Which effect is used in this image?

A.sepia effect

B.selective focus

C.zoom effect

D.soft focus

Answer:

Please show me the image, it is not there

Explanation:

I will wait, don't worry I will help you whenever you want! :)

Answer:

a bit

Explanation:

<3

Answer:

We assume that the NFA for the expression S is theorem by using the expressions given below.

Cases as

Thompson's Construction Algorithm proves that any expression can be expressions in the NFA's.

Answer:

the use of criminal thought by the name of education

Answer:

The capacitive reactance will be "100Ω" and RMS value of current is "2.2 A". A further explanation is provided below.

Explanation:

Given:

[tex]C =\frac{10^2}{\pi}\times 10^{-6} \ F[/tex]

[tex]V_{RMS}=220 \ V[/tex]

[tex]f = 50 \ Hz[/tex]

Now,

The capacitive reactance will be:

⇒ [tex]X_c=\frac{1}{\omega C} =\frac{1}{2 \pi f C}[/tex]

                   [tex]=\frac{1}{2\times \pi\times 50\times \frac{10^{-4}}{\pi} }[/tex]

                   [tex]=100 \ \Omega[/tex]

RMS value of current will be:

⇒ [tex]I_{RMS}=\frac{V_{RMS}}{X_c}[/tex]

             [tex]=\frac{220}{100}[/tex]

             [tex]=2.2 \ A[/tex]

So that,

⇒ [tex]V_m=220\times \sqrt{2}[/tex]

         [tex]=311 \ V[/tex]

⇒ [tex]I_m=2.2\times \sqrt{2}[/tex]

         [tex]=3.1 \ A[/tex]

hence,

The equation will be:

⇒ [tex]\nu=311 sin31 \ 4t[/tex]

and,

⇒ [tex]i=3.1 sin(314t+\frac{\pi}{2} )[/tex]

Answer:

Following are the code to the given question:

def getSAOneSide(edge):#defining a method that getSAOneSide that takes edge patameter

   return edge * edge#use return to calculate the edge value

def getSA(SA_one_side):#defining a method that getSA that takes SA_one_side patameter

   return 6 * SA_one_side#use return to calculate the SA_one_side value

def volume(edge):#defining a method that volume that takes edge patameter

   return edge * edge * edge#use return to calculate edge value

edge = int(input("Enter the length of edge of the cube:\n"))#defining edge variable that input value

SA_one_side = getSAOneSide(edge)#defining SA_one_side that holds getSAOneSide method value

print("Surface area of one side of the cube:", SA_one_side)

surfaceArea = getSA(SA_one_side)#defining a surfaceArea that holds getSA method value

print("Surface area of the cube:", surfaceArea)#print surfaceArea value

vol = volume(edge)#defining vol variable that holds Volume method value

print("Volume of the cube:", vol)#print vol Value

Output:

Please find the attached file.

Explanation:

In the code three method "getSAOneSide, getSA, and volume" method is declared that takes a variable in its parameters and use a return keyword that calculates and return its value.

In the next step,edge variable is declared that holds value from the user and defines three variable that holds method value and print its value with the message.

The statement "Unlike the collapse of Enron and WorldCom, TJX did not break any laws. It was simply not compliant with stated payment card processing guidelines" is definitely true.

The major cause of the TJX data breach was thought to be the hack that wasn't discovered until 2007, hackers had first gained access to the TJX network in 2005 through a WiFi connection at a retail store.

These situations were eventually able to install a sniffer program that could recognize and capture sensitive cardholder data as it was transmitted over the company's networks. They should be required to change the encryption methodology of the data they are using to save the personal identification information of their customers.

Therefore, the statement "Unlike the collapse of Enron and WorldCom, TJX did not break any laws. It was simply not compliant with stated payment card processing guidelines" is definitely true.

To learn more about, TJX data, refer to the link:

https://brainly.com/question/22516325

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Answer:

1.maayos

2. Lugar

3. mali

Explanation:

im correct if I'm rwong :-)

Answer:

4,400.

Explanation:

In order to determine what is 5 times 5 times 16 times 11 the following calcularion has to be done:

((11 x 16) x 5) x 5 = X

(176 x 5) x 5 = X

880 x 5 = X

4,400 = X

Therefore, 5 times 5 times 16 times 11 is equal to 4,400.

