Which could be the function graphed below?

Which Could Be The Function Graphed Below?

Answers

Answer 1

[tex]f(x)=\sqrt{x} -2[/tex] is the correct option

Which Could Be The Function Graphed Below?

Related Questions

For the diagram below, which equation is the correct use of the distance
formula?

Answers

9514 1404 393

Answer:

  D

Step-by-step explanation:

Any equation that does not have y2 as the first term in the second set of parentheses will be incorrect.

The correct usage is shown in equation D.

I think the answer is B

Mrs. Rodger got a weekly raise of $145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.

Answers

Answer:

her salary will increase by $ 145 for every week

Step-by-step explanation:

x=1st paycheck (integer).

weekly raise = $ 145.

After completing the 1st week she will get $ (x+145).

Similarly after completing the 2nd week she will get

$ (x + 145) + $ 145.

= $ (x + 145 + 145)

= $ (x + 290)

So in this way end of every week her salary will increase by $ 145.

The annual demand for a product is 16,400 units. The weekly demand is 315 units with a standard deviation of 90 units. The cost to place an order is $31.00, and the time from ordering to receipt is four weeks. The annual inventory carrying cost is $0.20 per unit.
a. Find the reorder point necessary to provide a 95 percent service probability.
b. Suppose the production manager is asked to reduce the safety stock of this item by 55 percent. If she does so, what will the new service probability be?

Answers

Answer:

a) The reorder point necessary to provide a 95 percent service probability is 1557 units.

b) The Z value of 0.74 corresponds to 77% service probability.

Step-by-step explanation:  

Average weekly demand (d) = 315 units  

The standard deviation of weekly demand (\sigmad) = 90 units  

Lead time (L) = 4 weeks  

At 95% service level value of Z = 1.65  

Reorder point = d x L + safety stock  

[tex]= d \times L + (Z \times \sigma d \times \sqrt L)\\\\= 315 x 4 + (1.65 x 90 x \sqrt 4)\\\\= 1260 +(1.65 x 90 x 2)\\\\= 1260 + 297\\\\= 1557 units[/tex]

b) Earlier the safety stock was 297 units(calculated in part a)

Now the safety stock is reduced to 55%.so,55% of 297 = 163.35 units  

So the new safety stock = 297 - 163.35 = 133.65  

[tex]Safety stock = Z \times \sigma d \times \sqrt L\\133.65 = Z x 90 x 2\\133.65 = 180Z\\ Z = 133.65/180\\Z = 0.74[/tex]  

The Z value of 0.74 corresponds to 77% service probability.

evaluate the expression when b=3
y = -7

4b-y​

Answers

Answer:

5

Step-by-step explanation:

Given :

b = 3 y = -7

To Find :

Value of 4b - y .

Solution:

Put on the respective values ,

⇒ 4b - y = 4 × 3 - 7

⇒ 4b - y = 12 - 7

4b - y = 5

Hence the required answer is 5 .

Answer: 5

Step-by-step explanation:

We can plug in the numbers for variables. So, our new equation would becomes 4x3-7. We first evaluate 4x3=12. Then, 12-7=5. Hence, your answer is 5.

Mischa wrote the quadratic equation 0=_x2+4x-7 in standard form. If a = -1, what is the value of c in her equation?
C=-7
C= 1
c=4
c=7

Answers

Answer:

A. c = -7

Step-by-step explanation:

Standard form of a quadratic equation is given as ax² + bx + c = 0, where,

a, b, and c are known values not equal to 0,

x is the variable.

Given a quadratic equation of -x² + 4x - 7, therefore,

a = -1

b = 4

c = -7

A motel in New Orleans charges $90 per day for double occupancy and $80 per day for single occupancy during off-season. If 80 rooms are occupied for a total of $6,930, how many rooms of each kind are occupied?

Answers

double occupancy room=x

single occupancy room=y

x + y =   80,    

90x + 80y = 6930

x=53

y=27

x - 3y +3=0
a) The length of the perpendicular drawn from the point (a, 3) on the line
3x + 4y + 5 = 0 is 4. Find the value of a.​

Answers

Answer:

We know that for a line:

y = a*x + b

where a is the slope and b is the y-intercept.

Any line with a slope equal to -(1/a) will be perpendicular to the one above.

So here we start with the line:

3x + 4y + 5 = 0

let's rewrite this as:

4y = -3x - 5

y = -(3/4)*x - (5/4)

So a line perpendicular to this one, has a slope equal to:

- (-4/3) = (4/3)

So the perpendicular line will be something like:

y = (4/3)*x + c

We know that this line passes through the point (a, 3)

this means that, when x = a, y must be equal to 3.

