Which of the following best describes reverberation?
A.The wave fronts become mixed and broken up due to contact with a rough or
irregular surface.
B. A change in the sound wave velocity causes the wave to bend in a different
direction.
C. A fraction of the sound waves are absorbed by an object and converted to heat
energy.
D. A single sound undergoes several reflections due to multiple reflecting surfaces.

Answers

Answer 1

Reverberation, in psychoacoustics and acoustics, is a persistence of sound after the sound is produced

Explanation:

I think it is right hope its helps

Answer 2

Answer:

D. A single sound undergoes several reflections due to multiple reflecting surfaces.

Explanation:

Sometimes, the source of a sound is surrounded by multiple reflecting surfaces. The waves traveling from the source strike these different surfaces, causing multiple reflections. For example, a single clap of thunder reflects on several clouds and the earth's surface, causing you to hear a rolling rumble instead of a single sound.


Related Questions

Write down the role played by four digestive juices in digestion and the
organs which secrete them.

Answers

Answer:

Digestive juices secreted by various organs such as salivary glands in the mouth, stomach, liver and pancreas help in the process of digestion of food. Saliva secreted by the salivary glands in the mouth aids in the breakdown of starch present in the food to simple sugar

Explanation:

A parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is connected in series to a 4.89 μF capacitor. This three‑capacitor combination is connected to a 15.5 V battery. Determine the charge on each capacitor.

Answers

Answer:

a. i. 35.96 μC  b. i. 11.98 μC ii. 24.04 μC

Explanation:

We need to find the total capacitance of the system C.

The total capacitance of the parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is C' = 1.47 μF + 2.95 μF = 4.42 μF.

C' = 4.42 μF is in series with the 4.89 μF capacitor and for a series combination of capacitors, we have the total capacitance, C from

1/C = 1/4.42 μF + 1/4.89 μF

1/C = (4.42 μF + 4.89 μF)/(4.42 μF × 4.89 μF)

1/C = 9.31 μF/21.6138 μF²

C = 21.6138/9.31 μF

C = 2.32 μF

So, the total charge in the circuit Q = CV where C = total capacitance = 2.32 μF and v = voltage = 15.5 V

So, Q = CV

Q = 2.32 μF × 15.5 V

Q = 35.96 μC

i. The charge on the 4.89 μF capacitor

Since the 4.89 μF is in series with C', the total charge flowing i the circuit is the total charge in the 4.89 μF capacitor. So, its charge Q = 35.96 μC

b. The charge in the 1.47 μF and 2.95 μF capacitors.

To find the charge in the 4.89 μF and 2.95 μF capacitors, we need to find the voltage across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor. The voltage, V' across the 4.89 μF capacitor, since Q = CV', V' = Q/C = 35.96 μC/4.89 μF = 7.35 V

So, the voltage V" across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor, C' is V" = 15.5 V - V' (since V' + V" = 15.5 V).

So, V" = 15.5 V - V'

V" = 15.5 V - 7.35 V

V" = 8.15 V

i. The charge on the 1.47 μF capacitor

Using Q' = CV" where Q' = charge across capacitor, C = 1.47 μF and V" = 8.15 V.

So, Q' = CV"

Q' = 1.47 μF × 8.15 V

Q' = 11.98 μC

ii. The charge on the 2.95 μF capacitor

Using Q" = CV" where Q' = charge across capacitor, C = 2.95 μF and V" = 8.15 V.

So, Q" = CV"

Q" = 2.95 μF × 8.15 V

Q" = 24.04 μC

What is the relationship between electric field lines and equipotential lines that you observed in doing the lab

Answers

Answer:

Explained below

Explanation:

Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.

Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.

Use the information below the answer the following 3 questions.

A 50 kg crate is being dragged across a floor by a force of 225 N at an angle of 40o from the horizontal. The crate is dragged a distance of 5.0 m and the frictional force is 60 N.



Question 2 (2 points)
Question 2 options:
The work done on the crate by the applied force is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 3 (2 points)
Question 3 options:
The work done on the crate by the frictional force is -___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 4 (2 points)
Question 4 options:
The net work done on the crate is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).

