Answer:Parallelogram, rhombus ,square
Step-by-step explanation:
The correlation between the height and weight of children aged 6 to 9 is found to be about r = 0.8. Suppose we use the height x of a child to predict the weight y of the child. We conclude that:
a. the least-squares regression line of y on x would have a slope of 0.8. about 80% of the time, age will accurately predict weight.
b. height is generally 80% of a child’s weight.
c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.
Answer:
[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]
The value of r is always between [tex]-1 \leq r \leq 1[/tex]
And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:
[tex]r^2 = 0.8^2 = 0.64[/tex]
So then the best conclusion for this case would be:
c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.
Step-by-step explanation:
For this case we know that the correlation between the height and weight of children aged 6 to 9 is found to be about r = 0.8. And we know that we use the height x of a child to predict the weight y of the child
We need to rememeber that the correlation is a measure of dispersion of the data and is given by this formula:
[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]
The value of r is always between [tex]-1 \leq r \leq 1[/tex]
And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:
[tex]r^2 = 0.8^2 = 0.64[/tex]
So then the best conclusion for this case would be:
c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.
Who’s good on algebra 1 ? Need help
Answer:
Which expression is equivalent to 3 over 175
I would say try - C or D
Determine the value of x for the triangle. show work.
Answer:
x=5
Step-by-step explanation:
x, x+7, x+8 must be a Pythagorean triple for it to make a right triangle. The only Pythagorean triple fitting these numbers is 5, 12, 13 so x must be 5.
Answer:
5
Step-by-step explanation:
Because this is a right triangle, you know that by the Pythagorean theorem:[tex]\sqrt{(x+7)^2+x^2}=x+8[/tex]
Squaring both sides to get rid of the square root:
[tex](x+7)^2+x^2=(x+8)^2[/tex]
Expanding all of the parentheses:
[tex]x^2+14x+49+x^2=x^2+16x+64[/tex]
Combine like terms:
[tex]x^2-2x-15=0[/tex]
Factor:
[tex](x-5)(x+3)=0[/tex]
Since x cannot be negative, it is equal to 5. Hope this helps!
What type of lines are shown?
Answer:
the angle is acute angle
Answer:
The type of angle shown is an acute angle
Step-by-step explanation:
there are 4 main types of angles. this is an acute angle as it is less than 90°.
Types of angles:
The 4 main types of angles are: acute, obtuse, right angles, reflex angles.
Acute angles- Acute angles are angles less than 90°.
Obtuse Angles-Obtuse angles are angles greater than 90° but less than 180°.
Right Angles- Right angles are angles of 90°.
Reflex Angles- Reflex angles are angles greater than 180° but less than 360°.
what is the equation to the following sentence?
Seven subtracted from two times a number is 13
Answer:
4x-7>13
add 7
4x>20
divide by 4
x>5
Step-by-step explanation:
A movie theater has a seating capacity of 387. The theater charges $5.00 for children, $7.00 for students, and $12.00 of
adults. There are half as many adults as there are children. If the total ticket sales was $ 2808, How many children,
students, and adults attended?
Answer:
The attendance was 198 children, 90 students and 99 adults.
Step-by-step explanation:
We define:
c: children attendance
s: students attendance
a: adult attendance
The equation that describes the total ticket sales is:
[tex]5c+7s+12a=2808[/tex]
We also know that the children attendance doubles the adult attendance:
[tex]c=2a[/tex]
The third equation is the seating capacity, which we assume is full:
[tex]c+s+a=387[/tex]
We start by replacing variables in two of the equations:
[tex]c=2a\\\\s=387-c-a=387-2a-a=387-3a[/tex]
Then, we solve the remaining equation for a:
[tex]5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99[/tex]
Then, we solve for the other two equations:
[tex]c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90[/tex]
The attendance was 198 children, 90 students and 99 adults.
Some shrubs have the useful ability to resprout from their roots after their tops are destroyed. Fire is a particular threat to shrubs in dry climates, as it can injure the roots as well as destroy the aboveground material. One study of resprouting took place in a dry area of Mexico. The investigation clipped the tops of samples of several species of shrubs. In some cases, they also applied a propane torch to the stumps to simulate a fire. Of 19 specimens of a particular species, 6 resprouted after fire. Estimate with 96% confidence the proportion of all shrubs of this species that will resprout after fire. Interval: .1884 to
The 96% confidence interval for the proportion of all shrubs of this species that will resprout after fire is approximately 0.1274 to 0.5042.
Here, we have,
To estimate the proportion of all shrubs of this species that will resprout after fire with 96% confidence, we will use the formula for a confidence interval for a proportion.
The formula for the confidence interval for a proportion (p) is given by:
CI = p ± Z * √(p * (1 - p) / n)
where:
CI is the confidence interval
p is the sample proportion (resprouted specimens / total specimens)
Z is the critical Z-score corresponding to the desired confidence level (96% confidence level corresponds to a Z-score of approximately 1.750)
n is the sample size (total number of specimens)
Given information:
Total number of specimens (n) = 19
Number of specimens that resprouted after fire = 6
Now, calculate the sample proportion (p):
p = (number of specimens that resprouted) / (total number of specimens)
p = 6 / 19 ≈ 0.3158 (rounded to four decimal places)
Now, calculate the critical Z-score for a 96% confidence level (use a Z-table or calculator):
Z ≈ 1.750
Now, calculate the margin of error (E):
E = Z * √(p * (1 - p) / n)
E = 1.750 * √(0.3158 * (1 - 0.3158) / 19)
E ≈ 0.1884 (rounded to four decimal places)
Finally, calculate the confidence interval:
CI = p ± E
CI = 0.3158 ± 0.1884
The 96% confidence interval for the proportion of all shrubs of this species that will resprout after fire is approximately 0.1274 to 0.5042.
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Please help ASAP! I will mark Brainliest! Please answer CORRECTLY! No guessing.
Answer:
27
Step-by-step explanation:
Input 5 for all x-values.
If that is an equal sign...
1/9*(3^5)
With PEMDAS, exponents are done before multiplication.
1/9*243
= 27
!!!!!!!!!!!!!!!!HELP
Answer:
You have to use this equation: [tex]a^{2} + b^{2} -c^{2}[/tex]
Step-by-step explanation:
C is the hypotenuse but you need another one so you got to do
[tex]x^{2} +8^{2} =17^{2}[/tex]
now you have to find [tex]x^{2}[/tex] which is
[tex]x^{2} = 17^{2} - 8^{2}[/tex]
[tex]x^{2} = 289 - 64[/tex]
[tex]x^{2} = 225[/tex]
[tex]x = \sqrt{255}[/tex]
[tex]x = 15[/tex]
if 8% is deducted from the bill,$384 bill remains to be paid. How much is the original bill?
Answer:
$353.28
Step-by-step explanation:
Sean tossed a coin off a bridge into the stream below. The path of the coin can be represented by the equation h = -16t2 + 72t + 100. How long will it take the coin to reach the stream?
Answer:
about 5.613 seconds
Step-by-step explanation:
Using the quadratic formula to find the value of t when h = 0, we have ...
at² +bt +c = 0
t = (-b±√(b²-4ac))/(2a)
t = (-72±√(72² -4(-16)(100)))/(2(-16))
t = (-72±√11584)/-32 = (9±√181)/4
Only the positive value of t is of interest.
The coin will hit the stream after (9+√181)/4 seconds ≈ 5.613 seconds.
If three points of a parallelogram are A (-5, -2), B (1,5), C (7.1). Which of the
following is the fourth point D of parallelogram ABCD?
(13,8)
(13.-6)
(1. -2)
(1,-6)
Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
Answer:
x > 25
Step-by-step explanation:
x+25> 50
Subtract 25 from each side
x+25-25 >50-25
x > 25
Answer:
x>25
Step-by-step explanation:
x+25>50
1. Subtract 25 from both sides of the equation
x+25>50
-25 -25
x>25
Which expression represents the following calculation subtract 32 from the product of 48 and 15
Answer:
x times y- q
Step-by-step explanation:
You can use the letters they give you on the answer choices. My answer makes sense because you multiply 48 times 15 and then subtract 32 from it
a candlemaker prices one set of scented candles at $10
y=10x
x= how many candles
Hello I need help not sure if I got it incorrectly
The first row of the table shows (x,y) = (-4,2). If we add in (-4,1), then we will re-use x = -4 a second time. The input x = -4 leads to multiple outputs of 2 and 1 at the same time. Visually the two points stack on each other to form a vertical line, therefore failing the vertical line test.
The second answer choice (1,-4) looks like your teacher might be trying to trick you or place out a trick/trap answer due to how similar it looks. This point can be added and the function is still valid because x = 1 hasn't been used yet in the table.
Talia is going to put a new carpet in her house. She measure's one side of her living room and finds it measures 17 meters which measurement does 17 meters represent
The answer in length
The length is used to measure the distance between to end points or edges. so 17 meters measurement represent the length.
What is perimeter?Its the sum of length of the sides used to made the given figure.
Talia is going to put a new carpet in her house. She measure's one side of her living room and finds it measures 17 meters.
Area is what is on the inside.
The perimeter is the outside of the hole thing.
Hence, the length is used to measure the distance between to end points or edges.
so 17 meters measurement represent the length.
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In ΔPQR, the measure of ∠R=90°, RP = 9.9 feet, and QR = 3.2 feet. Find the measure of ∠P to the nearest tenth of a degree.
Answer:
17.9
Step-by-step explanation:
There are k students in the class. m of them are girls. How many boys are in the class? How many more boys than girls are there? HELP
Answer:
[tex]k-m=b[/tex]
[tex]b-m=diff[/tex]
Step-by-step explanation:
If there are total of k students in a class, and m of those students are girls, the total amount of boys would be:
[tex]k-m=b[/tex]
(Where k, m, b are variables that represent the total number of students, the amount of girls and the amount of boys respectively)
As the amount of girls subtracted from the total amount would leave you with the amount of boys.
There would be:
[tex]b-m[/tex] more boys than girls.
If there were 10 total students in the class and 3 of those students were girls, lets use our above equations to see if they are correct - and if we get the expected amounts of:
7 boys in the class, and 4 more boys than there are girls.
[tex]k-m=b\\10-3=7\\7=7[/tex]
This is correct, as we expected this amount.
[tex]b-m=diff\\7-3=4[/tex]
The difference between them is 4, so this is correct.
Matt says 3/3 is equivalent to 1 is he correct?
Answer: Yes
Step-by-step explanation:
It isn't an
1 an improper fraction
Less than the denominator
Therefore, three thirds or 3/3 is one whole fraction
Rly hope I helped!
☆꧁Ashlin꧂☆
Answer:yes he his correct
Step-by-step explanation:
3/3=1
A linear pair of angles are adjacent and complementary
Answer:
You ugly i wanna fight on sight
Step-by-step explanation:
Hi guys, Can anyone help me with this tripple integral? Thank you:)
I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.
We have to turn K into the limits of integration on our integrals.
Clearly 0 is the lower limit for all three of x, y and z.
Now we have to incorporate
x+y+z ≤ 1
Let's do the outer integral over x. It can go the full range from 0 to 1 without violating the constraint. So the upper limit on the outer integral is 1.
Next integral is over y. y ≤ 1-x-z. We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y. So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.
Similarly the inner integral goes from z=0 to z=1-x-y
We've transformed our integral into the more tractable
[tex]\displaystyle \int_0^1 \int_0^{1-x} \int _0^{1-x-y} (x^2-z^2)dz \; dy \; dx[/tex]
For the inner integral we get to treat x like a constant.
[tex]\displaystyle \int _0^{1-x-y} (x^2-z^2)dz = (x^2z - z^3/3)\bigg|_{z=0}^{z= 1-x-y}=x^2(1-x-y) - (1-x-y)^3/3[/tex]
Let's expand that as a polynomial in y for the next integration,
[tex]= y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3[/tex]
The middle integration is
[tex]\displaystyle \int_0^{1-x} ( y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3)dy[/tex]
[tex]= y^4/12 + (x-1)y^3/3+ (2x+1)y^2/2- (2x^3+1)y/3 \bigg|_{y=0}^{y=1-x} [/tex]
[tex]= (1-x)^4/12 + (x-1)(1-x)^3/3+ (2x+1)(1-x)^2/2- (2x^3+1)(1-x)/3[/tex]
Expanding, that's
[tex]=\frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1)[/tex]
so our outer integral is
[tex]\displaystyle \int_0^1 \frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1) dx[/tex]
That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).
[tex]= (5/5 + 16/4 - 36/3 + 16/2 - 1)/12[/tex]
[tex]=0[/tex]
That's a surprise. You might want to check it.
Answer: 0
jared buts 2.4 pounds of broccoli for $3.24 which equation could jared use to find c, the cost of each pound of broccoli
Answer:
2.4c = 3.24
Step-by-step explanation:
Answer:
it is 4 ounces + 18 ounces
−7×8=?????????????????????????
Answer
the answer is -56
Step-by-step explanation:
If the fish tanks dimension are 60 by 15 by 34 and its is completely empty, what volume of water is needed to fill three fourths of the aquarium? Please help
Answer:
22,950 units³
Step-by-step explanation:
All you have to do is:
[tex]\frac{3}{4} *60*15*34=\\45*15*34=\\675*34=\\\\22,950[/tex]
If the mean of a symmetric distribution is 60, which of these values could be
the median of the distribution?
A. 100
B. 60
C. 80 As
D. 30
SUBMIT
Answer:
i think ...
Step-by-step explanation:
symmetric distribution usually be a bell shape distribution .
most likely the median = mean = 60
The required value of 60 could be the median of the distribution. Option B is correct.
What is mean?The mean of the values is the ratio of the total sum of values to the number of values.
What is the median?When a dataset is ordered, the median is the value that is exactly in the middle. It is a measure of central tendency that distinguishes between the lowest and top 50% of data.
Here,
The mean of a symmetric distribution is 60.
Since for the symmetric data and rational data, the mean is equal to the median,
So Mean = Median
Median = 60
Thus, the required value of 60 could be the median of the distribution.
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Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead. Exceptions are allowed, but they want the average to be 10 or below. The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages. (a-1) Find the test statistic. (Round your answer to 4 decimal places.) The test statistic (a-2) At the .01 level of significance, is the true mean greater than 10
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ ≤ 10
For the alternative hypothesis,
µ > 10
The inequality sign indicates that It is a right tailed.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 35,
Degrees of freedom, df = n - 1 = 35 - 1 = 34
t = (x - µ)/(s/√n)
Where
x = sample mean = 14.44
µ = population mean = 10
s = samples standard deviation = 4.45
t = (14.44 - 10)/(4.45/√35) = 5.9
We would determine the p value using the t test calculator. It becomes
p < 0.00001
Since alpha, 0.01 > than the p value, then we would reject the null hypothesis. Therefore, At a 1% level of significance, we can conclude that the true mean is greater than 10.
Lacy enjoys running around the lake, and Paul enjoys running around the park. Lacy contends that she runs
farther around the lake than Paul runs around the park, and Paul contends the opposite.
To settle their debate, they find satellite images of the lake and the park and juxtapose them on a single
coordinate grid (shown below).
The perimeter of the lake is m
Round the final answer to the nearest meter. Do not round intermediate calculations.
The perimeter of the park is m
Round the final answer to the nearest meter. Do not round intermediate calculations.
Who should win the debate?
Answer:
The perimeter of the lake is 314m. The perimeter of the park is 339 m. Paul should win the debate.
Step-by-step explanation:
F=440(2)h/12 where h is 6
Answer:440
Step-by-step explanation:
F=440(2)h/12 h=6
F=440 x 2 x 6/12
F=(440 x 2 x 6) ➗ 12
F=5280 ➗ 12
F=440
Two tanks are interconnected. Tank A contains 60 grams of salt in 50 liters of water, and Tank B contains 80 grams of salt in 40 liters of water.
A solution of 2 gram/L flows into Tank A at a rate of 5 L/min, while a solution of 3 grams/L flows into Tank B at a rate of 7 L/min. The tanks are well mixed.
The tanks are connected, so 8 L/min flows from Tank A to Tank B, while 3 L/min flows from Tank B to Tank A. An additional 12 L/min drains from Tank B.
Letting x represent the grams of salt in Tank A, and y represent the grams of salt in Tank B, set up the system of differential equations for these two tanks.
Let a(t) and b(t) denote the amounts of salt in tanks A and B, respectively.
The volume of liquid in tanks A and B after t minutes are
A: 50 L + (5 L/min + 3 L/min - 8 L/min)t = 50 L
B: 40 L + (7 L/min + 8 L/min - 3 L/min - 12 L/min)t = 40 L
so the amount of solution in the tanks stays constant.
Salt flows into tank A at a rate of
(2 g/L)*(5 L/min) + (b(t)/40 g/L)*(3 L/min) = (10 + 3/40 b(t)) g/min
and out at a rate of
(a(t)/50 g/L)*(8 L/min) = 4/25 a(t) g/min
so the net flow rate is given by the differential equation
[tex]\dfrac{\mathrm da(t)}{\mathrm dt}=10+\dfrac{3b(t)}{40}-\dfrac{4a(t)}{25}[/tex]
We do the same for tank B: salt flows in at a rate of
(3 g/L)*(7 L/min) + (a(t)/50 g/L)*(8 L/min) = (21 + 4/25 a(t)) g/min
and out at a rate of
(b(t)/40 g/L)*(3 L/min + 12 L/min) = 3/8 b(t) g/min
and hence with a net rate of
[tex]\dfrac{\mathrm db(t)}{\mathrm dt}=21+\dfrac{4a(t)}{25}-\dfrac{3b(t)}8[/tex]
Replace a(t) and b(t) with x and y. Then the system is (in matrix form)
[tex]\dfrac{\mathrm d}{\mathrm dt}\begin{bmatrix}x\\y\end{bmatrix}=\dfrac1{200}\begin{bmatrix}-32&15\\32&-75\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}+\begin{bmatrix}10\\21\end{bmatrix}[/tex]
with initial conditions x(0) = 60 g and y(0) = 80 g.