Replacing these in the above line equation, we get:

3 = (4/3)*a + c

c = 3 - (4/3)*a

Then the equation for our line is:

y = (4/3)*x + 3 - (4/3)*a

We can rewrite this as:

y = (4/3)*(x -a) + 3

now we need to find the point where this line ( y = -(3/4)*x - (5/4)) and the original line intersect.

We can find this by solving:

(4/3)*(x -a) + 3 =  y = -(3/4)*x - (5/4)

(4/3)*(x -a) + 3  = -(3/4)*x - (5/4)

(4/3)*x - (3/4)*x = -(4/3)*a - 3 - (5/4)

(16/12)*x - (9/12)*x = -(4/3)*a - 12/4 - 5/4

(7/12)*x = -(4/13)*a - 17/4

x = (-(4/13)*a - 17/4)*(12/7) = - (48/91)*a - 51/7

And the y-value is given by inputin this in any of the two lines, for example with the first one we get:

y =  -(3/4)*(- (48/91)*a - 51/7) - (5/4)

  = (36/91)*a + (153/28) - 5/4

Then the intersection point is:

( - (48/91)*a - 51/7,  (36/91)*a + (153/28) - 5/4)

And we want that the distance between this point, and our original point (3, a) to be equal to 4.

Remember that the distance between two points (a, b) and (c, d) is:

distance = √( (a - c)^2 + (b - d)^2)

So here, the distance between (a, 3) and ( - (48/91)*a - 51/7,  (36/91)*a + (153/28) - 5/4) is 4

4 = √( (a + (48/91)*a + 51/7)^2 + (3 -  (36/91)*a + (153/28) - 5/4 )^2)

If we square both sides, we get:

4^2 = 16 =  (a + (48/91)*a + 51/7)^2 + (3 -  (36/91)*a - (153/28) + 5/4 )^2)

Now we need to solve this for a.

16 = (a*(1 + 48/91)  + 51/7)^2 + ( -(36/91)*a  + 3 - 5/4 + (153/28) )^2

16 = ( a*(139/91) + 51/7)^2 + ( -(36/91)*a  - (43/28) )^2

16 = a^2*(139/91)^2 + 2*a*(139/91)*51/7 + (51/7)^2 +  a^2*(36/91)^2 + 2*(36/91)*a*(43/28) + (43/28)^2

16 = a^2*( (139/91)^2 + (36/91)^2) + a*( 2*(139/91)*51/7 + 2*(36/91)*(43/28)) +  (51/7)^2 + (43/28)^2

At this point we can see that this is really messy, so let's start solving these fractions.

16 = (2.49)*a^2 + a*(23.47) + 55.44

0 = (2.49)*a^2 + a*(23.47) + 55.44 - 16

0 = (2.49)*a^2 + a*(23.47) + 39.44

Now we can use the Bhaskara's formula for quadratic equations, the two solutions will be:

[tex]a = \frac{-23.47 \pm \sqrt{23.47^2 - 4*2.49*39.4} }{2*2.49} \\\\a = \frac{-23.47 \pm 12.57 }{4.98}[/tex]

Then the two possible values of a are:

a = (-23.47 + 12.57)/4.98  = -2.19

a = (-23.47 - 12.57)/4.98 = -7.23

When you compute with decimals you should always check your answer is reasonable why

Answers

Answer:

Ang pangit mo

Kamuka mo Yong clown

9. Mariah has 28 centimeters of reed
and 10 meters of reed for weaving
baskets. How many meters of reed
does she have? Write your answer as a
decimal and explain your answer.

Answers

10.28 , 28 cm in meters is 0.28. you have 10 meters therefore 10+.28= 10.28

The durations (minutes) of 26 electric power outages in Shah Alam over the past five years are shown below. 32 44 25 66 27 12 62 9 51 4 17 50 35 99 30 21 12 53 25 2 18 24 84 30 17 17 (a) Find the mean, median and mode.

Answers

Answer:

Mean = 33.31

Median = 26

Mode = 17

Step-by-step explanation:

Given the data:

32 44 25 66 27 12 62 9 51 4 17 50 35 99 30 21 12 53 25 2 18 24 84 30 17 17

Reordered data : 2, 4, 9, 12, 12, 17, 17, 17, 18, 21, 24, 25, 25, 27, 30, 30, 32, 35, 44, 50, 51, 53, 62, 66, 84, 99

The mean, xbar = Σx / n = 866 /26 = 33.31

The median = 1/2(n+1)th term

Median = 1/2(27)th term = 13.5th term

Median = (13 + 14)th / 2

Median = (25 + 27) / 2 = 26

The mode = 17 (highest frequency)

Please help solve this problem.

Answers

Answer:

Ang hirap naman niyan bakit kaya lahat na module mahirap

Can someone please help me with this math problem.

