Answer:
Explanation:
A bullet being shot out of a gun tends to leave tiny amounts of the bullet behind due to friction between the bullet and the gun barrel.
A roller skater pushing requires the conversion of food chemical energy to muscle contraction energy. This conversion increases the body temperature and sweat is excreted to counteract the heat increase. The evaporation of the sweat causes a slight decrease in body mass.
A jet plane taking off consumes some of the fuel carried onboard to provide thrust. The products of combustion become part of the exhaust stream leaving the airplane rearward providing forward thrust.
A charged particle of mass 0.0040 kg is subjected to a magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius at a speed of what is the magnitude of the charge on the particle
Complete Question
A charged particle of mass 0.0040 kg is subjected to a 40-T magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius 0.10 m at a speed of 20m/s, what is the magnitude of the charge on the particle?
Answer:
[tex]q=0.020C[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=0.004kg[/tex]
Magnetic field [tex]B=40-T[/tex]
Radius [tex]r=0.10m[/tex]
Speed [tex]v= 20m/s[/tex]
Generally the equation for Radius of a circular path is mathematically given by
[tex]r=\frac{p}{qB}[/tex]
Where
[tex]p=mv[/tex]
Therefore
[tex]q=\frac{mv}{rB}[/tex]
[tex]q=\frac{0.004kg*20m/s}{0.1*40}[/tex]
[tex]q=0.020C[/tex]
This percentage of all water on the planet is salt water . 97 % 95% 93% 91%
hurry please !
Answer:
none of those are right, its technically 96.5%. so i would say 97% is your best bet because thats closest and it just rounds up :)
Explanation:
A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy … (use g = 10 m/s 2)
A) at the moment of impact.
B) 2 seconds after the stone is released.
C) after the stone has fallen 40 m.
D) when the stone is moving at 20 m/s.
At the moment of impact both Kinetic Energy and Potential Energy should be 0, right? So it can't be A), right? Or is this wrong? Is it indeed A)? Please show work and explain it well.
Answer: c. 40m
Explanation:
See picture
A cylindrical water tank has a height of 20cm and a radius of 14cm. If it is filled to 2/5 of its capacity, calculate.
I. Quantity of water in the tank
II. Quantity of water left to fill the tank to its capacity.
Answer:
4.926 L Y 7.389 L
Explanation:
first you calculate the tank volume
V = π[tex](14 cm)^{2}[/tex](10 cm = [tex]12315 cm^{3}[/tex]
then you convert to liters
[tex]12315 cm^{3}[/tex] = 12.315 l
then you calculate the liters of water
2/5(12.35 l) = 4.926 l
finally we calculate the amount without water
12.315 l - 4.926 l = 7.389 l
HERE IS MORE INFORMATION ON THE SUBJECT. THEY REMOVED THE
ENGLISH SITE BUT YOU CAN USE TRANSLATOR
LINK: https://gscourses.thinkific.com/courses/fisicai
1L of a solution of oxalic acid [(). ] contains 2.52g of acid.
Calculate the molarity of the solution.
Answer:
0.028 M.
Explanation:
NOTE: This question is a chemistry question. However, the answer to the question can be obtained as shown below:
We'll begin by calculating the number of mole in 2.52 g of oxalic acid, C₂H₂O₄. This can be obtained as follow:
Mass of C₂H₂O₄ = 2.52 g
Molar mass of C₂H₂O₄ = (2×12) + (2×1) + (4×16)
= 24 + 2 + 64
= 90 g/mol
Mole of C₂H₂O₄ =?
Mole = mass / molar mass
Mole of C₂H₂O₄ = 2.52 / 90
Mole of C₂H₂O₄ = 0.028 mole
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of C₂H₂O₄ = 0.028 mole
Volume = 1 L
Molarity =?
Molarity = mole / Volume
Molarity = 0.028 / 1
Molarity = 0.028 M
Therefore, the molarity of the solution is 0.028 M.
A car starting at rest accelerates at 3m/seconds square How far has the car travelled after 4s?
Answer:
24 meters
Explanation:
Find the final velocity. 12m/s
d=[final-initial]/2×time
D=(6m/s)×4=24 m/s
A denser object will usually have a ____ index of
refraction.
Answer:
A denser object will usually have a high index of
refraction.
