Answer:
8 - 14b ≥ 27 ⇒ subtract 8 from both sides- 14b ≥ 27 -8 - 14b ≥ 19 ⇒ divide both sides by 14- b ≥ 19/14 ⇒ multiply both sides by -1 b ≤ - 19/14 ⇒ multiplication by a negative changes theinequality sign to opposite one
b ≤ - 19/14 and the answer choices B, C and D are all correct as are less than -19/14
A. 140 is the only one incorrect
Prove: The square of the sum of
two consecutive integers is odd.
[tex](2n+1)^2=4n^2+4n+1[/tex] therefore, the first blank is 1.
[tex]4n^2+4n+1=2(2n^2+2n)+1[/tex] therefore, the two other blanks are both 2.
The number in the proof ''The square of the sum of two consecutive integers is odd'' is 2 and 2.
To prove that, The square of the sum of two consecutive integers is odd.
The expression to prove is,
Let us assume that two consecutive integers are n and (n + 1).
Hence, the expression is written as,
[n + (n + 1)]² = (2n + 1)²
= (2n)² + 2 × 2n × 1 + 1²
= 4n² + 4n + 1
= 2 (2n² + 2n) + 1
= odd
Therefore, the number in the blanks are 2 and 2.
To learn more about the Number system visit:
https://brainly.com/question/17200227
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what is y ? x=1 y=? y=3x-7
Answer:
-4.
Step-by-step explanation:
y = 3x - 7; x = 1.
y = 3(1) - 7
= 3 - 7
= -4
Hope this helps!
Answer:
y = - 4
Step-by-step explanation:
y=3x-7
Let x =1
y = 3*1 -7
y = 3-7
y = - 4
A car can cover a distance of 522 km on 36 liters of petrol. How far can it travel on 14 liters of petrol?
522km / 36= 14.5km PER litre
14.5 x 14= 203
Use the distributive property to write an expression that is equivalent to 1/2 (8y - x - 12).
Answer:
4y - 0.5x - 6
Step-by-step explanation:
1/2 (8y - x - 12)
= (8y * [1/2]) - (x * [1/2]) - (12 * [1/2])
= (8y/2) - (x/2) - (12/2)
= 4y - 0.5x - 6
Tell me if I got it wrong! Hope this helps!
Answer:
4y+1/2x+6
Step-by-step explanation:
uh nvm someone already answered my bad
(x-1)(x+2)(x-3)(x+7)(x-5)/2x-2
=0
What can x be?
Answer:
see below
Step-by-step explanation:
Multiplying the equation by 2x - 2 on both sides to cancel out the denominator gives us (x - 1)(x + 2)(x - 3)(x + 7)(x - 5) = 0. Using Zero Product Property and setting each factor to 0, we get:
x - 1 = 0 or x + 2 = 0 or x - 3 = 0 or x + 7 = 0 or x - 5 = 0
x = 1, x = -2, x = 3, x = -7, x = 5
Unfortunately, x cannot be 1 as the numerator would become 0 and then the expression on the left side would become undefined so the final answer is x = -2, x = 3, x = 7, x = 5.
another find the equation of this line, please help meeee!
Answer:
y = 3/4x + 2
Step-by-step explanation:
to find the slope its rise over run and you go up 3 and run 4 to get 3/4. then you just look on the y axis and see that the line passes 2. so that is the answer
An owner of Honda City car sells his car at a price of RM 7.50,000 with a loss present of 12.5%. Then find the price at which he purchased the car and also find the loss suffered by the owner.
Answer:
Cost = RM 857143
Loss = RM 107143
Step-by-step explanation:
Given:
Selling price SP = RM 750000Loss% = 12.5Cost price CP = xCost price is found as:
SP = CP - 12.5%750000 = x - 12.5%750000= x*(100-12.5)/100750000= 0.875xx= 750000/0.875x≈ RM 857143Loss is:
RM 857143 - 750000 = RM 107143Convert the following: 2 liters is equivalent to ounces (rounded to the nearest hundredth)
Answer:
67.63 oz
Step-by-step explanation:
1 liter = 33.814 oz
2 litres = 2 x 33.814 oz = 67.628 oz
What is the median of the following set of measurements?
