Which equation represents an exponential function with an initial value of 500?

f(x) = 100(5)x
f(x) = 100(x)5
f(x) = 500(2)x
f(x) = 500(x)2

Answer:

Odd symetry I think

Step-by-step explanation:

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This is it

Answer:

Step-by-step explanation:

[tex]\Large \boldsymbol{} f(x) \ \ inverse \ \ function \ \ (f(x))^{-1} \\\\ y=7x+5 \\\\x=7y+5 \\\\ y=\dfrac{x-5}{7} \ \ or \ \ f(x)^{-1}= \dfrac{x-5}{7}[/tex]

9514 1404 393

Answer:

  A.  $674.43

Step-by-step explanation:

The account balance is given by ...

  A = P(1 +r/12)^(12t) . . . . . principal P invested at annual rate r for t years

  A = $500(1 +0.06/12)^(12·5) = $500(1.005^60)

  A ≈ $674.43

Step-by-step explanation:

Step 1:  Check to see if Connor is right

25 divided by the difference of 12 and seven

25 / (12 - 7)

Since we have a 12 and seven, that means that we have them together.  However, how Connor is presenting it, it would be 25 divided by 12 subtracted 7.  Therefore, Connor is incorrect.

Answer:

No he's not correct.

Step-by-step explanation: Let's take a step back and look at the question, he wants to represent the difference of 12 and 7 ÷ by 25. Therefore in order to do that we need to figure out the difference 12 and 7 so the equation would look like this 12-7=5  after doing that we divide 5 by 25 so it would look like this 25÷5=5.

So the correct equation is (12-5) ÷25

Hope this helps!

Answer:

Below

Step-by-step explanation:

From the graph the first local minimum is -16.18

The local maximum is 3.75

The second local minimum is -3.

Answer:

----------------------

Hope it helps..

Have a great day!!

Answer:

D; 2 * 3; -4

Step-by-step explanation:

The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column

In a row, we have 2 elements, in a column , we have 3 elements

So the matrix is of 2 * 3 dimension

a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4

Answer: See explanation

Step-by-step explanation:

Your question isn't well written, the store contains $227 and not $277.

let c be the number of $1 bills

let f be the number of $5 bills

let t be the number of $10 bills.

Therefore, the equation will be:

1c + 5f + 10t = 227

Since there are six more $5 bills than $10 bills, therefore,

f = t+6

Also, the number of $1 bills is two more than 24 times the number of $10 bills and this will be:

c = 24t + 2

Now, we substitute the equation for f and c into the main equation and this will be:

1c + 5f + 10t = 277

1(24t + 2) + 5(t + 6) + 10t = 227

24t + 2 + 5t + 30 + 10t = 227

39t + 32 = 227

39t = 227 - 32

39t = 195

t = 195/39

t = 5

Therefore, there are 5 $10 bills

Since c = 24t + 2

c = 24(5) + 2

c = 120 + 2

c = 122

Therefore, there are 122 $1 bills

Since f = t+6

f = 5+6

f = 11

Therefore, there are 11 $5 bills.

Answer:

[tex]{ \tt{ {x}^{2} + {y}^{2} - 6x - 2y + 4 = 0 }} [/tex]

Center:

[tex]{ \tt{(3, \: 1)}}[/tex]

Radius:

[tex]{ \tt{radius = \sqrt{ {g}^{2} + {f}^{2} - c } }} \\ = \sqrt{36 + 4 - 4} \\ = 6 \: units[/tex]

I'll do part (a) to get you started.

One possible answer to part (a) is 25,11,14,2,7,9,16

There are likely other possible answers.

The explanation is below.

==============================================================

Let's say 7 is the anchor value and we want to see which values could be its next door neighbor.

To summarize this subsection, the anchor value 7 could have the neighbors 9 and 2.

So we could have 2,7,9 or 9,7,2 as a subsequence. We'll keep this in mind for later.

------------------------------------------------

Now we'll make 11 the anchor. We already checked 7 and it doesn't work.

9 doesn't work either because 11+9 = 20 isn't a perfect square

Of that list, only 14 and 25 are possible neighbors of the anchor value 11.

So we could have the subsequence 14,11,25 or 25,11,14.

