Which of the following is a correctly written algebraic equation?


a + 0.2x

5b - 5x + 2

a- 3x = 0

The scale ratio of a point A to another point B is the division of the length of B by the length of A. The best equation that models the situation is: [tex]10.5k= 3214[/tex]

The page dimension is:

[tex]Length = 12[/tex]

[tex]Width = 12[/tex]

The length and the width of Uche's book are equal; this means the pages of Uche's book have the shape of a square

The margin of 0.75 on either sided means the usable dimension is:

[tex]Length = 12 - 2 * 0.75 =10.5[/tex]

The dimension of India is:

[tex]Length = 3214[/tex]

[tex]Width =2933[/tex]

The longest side in India's dimension is:

[tex]Longest = 3214[/tex]

From Uche's book, the longest dimension is:

[tex]Longest = 10.5[/tex]

So, the scale equation is:

k * longest length of Uche's book = longest side of India

This gives:

[tex]k * 10.5 =3214[/tex]

[tex]10.5k =3214[/tex]

Read more about scale ratio at:

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C 89. What is the power of 5, so that 1 its value become ?

The power is 0. because if 0 is tge powwe of any variable or letters the value becomes 1.

Answer:

x=7

Step-by-step explanation:

6x+11=7x+4

Answer:

f(- 10) = 150

Step-by-step explanation:

f(- 10) with t = - 10 corresponds to t ≤ - 10 with f(t) = t² - 5t , then

f(- 10) = (- 10)² - 5(- 10) = 100 + 50 = 150

for t=-10

So

f(-10)

Answer: 20 ft³

Step-by-step explanation:

volume of triangular pyramid = [tex]\frac{1}{3} bh[/tex]

Therefore, the volume is:

[tex]\frac{1}{3} *10*6=\frac{1}{3}*60=\frac{60}{3}=20[/tex]

Step-by-step explanation:

Forty three thousand one hundred and six

Answer:

Forty three AND one hundred six thousandths

Step-by-step explanation:

If there is a comma ( , ) between the two numbers, you are correct.  

If there is a period / dot ( . ) between them, and you need to read the place values, you must read the numbers to the right of the . as decimals.  Those are the "th" numbers.  1 is in the tenths place, 0 in the hundredths place and the 6 in the thousandths place.  

If you are simply reading out the digit names, without assigning their value, you might say "forty three POINT one hundred six"  or "forty three DOT one hundred six" or "forty three DECIMAL one hundred six".

Answer:

Step-by-step explanation:

Assume the dish opens upwards. The cross-section through the vertex is a parabola. You know three points on the parabola: (0,0), (2,2), and (-2,2). Plug the points into y = ax² + bx + c to get a system of three equations where a=0.5, b=c=0.

Equation of parabola: y = 0.5x²

:::::

Vertex (0,0)

Focal length = 1/(4×0.5) = 0.5

Focus (0,0+0.5) = (0, 0.5)

Directrix y = 0-0.5 = -0.5

:::::

At endpoints of latus rectum, y = 0.5

x = ±√0.5 = ±√2/2

Focal width = 2×√2/2 = √2

:::::

Place antenna at focus, (9,2)

Answer:

25

Step-by-step explanation:

Answer:

74.80

Step-by-step explanation:

First find the discount

88 * 15%

88*.15

13.2

Subtract the discount from the original price

88-13.2

74.80

Answer:

9/4

Step-by-step explanation:

f(x) is continuous and differentiable on (0,9).

We want to find c using the following equation.

f'(c)=(f(9)-f(0))/(9-0)

This will require us to find f'(x) first.

f(x)=sqrt(x) is the same as   f(x)=(x)^(1/2)

Using power rule to differentiate this gives f'(x)=(1/2)(x)^(1/2-1) or simplified f'(x)=(1/2)x^(-1/2) or f'(x)=1/(2x^(1/2)).

So we want to solve:

(1/2)c^(-1/2)=(f(9)-f(0))/(9-0)

Simplify denominator on right:

(1/2)c^(-1/2)=(f(9)-f(0))/9

This will require us to find f(9) and f(0).

If f(x)=sqrt(x), then f(9)=sqrt(9)=3 and f(0)=sqrt(0)=0.

