Which expression represents the situation below?
14 times the sum of 8 and 7, divided by 6.

Answer:

Answer is b

Step-by-step explanation:

just did it

Answer:

Step-by-step explanation:

Hope this helps u !!

Answer:

4?

Step-by-step explanation:

So, at from x 0 to x 2, y goes up 4

Answer:

2

Step-by-step explanation:

The rate of change is defined by [tex]\frac{Rise}{Run}[/tex] , [tex]\frac{y_{2} - y_{1} }{x_{2}-x_{1}}[/tex]. or [tex]\frac{Delta y}{Delta x}[/tex].

For your question, the points are (0,4) and (2,8).

Plugging these points into the formula:

[tex]\frac{8-4}{2-8}[/tex]

After calculations, you would end up with [tex]\frac{4}{2}[/tex] or 2.

Answer:

x=4, y=-2

Step-by-step explanation:

Answer:

x = 4

y = - 2

Step-by-step explanation:

3x + 8y = - 4

2x - 4y = 16                 Multiply the second equation by 2 and add it to the 1st

3x + 8y = - 4

4x - 8y = 32               Add

7x = 28                      Divide by 7

7x/7 = 28/7

x = 4

2x - 4y = 16              Substitute 4 for x

2*4 - 4y = 16            Combine  

8 - 4y = 16                Subtract 8 from both sides

-4y = 16 - 8

-4y = 8                     Divide by -4

y = 8/-4      

y = - 2

Answer

Step-by-step explanation:

8^-5/8^-2

=8^5-(-2)

=8^5+2

=8^7

=2097152

Note in division if the base the base are same then u can subtract their exponent but in multiplication bases are same u should add their exponent.

Answer:

the answer will be volume

please mark the answer as the brainlliest one

Answer:

3 5/12 cups of flour are needed

Step-by-step explanation:

The flour-sugar total is 3 2/3 cups, of which 1/4 cup is sugar.  So, to find the amount of flour used, we subtract 1/4 cup (sugar) from the total (3 2/3 cups):

 11       1

----- - ----              where 11/3 is the improper fraction form of 3 2/3

   3      4

The LCD is 12.  Rewriting this subtraction using the LCD, we get:

44     3

---- - ----- = 41/12 (cups) = 3 5/12 cups

12     12

3 5/12 cups of flour are needed

Answer:

12.5a + 6s = 264.5   and   a + s = 30

Step-by-step explanation:

They also intersect at (17, 13)

(17 student tickets, 13 adult tickets)

Good Luck!

Answer:

B 405

(=20*9 + 25*9)

what are the blue-ish dots on your screen? :|

PQ is an angle bisector since it is splitting the angle RPS in half to RPQ and SPQ

Answer:

10.5 km

Step-by-step explanation:

this can be solved using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

1² + 4² =

1 + 16 = 17

√17 = 4.123km

4² + 5²

16 + 25 = 41

√41 = 6.40 KM

total distance = 6.4 + 4.12 = 10.52

Answer:

g(x) = [tex]-\frac{2}{5} (10)^{x}[/tex]

Step-by-step explanation:

Looking at the equation of a Exponential Function:

The a-value [tex](\frac{2}{5})[/tex] determines whether the function reflects over the x-axis. If it's negative it reflects over the x-axis. If it's positive it stays over the x-axis.

Answer:

95 ≤ 8 < 1/7n

Step-by-step explanation:

95 ≤ 8 < 1/7n

no more = less than or equal to

product of a number n and 1/7 = 1/7•n = 1/7n

Answer:

The answer is below

Step-by-step explanation:

Let x represent the length of the rectangular pen and y represent the width of the rectangular pen.

One side of the pen uses the barn wall, hence the remaining side is 64 m, hence:

x + 2y = 64

x = 64 - 2y       (1)

The area of the wall is the product of the length and the width, hence:

Area (A) = length * width = xy = (64 - 2y)y = 64y - 2y²

A = 64y - 2y²

The maximum area of the dog house is gotten when the derivative of the area is equal to 0. Hence:

A' = 64 - 4y = 0

64 - 4y = 0

4y = 64

y = 16 m

Put y = 16, in equation 1 to find x:

x = 64 - 2(16) = 32 m

x = 32 m

Therefore the pen has a length of 32 m and width of 16 m.