"22 kg, 24 kg, 28 kg, 19 kg, 27 kg",
The median of the measurements is kg.
Answer:
24 kg
Step-by-step explanation:
The median can be found by putting the numbers in order and then finding the middle value.
In order from least to greatest:
19, 22, 24, 27, 28
24 is the middle value
So, 24 kg is the median.
Answer:
24 kg
Step-by-step explanation:
The median is the number in the middle of the data set. To find the median, arrange the numbers from least to greatest, then locate the middle number.
1. Arrange the numbers from least to greatest
Numbers: 22 kg, 24 kg, 28 kg, 19 kg, 27 kg
Least to greatest: 19 kg, 22 kg, 24 kg, 27 kg, 28 kg
2. Locate the middle number
Cross one number off each end of the set until the middle is reached.
19 kg, 22 kg, 24 kg, 27 kg, 28 kg
Cross off 19 and 28
22 kg, 24 kg, 27 kg
Cross off 22 and 28
24 kg
The middle number has been reached.
median= 24 kg
The median of the measurements is 24 kilograms.
please help me you will recieve 5 stars IF RIGHT ANSWER !
Answer:
[tex]\huge\boxed{\frac{7}{8}}[/tex]
Step-by-step explanation:
[tex](\frac{49 }{64})^{1/2}[/tex]
=> [tex](\frac{7^2}{8^2} )^{1/2}[/tex]
=> [tex]\frac{7^{2*1/2}}{8^{2*1/2}}[/tex]
=> [tex]\frac{7}{8}[/tex]
Answer:
Below
Step-by-step explanation:
You should now that:
● (m/n)^(1/2) = √(m/n)
So:
● (49/64)^(1/2) = √(m/n)
You shoukd now also that:
● √(m/n) = √m / √n
So:
● √(49/64) = √49/√64
Notice that 64 = 8^2 and 49 = 7^2
● √49 / √64 = √(7^2)/√(8^2) = 7/8
So the answer is 7/8
Solve the equation for X (If possible please show work)
Answer:
the correct answer is x=5
Helppp thanksss!!!!!!
Answer:
1 mile
Step-by-step explanation:
in 20 minutes Stuart has gone 1 mile
in 20 minutes Brandy has gone 4 miles
therefore they meet 1 mile from Stuart's house
Answer:
1 mile
Step-by-step explanation:
La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el peso del auto y el cuadrado de la velocidad del mismo. Supongamos que 400 libras de fuerza evitan que un auto que pesa 1600 libras derrape en una curva cuyo radio mide 800 si viaja a 50mph. ¿Cuánta fuerza evitaría que el mismo auto derrapara en una curva cuyo radio mide 600 si viaja a 60mph ?
Answer:
768 libras de fuerza
Step-by-step explanation:
Tenemos que encontrar la ecuación que los relacione.
F = Fuerza necesaria para evitar que el automóvil patine
r = radio de la curva
w = peso del coche
s = velocidad de los coches
En la pregunta se nos dice:
La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.
F ∝ 1 / r
Y luego con el peso del auto
F ∝ w
Y el cuadrado de la velocidad del coche
F ∝ s²
Combinando las tres variaciones juntas,
F ∝ 1 / r ∝ w ∝ s²
k = constante de proporcionalidad, por tanto:
F = k × w × s² / r
F = kws² / r
Paso 1
Encuentra k
En la pregunta, se nos dice:
Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.
F = 400 libras
w = 1600 libras
r = 800
s = 50 mph
Tenga en cuenta que desde el
F = kws² / r
400 = k × 1600 × 50² / 800
400 = k × 5000
k = 400/5000
k = 2/25
Paso 2
¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?
F = ?? libras
w = ya que es el mismo carro = 1600 libras
r = 600
s = 60 mph
F = kws² / r
k = 2/25
F = 2/25 × 1600 × 60² / 600
F = 768 libras
Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.
Find the distance between points K(−1, −3) and L(0, 0). Round to the nearest tenth.