Answers

Answer:

8 + 30 ÷ 2 + 4  = 27

8 + 30 ÷ (2 + 4 ) = 13

(8 + 30) ÷ 2 + 4  = 23

Step-by-step explanation:

For all positive integers n, let *n* equal the greatest prime number that is a divisor of n. What does *10*/*12* equal?

Answers

9514 1404 393

Answer:

  5/3

Step-by-step explanation:

The prime factorizations are ...

  10 = 2·5

  12 = 2·2·3

Then *10* = 5 and *12* = 3, so *10*/*12* = 5/3.

Round 620 to the nearest ten! Hurry please and please don't answer if you know you wrong !

Answers

Answer:

620 to the nearest ten is already rounded correctly.

Step-by-step explanation:

620 to the nearest ten is 620.

Respond to each of the four questions.

Describe the steps to graphing a linear equation. Be sure to provide an example to illustrate your description.
Describe the steps to graphing a quadratic equation. Be sure to provide an example to illustrate your description.
Describe how to solve a linear equation. Be sure to provide an example to illustrate your description.
Describe how to solve a quadratic equation. Be sure to provide an example to illustrate your description.

Answers

Answer:hello

Step-by-step explanation:

1+1

The functions f (x) = 1/2x-3 and g(x) = -2x+ 2 intersect
at x = -2. True or false?

Answers

9514 1404 393

Answer:

  False

Step-by-step explanation:

f(-2) = (1/2)(-2) -3 = -1 -3 = -4

g(-2) = -2(-2) +2 = 4 +2 = 6

The function values are not the same at x=-2, so the graphs do not intersect there.

__

The graphs intersect at x=2.

Use the P (A + B) = P (A) x P (B) rule to find the probability of system failure. Let A and B be the events that the first alarm and second alarm, respectively, fail. Do you get the same answer you did in the earlier question?

Answers

Answer:

answer is in the pic Mark me brainliest plz

Step-by-step explanation:

Answer:

The probability of the first alarm failing is  (1 - 0.8) = 0.2

The probability of the second alarm failing is (1−0.9)=0.1.

Using the multiplication rule (since A and B are independent), the probability of failure is 0.2 * 0.1 = 0.02

Step-by-step explanation:

A group of 40 bowlers showed that their average score was 192. Assume the population standard deviation is 8. Find the 95% confidence interval of the mean score of all bowlers.

Answers

Answer:

[tex]CI=189.5,194.5[/tex]

Step-by-step explanation:

From the question we are told that:

Sample size [tex]n=40[/tex]

Mean [tex]\=x =192[/tex]

Standard deviation[tex]\sigma=8[/tex]

Significance Level [tex]\alpha=0.05[/tex]

From table

Critical Value of [tex]Z=1.96[/tex]

Generally the equation for momentum is mathematically given by

 [tex]CI =\=x \pm z_(a/2) \frac{\sigma}{\sqrt{n}}[/tex]

 [tex]CI =192 \pm 1.96 \frac{8}{\sqrt{40}}[/tex]

 [tex]CI=192 \pm 2.479[/tex]

 [tex]CI=189.5,194.5[/tex]

25 x 2
help me
plz understand me by opening​

Answers

Answer:

[tex]25 \times 2 = 50 \\ you \: are \: idiot \: [/tex]

really?! :|

The answer is fifty/50

A display case of toy rings are marked 5 for $1. If Zach wants to buy 50 toy rings, how much will Zach spend (not including tax)

Answers

$10
Since it is five for $1 the amount of rings is 5x the amount of $

9514 1404 393

Answer:

  $10

Step-by-step explanation:

Price is proportional to the number of rings, so Zack will spend D dollars, where ...

  dollars/rings = D/50 = 1/5

  D = 50/5 = 10

Zack will spend $10 to buy 50 toy rings.

Find the interquartile range of the data set represented by this box plot.



25
20
45
35

Answers

Answer:

25

Step-by-step explanation:

im pretty sure i think only ok i think no saying bad things in the comment

The weight gain of beef steers were measured over a 140 day test period. the average daily gains (lb/day) of 10 steers on the same diet were as follows. The tenth steer had a weight gain of 4.02 lb/day.
3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27
determine the mean and median.