Answer:

A(max) =  512 m²

Dimensions:

x  =  32  m

y  =  16  m

Step-by-step explanation:

Area of the rectangular pen:

A(p) = x*y            x   and   y  sides of the rectangle. A barn will be used in place of a fence; let´s say that only one  x side will be fenced, then the perimeter of the rectangle is:

p  =  x  +  2*y         64  =  x  * 2*y      y  =  (  64  -  x ) / 2

A(p)  =  x*y

Area as a function of x

A(x)  =  x * ( 64  -  x  )/ 2

A(x)  = ( 64*x - x² ) /2

Tacking derivatives on both sides of the equation

A´(x)  = ( 64  -2*x )/2

A´(x)  =  0        64  - 2*x  = 0         2*x  =  64     x  =  32  m

y  =  (  64 - x ) / 2        y  =  (  64  -  32 )/2        y  = 16 m

A(max) =  32 *  16  = 512 m²

To check if x = 32 will bring a maximum to function A(x)

We take the second derivative

A´´(x)  = -  x/4          A´´(x)  < 0   then  x  =  32 is a local maximum

Answer:

here the value of X should be 8 to make this proportion true

3/8=15/40

by cross multiplying

15*8=40*3

120=120

therefore the option C is correct

Answer:

Step-by-step explanation:

In ΔFYG & ΔBUH

∠F = ∠B

FY = BU

YG = UH

ΔFYG ≅ ΔBUH   { Angle Side Side congruent}

The answer is the D ( the last one)

Answer:

19 Black Buttons

Step-by-step explanation:

1/4 of 40= 10

1/5 of 40= 8

10+8=18

18+4=21

So there are 21 white grey and orange.

The rest are black so 40-21=19

So 19 black buttons

Hope this helps

Step-by-step explanation:

40 button

1/4×40=10 white

1/5×40=8 grey

4 orange

Total=22

Then,subtract

40-22

=18 black buttons

16

Step-by-step explanation:

10x+2=9x+18

-2 -2

10x=9x+16

-9x -9x

x=16

Hope this helps! :)

Answer:

x = 16°

Step-by-step explanation:

(10x + 2)° = (9x + 18)°

10x + 2 = 9x + 18

10x + 2 - 2 = 9x + 18 - 2

10x = 9x + 16

10x - 9x = 9x - 9x + 16

x = 16°

Answer:

I believe it’s 3/8 since it’s the highest and that’s the weight most kittens are in the graph.

Step-by-step explanation:

If you want you could wait for somebody else to respond since I could be wrong, but I still hope I was able to help :)

The value of angle tanA in a right-angle triangle is 12/5. The correct option is C.

The branch of mathematics that sets up a relationship between the sides and the angles of the right-angle triangle is termed trigonometry.

The trigonometric functions, also known as a circular, angle, or goniometric functions in mathematics, are real functions that link the angle of a right-angled triangle to the ratios of its two side lengths.

Given that the three sides of the right-angled triangle are AB = 26, BC = 24, and AC = 10.

The value of angle tanA will be calculated as:-

tanA = P / B

tanA = 24 / 10

tanA = 12 / 5

Hence, the value of angle tanA in a right-angle triangle is 12/5. The correct option is C.

To know more about Trigonometry follow

https://brainly.com/question/24349828

#SPJ1

bearing in mind that cos(θ) < 0, is just another way to say that cos(θ) is negative, and sin(θ) > 0, is just another way to say that sin(θ) is positive.

Check the picture below.

Answer:

112

Step-by-step explanation:

Answer:

We have

Angle ORQ

we use the Thales theory

From the formulae

A²+B²=C²

consider

A=OR

B=RQ

C=OQ

so

48²+64²=C²

2304+4096=C²

6400=C²

(6400)¹/²=(C²)¹/²

80=C

But

C=OQ

《OQ=80

Answer:

Between 4 and 5

Step-by-step explanation:

The closest square numbers are 16 and 25, so it’s in between 4 and 5

Answer:

4

Step-by-step explanation:

Step-by-step explanation:

Datos;

una locomotora

recorre 5 horas

a una velocidad de 82 km/h

Se asume que la locomotora lleva un movimiento rectilíneo uniforme.

Su recorrido esta descrito por la siguiente ecuación de posición;

x = x₀+ v · t

x-x₀ = d = v · t

siendo;

d = distancia recorrida

v = 82 km/h

t = 5 horas

Sustituir:

d = (82)(5)

d = 410 km

82km/h * 5h= 410km

La locomotora recorrerá 410km

Answer:

[tex]Pr = 0.0479[/tex]

Step-by-step explanation:

Given

[tex]p =23\%[/tex] --- proportion of completed passes

Required

The probability that he has 6 incomplete before he has 1 completion

Let:

[tex]q \to[/tex] proportion of back passes not completed

Using complement rule:

[tex]q = 1 - p[/tex]

[tex]q = 1 - 23\%[/tex]

[tex]q = 1 - 0.23[/tex]

[tex]q = 0.77[/tex]

The event that he has 6 incomplete passes before he completed one is:

q q q q q q p

And the probability is:

[tex]Pr = q * q * q * q * q * q * p[/tex]

[tex]Pr = q^6* p[/tex]

[tex]Pr = 0.77^6* 0.23[/tex]

[tex]Pr = 0.0479[/tex]