So we have the following equation so far:

(1/2)c^(-1/2)=(3-0)/9

Simplify numerator on right:

(1/2)c^(-1/2)=3/9

Multiply both sides by 2:

c^(-1/2)=6/9

Raise both sides to the -2 power:

c^(1)=(6/9)^(-2)

Note c^1=c:

c=(6/9)^(-2):

Note negative exponent means to find reciprocal of base to change exponent to opposite

c=(9/6)^2

Apply the second power:

c=81/36

Reduce by dividing top and bottom by 9:

c=9/4

This means the slope of the tangent to the curve f at x=9/4 is the same value as the slope of the secant line going through points (0,0) and (9,3).

Also 9/4 is between 0 and 9... According to the theorem we were suppose to get a value c between x=0 and x=9.

Confirmation:

Slope of the secant line is (3-0)/(9-0)=3/9=1/3.

Slope of the tangent line to curve f at x=9/4.

f'(x)=(1/2)x^(-1/2)

f'(9/4)=(1/2)(9/4)^(-1/2)

f'(9/4)=(1/2)(3/2)^(-1)

f'(9/4)=(1/2)(2/3)

f'(9/4)=1/3

They are indeed equal values (talking about the 1/3 from the secant and the tangent.)

9514 1404 393

Answer:

  C. none of these

Step-by-step explanation:

The given information tells us ΔACD is isosceles, but gives no information about any lines that might conceivably be parallel.

Answer:

45 is the Answer

Step-by-step explanation:

Hope its helpful

ANSWER

8-2........3/4 but you have you ADD some people dont know that 8-2= 6

and so 6/1 + 3/4 is 24/4

Answer:

answer is

In empty set, n(A) = { }.

The following expressions are equivalent to 36x + 24y is 6(6x+4y).

6x(6+4y)

6(6x+4y)

12(3x+2y)

4(9x+6y)

We have,

The expression consists of numbers and arithmetic operators. It does not contain equality or inequality symbols. The expression consists of unknown variables

36x + 24y

=6(6x)+6(4y)

=6(6x+4y)

Therefore, The following expressions are equivalent to 36x + 24y is 6(6x+4y).

To learn more about the expression visit:

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Answer:

Answer : 1/8.

Step-by-step explanation:

Hey there!

Please see the attached picture for your answer.

Hope it helps!

Step-by-step explanation:

I am not sure but is this question like this

if it's not i am sorry

Answer:

he has 48 dollars left to spend on clothes

Answer:

1/4

Step-by-step explanation:

x^2 - x

Take the coefficient of x

-1

Divide by 2

-1/2

Square it

(-1/2)^2 = 1/4

Add it

x^2 -x +1/4

Answer:

It's option D. y = 1/2x - 4

Step-by-step explanation:

I used Desmos to find the answer, hope the graph helps!

Solution :

Let [tex]p_1[/tex] and [tex]p_2[/tex]  represents the proportions of the seeds which germinate among the seeds planted in the soil containing [tex]3\%[/tex] and [tex]5\%[/tex] mushroom compost by weight respectively.

To test the null hypothesis [tex]H_0: p_1=p_2[/tex] against the alternate hypothesis  [tex]H_1:p_1 \neq p_2[/tex] .

Let [tex]\hat p_1, \hat p_2[/tex] denotes the respective sample proportions and the [tex]n_1, n_2[/tex] represents the sample size respectively.

[tex]$\hat p_1 = \frac{74}{155} = 0.477419[/tex]

[tex]n_1=155[/tex]

[tex]$p_2=\frac{86}{155}=0.554839[/tex]

[tex]n_2=155[/tex]

The test statistic can be written as :

[tex]$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}[/tex]

which under [tex]H_0[/tex]  follows the standard normal distribution.

We reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance, if the P-value [tex]<0.05[/tex] or if [tex]|z_{obs}|>Z_{0.025}[/tex]

Now, the value of the test statistics = -1.368928

The critical value = [tex]\pm 1.959964[/tex]

P-value = [tex]$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$[/tex]

                                     [tex]$=2 \times 0.085667$[/tex]

                                     = 0.171335

Since the p-value > 0.05 and [tex]$|z_{obs}| \ngtr z_{critical} = 1.959964$[/tex], so we fail to reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the [tex]\text{proportion}[/tex] of the seeds that [tex]\text{germinate differs}[/tex] with the percent of the [tex]\text{mushroom compost}[/tex] in the soil.