Hint: Do not use rounded answers in subsequent calculations

Answers

Answer:

2. 8.62×10² Nm

3. 2.30×10² Nm

4. 6.32×10² Nm

Explanation:

2. Determination of the work done by the applied force.

Force (F) = 225 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fd × Cos θ

Wd = 225 × 5 × Cos 40

Wd = 8.62×10² Nm

3. Determination of the work done by the frictional force.

Frictional Force (Fբ) = 60 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fբd × Cos θ

Wd = 60 × 5 × Cos 40

Wd = 2.30×10² Nm

4. Determination of the net work done.

We'll begin by calculating the net force acting on the crate

Force applied (F) = 225 N

Frictional Force (Fբ) = 60 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 225 – 60

Fₙ = 165 N

Finally, we shall determine the net Workdone. This can be obtained as follow:

Net force (Fₙ) = 165 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fₙd × Cos θ

Wd = 165 × 5 × Cos 40

Wd = 6.32×10² Nm

Two astronomy students travel to South Dakota. One stands on Earth’s surface and enjoys some sunshine. At the same time, the other descends into a gold mine where neutrinos are detected, arriving in time to detect the creation of a new radioactive argon nucleus. Although the photon at the surface and the neutrinos in the mine arrive at the same time, they have had very different histories. Describe the differences.

Answers

Answer:

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

Explanation:

Although The Photon ( sunshine from the sun's surface ) heating up the student standing on the Earth's surface and the neutrinos discovered by the other student inside the gold mine are both formed in the Sun's core.

The difference between both are

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

help with this physics question please :)

Answers

Answer:

is that rm in you profile pic

HELP me
Which sentence best describes how the horse is doing work?
A It is using motion to transfer energy and force away from the heavy object
B it is using force to apply power and decrease the energy of the heavy object
C it is using energy to apply the force needed to move the object over a distance
D it is using power to force the heavy object to move over A certain distance

Answers

The answer to the question is C

Why is it difficult to maintain constant speed of a vehicle?​

Answers

Answer:

The road surface is always rough, so the frictional force between the tires and the road surface make it difficult to maintain constant speed because acceleration always changes.

Hey there!

Yes, it's difficult to maintain a constant speed of a vehicle.

Explanation:

Because, roads surfaces are not always smooth, they are rough too, for which friction occurs.

Hope it help you


A particular electric car is supplied with 300 kJ of chemical energy by the battery. Of this, a total of 70.5 kJ of energy is wasted as heat.
Calculate the overall efficiency of the electric car.

Answers

Supplied energy=300kJ

Wasted energy=70.5J

Used energy:-

[tex]\\ \sf\longmapsto 300-70.5=229.5kJ[/tex]

We know

[tex]\boxed{\sf Efficiency=\dfrac{Used\:Energy}{Supplied\:Energy}\times 100}[/tex]

[tex]\\ \sf\longmapsto Efficiency=\dfrac{229.5}{300}\times 100[/tex]

[tex]\\ \sf\longmapsto Efficiency=\dfrac{229.5}{3}[/tex]

[tex]\\ \sf\longmapsto Efficiency=76.5\%[/tex]

The overall efficiency of the electric car = 76.5 %

To find the efficiency the given values are:

Energy supplied = 300 kJ

Energy wasted = 70.5 kJ

Define efficiency and calculate the value of efficiency.

      In the system the output energy is compared to the input energy is known as efficiency. That can be written as percentage ratio of output energy to the input energy.

Formula of efficiency is,

             Efficiency = ( E out / E in ) × 100

Here, Energy supplied = 300 kJ

so, energy used = Energy supplied - Energy wasted

                           = 300 - 70.5

                           =  229.5 kJ

Thus, substituting E out = 300 kJ , E in = 229.5 kJ

            Efficiency = ( 229.5 / 300 ) ×100

                             = 229.5 / 3

                             = 76.5

Hence, The overall efficiency of the electric car is 76.5 %

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A hockey puck has a mass of 0.21 kg. If the hockey puck
is moving with 74 J of kinetic energy, what is its speed?
Show all your work.

