which correlation coefficient is most appropriate for the scatterplot shown below?

Answer:

Step-by-step explanation:

Apply the Distributive Property of Multiplication.  Multiply each of the three terms inside parentheses by -(1/2):

(3/4)x - 3x - (1/2) - 3x, or

(3/4)x - 6x - 1/2

The first two terms can be combined, to obtain:

(-5 1/4)x - 1/2, or (-21/4)x - 1/2

Answer:

Expression

Step-by-step explanation:

Given expression :

4a+3b-6cx9

So this is expression not equation because equation consist zero on the righ side

Example: ax+b=0 (This is equation )

And

ax+b (This is expression)

Answer:

It's actually 13 groups

4 students will be left over

Step-by-step explanation:

Add all the students together

134

Divide 10

13 and remainder 4

Answer:

13 ; 4

Step-by-step explanation:

Total students = 24 + 21 + 33 + 36 + 20 = 134

grups that will be made = 134 : 10 = 13,4 = 13

13 x 10 = 130

Students that will be left overs = 134 - 130 = 4

Answer:

y=80

Step-by-step explanation:

when solve y-intercept let x=0

y= -16(0)2+64(0)+80

y=0+0+80

y=80

(0;80)

f(-3)=g(-4) 123456789012345

Step-by-step explanation:

answer is in the photo above

Answer:

[tex]\displaystyle p = \frac{16}{q + 1}[/tex].

Step-by-step explanation:

Factor out the coefficient of [tex]x^{2}[/tex]:

[tex]\displaystyle \frac{1}{q + 1}\, [(q + 1)\, x^2 - 8\, x + p] = 0[/tex].

[tex]\displaystyle x^2 - \frac{8}{q + 1} \, x + \frac{p}{q + 1} = 0[/tex].

Let [tex]m[/tex] denote the real root of this equation. By the Factor Theorem, this equation would have the factor [tex](x - m)[/tex] repeated for two times in total:

[tex](x - m)^{2} = 0[/tex].

Expand to obtain: [tex]x^2 - 2\, m\cdot x + m^{2} =0[/tex].

Compare this expression with [tex]\displaystyle x^2 - \frac{8}{q + 1} \, x + \frac{p}{q + 1} = 0[/tex]:

[tex]\displaystyle -\frac{8}{q + 1} = -2\, m[/tex] (for the coefficient of [tex]x[/tex].)

[tex]\displaystyle \frac{p}{q + 1} = m^2[/tex] (for the constant.)

Rewrite the first equation to find an expression for [tex]m[/tex] in terms of [tex]q[/tex]:

[tex]\displaystyle m = \frac{4}{q + 1}[/tex].

Substitute this expression for [tex]m[/tex] into the second equation to find an expression for [tex]p[/tex] in terms of [tex]q[/tex]:

[tex]\displaystyle \frac{p}{q + 1} = m^2[/tex].

[tex]\displaystyle \frac{p}{q + 1} = \frac{4^2}{(q+1)^{2}}[/tex].

[tex]\displaystyle p = \frac{16}{q + 1}[/tex].

Verify that this expression for [tex]p[/tex] satisfies the requirements:

[tex]\displaystyle (q + 1) \, x^{2} - 8\, x + \frac{16}{q + 1} = 0[/tex].

[tex]\displaystyle x^2 - \frac{8}{q + 1} + \frac{16}{(q+1)^2} = 0[/tex].

[tex]\displaystyle x = \frac{4}{q + 1}[/tex] is the (repeated) real root of this quadratic equation.

Answer:

Part A: x = y+45

Part B: 40 125-45 = 80, 80÷2 = 40

Part C: Yes, because 80+45 adds up to 125.

Hope this helps! :)

Answer:

just subtract

Step-by-step explanation:

first go number by number and then subtract them and see the average rate of change and input that number

Answer:

Step-by-step explanation:

the second number be 2x. Therefore, the number 80 is divided in the ratio of 3:2 is, 48 and 32.