Answer:

third answer "a"

Step-by-step explanation:

Answer:

Option D, 12

Step-by-step explanation:

4x-8=80/2

or, 4x-8=40

or, 4x=48

or, x=12

Answer:

Given:-  

m∠DEF= (4x-8) °

m DE= 80°

Using a property :- m ∠DEF= 1/2 (m DE)

[tex](4x-8)[/tex] ° [tex]= 1/2 (80)[/tex]

[tex](4x-8)[/tex]° [tex]=(40)[/tex] °

[tex]4x-8=40[/tex]

Add 8 to both sides:-

[tex]4x=48[/tex]

Divide both sides by 4:-

[tex]\frac{4x}{4}=\frac{48}{4}[/tex]

[tex]x=12[/tex]

OAmalOHopeO

9514 1404 393

Answer:

  see below

Step-by-step explanation:

  [tex]\text{A. point: }X\\\\\text{B. ray through Y: }\overrightarrow{XY}\\\\\text{C. line through Z: }\overleftrightarrow{XZ}\\\\\text{D. plane: plane } XYZ[/tex]

__

Additional comment

When you don't have the benefit of typesetting, you can refer to the geometry by name: ray XY, line XZ,

Answer:

no

Step-by-step explanation:

-7+x^2-3x      =       9+x-10

-7+(-2)^2-3*(-2)                   9+(-2)-10

-7+4+6                                9-12

3                   >                      -3

if we substitute -2 to x, answer is not equal

Answer:

x= -2

-7 +x^2 - 3x = 9 +x - 10

-7 + (-2)^2 -3×(-2) = 9 + (-2) -10

-7 +4 +6 = 9 - 2 - 10

-7+10=9-12

3 =-3

Don't blame me if this is incorrect:)

Answer:

Option A i the right option.

First blank is 110-[tex]10\sqrt{61}[/tex] or 10(11-[tex]\sqrt{61}[/tex])

Second blank is 31.898

Let me know if anything didn't make sense.  

Step-by-step explanation:

So a diagonal through a rectangle makes two triangles.  The question wants to know how much walking is saved walking down the diagonal  vs walking along two sides that make the diagonal.  in this case the two non diagonal sides walked are 60 paces and 50 paces.

A diagonal through a rectangle specifically makes a right triangle, so to find the diagonal we can use the pythagorean theorem.  

c^2 = 60^2 + 50^2

c = [tex]\sqrt{60^2 + 50^2}[/tex]

c = [tex]\sqrt{6100} = 10\sqrt{61}[/tex]

if you don't get how to simplify a radical like that let me know.

Anyway, looking at the answers you can see right away the second option says no approximation is necessary.  Well, you need to approximate square root of 61, so we can say the second answer is not right.  So now we need to know what to fill in for option 1.

it wants the distance saved, well we know the distance of the diagonal is [tex]10\sqrt{61}[/tex]  Hopefully you can see the disctance walking the two other sides is just adding them up so 50+60=110.

Now, to find the difference, that is subtraction.  So subtract the smaller number from the larger number.  You do need to remember with a right triangle, the sum of the to non diagonal (hypotenuse) sides are always longer than said hypotenuse.  so that's 110-[tex]10\sqrt{61}[/tex].  That is the exact form.  Or you could use 10(11-[tex]\sqrt{61}[/tex])  They are the same.

Then just plug that into a calculator for a decimal approximation.

Answer:

C

Domain (-x,x): (-inf, inf)

Range (-y,y): [1, 0)

Step-by-step explanation:

Domain is -x to x which is the lowest x value marked to the parabola to the highest. Since their are arrows indicating that the parabola continues both ways, the domain is infinite both ways. The range has the endpoint of one and the continuation of 0 (you can tell by the brackets [], (), [), or (]; [ <- endpoint; ( or ) <- continuation), the range is [1, 0).  :)

Answer:

what's is the question anyway

Answer:

1/4

Step-by-step explanation:

Probability of red * number of candies

2/5 * 25 = 10

There are 10 red candies

25-10 = 15

There are 15 other candies

Remove 5 red

10-5 = 5 red candies

Now we have 5 red candies and 15 other candies= 20 candies

P(red) = red/total = 5/20 = 1/4