Answers

Answer:

v = 26.54 m/s

Explanation:

Given that,

The mass of a hockey puck, m = 0.21 kg

The kinetic energy of the hockey puck, E= 74 J

We need to find the speed of the hockey puck. Let the speed is v. We know that, the kinetic energy is given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

Where

v is the speed

So,

[tex]v=\sqrt{\dfrac{2E}{m}} \\\\v=\sqrt{\dfrac{2\times 74}{0.21}} \\\\v=26.54\ m/s[/tex]

So, the speed of the hockey puck is 26.54 m/s.

Which is an outer planet?

Answers

Answer:

pluto

Explanation:

Dwarf because it is very minut

Answer:

I think Saturn.

Explanation:

I think the inner planets are Mercury, Venus, Earth and Mars whereas the outer ones are Jupiter, Saturn, Uranus and Neptune.

A girl is travelling on her bike at a speed 2.59 m/s. If the
girl and her bike have a kinetic energy of 190 J, what is
the combined mass of the girl and her bike? Show all
your work

Answers

Answer:

Mass, m = 146.72 kilograms

Explanation:

Given the following data;

Kinetic energy = 190 J

Velocity = 2.59 m/s

To find the combined mass of the girl and her bike;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = ½mv²

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

190 = ½*m*2.59

Cross-multiplying, we have:

380 = 2.59m

Mass, m = 380/2.59

Mass, m = 146.72 kilograms

.
What is the equation for work?

Work = force / distance

Work = force - distance

Work = force + distance

Work = force * distance

Answers

work = force* distance

Answer:

Work = F X D

Explanation:

Work (J) equals Force (N) multiplied by Distance (M)

it will be easier to lift a load in wheel barrow if the load is moved towards the wheel. Give Reason.

Answers

Answer:

Here's your answer: The wheelbarrow's wheel and axle help the wheelbarrow to move without friction thus making it easier to push or pull. That's why it will be easier to lift a load in wheel barrow of the load is transferred towards the wheel.

Explanation:

Answer:

Explanation:

The wheel barrows wheel and axle helps the wheelbarrow to move without friction this making it easier to push or pull.thats why it will be easier to lift a load in a wheelbarrow if it's transferred towards the wheel..

Hope it helps

(d) Below shows a hydraulic press with a pump piston of area 4 cm2 and a ram area of

12 cm2 . IF A force of 300 N is applied on the pump piston, find:

(i)the maximum load on the ram.

(ii) the velocity ratio of the machine.

(iii) the mechanical advantage of the machine.

(iv)the efficiency of the machine.

Answers

Answer:

Explanation:

hi

How can we measure electromotive force of a battery illustrated answer with the help of circuit diagram

Answers

Answer:

the emf of the cell can be determined by measuring the voltage across the cell using a voltmeter and the current in the circuit using an ammeter for various resistances.

An electron enters the magnetic field at right angle from left B into paper. The electron will be deflected?

Answers

Answer:

According to this direction of force is perpendicular to the direction of current and magnetic field. Therefore force is opposite to electron into the paper at 90°.

if the pelican in item 3 was traveling at the same speed but was only 2.7m above the water, how far would the fish travel horizontally before hitting the water?​

Answers

Answer:

5.66 m

Explanation:

From online sources, the speed in item 3 being referred to was discovered to be 7.62 m/s

Now, let's get the time of flight from one of Newton's equation of motion;

S = ut + ½gt²

Considering the vertical component, we have u = 0 m/s.

Thus;.

S = ½gt²

Plugging in the relevant values;

2.7 = ½ × 9.8 × t²

t² = 2.7/4.9

t = √(2.7/4.9)

t = 0.7423 s

Now, when we consider the horizontal component of the motion, we have;

S = vt

Where;

S is the distance the fish will travel horizontally before hitting the water.

v = 7.62 m/s

t = 0.7423

Thus

s = 7.62 × 0.7423

s ≈ 5.66 m

A rectangular coil of wire, 22.0 cm by 35.0 cm and carrying a current of 1.40 A, is oriented with the plane of its loop perpendicular to a uniform 1.50-T magnetic field pointing into the plane of the loop. Let the loop be in x-y Cartesian plane so that the long and short sides of the loop are parallel to x- and y-axis, respectively. The loop center is at the origin of x-y Cartesian plane. Note that the magnetic field is in the direction of the negative z-axis.a. Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the z-axis that the magnetic field exerts on the coil.b. The plane of the coil is now rotated through +30º from its initial orientation (the x-y plane of the Cartesian coordinate system that remains the same). Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the rotation axis that the magnetic field exerts on the coil.