Answer:

There are two types of similar triangle problems; these are problems that require you to prove whether a given set of triangles are similar and those that require you to calculate the missing angles and side lengths of similar triangles. Subtract both sides by 130°. Hence; By Angle-Angle (AA) rule, ΔPQR~ΔXYZ.

Step-by-step explanation:

Answer:

(8,-9)

Step-by-step explanation:

solve the equation for x

x=13/5-3/5y

7x+8y=-16

substitute the given value of x into the equation 7x+8y= -16

7(13/5-3/5y)+8y= -16

solve the equation for y

7(13/5-3/5)+8y= -16

y= -9

substitute the given value of y into the equation x=13/5-3/5y

x=13/5-3/5x(-9)

solve for x

x=8

the ordered pair is (8,-9)

Answer:

The solution to this system of equations is x = 8, and y = -9

Step-by-step explanation:

Firstly we need to use the first equation to represent "x" in terms of "y", so we do the following...

[tex]5x + 3y = 13\\5x = 13 - 3y\\x = \frac{13}{5} - \frac{3}{5}y[/tex]

Now we take the second equation and replace "x" with an equal value in terms of "y" which we know from the previous equation, and just solve for "y".

[tex]7x + 8y = -16\\7(\frac{13}{5} -\frac{3}{5} y) + 8y = -16\\\\18\frac{1}{5} - 4\frac{1}{5} y + 8y = -16\\\\3\frac{4}{5}y = -34\frac{1}{5} \\\\y = -34\frac{1}{5} / 3\frac{4}{5} \\y = -9[/tex]

After we found the value of "y" we can find the value of "x" by using any of the two equations, we just have put "-9" instead of "y". For example...

[tex]5x + 3y = 13\\5x + 3(-9) = 13\\5x - 27 = 13\\5x = 13 + 27\\5x = 40\\x = 40 / 5\\x = 8[/tex]

Now we know that the solution to this system of equations is x = 8, and y = -9

Answer:

2) slope=2

y intervept=2

3) slope=1/2

y intercept=-6

4)slope=2

y intercept=4

Answer:

5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

Identify

0.3y + y/z

y = 10

z = 5

Step 2: Evaluate

Answer:

The half-life of the substance is of 1600 years.

Step-by-step explanation:

Amount of the substance:

The amount of the substance after t years is given by the following equation:

[tex]C(t) = A(0.999567)^t[/tex]

In which A is the initial amount.

Find the half-life:

This is t for which [tex]C(t) = 0.5A[/tex], that is, the amount is half the initial amount. So

[tex]C(t) = A(0.999567)^t[/tex]

[tex]0.5A = A(0.999567)^t[/tex]

[tex](0.999567)^t = 0.5[/tex]

[tex]\log{(0.999567)^t} = \log{0.5}[/tex]

[tex]t\log{0.999567} = \log{0.5}[/tex]

[tex]t = \frac{\log{0.5}}{\log{0.999567}}[/tex]

[tex]t = 1600[/tex]

The half-life of the substance is of 1600 years.

Answer:

14 - .5d

Step-by-step explanation:

To determine the amount of gas in the tank, take the amount in the tank to start and subtract the amount used per day

14 - .5d

Answer: There are 14 gallons total, and you would be using 0.5 gallons a day, which is expressed by 14 - 0.5d. Example = 8 days, 14 - 0.5(8) = 10 gallons left

Answer:

False

Step-by-step explanation:

Step-by-step explanation:

YOU ARE CORRECT

[tex] {7}^{(1 \times 9)} = {7}^{5 + 5} \\ {7}^{9} \: \: \: \: \: \: \: \: \: \: \: {7}^{10} [/tex]

the equation is false

Answer:

option 2

in the first equation y is greater than so it would be shaded above the line and in the second equation y is less than so it would be shaded below the line

Step-by-step explanation:

Answer:

(C).

[tex]height = \sqrt{ {29}^{2} - {21}^{2} } \\ = \sqrt{400} \\ = 20 \: units[/tex]

Answer:

I think it's option B ...