A denser object will usually have a high index of refraction.
What is index of refraction?The refractive index is the ratio of the speed of light in vacuum and speed of light in any medium.
n = c/v
The density is greater for the denser medium (water, oil, mercury, etc) then the rarer medium (any gas or air).
When a light ray travels through denser medium, its velocity is reduced and the refracted ray bends towards normal.
As, the index of refraction is inversely proportional to the velocity of light in the medium, index of refraction will be high for denser object.
Thus, denser object have high index of refraction.
Learn more about index of refraction.
https://brainly.com/question/23750645
#SPJ2
write a note on unity of ant
Answer: When a pathogen enters their colony, ants change their behavior to avoid the outbreak of disease. In this way, they protect the queen, brood and young workers from becoming ill. These results, from a study carried out in collaboration between the groups of Sylvia Cremer at the Institute of Science and Technology Austria (IST Austria) and of Laurent Keller at the University of Lausanne, are published today in the journal Science.
Explanation: search for it.
Which best describes what occurs when an object takes in a wave as the wave hits it?
A. transmission
B. absorption
C. reflection
D. refraction
Answer:
B
Explanation:
ABSORPTION
What is the rate of power flowing through phone if a 2.50V battery produces 1.50A of current?
Answer:
3.75 watts
Explanation:
power = volts * current
2.5 * 1.5 =
3.75
On a cello, the string with the largest linear density (1.44 x 10-2 kg/m) is the C string. This string produces a fundamental frequency of 93.0 Hz and has a length of 0.834 m between the two fixed ends. Find the tension in the string.
Answer:
[tex]T=346.5N[/tex]
Explanation:
From the question we are told that:
Density [tex]\rho= (1.44 * 10^{-2} kg/m)[/tex]
Frequency[tex]F=93.0Hz[/tex]
Length[tex]l=0.834m[/tex]
Generally the equation for Frequency is mathematically given by
[tex]F=\frac{1}{2 l}sqrt{\frac{T}{\rho}}[/tex]
Therefore
[tex]T=\rho(2 lF)^2[/tex]
[tex]T= (1.44 * 10^{-2}*(2*0.834)(93.0))^2[/tex]
[tex]T=346.5N[/tex]
In a physics lab, light with a wavelength of 560 nm travels in air from a laser to a photocell in a time of 17.2 ns . When a slab of glass with a thickness of 0.810 m is placed in the light beam, with the beam incident along the normal to the parallel faces of the slab, it takes the light a time of 20.8 ns to travel from the laser to the photocell.
Required:
What is the wavelength of the light in the glass?
Answer:
Distance traveled = 3 * 10E8 * 17.2 * 10E-9 = 5.16 m
.81 / 3 * 10E8 = 2.7 * 10E-9 normal time thru glass
(20.8 - 17.2) * E10-9 = 3.6 * 10E-9 additional time due to glass
c tg = c n ta where tg and ta are the times spent in glass and air
(Note you can also write Va = n Vg or D / ta = n D / tg)
n = tg / ta = 3.6 / 2.7 = 1.33 the index of refraction of the glass
Wavelength (air) = Wavelength (glass) * n
Wavelenght = 560 nm / 1.33 = 421 nm
Which two factors does the power of a machine depend on? А. work and distance B.. force and distance C. work and time D. time and distance?
[tex]Hello[/tex] [tex]There![/tex]
[tex]AnimeVines[/tex] [tex]is[/tex] [tex]here![/tex]
The answer is...