Answer:
d = √10
Step-by-step explanation:
[tex]K(-1, -3) , L(0, 0).\\\\d=\sqrt{((x_2-x_1)^2+ (y_2-y_1)^2) } \\\\x_1 =-1\\\\y_1 =-3\\\\x_2 =0\\\\y_2 =0 \\\\d = \sqrt{(0-(-1))^2+(0-(-3))^2}\\\\ d = \sqrt{(0+1)^2+(0+3)^2}\\\\ d = \sqrt{(1)^2 + (3)^2}\\\\ d = \sqrt{1 + 9}\\\\ d = \sqrt{10} \\[/tex]
Answer:
[tex]\huge\boxed{|KL|=\sqrt{10}\approx3.2}[/tex]
Step-by-step explanation:
METHOD 1:The formula of a distance between two points (x₁; y₁) and (x₂; y₂):
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
We have K(-1; -3) and L(0; 0). Substitute:
[tex]|KL|=\sqrt{(0-(-3))^2+(0-(-1))^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}}[/tex]
METHOD 2:Look at the picture.
We have the right triangle with the legs 3 and 1.
Use the Pythagorean theorem:
[tex]leg^2+leg^2=hypotenuse^2[/tex]
substitute:
[tex]3^2+1^2=|KL|^2\\\\|KL|^2=9+1\\\\|KL|^2=10\to|KL|=\sqrt{10}[/tex]
Three whole numbers have an HCF of 3 and an LCM of 180. Two of the numbers are 45 and 60. Find the third number.
Answer:
Step-by-step explanation:
45=3×3×5
60=2×2×3×5
L.C.M=180
2| 180
2|90
3|45
3|15
3|5
180=2×2×3×3×5
third number=2×3=6
or 2×2×3=12
or2×3×3=18
or 2×2×3×3=36
so third number can be one of 6,12,18,36
the cube root of 2 to the seventh power
Answer:
4 2^(1/3) or 5.0396841995794926590688424291129134022810058588060319203279004486... decimal
Step-by-step explanation:
Simplify the following:
(2^(1/3))^7
Hint: | For all a>=0, (a^(1/3))^m = a^(m/3). Apply this to (2^(1/3))^7.
Multiply exponents. (2^(1/3))^7 = 2^(7/3):
2^(7/3)
Hint: | Separate the exponent of 2^(7/3) into integer and fractional parts.
2^(7/3) = 2^(6/3 + 1/3) = 2^(6/3)×2^(1/3):
2^(6/3) 2^(1/3)
Hint: | Divide 6 by 3.
6/3 = (3×2)/3 = 2:
2^2 2^(1/3)
Hint: | Evaluate 2^2.
2^2 = 4:
Answer: 4 2^(1/3) or 5.0396841995794926590688424291129134022810058588060319203279004486... decimal
Jessie works at a car manufacturing plant. One day she installed a total of 46 axles, 2 in each car she worked on. She wants to know how many
cars she installed axles on. You can write an equation that relates the total number of cars, the total number of axles, and the number of axles
installed per car. This equation will have two known quantities and one unknown quantity.
Part A
Write an equation forj, the number of cars Jessie installed axles in.
BIŲ X, Font Sizes
EEE 를 를
!!!
Characters used: 0 / 15000
Answer:
Jessie instaled axels on 23 cars The equation: 2·j = 46Step-by-step explanation:
j - total number of cars she installed axles on
2 - number of axles she installed on one car
2·j - total number of axles she installed on
46 - total number of axles she installed on
2·j = 46 {divide both sides by 2}
j = 23Martha estimated there were 86 marbles in a jar for a contest. The actual number of marbles in the jar was 108. What was the percent error of Martha's estimation?
Answer:
Roughly 20.4%
Step-by-step explanation:
Use the formula of percent of error:
| Actual number - Guess / Actual number | (100)
The actual number is 108 and the guessed number is 86:
| 108 - 86 / 108 | (100)
= | 22/108 | (100)
= | 0.2037037037 | (100)
The vertical lines indicate absolute value. This means that anything inside of it must be turned into its positive form. Since it is already positive, just take the signs away:
0.2037037037(100)
≈ 0.204(100)
= 20.4
Turn this into a percent:
20.4%
Martha's percent of error is 20.4%
Please tell me if I was right or not. I really hope this helps!