Answer:

A.) F(x)=1/x-5

Step-by-step explanation:

Answer:

y = 9x + (-7) should be the answer

Answer:

y = -5/6x + 6

Step-by-step explanation:

Slope intercept form is: y = mx + b

- where m is the slope

- where b is the y-intercept.

The problem already gives you the slope and y-intercept, so all you have to do is put it in for m and b respectively. Therefore, we have:

y = -5/6x + 6

Answer:

[tex]y = - \frac{5x}{6} + 6[/tex]

Step-by-step explanation:

1: Formulate equations/expressions:

[tex]based \: on \: the \: given \: conditions \: formulate[/tex]

[tex]m = - \frac{5}{6} \\ b = 6[/tex]

2: Write the equation:

[tex]write \: the \: equation \: of \: linear \: function[/tex]

[tex]y = mx + b[/tex]

3: substitute:

[tex]y = mx + b \\ m = - \frac{5}{6} \: b = 6 \\ y = - \frac{5}{6} x + 6[/tex]

4: rewrite the equation:

[tex]y = - \frac{5}{6} x + 6 \\ slope - intercept \: form \\ fin \: the \: required \: form: \\ y = - \frac{5x}{6} + 6[/tex]

Answer:

35x^2-5x^4

Step-by-step explanation:

You have to multiply the numbers on the outside to the numbers on the inside.

For example, 5x^2 times 7 would be 35x^2.

Answer:

It does since lets say X and Y equal 10 it works

Step-by-step explanation:

Answer:

∠1 = 90°

∠2 = 66°

∠3 = 24°

∠4 = 24°

Step-by-step explanation:

Usually the diagonals of a rhombus bisect each other at right angles.

Thus; ∠1 = 90°

Since they bisect at right angles, then;

∠R1S = 90°

Now, sum of angles in a triangle is 180°

Thus;

66° + 90° + ∠4 = 180°

156 + ∠4 = 180

∠4 = 180 - 156

∠4 = 24°

Now, also in rhombus, diagonals bisect opposite angles.

Thus; ∠4 = ∠3

Thus, ∠3 = 24°

Similarly, the diagonal from R to T bisects both angles into 2 equal parts.

Thus; ∠2 = 66°

Answer:

S = {1, 2, 3, . . . 49, 50}, n(S) = 50 (i) Condition for event A : number is divisible by 6. A = {6, 12, 18, 24, 30, 36, 42, 48} n(A) = 8 (ii) Condition for event B : the number on the card is a complete square. B = {1, 4, 9, 16, 25, 36, 49} n(B)

Step-by-step explanation:

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Answer:

-9

Step-by-step explanation:

Find the common ratio by dividing one of the numbers in the sequence by the previous number:

117/-13

= -9

So, the common ratio is -9.

Answer:

[tex]\frac{47}{2} \to 6[/tex]

[tex]\frac{60}{12} \to 5[/tex]

[tex]\frac{40}{10} \to 4[/tex]

[tex]\frac{56}{8} \to 7[/tex]

[tex]\frac{64}{8} \to 8[/tex]

Step-by-step explanation:

Given

See attachment

Required

Complete the blanks

To do this, we simply carry out the division operation.

So, we have:

[tex]\frac{47}{2} \to 6[/tex]

[tex]\frac{60}{12} \to 5[/tex]

[tex]\frac{40}{10} \to 4[/tex]

[tex]\frac{56}{8} \to 7[/tex]

[tex]\frac{64}{8} \to 8[/tex]

The rates of the given equivalent unit rates are properly matched as follows:

42/7 = 6

60/12 = 5

40/10 = 4

56/8 = 7

64/8 = 8

To find the unit rate, the numerator is divided by the denominator such that the denominator is reduced to 1.

Thus, let's find the unit rates that matches with the equivalent rates given (see attachment below).

Divide the numerators by the denominators such that the value of the denominators are reduced to 1.

Learn more about unit rate on:

https://brainly.com/question/18296886

Answer:

x - 3

Step-by-step explanation:

Jenna picked x.

Josh picked 2x - 3.

The difference is:

2x - 3 - x

which simplifies to

x - 3

Answer: x - 3