Answers

Answer:

a)  [tex]F_{net}=0[/tex]

b)  [tex]T=0[/tex]

Explanation:

From the question we are told that:

Dimensions:

[tex]L*B=22.0*35.0cm[/tex]

Current [tex]I=1.40A[/tex]

Magnetic field [tex]B=1.40[/tex]

Therefore

[tex]Area=L*B[/tex]

[tex]A=22.0*35.0cm[/tex]

[tex]A=770cm=>770*0^{-4}[/tex]

a)

Generally Force on Looping gives

[tex]F_1-F_2[/tex]

[tex]F_3=F_4[/tex]

Therefore

[tex]F_{net}=0[/tex]

b)

Generally the equation for Torque is mathematically given by

[tex]T=i*Asin \theta[/tex]

Since A and B are on opposite direction

[tex]\theta=180[/tex]

Therefore

[tex]T=1.40*770*10^{-4}sin 180[/tex]

[tex]T=0[/tex]

you are pedaling forward on your bike. which of the following would decrease your acceleration?
A. A decrease in your mass
B. A increase in your applied force
C. An increase in your mass
D. An increase in your speed

Answers

Pedaling forward over the bike with the increase in your applied force would decrease your acceleration. Thus, option B is correct.

What is acceleration?

Acceleration is define as the rate at which velocity changes with time, in terms of both speed and direction. The equation for acceleration is:

a=F/m

where, a = acceleration,

F = force applied

m =  mass of the object

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object.

As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Therefore, if you are pedaling forward on your bike then a increase in your applied force would decrease your acceleration. Thus, option B is correct.

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Answer:

I just did it. A is right.

Explanation:

Help me frfr I don’t understand

Answers

The points are

(1,10)

(6,0)

[tex]\boxed{\sf slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}[/tex]

[tex]\\ \sf\longmapsto m=\dfrac{0-10}{6-1}[/tex]

[tex]\\ \sf\longmapsto m=\dfrac{-10}{5}[/tex]

[tex]\\ \sf\longmapsto m=-2[/tex]

When developing an experiment design, which could a scientist take to improve the quality of the results?

Answers

The options missing are;

A. Make only a few changes to the manipulated variable.

B. Identify any biases about the answer to the scientific question.

C. Include as many details as possible when writing the conclusion.

D. Share her ideas through peer review.

Answer:

B. Identify any biases about the answer to the scientific question.

Explanation:

Since the question is asking what can be done to improve the quality of the results, it means what can the scientist do to make sure that the result answers the question properly and has little or no biases.

Thus, looking at the options, the only one that comes close to actually improving on the quality of the results before finalizing is option B where the scientist is to identify any biases.

20. A semiconductor is a
crystalline solid that conducts current under any condition
metallic solid that conducts current under any condition
metallic solid that conducts current under certain conditions
crystalline solid that conducts current under certain conditions

Answers

Answer:

D. crystalline solid that conducts current under certain conditions

Explanation:

Semiconductors are crystalline solids that has the ability to conduct electrical currents but on certain conditions e.g heat. The conduction of semiconductors is less than that of conductors (metals) but more than insulators (nonmetals), hence, they are said to be intermediates of conductors and insulators in terms of electrical conductivity.

Examples of semiconductors are silicon, boron, carbon, germanium, arsenic etc.

A cricketer throws a ball sideways with an initial velocity of 30 m/s. She releases the ball from a height of 1.3m. Calculate how far the ball travels before hitting the ground.

