Which of the following is NOT considered a test to evaluate whether an engineer is in responsible charge of a project?

a. The project size as determined by its dollar value.
b. The engineer's technical knowledge of the work performed.
c. The geographical and organizational span of control exercised.
d. The engineer's ability to answer questions concerning the project.

Answers

Answer 1

The answer is "Option a", and more explanation can be defined as follows:

The method compares a system or parts with needs and demands through testing. The results are assessed to measure design development, performance, endurance, etc.The phrase "responsible charge" as used in the Professional Engineers Law directly refers to how much control a professional engineer is obliged to exercise independent direction and control over-engineering and creative work, as well as to the making the correct decision that can only be taken by a professional engineer.

The description of the correct choice:

The technique of the engineer's work was done.The controlling span was carried out and in geography & organization.The ability of an engineer to address technical questions.

Therefore, except for "Option a", all were right because tests for responsible charges consist of technical knowledge, the scope of control, and capability.

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0/5 pts
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(a) The total number of people in the population is 100 x −1. (b) Let's suppose we want to find y, such that \frac{y}{100} is an unbiased estimate for \frac{\sum_{i=1}^{100}x_i}{100}. Then \frac{y}{100} = \frac{\sum_{i=1}^{100}x_i}{100}. Let's now plug in 100 x −1 for \sum_{i=1}^{100}x_i. This means y = \frac{99 x −1}{100}. (c) Recall that the average of a vector is 0 x + 1. Then the average age of the population is 0(100 − 1) + 1 = 50. (d) An unbiased estimate for the average age of the population exists, because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}.

50 People are 65 and over

The number of people who are 65 and older is 50 x − 1 = 45.

I think this may be either (b) or (c). An unbiased estimate for the average age of the population exists because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}. An unbiased estimate is \frac{99 x −1}{100}.

(c) Recall that the average of a vector is 0 x + 1. Then the average age of the population is 50. (b) Let's suppose we want to find y, such that \frac{y}{100} is an unbiased estimate for \frac{\sum_{i=1}^{100}x_i}{100}. Then \frac{y}{100} = \frac{\sum_{i=1}^{100}x_i}{100}. Let's now plug in 100 x −1 for \sum_{i=1}^{100}x_i. This means y = \frac{99 x −1}{100}. (d) No, because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}.

45 People are 65 and over

The number of people who are 65 and older is 45. There is no unbiased estimate for the average age of a population.

(b) Let's suppose we want to find y, such that \frac{y}{100} is an unbiased estimate for \frac{\sum_{i=1}^{100}x_i}{100}. Then \frac{y}{100} = \frac{\sum_{i=1}^{100}x_i}{100}. Let's now plug in 100 x −1 for \sum_{i=1}^{100}x_i. This means y = \frac{99 x − 1}{100}. (c) Recall that the average of a vector is 0 x + 1. Then the average age of the population is \frac{99 x −1}{100}. (d) An unbiased estimate for the average age of a population exists, because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}.

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