Which of the following equations has only one solution?

Answer:

6ab

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

that is the procedure above

Answer:

Its the first one

Answer:

[tex]12 \sqrt{6} [/tex]

Step-by-step explanation:

[tex]2 \sqrt{3} \times 3 \sqrt{8} \\ (2 \times 3) \sqrt{(3 \times 8)} \\ 6 \sqrt{24} \\( 6 \times 2) \sqrt{6 } \\ 12 \sqrt{6} [/tex]

Answer:

The sale price was 60% of the purchase price.

Step-by-step explanation:

Given that Blake bought a motorcycle for $ 550 last year and sold it for $ 330 this year, to determine what is his sale price as a percentage of his purchase price, the following calculation must be performed:

550 = 100

330 = X

330 x 100/550 = X

33000/550 = X

60 = X

Therefore, the sale price was 60% of the purchase price.

Answer:

pretty sure its the third one

Step-by-step explanation:

Answer:

AE = 18

Step-by-step explanation:

The triangles must be similar so we can use ratios

2x+4         12

--------  = ---------

x+8          10

Using cross products

(2x+4)10 = 12 (x+8)

20x +40 = 12x+96

Subtract 12x from each side

20x-12x +40 = 12x-12x +96

8x +40 = 96

Subtract 40 from each side

8x = 96-40

8x = 56

Divide by 8

x = 56/8

x = 7

AE = 2x+4 = 2(7) +4 = 14+4 = 18

the first one is a quadrilateral

Step-by-step explanation:

a quadrilateral have four side

Answer:

32year

Step-by-step explanation:

let Ahmed be x years then sheriff will be x+8

in 7years time

sheriff will be x+8+7=x+15

Then Ahmed will be x+7

sum of their ages will be 7\10×100=70years

x+15+x+7=70

collect like terms

2x+22=70

2x=70-22

2x/2=48/2

x=24years

Sheriff=24+8

32years

Answer:

12500

Step-by-step explanation:

2:3:5

^

smallest share

5 - 2 = 3

7500 / 3 = 2500

2500 × 5 = 12500

2500 × 2 = 5000

Check to see if correct:

12500 - 5000 = 7500

The answer will be 12500, hope this helps.

Answer:

3.39794000867

Step-by-step explanation:

first add log 125 and 625 and divide the answer by log 25 and minus the answer by 5

Answer:

The answer is 7.

Answer:

Step-by-step explanation:

True. They are both 30-60-90 triangles, and the side opposite the 60° angle is 5 in both. The side opposite the 30° angle is 5/√3 and the side opposite the 90° angle is 10/√3.

Answer:

429 & 431

Step-by-step explanation:

Consecutive numbers are numbers that come right after the other.

Let x = first room number

[tex]x+x+2=860\\2x+2=860\\2x=858\\x=429\\\\(429) + 2 = 431[/tex]

Therefore, the two room numbers are 429 and 431.

Answer: Choice D. 3 : r=3

Step-by-step explanation:

Easiest method and probably only method given the graph without knowing exact points besides an asymptote at x=-3.

Since we know there is an asymptote at x=-3, we just solve for the denominator and find r, when x=-3.

We are setting equation equal to 0, because when the denominator is 0, the graph has an asymptote at that point.

x+r=0

-3+r=0

r=3

Answer:

r=3

Step-by-step explanation:

Answer:

9.9

Step-by-step explanation:

We can use the Pythagorean theorem to solve.  The legs are both 7 and we are booking for the hypotenuse

a^2 +b^2 = c^2  where a and b are the legs and c is the hypotenuse

7^2+7^2 = c^2

49+49 = c^2

98 =c^2

Taking the square root of each side

sqrt(98) = sqrt(c^2)

9.899494937=c

9.9 = c

Answer:

x = 5

I hope it's helps you

Answer:

x=5 this might be helpful to you.

Answer:

[tex]\pm 9in^2[/tex]

Step-by-step explanation:

We are given that

Radius of end of a log, r= 9 in

Error, [tex]\Delta r=\pm 1/2[/tex]in

We have to find the error in computing the area of the end of the log by using differential.

