Assuming the theoretical yield of the sulfuric acid, H2SO4, is 100g.
To solve this question we must use the equation of percent yield:
Percent yield = Actual yield / Theoretical yield * 100
Where percent yield = 92.0%, actual yield is the mass of H2SO4 produced and theoretical yield is 100g, the mass we are assuming
Replacing:
92.0% = Actual yield / 100g * 100
92.0g = Actual Yield
The mass of H2SO4 collected is 92.0g assuming the theoretical yield of H2SO4 is 100gneed help asap!!!
so i don’t necessarily need an answer just how to solve everything.
this is the first one:
calcium hydroxide + ammonium chloride
the instructions are attached to this question. i’m just not sure how to do everything. it doesn’t give me the products side only the reactants so how am i supposed to write and balance the equation?
Explanation:
とおふぉくぉをえおろとようおいおぽあおそ・
'」*とまっぉのもヴぉこぉぞぽ、こ、
Answer:
Ca(OH)2 + 2NH4Cl .................. CaCl2 + 2NH3 + 2H2O
Trends in the periodic table indicate that the element with the greatest ionization energy is in which of the following periods and groups?
a
Period 2, Group 1
b
Period 7, Group 2
c
Period 6, Group 17
d
Period 1, Group 18
Answer:
D Period 1, Group 18
Explanation:
it's helium
it's top right corner of the periodic table
Of the following transitions in the Bohr hydrogen atom, which of the following
results in the emission of the lowest-energy photon.
n = 1 ® n= 6
n=5 ® n=1
n = 6® n=1
n=3® n=5
n=1 ® n=5
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?
CSF + XeF6 → CsXeF7
Answer: A mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
Explanation:
Given: Mass of cesium xenon heptafluoride = 73.1 g
The molar mass of cesium xenon heptafluoride is 131.3 g/mol. So, moles of [tex]CsXeF_{7}[/tex] is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{73.1 g}{131.3 g/mol}\\= 0.556 mol[/tex]
According to the given equation, 1 mole of CsF yields 1 mole of [tex]CsXeF_{7}[/tex].
Hence, moles of CsF reacting will also be equal to 0.556 mol. As molar mass of CsF is 151.9 g/mol so its mass is calculated as follows.
[tex]Moles = \frac{mass}{molarmass}\\0.556 mol = \frac{mass}{151.9 g/mol}\\mass = 84.46 g[/tex]
Thus, we can conclude that a mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?
CSF + XeF6 → CsXeF7
Answer:
27.9 g
Explanation:
CsF + XeF₆ → CsXeF₇
First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:
Molar mass of CsXeF₇ = 397.193 g/mol73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.
Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:
Molar mass of CsF = 151.9 g/mol0.184 mol * 151.9 g/mol = 27.9 gPLS HELP!!
Compare and contrast an electrolytic cell with a voltaic cell. Provide one example where both are present in daily life.
Answer:
See explanation
Explanation:
An electrolytic cell functions by a non spontaneous chemical process. Energy is supplied in the form of electricity through a battery to drive the electrochemical process.
A voltaic cell functions by a spontaneous chemical process. Energy or work can be derived from a voltaic cell.
When iron is rusting, a natural voltaic cell is set and the iron is converted to hydrated iron III hydroxide. The set up used for the extraction of sodium metal from brine functions on the basis of electrolysis.
Cuál o cuáles de las siguientes características son correctas para la mayoría de los compuestos del carbono?
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos
IV) El enlace covalente es característico de los compuestos del carbono
Todas son correctas
II
I y IV
I, III y IV
Answer:
Todas son correctas
Explanation:
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc. VERDADERO. La mayoría de los compuestos de carbono son apolares, y basados en la regla: Similar disuelve similar, podemos presumir que la mayoría de compuestos de carbono se disuelven en solventes no polares.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos. VERDADERO. Al ser sustancias apolares, sus fuerzas electrostáticas son bajas. De la misma manera, como su masa atómica es pequeña, las fuerzas de Van der Waals son despreciables haciendo que sus puntos de fusión y ebullición sean bajos respecto a sustancias de estrucutra similar.
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos. VERDADERO. Los gases (Como el gas natural) son combustibles usados para cocina. Los líquidos (Como la gasolina) son combustibles y bastante inflamables. Los sólidos (Como la madera) se usan como combustibles para hacer asados o son el combustible en incendios forestales.