------------------------------------------------

If 9 is the anchor, then,

The values 7 and 16 are possible neighbors of 9. We could have the subsequence 7,9,16 or 16,9,7

Let's go back to the subsequence 2,7,9 and tack 16 at the end to get 2,7,9,16

------------------------------------------------

If 14 is the anchor, then,

We could have the subsequence 11,14,2 or 2,14,11

Let's go with the first option and stick "11,14,2" in front of "2,7,9,16" to end up with the larger subsequence 11,14,2,7,9,16

We can then stick 25 at the front because 25+11 = 36 is a perfect square.

------------------------------------------------

So one possible sequence of values is 25,11,14,2,7,9,16

Here's the verification

Each pair of adjacent terms add up to a perfect square, so the answer is confirmed.

There are probably other solutions as well.

Side note: The video math channel "Numberphile" has a video discussing this topic in which you might be interested in. Search out "The square sum problem" with quotes (the presenter/teacher in the video is Matt Parker).

Answer:

25, 11, 14, 2, 7, 9, 16.

Step-by-step explanation:

25 + 11 = 6^2

11 + 14 = 5^2

14 + 2 = 4^2

2 + 7 = 3^2

7 + 9 = 4^2

9 + 16 = 5^2

Answer:

A. Function

B. Not a function

C. function

Answer:

Les deux nombres doivent avoir une différence de 3. Algébriquement, ce serait x + (x + 3) = 129. 2x est alors égal à 126. X est égal à 63 et x + 3 est à 66. Ces nombres sont des multiples consécutifs de 3 dont la somme est de 129.

Step-by-step explanation:

The two numbers must have a difference of 3. Algebraically, it would be x + (x + 3) = 129. 2x then is equal to 126. X equals 63 and x + 3 is 66. These numbers are consecutive multiples of 3 whose sum is 129.

Answer:

84%

Step-by-step explanation:

3360/4000=.84

.84=84%

Step-by-step explanation:

Solution

First equation x ² - 4

= (x+2) (x-2)

Second equation = x ³ +8 + = x³+2^3

= (x-2) (x² + x₁2 +2²) = (x-2) (x² + 2x+4)

3 Third equation = x ² + 5x + 6

= x² + 6x= x +6 = x(x+6)-1(x+6)

(x-1) (x+6)

H.C. F= x-2

Answer:

0.017741

Step-by-step explanation:

Answer:

I think 5q+3(8-q) =36 is the answer for this question

Based on the amount the restaurant manager spends on the juice mixture, the amount of cherry juice can be found as 5q + 3(8 – q) = 8.

Assuming the cherry juice is q and the lime juice is r, the following formulas would be true:

q + r = 8

5q + 3r = 36

The first equation can be rewritten as:

q + r = 8

r = 8 - q

Using substitution into the second formula we get:

5q + 3r = 36

5q + 3(8 - q) = 36

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Answer:

The volume of water that will fill the spa tub is 5.9 cubic meters.

Step-by-step explanation:

Volume of water that would fill the spa tub = volume of semi sphere - (volume of the first cylinder + volume of the second cylinder)

i. volume of first cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h

where r is the radius and h is the height of the cylinder.

r = [tex]\frac{0.75}{2}[/tex] = [tex]\frac{3}{8}[/tex]

 = 0.375 m

h = 0.80 m

volume of the first cylinder = [tex]\frac{22}{7}[/tex] x [tex](\frac{3}{8} )^{2}[/tex] x 0.8

                                        = 0.3536 cubic meters

ii. volume of the cylinder underneath = [tex]\pi[/tex][tex]r^{2}[/tex]h

r = [tex]\frac{1.25}{2}[/tex] = [tex]\frac{5}{8}[/tex]

 = 0.625

h = 0.70 m

volume of the cylinder underneath = [tex]\frac{22}{7}[/tex] x [tex](\frac{5}{8}) ^{2}[/tex] x 0.7

                                                      = 0.8594 cubic meters

iii. volume of the semi sphere = [tex]\frac{2}{3}[/tex] [tex]\pi[/tex][tex]r^{3}[/tex]

where r is the radius = 1.5 m

volume of the semi sphere = [tex]\frac{2}{3}[/tex] x [tex]\frac{22}{7}[/tex] x [tex](1.5)^{3}[/tex]

                                             = 7.0714 cubic meters

Thus,

volume of the water to fill the spa tub = 7.0714 - (0.3536 + 0.8594)

                                                     = 5.8584

The volume of water that will fill the spa tub is 5.9 cubic meters.