Answer:

use a cucullated

Explanation:

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

public static void main(String[] args) {

 int n, num;

 Scanner input = new Scanner(System.in);

 System.out.print("Number of inputs: ");

 n = input.nextInt();

 LinkedList<Integer> myList = new LinkedList<Integer>();

 for(int i = 0; i<n;i++){

     System.out.print("Input Integer: ");

     num = input.nextInt();

     while (num > 0) {

     myList.push( num % 10 );

     num/=10;

     }

     while (!myList.isEmpty()) {

         System.out.print(myList.pop()+" ");

     }

     System.out.println();

     myList.clear();

 }

}

}

Explanation:

This declares the number of inputs (n) and each input (num) as integer

 int n, num;

 Scanner input = new Scanner(System.in);

Prompt for number of inputs

 System.out.print("Number of inputs: ");   n = input.nextInt();

The program uses linkedlist to store individual digits. This declares the linkedlist

 LinkedList<Integer> myList = new LinkedList<Integer>();

This iterates through n

 for(int i = 0; i<n;i++){

Prompt for input

     System.out.print("Input Integer: ");

This gets input for each iteration

     num = input.nextInt();

This while loop is repeated until the digits are completely split

     while (num > 0) {

This adds each digit to the linked list

     myList.push( num % 10 );

This gets the other digits

     num/=10;

     }

The inner while loop ends here

This iterates through the linked list

     while (!myList.isEmpty()) {

This pops out every element of thelist

         System.out.print(myList.pop()+" ");

     }

Print a new line

     System.out.println();

This clears the stack

     myList.clear();

 }

Answer:

1.)

def two(a, b) :

print(a+b)

print(a*b)

2.)

a = int(input('enter an integer values '))

b = int(input('Enter another integer value' ))

print(a+b)

print(a*b)

3.)

Take side of a square from user and print area and perimeter of it.

def square(a):

area = a**2

perimeter = 4*a

print(area, perimeter)

Explanation:

Code written in python :

The first function named two, takes to arguments a and b ;

The sum of integers a and b is taken and displayed using ; print(a+b)

The product of integers a and b is taken and displayed using ; print(a*b)

2.)

User can enter an input and converted to an integer value using the command ;

int(input()) ; the sum and product of these values are displayed using :

print(a*b) and print(a+b)

The Area and perimeter of a square requires the side length, which is taken as the argument a in the square function defined.

Area of square = a² = a**2

Perimeter = 4 * a

Answer:A

Explanation:i need points

Answer:

Following are the code to the given question:

For code 1:

start = int(input())#defining a start variable that takes input from the user end

end = int(input())#defining a end variable that takes input from the user end

if start > end:#use if that checks start value greater than end value

   print("Second integer can't be less than the first.")#print message

else:#defining else block

   while start <= end:#defining a while loop that checks start value less than equal to end value

       print(start, end=' ')#print input value

       start += 5#incrementing the start value by 5

   print()#use print for space

For code 2:

while True:#defining a while loop that runs when its true

   data = input()#defining a data variable that inputs values

   if data == 'Done' or data == 'done' or data == 'd':#defining if block that checks data value

       break#use break keyword

   rev = ''#defining a string variable rev

   for ch in data:#defining a for loop that adds value in string variable  

       rev = ch + rev#adding value in rev variable

   print(rev)#print rev value

Explanation:

In the first code two-variable "first and end" is declared that takes input from the user end. After inputting the value if a block is used that checks start value greater than end value and use the print method that prints message.

In the else block a while loop is declared that checks start value less than equal to end value and inside the loop it prints input value and increments the start value by 5.

In the second code, a while loop runs when it's true and defines a data variable that inputs values. In the if block is used that checks data value and use break keyword.

In the next step, "rev" as a string variable is declared that uses the for loop that adds value in its variable and prints its values.

Answer:

Some examples of convergence in the wireless market include mobile phones, data communication, radio device etc.