IV) El enlace covalente es característico de los compuestos del carbono. VERDADERO. La polaridad del carbono es neutral haciendo que la mayoría de los enlaces que forma sean covalentes.
Todas son correctas
How does fluorine (F)differ from iodine(I)
A. Fluorine (F) has 3 more energy shells than iodine (I).
B. Fluorine (F) has 1 less energy shell than iodine (I).
C. Fluorine (F) has 1 more energy shell than iodine (I).
D. Fluorine (F) has 3 less energy shells than iodine (I).
Fluorine (F) and iodine(I) are the halogen elements that belong to group 17. They differ from each other as fluorine has 3 fewer energy shells than iodine. Thus, option D is correct.
What are halogen groups?Halogen is a nonmetallic element that belongs to group 17 and consists of six elements namely fluorine, bromine, tennessine, chlorine, astatine, and iodine.
They are diatomic and have 7 valence electrons in the outer shell, which makes them highly reactive and electronegative. The shielding effect is less in F than I due to the closer placement and attraction of the valence electron to the nucleus.
Fluorine differs from iodine as it has a smaller size with fewer energy shells than iodine. Iodine has five energy shells, whereas fluorine has two energy shells that make the difference of three shells between them.
Therefore, F and I differ from each other.
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Write a hypothesis to answer the lesson question
"How can electrolysis be used to separate a
compound into its components?"
If_____ (an electrical current, a salt, an electrode, or oxygen)?
is applied to water
containing an electrolyte, then the water will
decompose into____( water vapor, sodium gas, hydrogen gas, oxygen gas, hydrogen and oxygen gas)?
because____________?
Answer:
Electric current
Hydrogen and oxygen gas
Explanation:
Electrolysis is defined as a method of separation whereby an electric current is introduced into compounds to separate them . The electric current used here is a direct electric current (DC) and it makes the compound to be spit into its' component elements.
Now, in the case of water like it says in the question. Water is a mixture of hydrogen and oxygen gas. Thus, when electric current is passed through water which has an Electrolyte, it makes the water to decompose into its compound elements which are hydrogen and oxygen.
If 46.3 grams of acetylene are required to run a carbide lamp for 8 hours, how many moles of water are required
Answer:
1.78 mol
Explanation:
Step 1: Write the balanced equation
CaC₂ + H₂O ⇒ C₂H₂ + CaO
Step 2: Calculate the moles corresponding to 46.3 g of C₂H₂
The molar mass of C₂H₂ is 26.04 g/mol.
46.3 g × 1 mol/26.04 g = 1.78 mol
Step 3: Calculate the moles of H₂O required to form 1.78 moles of C₂H₂.
The molar ratio of H₂O to C₂H₂ is 1:1. The moles of H₂O required are 1/1 × 1.78 mol = 1.78 mol.
In which of the following will the density increase?
Group of answer choices
An iron bar is heated.
A lead weight is moved from sea level to the top of a high mountain.
A sample of water is frozen.
A diamond is submerged in water.
A sample of chlorine gas is compressed.
True or false, In a neutral atom of an element, the number of protons always equals the number of electrons.
Answer:
true
Explanation:
As an atom with no charge have same number of proton and electrons
A 80°C la presion de vapor del benceno (C6H6) es de 1 atm. Calcula la cantidad de hexano (C6H14) que debemos añadir a 200g de benceno para que su presion de vapor sea de 700mm de Hg
Answer:
18,9g de hexano son necesarios
Explanation:
Basados en la ley de Raoult, la presión de vapor ejercida por una solución es:
P = P°*Xsolvente
Donde P es la presión de la solución deseada = 700mmHg, P° la presión de vapor de vapor del benceno = 1atm = 760mmHg y X es la fracción molar del solvente (Benceno).
Reemplazando:
700mm Hg = 760mmHg * X(Benceno)
0.9211 = X(Benceno)
La fracción molar de benceno se define como:
X = Moles benceno / Moles benceno + Moles hexano
Moles benceno -Masa molar: 78g/mol-
200g * (1mol/78g) = 2.5641 moles benceno
X = Moles benceno / Moles benceno + Moles hexano
0.9211 = 2.5641 moles benceno / 2.5641 moles benceno + Moles hexano
0.9211moles Hexano + 2.3618 = 2.5641
0.9211*Moles Hexano = 0.2023
Moles hexano = 0.2023/0.9211 = 0.2196 moles hexano.
