Which of these is an example of technology?
an idea for a story
the first wheel ever built
an engineer

Answer:

8 classes

Step-by-step explanation:

Given

[tex]Least = 2403[/tex]

[tex]Highest = 11998[/tex]

[tex]n = 225[/tex]

Required

The number of class

To calculate the number of class, the following must be true

[tex]2^k > n[/tex]

Where k is the number of classes

So, we have:

[tex]2^k > 225[/tex]

Take logarithm of both sides

[tex]\log(2^k) > \log(225)[/tex]

Apply law of logarithm

[tex]k\log(2) > \log(225)[/tex]

Divide both sides by log(2)

[tex]k > \frac{\log(225)}{\log(2)}[/tex]

[tex]k > 7.8[/tex]

Round up to get the least number of classes

[tex]k = 8[/tex]

Answer:

32

Step-by-step explanation:

18 : 6 = 3

therefore, x : 3 has to equal 3.

X : 3 = 3

X = 3 × 3

X = 9

To verify:

18 : 6 = 9 : 3

3 = 3

It's true that X = 9, so now just replace the X with 9 in the next equation

5 + 3(9) = 32

Answer:

32

Step-by-step explanation:

18 :  6 = x : 3

Product of means  =  Product of extremes

6 * x = 3*18

     x = [tex]\frac{3*18}{6}[/tex]

     x = 3*3

x = 9

Now plugin x = 9 in the expression

5 + 3x = 5 + 3*9

          = 5 + 27

          = 32

Answer:

(x+5)(x-3) / (x+5)(x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator.  It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x.  In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

Answer:

9614

Step-by-step explanation:

Generic number with 4 digit

1000t + 100h + 10y + x

x = 3 + y

x = m - 5

h = 6

m = 9

if we substitute the value we have:

x = 9 - 5 = 4

4 = 3 + y

y = 1

Final number

9614

Answer:

hope it will be helpful to you.....

Answer:

K+T=20

$9K + $6T = $168

K is the Kentucky blue grass in pounds

T is the Tall fescue in pounds

Step-by-step explanation:

You can start with the first equation. We don't know the exact amounts of each but we know that there was a total of 20 pounds, and there were 2 types of grass seeds, so we can get that the amount of pounds of Kentucky blue grass(K) and the pounds of Tal Fescue(T) has a sum of 20.

K + T = 20

For the second equation we know that there is a sum of $168 so we'll start with that. Then, we know he paid $9 per pound of K so $9* the value of K is the amount paid for Kentucky blue grass total. This can be represented as 9K. We do the same for T, 6T. Since the sum of the cost of $9T and $6K must be $168 we can write this as:

$9K + $6T = $168

Answer:

11

Step-by-step explanation:

y-1=10

Any figure that crosses equal sign, the operational sign changes.

y=10+1

y= 11

Answer:

1 hour

Step-by-step explanation:

J = 50 mph by 2 hours

S = 50 mph by 1 hour

2-1 = 1

Answer:

the total number of participants required is 90

Step-by-step explanation:

Given the data in the question;

Factor A has three levels

Factor B has three levels

sample size n; ten participants

we have two Way ANOVA involving Factor A and Factor B.

Now,

{ Total # Participants Required } = { #Levels factor A } × { #Levels factor B } × { Sample size of each level }

we substitute

{ Total # Participants Required } = 3 × 3 × 10

{ Total # Participants Required } = 9 × 10

{ Total # Participants Required } = 90

Therefore, the total number of participants required is 90

The question is incomplete. The complete question is :

Determine whether the given functions are linearly dependent or linearly independent on the specified interval. Justify your decision.

[tex]$\{ x^5, x^5-1,3 \} \text{ on } (- \infty, \infty)$[/tex]

Solution :

Given :

Function : [tex]$\{ x^5, x^5-1,3 \} \text{ on } (- \infty, \infty)$[/tex]

We have to determine whether the given function is linear dependent or linearly independent for the interval [tex]$(-\infty, \infty)$[/tex].

The given function are linearly dependent because for the constants, [tex]c_1[/tex] and [tex]c_2[/tex], the equation is :

[tex]$c_1x^5 + c_23 = x^5-1$[/tex]  has the solution [tex]$c_1 = 1$[/tex] and [tex]$c_2 = -\frac{1}{3}$[/tex]

Therefore,

[tex]$1x^5 + \left(-\frac{1}{3}\right)3 = x^5-1$[/tex]

Answer:

[tex]\sqrt{49}[/tex]

Step-by-step explanation:

Define a rational number by a number able to expressed a fraction where the denominator is not 0 or 1.