Answers

Answer:

78.34

Explanation:

1.3/30=78.3m

absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

Answers

Answer:

[tex] \implies U = \dfrac{kq}{r} [/tex]

[tex]\implies U = \dfrac{9 \times {10}^{9} \times 1}{1} [/tex]

[tex]\implies U = 9 \times {10}^{9} \: J[/tex]

We have that absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

[tex]\rho=9x10 ^{10}J[/tex]

From the question we are told that

point charge of 1C at a distance of 1 m

Generally the equation for the Electrostatic potential energy  is mathematically given as

[tex]\rho=\frac{kq_1q_2}{r}[/tex]

Where k is a constant

[tex]k=9*10^9Nm^2/c^2[/tex]

Therefore

[tex]\rho=\frac{(9*10^9)1*10^(-6)*1*10^{-6}}{1}[/tex]

[tex]\rho=9x10 ^{10}J[/tex]

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Define measurement with examples.​

Answers

Explanation:

Measurement is defined as the act of measuring or the size of something. An example of measurement means the use of a ruler to determine the length of a piece of paper. An example of measurement is 15" by 25". ... The dimension, quantity, or capacity determined by measuring.

Measurement refers to the comparison of unknown physical quantity with a known quantity.

for eg. measurement of body while sewing clothes.......

A sound frequency 100Hz and wavelength 3.34m is travelling through air, calculate the Velocity of sound in air.

Answers

Answer:

334m/s

Explanation:

If you take the data you gave and insert it into the equation f=v/λ the frequency would come out to be 3.34m

334 m/s is  the Velocity of sound in air.

What is the velocity of a wave?

Wave velocity in common usage refers to speed, although, properly, velocity implies both speed and direction.

The velocity of a wave is equal to the product of its wavelength and frequency (number of vibrations per second) and is independent of its intensity.

Mathematically , v=fλ

According to the question,

Sound frequency (f)  = 100Hz

Wavelength (λ)= 3.34m

Computing the values in the formula,

v=fλ

v = 100Hz x 3.34m

v= 334m/s

Therefore,

Velocity of sound in air is 334 m/s.

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A ferrari has a mass of 1485kg.what is it's weight on Earth ​

Answers

F = m · g

m = 1485 kg

g = 10 N/kg

F = 1485 kg · 10 N/kg = 14 850 N = 14,85 kN

Answer: The weight on Earth is 14,85 kN.

8. A copper container of 84g mass contains 84g of water at 20°C. 46g of water at 200°C is mixed with water in the copper ontainer. What is the final temperature of the water? Specific heat capacity of water = 4200 J kg-1 °C-1, Specific heat capacity of copper = 400 J kg-1 °C-1 ​

Answers

Answer:

80 °C

Explanation:

The heat transfer parameters for the water and copper container are;

Mass of the copper container, m₁ = 84 g

Mass of the water in the container, m₂ = 84 g

Initial temperature of the water in the container, T₂ = 20°C

Mass of the hot water added, m₃ = 46 g

Initial temperature of the hot water, T₃ = 200°C

Specific heat capacity of water, c₂ = 4,200 J·kg⁻¹·°C⁻¹

Specific heat capacity of copper, c₁ = 400 J·kg⁻¹·C⁻¹

The formula for the specific heat, ΔQ = m·c·ΔT

The heat lost by the hot water = The heat gained by the container the and the cold water

The formula for the specific heat of the mixture is presented as follows;

m₃ × c₃ × (T₃ - T)  = m₁ × c₁ × (T - T₁) + m₂ × c₂ × (T - T₂)

Where T represents the final temperature of the water

Therefore, by plugging in the values, we get;

46 × 4200 × (200 - T) = 84 × 400 × (T - 20) + 84 × 4200 × (T - 20)

38640000 - 193200·T = 386400·T - 7728000

38640000 + 7728000 = 46368000 = 386400·T + 193200·T = 579,600·T

∴ T = 46368000/579,600 = 80

The final temperature of the water, T = 80°C

An object moving north with an initial velocity of 14 m/s accelerates 5 m/s2 for 20 seconds. What is the final velocity of the object?
39 m/s
90 m/s
114 m/s
414 m/s

Answers

Answer:

option C

Explanation:

Final velocity of the object is 114 m / s. Hence, final velocity of the object is 114 m / s.

Here is the answer ! Hope it helps.
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