Masa Hexano -Masa molar: 86g/mol-
0.2196 moles hexano * (86g/mol) =
18,9g de hexano son necesariosLa cantidad de hexano (C6H14) que se debe agregar a 200 g de benceno para permitir que la presión de vapor se convierta en 700 mm de Hg sería:
18.9 g
Usando la ley de Raoult, la presión de vapor que libera una solución se encuentra por:
P = P ° × X disolvente
Donde (P) denota la presión de la solución deseada
P ° denota la presión de vapor del benceno y
X denota la fracción molar del disolvente (benceno).
En el caso dado,
(P) = 700 mmHg,
P° = 1atm = 760mmHg
Fracción molar de benceno = 0,9211 (∵ 700/760)
La fracción molar de benceno (X) = Moles de benceno/Moles de benceno + Moles de hexano
Moles de benceno - Masa molar: 78g / mol - 200 g × (1 mol / 78 g)
= 2.5641 moles de benceno
X = Moles de benceno/Moles de benceno + Moles de hexano
0.9211 = 2.5641 moles Benceno/2.5641 moles Benceno + Moles de Hexano
⇒ 0,9211 × moles de Hexano + 2,3618 = 2,5641
⇒ 0.9211 × moles de Hexano = 0.2023
∵ Moles de Hexano = 0.2023/0.9211
[tex]= 0.2196 moles[/tex]
[tex]Hexane mass - Molar mass = 86g/mol - 0.2196 mole hexane[/tex] × [tex](86g/mole)[/tex]
[tex]= 18.9g[/tex]
Por tanto, 18,9 g es la respuesta correcta.
Learn more about "Benzene" here:
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define hydroscopy in chemistry
Answer: A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption
Explanation:
Can someone help me with this one :")
Answer:
i think is probably A
Explanation:
because at constant temperature, the product of the pressure and volume of a given mass of and ideal gass in a closed system is always constant
Answer:
I believe the answer is A or D
Explanation:
I hope this helps you out!
the sum of two numbers is 54 one exceed the other by 14 find the number
Answer:
x=34
y=20
Explanation:
let the first number be 'x'
let the second number be 'y'
Equation 1:-
x + y = 54
Equation 2:-
x = y + 14 (Since one exceeds the other by 14)
Substituting Equation 2 in Equation 1:-
(y + 14) + y = 54
=> y + 14 + y = 54
=> 2y + 14 = 54
=> 2y = 54 - 14
=> 2y = 40
=> y = 40/2
=> y = 20
Now in Equation 1:-
x + y = 54
Substituting y=20,
x + 20 = 54
x = 54 - 20
x = 34
I need answers to question 1,2,3
Answer:
1. 0.125 mole
2. 42.5 g
3. 0.61 mole
Explanation:
1. Determination of the number of mole of NaOH.
Mass of NaOH = 5 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass /molar mass
Mole of NaOH = 5/40
Mole NaOH = 0.125 mole
2. Determination of the mass of NH₃.
Mole of NH₃ = 2.5 moles
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 2.5 × 17
Mass of NH₃ = 42.5 g
3. Determination of the number of mole of Ca(NO₃)₂.
Mass of Ca(NO₃)₂ = 100 g
Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]
= 40 + 2[14 + 48]
= 40 + 2[62]
= 40 + 124
= 164 g/mol
Mole of Ca(NO₃)₂ =?
Mole = mass /molar mass
Mole of Ca(NO₃)₂ = 100 / 164
Mole of Ca(NO₃)₂ = 0.61 mole
Si se analizan muestras de Al2O3 en diversos laboratorios se encuentra que todas tienen 52,94% de aluminio (Al) y 47,06% de oxígeno (O). Este dato experimental corresponde a lo expresado por la ley de:
A) La ley de las proporciones definidas
B) La ley de las proporciones múltiples
C) La ley de la conservación de la masa
D) La ley de la conservación de la energía
PLEASE HELP ASAP!!!!!!!!
Answer:
ouch......it's kinda a practical question..
Answer: ?
Explanation: what was the answer?