Non-terminating (never-ending) decimals cannot be expressed as a fraction and therefore are irrational. However, recall that [tex]\sqrt{49}=7[/tex], which can be expressed as a fraction (e.g. [tex]\frac{14}{2}[/tex], etc). Thus, the answer is [tex]\boxed{\sqrt{49}}[/tex].

Answer:

The interval is [98,132]

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normal with mean 115 and standard deviation 25.

This means that [tex]\mu = 115, \sigma = 25[/tex]

Determine the interval of values that is centered at the mean and for which 50% of the students have IQ's in that interval.

Between the 50 - (50/2) = 25th percentile and the 50 + (50/2) = 75th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.675 = \frac{X - 115}{25}[/tex]

[tex]X - 115 = -0.675*25[/tex]

[tex]X = 98[/tex]

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.675 = \frac{X - 115}{25}[/tex]

[tex]X - 115 = 0.675*25[/tex]

[tex]X = 132[/tex]

The interval is [98,132]

Answer:

z (min)  =  2079

L = 26     D =  39.6    S  =  16.5

Step-by-step explanation:

L  numbers of hours assigned to Lisa

D numbers of hours assigned to David

S numbers of hours assigned to Sara

Objective Function to minimize:

z = 30*L  +  25*D  +  18*S

Constraints:

Total time available

L  +  D  +  S  ≤ 110

Lisa experience

L  ≥  0.4 *  ( L + D )  then    L ≥ 0.4*L  +  0.4*D

0.6*L - 0.4*D ≥ 0

To provide designing experience to Sara

S ≥ 0.15*110        then     S ≥ 16.5

Time for Sara

S  ≤ 0.25 * ( L + D )     S ≤ 0.25*L  +  0.25*D   or    -0.25*L - 0.25*D + S ≤0

Availability of Lisa

L ≤ 50

The Model is:

z = 30*L  +  25*D  +  18*S  to minimize

Subject to:

L  +  D  +  S  ≤ 110

0.6*L - 0.4*D ≥ 0

S ≥  16.5

-0.25*L - 0.25*D + S ≤0

L ≤ 50

L ≥   0  ;   D  ≥  0  , S  ≥  0

After  6  iterations  optimal ( minimum ) solution is:

z (min)  =  2079

L = 26     D =  39.6    S  =  16.5

The formula that can be used to determine the number of hours each graphic designer should be assigned to the project to minimize the total cost is z = 30L + 25D + 18S and the minimum z is 2079.

Given :

The formula that can be used to determine the number of hours each graphic designer should be assigned to the project to minimize the total cost is given by:

z = 30L + 25D + 18S

The constraints are given by:

1) L + D + S [tex]\leq[/tex] 110

2) L [tex]\geq[/tex] 0.4(L + D)  

   L [tex]\geq[/tex] 0.4L + 0.4D

   0.6L - 0.4D [tex]\geq[/tex] 0

3) S [tex]\geq[/tex] 0.15(110)

   S [tex]\geq[/tex] 16.5

Now, to minimize 'z' then use:

[tex]\rm -0.25L-0.25D+S\leq 0[/tex]

L [tex]\leq[/tex] 50

L [tex]\geq[/tex] 0, D [tex]\geq[/tex] 0, S [tex]\geq[/tex] 0

Now, the minimum z is given by:

z = 2079

L = 26,  D = 39.6,  S = 16.5

For more information, refer to the link given below:

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Answer:

1) any number that is greater than ten is considered an integer bigger than ten: for example, 11, 12, 100, 1000000, etc.

2) any number that is smaller than ten is considered an integer smaller than ten: for example, 9, 8, 7, -100, -100000, etc.

3) any number that is bigger than zero is considered an integer bigger than ten: for example, 1, 2, 10, 100, 100000, etc.

4) any number that is smaller than zero is considered an integer smaller than zero: for example, -1, -2, -3, -10, -100000, etc.

Step-by-step explanation:

An integer is any whole number

Answer:

Step-by-step explanation:

integer bigger than 10 is 11

integer smaller than 10 is 9

integer greater than 0 is 1.

integer smaller than 0 is -1.