Hellllllllllppppppppppp please
Answer:
As x decreases in value.f(x) decreases in value.......
B) What is the value of f(n-1)?
Answer:
Add information
Step-by-step explanation:
According to mu understanding, this is the part (B) of the question. If you could provide the first part, I can complete it because some useful information is left out.
Evaluate the function below at x=7. Then enter your solution rounded up to 2 decimal places. 1500•1.09^x
Answer:
Value of the function will be 2742.06
Step-by-step explanation:
Given function is,
f(x) = 1500(1.09)ˣ
By substituting the value of x we can find the value of the given function.
For x = 7,
f(7) = 1500(1.09)⁷
= 1500(1.828)
= 2742.0587
≈ 2742.06
Value of the function will be 2742.06
Which one of these relations are functions ?
Please helpppp fast
Answer:
the 4th and 6th one
Step-by-step explanation:
A function is when there are x- and y-values but each x value has only 1 y-value
Simple: If the x-value is repeated its not a function
Answer:
Step-by-step explanation:
1,2,3
3-2(x-1)=2+4x
How do you solve
Answer:
x = 1/2
Step-by-step explanation:
3 - 2(x - 1) = 2 + 4x
3 - 2x + 2 = 2 + 4x
-2x + 5 = 2 + 4x
-2x - 4x = 2 - 5
-6x = -3
x = -3/-6
x = 1/2
Jake ran 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday he ran 1 fewer miles then he ran on Monday. How many miles did he run in all? PLEASE SHOW YOUR WORK I WILL MARK YOU BRAINLIEST AND PLEASE EXPLAIN
Answer:
Jake ran 10 1/6 miles in total
Step-by-step explanation:
4 1/4 + 2 2/3 - (4 1/4-1).
v
6 11/12 + 3 1/4
v
6 11/12 + 3 3/12 = 10 1/6
Jake ran 10 1/6 miles in total (Mon, Tues, Wed).
Answer:
61/6 or 10.1666666667
Step-by-step explanation:
Monday = 4 1/4
Tuesday = 2 2/3
Wednesday = Monday - 1
=> Monday = 17/4 miles
=> Tuesday = 8/3 miles
=> Wednesday = 17/4 - 4/4 = 13/4 miles.
=> (17/4 + 13/4) + 8/3
=> 30/4 + 8/3
=> Take the LCM of the denominators.
=> LCM = 12
=> 90/12 + 32/12
=> 122/12
SImplify 122/12
=> 61/6 or 10.1666666667
Can you help Jorge organize the results into a two-way frequency table? Please answer this ASAP
Answer:
The table is attached!
Step-by-step explanation:
6 students play both musical instrument and a sport3 students play neither a musical instrument nor a sport14 students in total play a sportGiven: There are 24 students in the class
The number of students that does not play a sport is 24 - 14 = 10
The number of students that does not play a musical instrument but play a sport = 14 - 6 = 8
The frequency table thus is attached below:
If you add 12 marshmallows to each of 5 bags of marshmallows, and each bag started with the same number of marshmallows, the total number of marshmallows is given by the expression 5(x+12). Identify an equivaler expression
The answer of the question is 60.
Answer:
The expression that is equivalent to the given expression is:
5x+60
Step-by-step explanation:
It is given that:
if you add 12 marshmallows to each of 5 bags of marshmallows, and each bag started with the same number of marshmallows.
so, let x be the initial number of marshmallows in each bag and now 12 are added to each bag this means that the number of marshmallows in each bag is:
x+12
Hence, total number of marshmallows in 5 bags is:
5(x+12)=5×x+5×12
5(x+12)=5x+60
Hence, the answer is:
5x+60
Feel free to brainliest :)
-7p+2(5p-8)=6(p+6)-7
Answer:
-15
Step-by-step explanation:
-7p+10p-16=6p+36-7
3p-16=6p+29
3p-6p=29+16
-3p=45
p=45/-3
p=-15
Pick out the set of numbers that is not Pythagorean triple
9 40 46
16 30 34
10 24 26
50 120 130
Answer:
[tex]\huge\boxed{9,40,46}[/tex]
Step-by-step explanation:
Let's check it using Pythagorean Theorem:
[tex]c^2 = a^2 + b^2[/tex]
Where c is the longest sides, a and b are rest of the 2 sides
1) 9 , 40 , 46
=> [tex]c^2 = a^2 + b^2[/tex]
=> [tex]46^2 = 9^2 + 40^2[/tex]
=> 2116 = 81 + 1600
=> 2116 ≠ 1681
So, this is not a Pythagorean Triplet
2) 16, 30 and 34
=> [tex]c^2 = a^2 + b^2[/tex]
=> [tex]34^2 = 16^2 + 30^2[/tex]
=> 1156 = 256 + 900
=> 1156 = 1156
No need to check more as we've found the one which is not a Pythagorean Triplet.