Explanation:

Some examples of convergence in the wireless market are as follows –  

a) Using feature of radio device on phone which is nothing but a default application on the mobile device in the wireless market

b) Data communication is a mode to share data in wireless mode through the internet

c) Mobile phones – Mobile phones are best example of devices operating in the wireless market. It is basically used to call to one or many at a time through network service provider without using an internet

Answer:

The CISO (Chief Information Security Officer) of an organization should understand the following components of an information security program:

1) Every organization needs a well-documented information security policy that will govern the activities of all persons involved with Information Technology.

2) The organization's assets must be classified and controlled with the best industry practices, procedures, and processes put in place to achieve the organization's IT objectives.

3) There should be proper security screening of all persons in the organization, all hardware infrastructure, and software programs for the organization and those brought in by staff.

4) Access to IT infrastructure must be controlled to ensure compliance with laid-down policies.

Explanation:

As the Chief Information Security Officer responsible for the information and data security of my organization, I will work to ensure that awareness is created of current and developing security threats at all times.  I will develop, procure, and install security architecture, including IT and network infrastructure with the best security features.  There will good management of persons' identity and controlled access to IT hardware.  Programs will be implemented to mitigate IT-related risks with due-diligence investigations, and smooth governance policies.

Answer:

what are the choices

:"

Explanation:

Answer:

Following are the program to the given question:

#include<iostream>//defining header file  

using namespace std;

float temperatures()//defining a method temperatures

{

int a[10],i,j,n,min,max,sum=0,temp;//defining integer variable

float avg;//defining floating point variable

cout<<"Please input the number of temperatures to be read: ";//print message

cin>>n;//input integer value

if(i>10)//use if to check array length greater than 10

return -1;//return integer value -1

for(j=0;j<n;j++)//defining loop to input value

{

cout<<"Input temperature: "<<endl;//print message

cin>>a[j];//holding value in loop

}

for(i=0;i<n-1;i++)//defining loop to compare array value

{

for(j=i+1;j<n-1;j++)//defining loop to compare array value

{

if(a[i]>a[j])//use if to compare array values

{

   //swapping

temp=a[j];//holding array value in temp

a[j]=a[i];//holding value in first index of array  

a[i]=temp;//holding temp value

}

}

}

max=min=a[0];//holding max value  

for (i = 0; i < n; i++)//defining loop to compare array value

{

if (a[i] > max)//use if to compare max array value

{

max = a[i];//holding max array value

}

else if (a[i] < min)//use else if to compare min array value

{

min = a[i];//holding min array value

}

}

for(i=0;i<n;i++)//use loop to add array value

sum=sum+a[i];//adding array value

avg=(float) sum/n;//calculating avg of the array

std::cout.setf(std::ios::fixed);//using namespace

std::cout.precision(2);//using precision method

cout<<"The average temperature is: "<<avg<<endl;//print avg value with message

cout<<"The highest temperature is: "<<max<<endl;//print max value with message

cout<<"The lowest temperature is: "<<min<<endl;//print min value with message

return avg;//return avg value

}

int main()//defining main method

{

float k;//defining float variable

k=temperatures();//calling method  

}

Output:

Please find the attached file.

Explanation:

In this code, a method "temperatures" is declared that defines the integer and float variable in which "n, array" is used to store the array value and inside the method min and max variable is declared that use the conditional statement to store its value.

Outside the main method, a floating-point variable "k" is declared that calls the method and stores its value.  

Answer:

True

Explanation:

It is TRUE that Internal monitoring is accomplished by inventorying network devices and channels, IT infrastructure and applications, and information security infrastructure elements.

The above statement is true because Internal Monitoring is a term used in defining the process of creating and disseminating the current situation of the organization’s networks, information systems, and information security defenses.

The process of Internal Monitoring involved recording and informing the company's personnel from top to bottom on the issue relating to the company's security, specifically on issues about system parts that deal with the external network.

Answer:

Replace  /* Your solution goes here */ with:

System.out.println(randGen.nextInt(49) + 100);

System.out.println(randGen.nextInt(49) + 100);

Explanation:

Required

Statements to print two random numbers between 100 and 149 (both inclusive)

First, the random numbers must be generated. From the template given, the random object, randGen, has been created.