Answers

Answer:

[tex]\bar x = 3.545[/tex]

[tex]Median = 3.435[/tex]

Step-by-step explanation:

Given

[tex]x:3.89, 3.51, 3.97, 3.31, 3.21, 3.36, 3.67, 3.24, 3.27[/tex]

[tex]10th: 4.02[/tex]

Solving (a): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{3.89 +3.51 +3.97 +3.31 +3.21 +3.36 +3.67 +3.24 +3.27+4.02}{10}[/tex]

[tex]\bar x = \frac{35.45}{10}[/tex]

[tex]\bar x = 3.545[/tex]

Solving (b): The median

First, we sort the data; as follows:

[tex]3.21, 3.24, 3.27, 3.31, 3.36, 3.51, 3.67, 3.89, 3.97, 4.02[/tex]

[tex]n = 10[/tex]

So, the median position is:

[tex]Median = \frac{n + 1}{2}th[/tex]

[tex]Median = \frac{10 + 1}{2}th[/tex]

[tex]Median = \frac{11}{2}th[/tex]

[tex]Median = 5.5th[/tex]

This means that the median is the average of the 5th and 6th item

[tex]Median = \frac{3.36 + 3.51}{2}[/tex]

[tex]Median = \frac{6.87}{2}[/tex]

[tex]Median = 3.435[/tex]

the admission fee for a charity event is $7 for children and 10$ for adults. The event was attended by 700 people, and the total amount collected in admissions was $6,400.

Answers

Answer:

200 kids and 500 adults

Step-by-step explanation:

x+y=700

7x+10y=6,400

(200,500)

kids=200

adults=500

Give two examples of subtraction of fractions ( between 0-1) with different denominators.
SHOW ALL STEPS

Answers

Answer:

3/4-1/2=1/4 4/5-3/15

Step-by-step explanation:

3/4-1/2

=3/4-2/4

=1/4

4/5-3/15

=4/5-1/5

=3/5

Suppose f(x)=x^2 and g(x)=(1/2x)^2. Which statement best compares the graph of g(x) with the graph of f(x)?

Answers

Answer:

"A"

Step-by-step explanation:

the voltage in a lightbulb is given by the equation V= IR. in this equation V is the voltage, I is the current , and R is the resistance. what is the current in a lightbulb with a voltage of 35.0 V and a resistance of 175

Answers

Answer:

a

Step-by-step explanation:

Suppose X and Y are two independent exponential variables. The mean of X is twice the mean of Y. If the probability of X exceeding 50 is 0.7788, what is the probability of Y exceeding 40

Answers

If X ~ Exponential(µ), then the mean of X is 1/µ. So if the mean of X is twice the mean of Y, then the mean of Y is 1/(2µ), so that Y ~ Exponential(2µ).

We're given that

P(X > 50) = 1 - P(X ≤ 50) = 1 - Fx (50) ≈ 0.7788

==>   Fx (50) = P(X ≤ 50) ≈ 0.2212

where Fx is the CDF of X, which is given for 0 ≤ x < ∞ to be

Fx (x) = 1 - exp(-µx)

Solve for µ :

1 - exp(-50µ) ≈ 0.2212   ==>   µ ≈ -ln(0.7788)/50 ≈ 0.005

Then we have

P (Y > 40) = 1 - P (Y ≤ 40) = 1 - Fy (40)

where Fy is the CDF of Y,

Fy (y) = 1 - exp(-2µy)

so that

P (Y > 40) ≈ 1 - exp(-2 × 0.005 × 40) ≈ 0.3297

Type the standard form of "three thousand four hundred eight."
The solution is

Answers

Answer:

the standard form of "three thousand four hundred eight is

3408

hope it is helpful to you ☺️

In standard form we can write 3408 as 3.408 x [tex]10^{3}[/tex].

We have the following statement - three thousand four hundred eight

We have to write it in standard form.

What do you understand by Standard form of a Number ?

A number when expressed as a decimal number, between 1 and 10, multiplied by a power of 10, is said to be in standard form.

According to the question, we have -

three thousand four hundred eight.

In the digit form, we can write it as - 3408.

In Standard form, we can write it as -

3408 = 3.408 x [tex]10^{3}[/tex]

Hence, in standard form we can write 3408 as 3.408 x [tex]10^{3}[/tex].

To solve more questions on Standard form, visit the link below -

https://brainly.com/question/17136267

#SPJ2

A nut mixture has peanuts,almonds and cashews in the ratio 5:3:1. Question:How much nust mixture should Helen buy if she wants to ensure she has 750g of almonds in the mix? please help!!will submit it today....​

Answers

Answer:

2250 g of nut mixture

Step-by-step explanation:

In order to use the ratio, we have to divide that 750 g by 3.

So 250 g multiplied by 5 is 1250. That's the amount of peanuts. Then just 1 for the cashews.

So, adding all of that up, the answer is 2250 g of nut mixture.

Answer:

1350g of nut mixture

Step-by-step explanation:

5:3:1 = 5x + 3x + x

5x = 750

x = 150

5x + 3x + x

= 5(150) + 3(150) + (150)

=750 + 450 + 150

=1350g

Hope it helps...

he parent function f(x) = x3 is represented by graph A. Graph A is transformed to get graph B and graph C. Write the functions represented by graph B and graph C.

Graph B represents the function g(x) =
.

Graph C represents the function h(x) =
.

Answers

Graph b and


Answer is graph b I believe


Graph b
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