C. Work and time.
[tex]HopeThisHelps!![/tex]
[tex]AnimeVines[/tex]
Consider two oppositely charged, parallel metal plates. The plates are square with sides L and carry charges Q and -Q. What is the magnitude of the electric field in the region between the plates
Answer:
E = [tex]\frac{Q}{L^2 \epsilon_o}[/tex]
Explanation:
For this exercise we use that the electric field is a vector, so the resulting field is
E_total = E₁ + E₂ (1)
since the field has the same direction in the space between the planes
Let's use Gauss's law for the electric field of each plate
Let's use a Gaussian surface that is a cylinder with the base parallel to the plate, therefore the normal to the surface and the field lines are parallel and the angle is zero so cos 0 = 1
Ф = ∫ .dA = [tex]q_{int}[/tex] /ε₀
if we assume that the charge is uniformly distributed on the plate we can define a charge density
σ = q_{int} A
as the field exists on both sides of the plate on the inside
E A = A σ / 2ε₀
E = σ / 2ε₀
we substitute in equation 1
E = σ /ε₀
for the complete plate
σ = Q / A = Q / L²
we substitute
E = [tex]\frac{Q}{L^2 \epsilon_o}[/tex]
Hellohellp fastttttttttt
Answer:
Explanation:
[tex]w_f^2=w_o^2-2\alpha\theta\\\\0=w_o^2-2\alpha\theta\\\\\theta={w_o^2\over{2\alpha}}[/tex]
[tex]w_o=2\pif=2\pi*8Hz=16\pi{rad\over{s}}\\\\\alpha=2.2{rad\over{s^2}}\\\\\theta={(16\pi{rad\over{s}})^2\over{2*2.2{rad\over{s^2}}}}=574.23rad[/tex]
[tex]revolutions={\theta\over{2\pi}}={574.23\over{2\pi}}=91.39[/tex]
what is threshold of hearing?
-> The minimum sound pressure level at which a sound of a given frequency can be perceived by the human ear is known as threshold of hearing.
Explanation:
The absolute threshold of hearing is the minimum sound level of a pure tone that an average human ear with normal hearing can hear with no other sound present. The absolute threshold relates to the sound that can just be heard by the organism.
A source of emf is connected by wires to a resistor and electrons flow in the circuit the wire diameter is teh same throughout teh circuit compared to the drift speed of the electrons before entering the source of emf, the drift speed ot eh electrons afte rleaving the source of emf is: ___________
a. faster.
b. slower.
c. the same.
d. either A or B depending on circumstances.
e. any of A, B , or C depending on circumstances.
which of the following is correct for solids? a. y=2/3 alpha b.y= 2/3 bita c.y = 3/2 bita d.y=3/2 alpha
option a ...
please mark hcfhvx
Compare and contrast how sound waves behave when they
encounter solid hard surfaces
encounter soft surfaces
pass through an opening
encounter a barrier
Answer:
They sound tinkling in solid hard like metal.
They can vibrate soft surface
I could just Ans this
Wind instruments like trumpets and saxophones work on the same principle as the "tube closed on one end" that we examined in our last experiment. What effect would it have on the pitch of a saxophone if you take it from inside your house (at 76 degrees F) to the outside on a cold day when the outside temperature is 45 degrees F ?
Answer:
f = v / 4L
the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.
Explanation:
In wind instruments the wave speed must meet
v = λ f
λ = v / f
from v is the speed of sound that depends on the temperature
v = v₀ [tex]\sqrt{1+ \frac{T [C]}{273} }[/tex]
where I saw the speed of sound at 0ºC v₀ = 331 m/s the temperature is in degrees centigrade, we can take the degrees Fahrenheit to centigrade with the relation
(F -32) 5/9 = C
76ºF = 24.4ºC
45ºF = 7.2ºC
With this relationship we can see that the speed of sound is significantly reduced when leaving the house to the outside
at T₁ = 24ºC v₁ = 342.9 m / s
at T₂ = 7ºC v₂ = 339.7 m / s
To satisfy this speed the wavelength of the sound must be reduced, so the resonant frequencies change
λ / 4 = L
λ= 4L
v / f = 4L
f = v / 4L
Therefore, the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.
After a successful experiment involving the Sun, an astrophysicist proposes a theory for how stars change during the course of their existence. Is the astrophysicist correct in doing this
Answer:
Yes
Explanation:
A scientific theory is an explanation of a natural phenomenon based on available facts. If an Astrophysicist (a scientist who studies the universe and its celestial constituents) performs several successful experiments about a natural body like the sun and tests the results of his experiment using the principles of maths and physics and they come out as true, then he can propose a scientific theory based on his findings.
Unlike a scientific law that simply states a fact, a scientific theory provides evidence and explanation to support the facts.
Two wires are made of the same material and have the same length but different radii. They are joined end-to- end and a potential difference is maintained across the combination. Of the following quantities that is same for both wires is
A. Potential difference
B. Electric current
C. Current density
D. Electric field
Answer:
Current
I think The choose (B)
B. Electric current
I NEED HELP ASAP!!!
which of the following causes the magnetic force between the magnet and the scrap metal?