Answer:
[tex] \boxed{ \huge{ \boxed{ \sf{ \blue{9 , \: 40 \:, 46 \: }}}}}[/tex]Option A is the correct option.
Step-by-step explanation:
1. Let h , p and b are the hypotenuse , perpendicular and base of a right - angled triangle respectively.
From Pythagoras theorem,
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
Here, we know that the hypotenuse is always greater than perpendicular and base,
h = 46 , p = 40 , b = 9
⇒[tex] \sf{ {46}^{2} = {40}^{2} + {9}^{2} }[/tex]
⇒[tex]2116 = 1600 + 81[/tex]
⇒[tex] \sf{2116 ≠ 1681}[/tex]
Thus , the relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is not satisfied by h = 46 , p = 40 , b = 9
So, The set of numbers 9 , 40 , 46 is not Pythagorean triple.
------------------------------------------------------
2. 16 , 30 , 34
h = 34 , p = 30 , b = 16
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
⇒[tex] \sf{ {34}^{2} = {30}^{2} + {16}^{2} }[/tex]
⇒[tex] \sf{1156 = 900 + 256}[/tex]
⇒[tex] \sf{1156 = 1156}[/tex]
The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 34 , p = 30 , b = 16
So, the set of numbers 16 , 30 , 34 is a Pythagorean triple.
------------------------------------------------------
3. 10, 24 , 26
h = 26 , p = 24 , b = 10
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
⇒[tex] \sf{ {26}^{2} = {24}^{2} + {10}^{2} }[/tex]
⇒[tex] \sf{676 = 576 + 100}[/tex]
⇒[tex] \sf{676 = 676}[/tex]
The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and h i.e h = 26 , p = 24 , b = 10
So, the set of numbers 10, 24 , 26 is the Pythagorean triple.
-----------------------------------------------------
4. 50 , 120 , 130
h = 130 , p = 120 , b = 50
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
⇒[tex] \sf{ {130}^{2} = {120}^{2} + {50}^{2} }[/tex]
⇒[tex] \sf{16900 = 14400 + 2500}[/tex]
⇒[tex] \sf{16900 = 16900}[/tex]
The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 130 , p = 120 , b = 50
So, the set of numbers 50, 120 , 130 is the Pythagorean triple.
-----------------------------------------------------
In this way, to satisfy the Pythagoras Theorem , the hypotenuse ( h ) , perpendicular ( p ) and the base ( b ) of a right - angles triangle should have the particular values in order. These values of h , p and b are called Pythagorean triple.
Hope I helped!
Best regards!!
Suppose y varies jointly as x & z. If y = -180 when z = 15and x = -3,then find y when x = 7 and z = -5.
Answer:
y = - 140
Step-by-step explanation:
Given that y varies jointly as x and z then the equation relating them is
y = kxz ← k is the constant of variation
To find k use the condition y = - 180 when z = 15 and x = - 3, thus
- 180 = k × - 3 × 15 = - 45k ( divide both sides by - 45 )
4 = k
y = 4xz ← equation of variation
When x = 7 and z = - 5, then
y = 4 × 7 × - 5 = - 140
help with geometry pls
Answer:
option 2 must be the correct answer because the two figure are congruent figure.
Answer:
B
Step-by-step explanation:
Since Δ ABC ~ Δ DEF then the ratios of corresponding sides are equal, that is
[tex]\frac{AB}{DE}[/tex] = [tex]\frac{BC}{EF}[/tex] = [tex]\frac{CA}{FD}[/tex] → B
