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A greater force is required to move an object with a larger mass than one with a smaller
mass.
Answer:
Explanation:
what do u need to know
*
14. An AREA which drains into a common river system.
watershed
tributary
drainage divide
riparian zone
If 4.04g of h2 gas react with oxygen gas to create 36.36g of water, how many grams of oxygen reacted?
Answer:
gO₂ = 32.32 g
Explanation:
In this case, let's write the general equation:
2H₂ + O₂ -------> 2H₂O
In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.
According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:
gO₂ = 36.36 - 4.04
gO₂ = 32.32 gHope this helps
Sample A has a mass of 40g and a volume of 10cm^3. Sample B has a volume of 15cm^3 and a mass of 45g. Which sample has a greater density? Show your work.
The Answer Is Sample A
Density -
[tex]density = \frac{mass}{volume} [/tex]
Input The Formula For Both Equations To Find Density.
Sample A -
[tex]d = \frac{40}{10} [/tex]
[tex]d = 4[/tex]
Sample B -
[tex]d = \frac{45}{15} [/tex]
[tex]d = 3[/tex]
What is a precipitation
reaction?
Answer:
A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con 1 g de H2O.
Answer:
0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.
Explanation:
¡Hola!
En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:
[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]
Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:
[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]
De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.
¡Saludos!
Si la masa de una muestra de un compuesto Y es de 196 gramos y contiene 2 mol, la masa molar de Y es
Answer:
98 g/mol
Explanation:
La masa molar de un compuesto es la cantidad de materia (medida como masa) que hay en 1 mol de dicho compuesto. Por lo tanto, puede calcularse como sigue:
masa molar = masa/número moles
Tenemos los siguientes datos del compuesto Y:
masa Y = 196 g
número de moles de Y = 2 mol
Entonces, podemos calcular la masa molar de Y de la siguiente manera:
masa molar Y = (masa Y)/(número de moles de Y) = 196 g/2 mol = 98 g/mol
i hate chemistry but someone help please, no links or you’ll be reported
Answer:
A, D, E
Explanation:
Which two moon phases can occur while the
relative positions of the sun, Earth, and moon
form a straight line?
Answer:
its the lunar and solar eclipse
Explanation:
the solar eclipse happens when the moon is in between the sun and earth