Answer:
Alternating current at which when entered into the loop cause it to magnetize
Which of the following careers would physicists be least qualified to perform,
based on their training?
A. Artist
B. Mechanical engineer
C. Laser designer
D. Power plant engineer
4. Describe (in words) the relationship between the distance and time2 as the duster accelerated down the slope, 4.1 with its rough surface in contact with the track
Direct relation is present between distance and time which means one has direct impact on the value of other.
There is direct relationship between distance and time. Direct relation means if one increases the other automatically increases while on the other hand, if one decreases the other will also decreases. If there is a large amount of distance so more time is required to pass it while on the other hand, if there is less distance so less time is required to complete it so we can conclude that there is direct relationship between distance and time.
https://brainly.com/question/24323600
Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB 23.4 km/hr. at t = 0.0. Knowing that automobile A has a constant acceleration of 0.8 m/s? and automobile B has a constant deceleration of 0.4 m/s2. Automobile A will overtake B after traveling a distance SA: A B. Side view
Answer:
x = 240 m
Explanation:
This is a kinematics exercise
Let's fix our frame of reference on car A
x = x₀ₐ+ v₀ₐ t + ½ aₐ t²
the initial position of car a is zero
x = 0 + v₀ₐ t + ½ 0.8 t²
for car B
x = x_{ob} + v_{ob} t - ½ a_b t²
car B's starting position is 30 m
x = 30 + v_{ob} t - ½ 0.4 t²
at the point where they meet, the position of the two vehicles is the same
0 + v₀ₐ t + ½ 0.8 t² = 30 + v_{ob} t - ½ 0.4 t²
let's reduce the speeds to the SI system
v₀ₐ = 14.4 km / h (1000 m / 1 km) (1h / 3600s) = 4 m / s
v_{ob} = 23.4 km / h = 6.5 m / s
4 t + 0.4 t² = 30 + 6.5 t - 0.2 t²
0.2 t² - 2.5 t - 30 = 0
t² - 12.5 t - 150 = 0
we solve the quadratic equation
t = [tex]\frac{12.5 \pm \sqrt{12.5^2 + 4 \ 150} }{2}[/tex]
t = [tex]\frac{12.5 \ \pm 27.5}{2}[/tex]
t₁ = 20 s
t₂ = -7.5 s
time must be a positive quantity so the correct result is t = 20 s
let's look for the distance
x = 4 t + ½ 0.8 t²
x = 4 20 + ½ 0.8 20²
x = 240 m
Can a conductor be given limitless charge
Answer:
No
Explanation:
You could try to give it enough to fill all valence electrons in all of the atoms in the conductor, but practically this could not be achieved.
The following are ways to properly manage your stress except
Answer:
you should provide the options for us to answer?
A 1.8-m-tall diver is standing completely submerged on the bottom of a swimming pool, in 3.0 m of water. You are sitting on the end of the diving board, almost directly over her.
Required:
How tall does the diver appear to be?
Answer:
[tex]H=1.35m[/tex]
Explanation:
From the question we are told that:
Height [tex]h=1.8m[/tex]
Depth of Water [tex]d=3.0m[/tex]
Where
Refraction index of water [tex]n = 4 / 3[/tex]
Generally the equation for Apparent height of the diver is mathematically given by
[tex]H=h\frac{h}{n}[/tex]
[tex]H=\frac{1.8}{\frac{4}{3}}[/tex]
[tex]H=1.35m[/tex]
1. Consider a 1000 kg car rounding a curve on a flat road of radius 50 m at a speed of
50 km/h (14 m/s).
a. Will the car make the turn if the pavement is dry and the coefficient of static
friction is 0.60?
Answer:
The car will make the turn perfectly
Explanation:
Given that the centripetal force= mv^2/r
M= mass of the car
v = speed of the car
r= radius
Hence;
F = 1000 × (14)^2/50
F= 3920 N
The frictional force = μmg
μ = coefficient of static friction
m= mass
g = acceleration due to gravity
Frictional force= 0.6 × 1000× 10
Frictional force = 6000 N
The car will not skid off the curve because the frictional force is greater than the centripetal force.