Area of end of the log, A=[tex]pi r^2[/tex]

[tex]\frac{dA}{dr}=2\pi r[/tex]

[tex]\frac{dA}{dr}=2\pi (9)=18\pi in^2[/tex]

Now,

Approximate error in area

[tex]dA=\frac{dA}{dr}(\Delta r)[/tex]

Using the values

[tex]dA=18\pi (\pm 1/2)[/tex]

[tex]\Delta A\approx dA=\pm 9in^2[/tex]

Hence, the possible propagated error in computing the area of the end of the log[tex]=\pm 9in^2[/tex]

Answer:

[tex]A = (254.34 \pm 28.26) in^2[/tex]

Step-by-step explanation:

radius, r = 9 inches

error = 0.5 inch

The area of the end is

A = 3.14 x r x r = 3.14 x 9 x 9 = 254.34 in^2

[tex]A = \pi r^2\\\\\frac{dA}{dr}=2\pi r\\dA = 2 pi r dr \\\\dA = 2 \times 3.14\times 9\times 0.5 = 28.26[/tex]

So, the area is given by

[tex]A = (254.34 \pm 28.26) in^2[/tex]

Answer:

CD=20

Step-by-step explanation:

Use the pythagorean theorem: a²+b²=c²

(20√2)²-20²=a²

400(2)-400

800-400=400

√400=20

9514 1404 393

Answer:

  3 3/8 inches

Step-by-step explanation:

If you spend a little time looking at the marks on the ruler, you see that the smallest marks divide each inch into 8 parts. The ribbon comes to the 3rd small mark* after the 3-inch mark, so the length of the ribbon is 3 3/8 inches.

_____

* Technically, it is the second small mark, as the marks are small, medium, small. It marks the end of the third space, where each space is 1/8 inch.

Answer:

[tex]a = \frac{dv}{dt } = \frac{20 - 0}{2} = 10[/tex]

Let X be a random number selected from the interval. Then the probability density for the random variable X is

[tex]f_X(x)=\begin{cases}\dfrac1{10-6.35}=\dfrac1{3.65}\approx0.2740&\text{if }6.35\le x\le 10\\0&\text{otherwise}\end{cases}[/tex]

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute

P(|X - 8| < 0.25) + P(|X - 10| < 0.25)

… = P(7.75 < X < 8.25) + P(9.75 < X < 10.25)

… = P(7.75 < X < 8.25) + P(9.75 < X < 10)

(since P(X > 10) = 0)

… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)

… = 0.2055

[tex]v = k {r}^{3} [/tex]

[tex]562.54 = k \times {7.5}^{3} [/tex]

[tex]562.54 = 421.88k[/tex]

[tex]k = 562.54 \div 421.88[/tex]

[tex]k = 1.33[/tex]

since

[tex]v = k {r}^{3} [/tex]

[tex]v = 1.33 \times {9}^{3} [/tex]

[tex]v = 729 \times 1.33[/tex]

[tex]v = 969.57[/tex]

Answer:

The solutions are x = -4 and x = 4.

Step-by-step explanation:

Solving a quadratic equation:

We have to find x for which [tex]y = 0[/tex].

In this question:

[tex]y = 16 - x^2[/tex]

So

[tex]16 - x^2 = 0[/tex]

[tex]x^2 = 16[/tex]

[tex]x = \pm \sqrt{16}[/tex]

[tex]x = \pm 4[/tex]

The solutions are x = -4 and x = 4.

Answer:

im not sure but i think the answer is C) y = 2(x - 6)^2 + 5

The equation models the same quadratic relationship as function f(x) = 2x^2 - 12x + 11 will be 2(x-3)²-7.Option B is correct.

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that, the function is,

f(x) = 2x^2 - 12x + 11

We have to find the equation models the same quadratic relationship as the given function,

⇒2x²-12x+11

Take common 2 in the complete equation,

⇒2(x²-6x+11/2)

Add and subtract 9 from the complete equation,

⇒2(x²-6x+9-9+11/2)

Rearrange the equation as,

⇒2[(x-3)²-(7/2)]

⇒2(x-3)²-7

Thus, the equation models the same quadratic relationship as function f(x) = 2x^2 - 12x + 11 will be 2(x-3)²-7.Option B is correct.

Learn more about the equation here,

https://brainly.com/question/10413253

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