The syntax to then follow to generate between the interval is:

randGen.nextInt(high-low) + low;

Where:

high = 149 and low = 100

So, the statement becomes:

randGen.nextInt(149 - 100) + 100;

randGen.nextInt(49) + 100;

Lastly, print the statements:

System.out.println(randGen.nextInt(49) + 100);

System.out.println(randGen.nextInt(49) + 100);

Answer:

See attachment

Explanation:

The solution and the explanation could not be submitted directly. So,I added both as attachments

To print a rectangle based on the given number of rows and columns, you will use nested loops using the following code:

num_rows = int(input())

num_cols = int(input())

for i in range(num_rows):

   for j in range(num_cols):

       print('*', end=' ')

   print()

By using nested loops, you will iterate through each row and column to print the desired shape. The outer loop controls the rows while the inner loop controls the columns. Within the inner loop, the desired symbol or character, such as "*", is printed with the print() statement.

The end=' ' parameter is used to separate each character by a space. The outer loop then moves to the next row and the process continues until the desired number of rows and columns are printed forming a rectangle.

Read more about nested loops

brainly.com/question/31921749

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Answer:

4 * 10^9

2.7 * 10^-8

6.776 * 10^7

9.05*10^4

5.409*10^5

9.04 * 10^-3

3.2 * 10^-2

5.12 * 10^8

Explanation:

1. 4,000,000,000

4 * 1,000,000,000 = 4 * (10*10*10*10*10*10*10*10*10) = 4 * 10^9

2. 0.000000027

27 * 10^-9 = 2.7 * 10^-8

0.000000027 = 2.7 * 10^-8

3. 67,760,000 = 6776 * 10000

6776 * 10000 = 6776 * 10^4

6776 * 10^4 = 6.776 * 10^3 * 10^4 = 6.776 * 10^7

4. 90,500

905 * 100 = (9.05 * 100) * 100

(9.05*100) * 100 = 9.05 * 10^2 * 10^2 = 9.05*10^4

5. 540,900

5409 * 100 = (5.409 * 1000) * 100

(5.409*1000)*100 = 5.409*10^3 * 10^2

5.409*10^3 * 10^2 = 5.409*10^5

6.) 0.00904

0.00904 = 904 * 10^-5

904 * 10^-5 = 9.04 * 10^-3

7. 0.032

32 * 10^-3 = 3.2 * 10^-2

8. 512,000,000

512 * 1000000

512 * 10^6 = 5.12 * 10^2 * 10^6 = 5.12 * 10^8

Answer:

=AVERAGE(C5:C8)

Explanation:

The function calculates the average of the values in the cell range C5:C8 - C5, C6, C7, C8.

Answer:

split() wordCount = len(words) # start with zero characters ch = 0 for word in words: # add up characters ch += len(word) avg = ch / wordCount if avg == 1: print "In the sentence ", s , ", the average word length is", avg, "letter." else: print "In the sentence ", s , ", the average word length is", avg, "letters.

Answer:

British Broadcasting Corporation Microcomputer System

Explanation:

The British Broadcasting Corporation Microcomputer System, or BBC Micro, is a series of microcomputers and associated peripherals designed and built by the Acorn Computer company in the 1980s for the BBC Computer Literacy Project.

Answer:

British Broadcasting Corporation

Explanation:

This is a UK company which provides television and radio news in over 40 languages. This is the computer related meaning, there are other meanings to the abbreviation but they seem irrelevant in this case.

Hope this information was of any help to you. (:

Answer:

The summary of the given question would be summarized throughout the below segment.

Explanation:

Answer:

a) a plotting object like point, line, or other shape

Explanation:

A geom in the ggplot2 system is "a plotting object like point, line, or other shape."

A Geom is used in formulating different layouts, shapes, or forms of a ggplot2 such as bar charts, scatterplots, and line diagrams.

For example some different types of Geom can be represented as geom_bar(), geom_point(), geom_line() etc.

Go To View -> Navigation Pane -> Then Click Navigation Pane

Answer:

There are 28 chocolate-covered peanuts in 1 ounce (oz). Jay bought a 62 oz. jar of chocolate-covered peanuts.

Problem:

audio

How many chocolate-covered peanuts were there in the jar that Jay bought?

Enter your answer in the box.

Explanation: