Answer:
B.
Explanation:
Answer:
B
Explanation:
using the following balanced chemical equation: PCL5 -> PCL3 + CL2 and knowing that Keq = 7.9, [PCL3] = 0.054M and [CL2] = 0.34M
a. write the Keq expression for the reaction
b. find the [PCL5]
c circle the correct answer: the reaction favored is the (forward, reverse)
Answer:
see explanations
Explanation:
PCl₅ => PCl₃ + Cl₂
C(eq): [PCl₅] 0.054M 0.34M
a. Keq = [PCl₃][Cl₂]/[PCl₅]
b. 7.9 = (0.054)(0.34)/[PCl₅] => [PCl₅] = (0.054)(0.34)/(7.9) = 0.0023M
c. If [PCl₃] = 0.054M; [Cl₂] = 0.34M and [PCl₅] = 0.0023M then the reaction is at equilibrium and will not shift forward or in reverse. In order to determine if reaction is not at equilibrium, a set of concentration values needs to be given in problem, used to calculate Qeq and compared to the given Keq value. The following defines direction of shift ...
Keq < Qeq => rxn shifts left
Keq = Qeq => rxn is at equilibrium (no shift)
Keq > Qeq => rxn shifts right
NOTE: If Keq is listed first followed by Qeq in the above conditions, the inequality symbol indicates direction of shift.
Nitrogen gas was collected by water displacement. What was the pressure of the N2 collected if the temperature was 50 degrees celcius?
Answer:
Explanation:
Atmospheric pressure = 101.325 kPa
vapor pressure of water at 50°C = 12.332 kPa
pressure of N₂ = (Atmospheric pressure) - (vapor pressure of water at 50 oC)
pressure of N₂ = (101.325 kPa) - (12.332 kPa)
pressure of N₂ = 88.993 kPa
Therefore, the pressure of the N₂ collected if the temperature was 50 degrees celcius is 88.993 kPaWhich of the following is not an indication of a chemical change?
A. Fracture Formation
B. Energy transfer
C. Precipitate formation.
D. Gas production
Answer:
C. precipitate formation.
Explanation:
options C is correct answer.
Answer:
C. precipitate formation.
Explanation:
The temperature of a 350. mL sample of gas increases from 27 °C to 227 °C. What is the final volume of the sample of gas, if the pressure and amount of gas in the container is kept constant?
Group of answer choices
Answer:
[tex]V_2=583.3mL[/tex]
Explanation:
Hello,
In this case, for the given constant amount and pressure of the, we apply the Charles' law which allows us to understand the volume-pressure behavior as a directly proportional relationship:
[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
Thus, since we need to compute the volume after the temperature increase (which must be expressed in absolute Kelvins), we obtain V2 as:
[tex]V_2=\frac{V_1T_2}{T_1} =\frac{350.0mL*(227+273.15)K}{(27+273.15)K}\\ \\V_2=583.3mL[/tex]
Best regards.
Lifting a box off the floor is an example of what type of force?
A). Natural
B).applied
C).frictional
D).gravitational
Answer:
It would be applied force.
Explanation:
Hope it helps:)
what is the reaction?
Answer:
A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. ... A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.
Explanation:
Hopefully this is what you needed
pls I need help with these ques. help plsssssssssssssss
Answer:
q1..no.2 and 4 are aromatic
Question 17 In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that 786. liters per second of dinitrogen are consumed when the reaction is run at 222.°C and 0.35atm. Calculate the rate at which ammonia is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.
Answer:
Explanation:
N₂ + 3H₂ = 2 NH₃
1 vol 2 vol
786 liters 1572 liters
786 liters of dinitrogen will result in the production of 1572 liters of ammonia
volume of ammonia V₁ = 1572 liters
temperature T₁ = 222 + 273 = 495 K
pressure = .35 atm
We shall find this volume at NTP
volume V₂ = ?
pressure = 1 atm
temperature T₂ = 273
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
[tex]\frac{.35\times 1572}{495} =\frac{1\times V_2}{ 273 }[/tex]
[tex]V_2 =303.44[/tex] liter .
mol weight of ammonia = 17
At NTP mass of 22.4 liter of ammonia will have mass of 17 gm
mass of 303.44 liter of ammonia will be equal to (303.44 x 17) / 22.4 gm
= 230.28 gm
=.23 kg / sec .
Rate of production of ammonia = .23 kg /s .
0.5 moles of CO2 have a volume of 50 L and a pressure of 0.8210 atm. What must be the temperature of the gas?
Answer:
1000 K
Explanation:
Given data
Moles of carbon dioxide (n): 0.5 molesVolume of carbon dioxide (V): 50 litersPressure of carbon dioxide (P): 0.8210 atmospheresTemperature of carbon dioxide (T): ?We can find the temperature of carbon dioxide using the ideal gas equation.
[tex]P \times V = n \times R \times T\\T = \frac{P \times V}{n \times R} = \frac{0.8210atm \times 50L}{0.5mol \times \frac{0.08206atm.L}{mol.K} }=1000 K[/tex]
The temperature of the gas is 1000 K.
An aqueous solution of HNO2 is poured onto a solid pile of SrCO3. Identify the net ionic equation for this reaction.
A) SrCO3(s) + 2 HNO2(aq) → Sr(NO2)2(aq) + HCO3(aq)
B) no reaction occurs
C) Sr2+ + CO32- + 2 H+ → Sr2+ + H2O + CO2(g)
D) SrCO3(s) + 2 HNO2(aq) → Sr(NO2)2 + H2O + CO2(g)
E) SrCO3(s) + 2 H+ → Sr2+ + H2O + CO2(g)
Answer:
D) SrCO3(s) + 2 HNO2(aq) → Sr(NO2)2 + H2O + CO2(g)
Explanation:
When an acid react with carbonate, it produces nitrate, carbon-dioxide gas and water molecule. When nitrous acid react with Strontium carbonate, three products are formed i. e. Strontium nitrate, carbon-dioxide gas and water. In the reaction, both nitrous acid and Strontium carbonate exchange their partners with each other and forming a different products.
Answer:
Option E is correct.
The net ionic equation is given as
SrCO₃(s) + 2H⁺ → Sr²⁺ + H₂O + CO₂(g)
Explanation:
When acids react with carbonate compounds, it leads to the liberation of CO₂, hence, when an aqueous solution of HNO₂ is poured onto a solid pile of SrCO₃, the balanced overall equation is given as
SrCO₃(s) + 2HNO₂(aq) → Sr(NO₂)₂ + H₂O + CO₂(g)
But for the net ionic reaction, it is obtained by eliminating ions that occur on both sides of the overall reaction. Note that ions exist onlubone the aqueous compounds.
Hence, the two aqueous compounds that exist in the balanced overall equation are
2HNO₂(aq) on the left hand side and Sr(NO₂)₂ on the right hand side
In their ionic form, 2HNO₂ ⇌ 2H⁺ + 2NO₂⁻
And Sr(NO₂)₂ ⇌ Sr²⁺ + 2NO₂⁻
And it is evident that the ion that occurs on both sides and needs to be deleted is NO₂⁻,
Hence, the net ionic equation is
SrCO₃(s) + 2H⁺ → Sr²⁺ + H₂O + CO₂(g)
Hope this Helps!!!
An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0 L tank?
Answer:
1.2 atm
Explanation:
Given data
Volume of the gas in the tank (V₁): 200.0 LPressure of ethylene gas in the tank (P₁): ?Volume of the gas in the torch (V₂): 300 LPressure of the gas in the torch (P₂): 0.8 atmIf we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.
[tex]P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm[/tex]
State whether the following is an example of a physical or chemical change:! 21. Burning a log: ________________________________! 22. Folding a piece of paper: _________________________! 23. Freezing water: _________________________! 24. Bending a copper wire. _________________________!
Answer:
Physical change
Explanation:
Because it doesn't require any chemical to change
Answer:
Physical change
Physical change
Physical change
Physical change
Explanation:
Identifying the Body's Responses to
Quick
Check
Which type of response identifies a specific pathogen in the body?
A(n)
response
Answer:
Specific Immune Response
Explanation:
A specific immune response identifies the pathogen which then allows it to produce antibodies that protect against that SPECIFIC pathogen.
Answer:
immuneExplanation:
2. What happens to the pH when you add more H+ ions to a solution that has no buffers?
In a titration, 100 mL of 0.026 M HCl (aq) is neutralized by 13 mL of KOH(aq). Calculate the molarity of KOH (aq).
Answer:
0.2M
Explanation:
Step 1:
Data obtained from the question.
Volume of acid (Va) = 100mL
Molarity of the acid (Ma) = 0.026 M
Volume of base (Vb) = 13mL
Molarity of the base (Mb) =..?
Step 2:
The balanced equation for the reaction. This is given below:
HCl + KOH —> KCl + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Step 3:
Determination of the molarity of the base, KOH. This can be obtained as follow:
MaVa/MbVb = nA/nB
0.026 x100 / Mb x 13 = 1
Cross multiply to express in linear form
Mb x 13 = 0.026 x 100
Divide both side by 13
Mb = 0.026 x 100 / 13
Mb = 0.2M
Therefore, the molarity of the base, KOH is 0.2M
Answer:
0.2M
Explanation:
KOH(aq) + HCl(aq) ⇒ KCl(aq) + H2O(l)
We express the moles of analyte (HCl) and titrant based (KOH) on their molar concentration:
M1 * V1 = M2 * V2
The molarity of the solution is calculated with the following equation:
M2 = V1 x M1 / V2
Where:
V2 = valued sample volume
V1 = volume of titrant consumed (measured with the burette)
M1 = concentration of titrant solution
M2 = concentration of sample
M2 = 100mL * 0.026M / 13mL = 0.2M
If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?
Answer:
204g of NH3
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 —> 2NH3
Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.
Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:
Number of mole of NH3 = 12 moles.
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 =..?
Mass = mole x molar mass
Mass of NH3 = 12 x 17
Mass of NH3 = 204g.
Therefore, 204g of NH3 will be produced from the reaction.
What should happen if a good experiment is replicated?
The results will decrease.
The results will increase.
The results will be different.
The results will be similar.
Answer:
The results will be similar.
Which shows an isomer of the molecule below?
Answer:
D
Explanation:
An isomer is a molecule with the same number of atoms as another compound, but they differ in arrangement of the atoms.
Answer:
D
Explanation:
A P E X
What is another term for anode?
Answer:positive electrode
Explanation:
Anode can also be referred to as positive electrode in a cell
a fertilizer manufacturer makes a batch of 20kg of ammonium nitrate. what mass of ammonia in kg, does the manufacturer need to start with?
Answer:
[tex]m_{NH_3}=4.25kgNH_3[/tex]
Explanation:
Hello,
In this case, for the production of ammonium nitrate we shall consider the following chemical reaction:
[tex]NH_3+HNO_3\rightarrow NH_4NO_3[/tex]
Hence, since the molar mass of ammonium nitrate is 80 g/mol and the molar mass of ammonia is 17 g/mol, we could compute the required mass of ammonia to produce 20 kg of ammonium nitrate by using kilo-based units:
[tex]m_{NH_3}=20kgNH_4NO_3*\frac{1kmol}{80kgNH_4NO_3}*\frac{1kmolNH_3}{1kmolNH_4NO_3}*\frac{17kgNH_3}{1kmolNH_3} \\\\m_{NH_3}=4.25kgNH_3[/tex]
Best regards.
Plants remove carbon to the atmosphere during
Answer:
respiration
Explanation:
Plants give out carbon dioxide not only at night but during the day too. It happens because of the process of respiration in which plants take in oxygen and give out carbon dioxide. As soon as the sun rises another process called photosynthesis starts, in which carbon dioxide is taken in and oxygen is given out.
Plants use photosynthesis to capture carbon dioxide and then release half of it into the atmosphere through respiration. Plants also release oxygen into the atmosphere through photosynthesis
In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percent yield of this reaction? *
85.0%
72.0%
75.0%
67.0%
Answer:
75.0%
Explanation:
Data obtained from the question. This includes the following:
Actual yield = 6.13g
Theoretical yield = 8.17g
Percentage yield =...?
The percentage yield can be obtain by using the following formula:
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield = 6.13/8.17 x 100
Percentage yield = 75.0%
Therefore, the percentage yield of water from the reaction above is 75.0%
Please help! BRAINLIEST to correct answer!!!!
Answer:
Exothermic ProcessExplanation:
The tribute states of the ancient Aztec empire
were governed directly by the emperor.
made regular payments to the emperor.
acted as powerful independent city-states.
O surrounded the main Aztec city-state.
Answer:
made regular payments to the emperor.
Explanation:
The Aztec Empire was an alliance of three states: Mexico-Tenochtitlan, Texcoco, and Tlacopan. The area in and around the Valley of Mexico was ruled by these three city-states from 1428 to 1521. The state religion of the empire was polytheistic. The tribute states of the ancient Aztec empire made regular payments to the emperor.
Answer:
B
Explanation:
CH³C⁴HCOCH³ how many atoms of each element are in one molecule of 2-heptanone
Answer:
- 7 carbon atoms.
- 14 hydrogen atoms.
- 1 oxygen atom.
Explanation:
Hello,
In this case, for the given compound, heptanone, whose chemical formula is:
[tex]CH_3COCH_2CH_2CH_2CH_2CH_3[/tex]
We can write the molecular formula showing the present atoms of each element:
[tex]C_7H_{14}O[/tex]
In such a way we have:
- 7 carbon atoms.
- 14 hydrogen atoms.
- 1 oxygen atom.
Best regards.
Creatinine, �!�!�!�, is a by-product of muscle metabolism, and creatinine levels in the body are known to be a fairly reliable indicator of kidney function. The normal level of creatinine in the blood for adults is approximately 1.0mg per deciliter (dL) of blood. If the density of blood is 1.025g/mL, calculate the molality of a normal creatinine level in a 10.0mL blood sample. What is the osmotic pressure (in atm) of this solution at 25.0°C?
Answer:
Explanation:
molecular weight of creatinine = 131
1 mg of creatinine = 1 x 10⁻³ / 131 = 7.63 x 10⁻⁶ mole of creatinine.
volume of solution = .1 L
mass of blood solution = .1 x 1025
= 102.5 g
mass of solvent = 102.5 g approximately
= .1025 kg
molality = mole of solute / mass of solvent in kg
= 7.63 x 10⁻⁶ / .1025 kg
= 74.44 x 10⁻⁶ .
Osmotic pressure :---
π V / T = nR π is osmotic pressure , V is volume of solution in liter , T is absolute temperature , n is molality .
π x .1 / 298 = 74.44 x 10⁻⁶ x .082
π = 18.19 x 10⁻³ atm
A characteristic that describe a plant that can make its own food is
Answer:
Photosynthesis
this is correct
The percent yield of a reaction in which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What is the actual yield of the reaction? A) 13 grams B) 120 grams C) 208 grams D) 7.5 grams
Answer:
D) 7.5 grams
Explanation:
Hello,
In this case, since the percent yield is defined by:
[tex]Y=\frac{m^{actual}}{m^{theoretical}} *100\%[/tex]
In such a way, since the percent yield is up to 25% and the expected or theoretical amount is 30 g of the product, the actual yield of the reaction is:
[tex]m^{actual}=\frac{Y*m^{theoretical}}{100\%} =\frac{25\%*30g}{100\%} \\\\m^{actual}=7.5g[/tex]
Therefore the answer is D) 7.5 grams.
Best regards.
How is a niche different than a habitat?
A habitat is more than a physical place; it's a species' role in a specific place and it can change from niche to niche.
A niche is more than a physical place; it's a species' role in a specific place and it can change from habitat to habitat.
A niche and a habitat are the same.
A niche is just a physical place; a habitat is a species' role in a specific place.
Answer:
A niche is more than a physical place; it's a species' role in a specific place and it can change from habitat to habitat.
Explanation:
Niche: In biology, the term "niche" is described as a process through which different organisms tends to fit-in into a specific ecosystem or an ecological community. However, a niche is considered as the "evolutionary result" of a specific species behavioral, morphological, and physiological adaptations associated with its surroundings.
Habitat: In biology, the term "habitat" is described as an environmental or ecological area that is being inhabited by a specific species of plants, animals, or other organisms.
Therefore, a niche is entirely different from a habitat because an organism's niche tends to explain every different aspect of its life whereas its habitat explains the place it lives.
The first step that you will do in lab is to prepare approximately 20.0 mL each of the following solutions of NaOH, using the NaCl solution to dilute the concentrated (0.300 M) solution of NaOH. After you prepare each solution, transfer it to a clean 50 mL beaker on top of a labeled piece of paper. 0.200 M NaOH 0.150 M NaOH 0.100 M NaOH 0.050 M NaOH 0.025 M NaOH
Answer:
0.200 M NaOH: 13.3 mL of the concentrated solution and complete to 20.0mL
0.150 M NaOH: 10.0 mL of the concentrated solution and complete to 20.0mL
0.100 M NaOH: 6.67 mL of the concentrated solution and complete to 20.0mL
0.050 M NaOH: 3.33 mL of the concentrated solution and complete to 20.0mL
0.025 M NaOH: 1.67 mL of the concentrated solution and complete to 20.0mL
Explanation:
It is possible to prepare a solution from a more concentrated one. In the problem, the concentrated solution is 0.300M NaOH. Thus, to prepare 20.0mL of each of the solutions you will need:
0.200 M NaOH: 20.0mL × (0.200M / 0.300M) = 13.3 mL of the concentrated solution and complete to 20.0mL
The ratio between the concentrated solution and the solution you want to prepare is called "dilution factor"
0.150 M NaOH: 20.0mL × (0.150M / 0.300M) = 10.0 mL of the concentrated solution and complete to 20.0mL
0.100 M NaOH: 20.0mL × (0.100M / 0.300M) = 6.67 mL of the concentrated solution and complete to 20.0mL
0.050 M NaOH: 20.0mL × (0.050M / 0.300M) = 3.33 mL of the concentrated solution and complete to 20.0mL
0.025 M NaOH: 20.0mL × (0.025M / 0.300M) = 1.67 mL of the concentrated solution and complete to 20.0mL