Answer:

D

Step-by-step explanation:

Since ∠ RPQ = ∠ SPQ = 60° , then

PQ bisects ∠ RPS and is an angle bisector

PQ exists the angle bisector of angle RPS. It means PQ divides the angle RPS in two equivalent parts.

Angle bisector in geometry directs to a line that divides an angle into two equivalent angles. A bisector represents the thing that bisects a shape or an object into two equivalent regions. If we draw a ray that bisects an angle into two equivalent parts of the exact measurement, then it exists named an angle bisector.

It is given that ray PQ is the angle bisector of angle RPS. It means PQ divides the angle RPS in two equivalent parts.

[tex]$m \angle R P Q=m \angle QP S=60^{\circ}$[/tex]

Now, [tex]&m \angle R P S=m \angle R P Q+m \angle Q P S \\[/tex]

[tex]&m \angle R P S=60^{\circ}+60^{\circ} \\[/tex]

[tex]&m \angle R P S=120^{\circ}[/tex]

Therefore, the measure of angle RPS is [tex]$60^{\circ}$[/tex].

Therefore, the correct answer is option D. angle bisector.

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Answer:

66.6666666667

Step-by-step explanation:

answer is 66.6666666667

The solution of the division of 5⁻² by 8^(1/3) will be 50.

The mathematical expression is the combination of numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also be used to denote the logical syntax's operation order and other properties.

Given numbers will be solved as:-

Division = ( 8 ^ (1/3) / 5⁻²

Division = 2 x5²

Division = 50

Therefore, the solution of the division of 5⁻² by 8^(1/3) will be 50.

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Answer:

LP = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

[tex]\frac{LM}{LN}[/tex] = [tex]\frac{LQ}{LP}[/tex] , substitute values

[tex]\frac{4}{10}[/tex] = [tex]\frac{LQ}{LQ+QP}[/tex]

[tex]\frac{2}{5}[/tex] = [tex]\frac{LQ}{LQ+9 }[/tex] ( cross- multiply )

5LQ = 2(LQ + 9) = 2LQ + 18 ( subtract 2LQ from both sides )

3LQ = 18 ( divide both sides by 3 )

LQ = 6

Then

LP = LQ + QP = 6 + 9 = 15

Answer:

first we need to find the LCM of the given numbers i.e. 8, 12, 15 and 20

2*2*2*5*3=120

Then

as 2, 3, 5 are not in pairs, we need to multiply the LCM with 2*5*3=30

so,

least perfect square number which is divisible by each of numbers 8 12 15 and 20

=120*30=3600

Step-by-step explanation:

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Answer:

3283m/s

Step-by-step explanation:

V=U+2at

V=35+2(28)(58)

V=35+3248

V=3283m/s

Answer:

26.124

Step-by-step explanation:

SOH CAH TOA

tan 43 = about 0.933

than times it by 28 and get

26.124

Given:

The given equation is:

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

To find:

The value of p.

Solution:

We have,

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

Multiply both sides by 3.

[tex]3(16-3p)=3\left(\dfrac{2}{3}p+5\right)[/tex]

[tex]48-9p=2p+15[/tex]

Isolating the variable terms, we get

[tex]48-15=2p+9p[/tex]

[tex]33=11p[/tex]

Divide both sides by 11, we get

[tex]\dfrac{33}{11}=p[/tex]

[tex]3=p[/tex]

Therefore, the required solution is [tex]p=3[/tex].

Answer:

p=3

Step-by-step explanation:

i got it right on khan

Answer:

x = 3.3

Step-by-step explanation:

A equation is given to us and we need to solve out for x. The given equation is ,

[tex]\sf\longrightarrow 5^{x -2}= 8 [/tex]

Take log on both sides with base as " 10" . We have ,

[tex]\sf\longrightarrow log_{10} 5^{x-2}= log_{10}\ 8[/tex]

Simplify using the property of log , [tex]\sf log a^m = m log a [/tex] , we have ,

[tex]\sf\longrightarrow ( x -2) log_{10} 5 = log_{10} 8 [/tex]

Simplify ,

[tex]\sf\longrightarrow ( x -2 ) log_{10}5 = log_{10} 2^3[/tex]

Again simplify using the property of log ,

[tex]\sf\longrightarrow (x-2) log 5 = 3 log 2[/tex]

We know that log 5 = 0.69 and log 2 = 0.301 , on substituting this , we have ,

[tex]\sf\longrightarrow ( x - 2 ) = \dfrac{ 3\times 0.301}{0.69}[/tex]

Simplify the RHS ,

[tex]\sf\longrightarrow x - 2 = 1.30 [/tex]

Add 2 both sides ,

[tex]\sf\longrightarrow \boxed{\blue{\sf x = 3.30}}[/tex]

Hence the Value of x is 3.30 .