Answer:

Degree of freedoms F(4,40)

Step-by-step explanation:

Given:

There is a study which is involving 5 different groups that each contains 9 participants (totally 45)

The objective is to calculate the degree of freedoms

Formula used:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Solution:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Where,

K= number of groups = 5

N= total number of observations

which is given as follows,

N=45

Then,

Numerator degree of freedom = k-1

=5-1

=4

Denominator degree of freedom = N-K

=45-5

=40

Therefore,

Degree of freedoms, F(4,40)

Answer:

[tex]\boxed{\sf x- intercepts = 0 , 5 \ and \ -4}[/tex]

Step-by-step explanation:

A function is given to us and we need to find the x Intercepts of the graph of the given function . The function is ,

[tex]\sf \implies f(x) = 2x( x - 5 ) ^2(x+4)^3 [/tex]

For finding the x intercept , equate the given function with 0, we have ;

[tex]\sf \implies 2x ( x - 5 )^2(x+4)^3= 0 [/tex]

Equate each factor with 0 ,

[tex]\sf \implies 2x = 0[/tex]

Divide both sides by 2 ,

[tex]\sf \implies\bf x = 0[/tex]

Again ,

[tex]\sf \implies ( x - 5)^2=0 [/tex]

Taking squareroot on both sides,

[tex]\sf \implies x - 5 = 0 [/tex]

Add 5 to both sides,

[tex]\sf \implies \bf x = 5[/tex]

Similarly ,

[tex]\sf \implies \bf x = -4 [/tex]

Hence the x Intercepts are -4 , 0 and 5 .

{ See attachment also for graph } .

===============================================

Explanation:

It might help to draw out the picture as shown below. The pool itself (just the water only) is the inner rectangle. The outer rectangle is the pool plus the border of those 1 by 1 tiles.

The pool is a rectangle 90 feet by 80 feet. If we add on the tiles, then we get a larger rectangle that is 90+2 = 92 feet by 80+2 = 82 feet.

We add on 2 since we're adding two copies of "1" on either side of each dimension.

The larger rectangle's area is 92*82 = 7544 square feet

The smaller rectangle's area is 90*80 = 7200 square feet

The difference in areas is 7544-7200 = 344 square feet.

Each 1 by 1 tile is of area 1*1 = 1 sq foot, meaning that 344 tiles will get us the 344 square foot border around the pool.

Answer:

y = 4 x − 4

Step-by-step explanation:

Answer:

Area of ellipse=[tex]\pi ab[/tex]

Step-by-step explanation:

We are given that

[tex]x=acos\theta[/tex]

[tex]y=bsin\theta[/tex]

[tex]0\leq\theta\leq 2\pi[/tex]

We have to find the area enclose by it.

[tex]x/a=cos\theta, y/b=sin\theta[/tex]

[tex]sin^2\theta+cos^2\theta=x^2/a^2+y^2/b^2[/tex]

Using the formula

[tex]sin^2x+cos^2x=1[/tex]

[tex]\frac{x^2}{a^2}+\frac{y^2}{b^2}=1[/tex]

This is the equation of ellipse.

Area of ellipse

=[tex]4\int_{0}^{a}\frac{b}{a}\sqrt{a^2-x^2}dx[/tex]

When x=0,[tex]\theta=\pi/2[/tex]

When x=a, [tex]\theta=0[/tex]

Using the formula

Area of ellipse

=[tex]\frac{4b}{a}\int_{\pi/2}^{0}\sqrt{a^2-a^2cos^2\theta}(-asin\theta)d\theta[/tex]

Area of ellipse=[tex]-4ba\int_{\pi/2}^{0}\sqrt{1-cos^2\theta}(sin\theta)d\theta[/tex]

Area of ellipse=[tex]-4ba\int_{\pi/2}^{0} sin^2\theta d\theta[/tex]

Area of ellipse=[tex]-2ba\int_{\pi/2}^{0}(2sin^2\theta)d\theta[/tex]

Area of ellipse=[tex]-2ba\int_{\pi/2}^{0}(1-cos2\theta)d\theta[/tex]

Using the formula

[tex]1-cos2\theta=2sin^2\theta[/tex]

Area of ellipse=[tex]-2ba[\theta-1/2sin(2\theta)]^{0}_{\pi/2}[/tex]

Area of ellipse[tex]=-2ba(-\pi/2-0)[/tex]

Area of ellipse=[tex]\pi ab[/tex]

Answer:

Step-by-step explanation:

The measure for each angle is shown below.

A triangle is said to be equilateral if each of its three sides is the same length. In the well-known Euclidean geometry, an equilateral triangle is also equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others.

Given:

As, ∆ABC and ∆DBE is an equilateral triangle.

In Equilateral Triangle all the angles are Equal.

So,  4x+ 3= 9x- 7

5x = 50

x= 10

and, <1 = <9 = 4x+ 3= 43

and, <4 = <5 = <6 = 180/ 3= 60

ans, <3 = <8 = 180-60= 120

Also, <2 = < 7 = 180- <1- <3= 17

Learn more about Equilateral Triangle here:

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Answer:

Step-by-step explanation:

Answer:

[tex]y=(x-7)^2-1[/tex]

Step-by-step explanation:

We want to convert the equation:

[tex]\displaystyle y=x^2-14x+48[/tex]

Into vertex form, given by:

[tex]\displaystyle y=a(x-h)^2+k[/tex]

Where a is the leading coefficient and (h, k) is the vertex.

There are two methods of doing this. We can either: (1) use the vertex formulas or (2) complete the square.

Method 1) Vertex Formulas

Let's use the vertex formulas. First, note that the leading coefficient a of our equation is 1.

Recall that the vertex is given by:

[tex]\displaystyle \text{Vertex}=\left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)[/tex]

In this case, a = 1, b = -14, and c = 48. Find the x-coordinate of the vertex:

[tex]\displaystyle x=-\frac{(-14)}{2(1)}=7[/tex]

To find the y-coordinate, substitute this value back into the equation. Hence:

[tex]y=(7)^2-14(7)+48=-1[/tex]

Therefore, our vertex (h, k) is (7, -1), where h = 7 and k = -1.

And since we already determined a = 1, our equation in vertex form is:

[tex]\displaystyle y=(x-7)^2-1[/tex]

Method 2) Completing the Square

We can also complete the square to acquire the vertex form. We have:

[tex]y=x^2-14x+48[/tex]

Factor out the leading coefficient from the first two terms. Since the leading coefficient is one in this case, we do not need to do anything significant:

[tex]y=(x^2-14x)+48[/tex]

Now, we half b and square it. The value of b in this case is -14. Half of -14 is -7 and its square is 49.

We will add this value inside the parentheses. Since we added 49 inside the parentheses, we will also subtract 49 outside to retain the equality of the equation. Hence:

[tex]y=(x^2-14x+49)+48-49[/tex]

Factor using the perfect square trinomial and simplify:

[tex]y=(x-7)^2-1[/tex]

We acquire the same solution as before, with the vertex being (7, -1).

9514 1404 393

Answer:

  $72.00

Step-by-step explanation:

The relationship between price and tax is ...

  tax amount = (tax rate) × (price)

Then the price can be found by dividing by the tax rate:

  price = (tax amount)/(tax rate)

  price = $3.60 / 0.05 = $72.00

The original price of the chair was $72.00.

__

Bianca apparently did not pay any attention to the way tax is computed. Nor did she check her work. The original price is not a small fraction of the tax. It is the other way around. Bianca used a wrong relationship between tax and price.

Answer:

[tex]Q_1 = 19[/tex] --- first quartile

[tex]Q_3 = 41.5[/tex] --- third quartile

Step-by-step explanation:

Required:

The first and the third quartile

First, we order the dataset in ascending order[tex]Sorted: 6, 10, 11, 12, 15, 18, 20, 21, 24, 25, 26, 29, 30, 34, 35, 38, 40, 41, 42, 43, 44, 46, 55, 61[/tex]

The count of the dataset is:

[tex]n = 24[/tex]

Calculate the median position

[tex]Median=\frac{n+1}{2}[/tex]

[tex]Median=\frac{24+1}{2}[/tex]

[tex]Median=\frac{25}{2}[/tex]

[tex]Median=12.5th[/tex]

This means that the median is between the 12th and the 13th item

Next;

Split the dataset to two parts: 1 to 12 and 13 to 24

[tex]First: 6, 10, 11, 12, 15, 18, 20, 21, 24, 25, 26, 29[/tex]

[tex]Second: 30, 34, 35, 38, 40, 41, 42, 43, 44, 46, 55, 61[/tex]

The median position is:

[tex]Median = \frac{n + 1}{2}[/tex]

In this case; n = 12

So:

[tex]Median = \frac{12 + 1}{2}[/tex]

[tex]Median = \frac{13}{2}[/tex]

[tex]Median = 6.5th[/tex]

This means that the median is the average of the 6th and 7th item of the sorted dataset

So, we have:

[tex]Q_1 = \frac{18 + 20}{2}[/tex]

[tex]Q_1 = \frac{38}{2}[/tex]

[tex]Q_1 = 19[/tex] --- first quartile

[tex]Q_3 = \frac{41+42}{2}[/tex]

[tex]Q_3 = \frac{83}{2}[/tex]

[tex]Q_3 = 41.5[/tex] --- third quartile

Answer:

[tex]224cm^3\\[/tex]

Step-by-step explanation:

[tex]4cm*7cm*8cm=[/tex]

[tex]=224cm^3[/tex]

Hope this is helpful.

LWH=A

Plug in the numbers:

4*7*8=224^2

The area would be 224cm^2.

Answer:

[tex]c = \frac{1}{12}[/tex]

The mean of the distribution is 0.25.

The variance of the distribution is of 0.6875.

Step-by-step explanation:

Probability density function:

For it to be a probability function, the sum of the probabilities must be 1. The probabilities are 3c, 3c and 6c, so:

[tex]3c + 3c + 6c = 1[/tex]

[tex]12c = 1[/tex]

[tex]c = \frac{1}{12}[/tex]

So the probability distribution is:

[tex]P(X = -1) = 3c = 3\frac{1}{12} = \frac{1}{4} = 0.25[/tex]

[tex]P(X = 0) = 3c = 3\frac{1}{12} = \frac{1}{4} = 0.25[/tex]

[tex]P(X = 1) = 6c = 6\frac{1}{12} = \frac{1}{2} = 0.5[/tex]

Mean:

Sum of each outcome multiplied by its probability. So

[tex]E(X) = -1(0.25) + 0(0.25) + 1(0.5) = -0.25 + 0.5 = 0.25[/tex]

The mean of the distribution is 0.25.

Variance:

Sum of the difference squared between each value and the mean, multiplied by its probability. So

[tex]V^2(X) = 0.25(-1-0.25)^2 + 0.25(0 - 0.25)^2 + 0.5(1 - 0.25)^2 = 0.6875[/tex]

The variance of the distribution is of 0.6875.

Answer:

A. TRUE

Step-by-step explanation:

To determine if two triangles are congruent, we need to establish the facts that the three angles and three side lengths of one is congruent to corresponding angles and side lengths of the other triangle.

The diagram given only tells us the angle measure of the two triangles which are congruent to each other. The side length wasn't given. Therefore, the triangles may not be congruent.

9514 1404 393

Answer:

  44°

Step-by-step explanation:

The sum of the marked angles on the right is equal to the sum of the marked angles on the left:

  ? + 74 = 92 + 26

  ? = 92 +26 -74 = 44

The missing angle is 44°.

_____

Additional comment

The vertical angles in the center of the figure are v = 62°, the measure required to bring the total to 180° in each triangle. We have shortcut the equation(s) ...

  ? + 74 + v = 180 = 92 + 26 + v

by subtracting v from both sides, giving ...

  ? +74 = 92 +26

Answer:

16.5

Step-by-step explanation:

Answer:

file cabinet = 50

chair = 90

Step-by-step explanation:

x = chair

y = file cabinet

1st year, solve for x

2x+4y = 380

2x = 380 - 4y

x = 190 - 2y

2nd year

Now substitute x = 190 - 2y in your 2nd year formula

4x+6y = 660

4(190-2y)+6y = 660

760 - 8y + 6y = 660

-2y = -100

y = 50

The cost of the filling cabinet is 50 each

Now use the value for y (50) in your first formula to get x

2x+4y=380

2x+4*50=380

2x=380-200

2x=180

x=90

Answer:

-73, -71, -69

Step-by-step explanation:

Suppose the middle of the 3 integers is x.

(x-2)+(x)+(x+2)=-213

x-2+x+x+2=-213

3x=-213

x=-71

The integers are -69, -71, and -73

Answer:

-73,-71,-69

Step-by-step explanation:

Let x represent an odd interger

Odd intergers are serpated by the value of 2 so let the three consective intergers be represented by

[tex](x )+ (x + 2) +( x + 4)[/tex]

Set that equation equal to 213.

[tex]x + x + 2 + x + 4 = - 213[/tex]

[tex]3x + 6 = - 213[/tex]

[tex]3x = - 219[/tex]

[tex]x = - 73[/tex]

Plug -73 in the consective intergers expression.

[tex] - 73 + ( - 73 + 2) + ( - 73 + 4)[/tex]

So our three intergers are

[tex] - 73[/tex]

[tex] - 71[/tex]

[tex] - 69[/tex]

Answer:

I don't understand the meaning of question