Mathematics College

Which of the following best forms the figure shown?
2 angles that meet at an endpoint
2 lines that meet at an endpoint
2 line segments that meet at an
endpoint
2 rays that meet at an endpoint
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Which Of The Following Best Forms The Figure Shown?2 Angles That Meet At An Endpoint2 Lines That Meet

Answers

Answer 1

Answer: 2 rays that meet an endpoint

Related Questions

please help asap!!!!

Answers

Answer:

z = 25

Step-by-step explanation:

adjacent angles in a rhombus are supplementary

3z - 15 + 7z - 55 = 180

10z - 70 = 180

10z = 250

z = 25

Solve for x.
ASAP, please help me

Answers

Answer:

8

Step-by-step explanation:

180=90+40+6x+2

180=132+6x

48=6x

x=8

Answer:

x=4 i think havent done this in a long time

Step-by-step explanation:

Bryan has a number cube and
the spinner shown. What is
the probability of rolling a
prime number and spinning
yellow?
01/12
01/8

Answers

Answer:

1/8

Step-by-step explanation:

That's the same assignment I have and you just have to think it through mate.

Solve the triangle given that a=19 b=16, c=11.

Answers

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle ([tex]a[/tex], [tex]b[/tex], [tex]c[/tex]), but all angles are unknown ([tex]A[/tex], [tex]B[/tex], [tex]C[/tex]). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that [tex]a = 19[/tex], [tex]b = 16[/tex] and [tex]c = 11[/tex], then the missing angles are, respectively:

Angle A

[tex]a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A[/tex] (1)

[tex]A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)[/tex]

[tex]A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right][/tex]

[tex]A \approx 87.395^{\circ}[/tex]

Angle B

[tex]b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B[/tex] (2)

[tex]B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)[/tex]

[tex]B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right][/tex]

[tex]B\approx 57.271^{\circ}[/tex]

Angle C

[tex]C = 180^{\circ}-A-B[/tex]

[tex]C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}[/tex]

[tex]C = 35.334^{\circ}[/tex]

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

please help, thanks :)​

Answers

I think its A OR C I just think

Answer:

D :)

Step-by-step explanation:

Please solve the question below 4

Answers

Answer:

The answer is C

Step-by-step explanation:

The graph has a normal distribution, mean at 3.6, and a standard deviation of 0.6

Answer:

the Correct Answer Is c

Step-by-step explanation:

PLZ PLZ PLZ MARK AS BRAINLIEST LOL PLZ

In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=60°, and JH = 80 feet. Find the length of IJ to the nearest foot.

Answers

Answer:

46.2

Step-by-step explanation:

46.188= 46.2

I need help with math pls

Answers

The answer is 6

Explanation:

Help plz:)))I’ll mark u Brainliest

Answers

Answer:

Scale factor = 1.5

Step-by-step explanation:

Formula for the scale factor,

Scale factor = [tex]\frac{\text{Measure of one side of the Image}}{\text{Measure of one side of the preimage}}[/tex]

In this question, image is triangle Y and preimage is triangle X.

Scale factor of X to Y = [tex]\frac{15}{10}[/tex]

                                    = 1.5

Therefore, scale factor = 1.5 is the answer.

Solve the system by substitution.
-9x – 2y = -44
8x – 3 = y

Answers

Answer:

x = 2, y = 13

(2, 13)

Step-by-step explanation:

hope this helps!

A stockbroker knows from experience that the probability that a client owns stocks is 0.60. P(A) The probability that a client owns bonds is 0.50. P(B) The probability that the client owns bonds if he/she already owns stock is 0.55 What is the probability of a client owning stocks OR bonds

Answers

Answer:

the probability of a client owning stocks OR bonds is 0.825

Step-by-step explanation:

The computation of the probability of a client owning stocks OR bonds is given below:

= P(stocks) + P(bonds) - P(stocks and bonds)

= 0.60 + 0.50 - (0.55 × 0.50)

= 0.60 + 0.50 - 0.275

= 0.825

Hence, the probability of a client owning stocks OR bonds is 0.825

Need help #2. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.

Answers

Answer:

please refer to the above attachment

(D) is the right answer.
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