Answer:

its actually 3.292 because we round to the nearest thousandth and thats not even the equation you use above

Step-by-step explanation:

For this equation we use the formula log a^m=m (log a) so the equation will be written as log 5 (5^x-2) = log 5 (8). You use the base, which is 5, and use log to base 5 on both sides of the equation. Then you take the exponent " x-2" and write( x-2) log 5 (5) = log 5(8). Since log a =1, you multiply that 1 by x-2, which keeps it x-2. Making the equation x-2 = log 5 (8). Next, we use the change of the base properties with the formula log b^y= log y/ log b. The equation will be written as x-2 = log 8/ log 5, since 5 is the base it stays in the bottom or basement. We then add +2 to both sides of x-2 and log 8/ log 5. To solve this equation, you can find out what log 8 and log 5 are and divide those and add +2 to solve. So log 8 = 0.903 and log 5 = 0.698970 and divide those to get 1.29190 +2 and you get the answer rounded as 3.292. 

Answer:

Solution: To determine mass of the block we can use second Newton' law \vec F=m\vec a

F

=m

a

. The force and acceleration according the problem is directed along a horizontal surface, and we can omit the vector sign in Newton's law. The force we know F=45NF=45N, thus we should deduce the acceleration. The problem does not specify the initial speed at which time began to count, so for the first time interval, we may write the kinematics equation in the form

(1) S_1=v_1\cdot t_1+a\frac {t_1^2}{2}S

1

=v

1

⋅t

1

+a

2

t

1

2

, where S_1=8m, t_1=2s S

1

=8m,t

1

=2s , other quantities we don't know. The similar equation we can write for next time interval

(2) S_2=v_2\cdot t_2+ a\frac{t_2^2}{2}S

2

=v

2

⋅t

2

+a

2

t

2

2

. where S_2=8.5m, t_2=1s S

2

=8.5m,t

2

=1s

Note that during the first time interval, the speed of the block increased in accordance with the law of equidistant motion and it became the initial speed of the second interval, i.e.

(3) v_2=v_1+a\cdot t_1v

2

=v

1

+a⋅t

1

Substitute (3) to (2) we get

(4) S_2=(v_1+a\cdot t_1)\cdot t_2+ a\frac{t_2^2}{2}=v_1\cdot t_2+a\cdot t_1\cdot t_2+a\frac{t_2^2}{2}S

2

=(v

1

+a⋅t

1

)⋅t

2

+a

2

t

2

2

=v

1

⋅t

2

+a⋅t

1

⋅t

2

+a

2

t

2

2

From equation (1) and (4) we can exclude unknown quantity v_1v

1

, then remain only one unknown aa. For determine aa we dived (1) by t_1t

1

, (4) by t_2t

2

to find the average speed at time intervals and subtract (1) from (4).

(5) \frac {S_2}{t_2}-\frac {S_1}{t_1}=v_1+a\cdot t_1 +a\frac {t_2}{2}-(v_1+a\frac{t_1}{2})=a\frac{t_1+t_2}{2}-

t

2

S

2

−

t

1

S

1

=v

1

+a⋅t

1

+a

2

t

2

−(v

1

+a

2

t

1

)=a

2

t

1

+t

2

− For acceleration we get

(6) a=2\cdot ( {\frac{S_2}{t_2}-\frac{S_1}{t_1})/(t_1+t_2)}=2\cdot \frac{(8.5m/s-4m/s)}{3s}=3ms^{-2}a=2⋅(

t

2

S

2

−

t

1

S

1

)/(t

1

+t

2

)=2⋅

3s

(8.5m/s−4m/s)

=3ms

−2

For mass from second Newton's law we get

(7) m=\frac{F}{a}=\frac{45N}{3ms^{-2}}=15kgm=

a

F

=

3ms

−2

45N

=15kg

Answer: The mass of the block is 15 kg

Answer:

A) 5

Step-by-step explanation: