Which pair of parallelograms is similar?

Answer:

AC = 4.5 units

Step-by-step explanation:

In the given triangle ABC,

Segment AD is the angle bisector of ∠BAC.

m∠CAD = m∠BAD = θ

By applying angle bisector theorem in ΔABC,

An angle bisector of the interior angle in a triangle divides the opposite side into segments that are proportional to the other two sides.

[tex]\frac{\text{AB}}{\text{BD}}=\frac{\text{AC}}{\text{CD}}[/tex]

By substituting measures of the given sides,

[tex]\frac{6.8}{3.8}=\frac{\text{AC}}{2.5}[/tex]

AC = [tex]\frac{6.8\times 2.5}{3.8}[/tex]

AC = 4.473

AC ≈ 4.5 units

Therefore, measure of the missing side AC will be 4.5 units.

Answer:

Malcom's maximum speed = 200 km/h

Ravi's maximum speed = 320 km/h

Step-by-step explanation:

Let m = Malcom's maximum speed

Let r = Ravi's maximum speed

Average of their maximum speed would be represented as [tex] \frac{m + r}{2} = 260 [/tex]

[tex] m + r = 520 [/tex].

Make m the subject of the formula by subtracting r from both sides:

[tex] m = 520 - r [/tex]. Let this be equation 1.

Given that Malcom's speed (m), when doubled is 80 km/h more than that of Ravi (r). This can be expressed as: [tex] 2m = r + 80 [/tex]. This is equation 2.

Plug in (520 - r) into equation 2 to replace m:

[tex] 2(520 - r) = r + 80 [/tex]

[tex] 1040 - 2r = r + 80 [/tex]

Solve for r. Subtract 1040 from both sides:

[tex] 1040 - 2r - 1040 = r + 80 - 1040 [/tex]

[tex] - 2r = r - 960 [/tex]

Subtract r from both sides

[tex] - 2r - r = r - 960 - r [/tex]

[tex] - 3r = - 960 [/tex]

Divide both sides by -3

[tex] \frac{-3r}{-3} = \frac{-960}{-3} [/tex]

[tex] r = 320 [/tex]

To find m, plug in the value of r into equation 1.

[tex] m = 520 - r [/tex]. =>Equation 1

[tex] m = 520 - 320 [/tex]

[tex] m = 200 [/tex].

Malcom's maximum speed = m = 200 km/h

Ravi's maximum speed = r = 320 km/h

Answer:

[tex]-\frac{5}{2}[/tex]

Step-by-step explanation:

Step 1: Put this into an equation

[tex]-\frac{5}{3} - x = \frac{5}{6}[/tex]

Step 2: Solve for x

[tex]-x = \frac{5}{6} + \frac{5}{3}[/tex]

[tex]-x = \frac{5}{2}[/tex]

[tex]x =- \frac{5}{2}[/tex]

Therefore you need to subtract [tex]-\frac{5}{2}[/tex] from [tex]-\frac{5}{3}[/tex] to get [tex]\frac{5}{6}[/tex]

Answer:i don’t know

Step-by-step explanation:I’m sorry dude I have no idea I tried doing it in the browser and I could not find an answer sorry

Answer:

DI = 38

Step-by-step explanation:

Δ EHC and Δ DIC are similar and ratios of corresponding sides are equal, that is

[tex]\frac{DI}{EH}[/tex] = [tex]\frac{DC}{EC}[/tex] , substitute values

[tex]\frac{DI}{76}[/tex] = [tex]\frac{1}{2}[/tex]  ( cross- multiply )

2DI = 76 ( divide both sides by 2 )

DI = 38

Answer:

  swap the middle two steps to put them in order

Step-by-step explanation:

The steps in order would be ...

Answer:

the horizontal distance is the x-intercept, and the vertical distance is the y-intercept

1) x-int=1, y-int=1

2) x-int=6, y-int=5

Answer:

122

Step-by-step explanation:

5!=5 x 4 x 3 x 2 x 1 = 120

2!=2 x 1 = 2

120+2=122

Answer:

Step-by-step explanation:

Sum of measures of an interior angle of a polygon is given by

( n - 2) × 180

where n is the number of sides

From the question the number of sides is 8 so n = 8

The sum of it's interior angles is

(8 - 2) × 180

6 × 180

Hope this helps you

Answer:

(-3,6) (1,8) (2,10) and so on.

Answer:

....the answer is 682.5

Answer:

The answer is 702. Hope it helped! :D

Step-by-step explanation:

Answer:

population parameter

Step-by-step explanation:

A population  is said to be category of individuals under study.

A population parameter is a numerical value which provides a summary to a measure of an average or percentage which describes the entire population under a study.

In a Normal Curve, the population parameter can be a population mean or population standard deviation , population proportion which represent the population.

∴

The average SAT score of  1356 in the given study  is a population parameter

Answer:

Option a. Y=3x

Step-by-step explanation:

Let us use cross multiplication method.

Let the cost of 1 magazine be x.

No. of copies                               Cost

1)50                                                $150

2)1                                                      x

50x=150 x 1               equation(1)

x=150/50

x=$3

Now see equation (1),

150=50x

150=50 x 3

Here let us represent the cost as y and no. of copies as x.

Y=3x

Therefore, a. Y=3x is the right answer.

Thank you!

2x+10=14

x=2

Area: 14.4= 56

3x+16=25

3x=9

x=3

17x-1,7=37,4

17x=39,1

x=2,3

Answer:

10800

Step-by-step explanation:

1 trimesters cost = 1450 + 350  $

2 year -> 6 trimester

1800$ x 6 = 10800 $

==========================================================

Explanation:

Let's find the area of the hexagon. It's composed of two identical (aka congruent) trapezoids.

Each trapezoid has two parallel bases of 4+4 = 8 and 5 units. The height is 3. The area of one trapezoid is

area = height(base1+base2)/2

area = 3*(8+5)/2

area = 19.5

which doubles to 2*19.5 = 39 to represent the area of the entire hexagon

--------------------------------

The volume of any prism is found through this formula

volume = (area of base)*(height of prism)

We just found the area of the base to be 39. The height is unknown, so we'll call it h. The volume is given to be 234.

We end up with this equation

234 = 39h

which solves to h = 6 after dividing both sides by 39. This prism has a height of 6 units.

The height of the prism is 6 units

The hexagonal prism is a prism with hexagonal base.

An isosceles trapezoid is a convex quadrilateral with a line of symmetry bisecting one pair of opposite sides.

Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

Given,

Each hexagon is made from two congruent isosceles trapezoids

Therefore

Area of one isosceles trapezoids = [tex](a+b).(\frac{h}{2} )[/tex]

where,

a =4+4 = 8 units

b = 5 units

h = 3 units

Area of one isosceles trapezoids =[tex](8+5)(\frac{3}{2} )[/tex] =19.5 unit square

Area of  the hexagon = Area of two isosceles trapezoids

Area of hexagon = 2× 19.5 = 39 unit square

We know that,

Volume = Base area × Height

Volume = 234 cubic units

234 = 39 × h

h = [tex]\frac{234}{39}[/tex] = 6 units

Hence, the height of the prism is 6 units

Learn more about Hexagonal prism, Isosceles trapezoids and Volume here

https://brainly.com/question/3336447

#SPJ2

Answer:

The expression in factored form is (3x - 7)(3x + 7)

Step-by-step explanation:

Here in this question, we are interested in using the difference of two squares to factor the given expression.

Mathematically, supposed we have two squares a^2 and b^2, and we are told to factorize a^2-b^2.

By using the difference of two squares;

a^2-b^2 can thus be written as;

(a-b)(a + b)

Now, we can apply same approach to the problem at hand.

9x^2 - 49

kindly note that 9x^2 can be written as ((3x)^2 and 49 can be written as 7^2

So applying what we have said earlier about difference of two squares;

9x^2 - 49 will be ;

(3x-7)(3x + 7)

Answer:

The answer is (3x - 7) (3x +7)

Step-by-step explanation:

Answer:

x= 7/4 =1.750

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given one side and diagonal of rectangle we can use Pythagorean theorem to calculate the other side of it.

[tex]L=40\, cm\\D=41\,cm\\W=\ ?\\\\W^2+L^2=D^2\\\\W^2+40^2=41^2\\\\W^2+1600=1681\\\\W^2=81\\\\W=9[/tex]

Perimeter:

P = 2W + 2L = 2•40 + 2•9 = 80 + 18 = 98

Answer:

Dimensions of the product matrix = (3 × 3)

Step-by-step explanation:

If matrix P having dimensions (m × n) and matrix Q having dimensions (n × r) are multiplied,

Dimensions of the product matrix PQ will have the dimensions as (m × r).

That means product of the two matrices are defined when columns of first matrix P is equal to the rows of the second matrix Q.

Following this rule,

Dimensions of matrix A = (2 × 3)

[ Rows × Columns]

Dimensions of matrix B = (3 × 3)  [Rows of B = 3, columns of B = 3]

Dimensions of matrix C = (3 × 2) [Rows of C = 3, columns of C = 2]

Since columns of C and rows of A are equal.

Therefore, product of C and A is defined.

Product of the matrices C & A will have the dimensions as (3 × 3).

Answer:

484 meters

Step-by-step explanation:

diameter of a circular Garden = 140 metre

we know diameter = 2*radius

140 = 2*radius

radius = 140/2 = 70 meter

thus, radius of garden is 70 meter

Given that

On its outside there is a road of 7 metre wide

Thus, radius of garden along-with road will increase by 7 meters

Total radius of garden and road = 70 meter + 7 meter = 77 meter

 outer circumference of the road can be calculated using radius 77 meter.

we know that circumference = [tex]2\pi r[/tex]

we will use value of [tex]\pi = 22/7[/tex]

Thus, outer circumference of the road ​ with radius 77 m

= [tex]2\pi r \\=>2*22/7 *77\\=> 44*11 = 484[/tex]

Thus,

The outer circumference of the road ​is 484 meters.

Answer:

D) 11 13 15 19 23 23 24 26.5 28 33​

Step-by-step explanation:

The box-and-whisker plot displayed above has the following key values that we can use to identify which of the given data set it matches. It has:

Minimum value = 11

Q1 = 15

Median = 23

Q3 = 26

Maximum value = 33

From the options given, using just the max and min value, we can conclude that the data set in option D matches the box plot.

The data set in option D has a minimum value of 11, and a maximum value of 33.

The answer is 4.05

Step-by-step explanation:

20^2 is 20•20 which is 400 || +5=405 || /100=4.05

Answer:

[tex]\large \boxed{\sf \bf \ \ a^2+b^2=20 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

[tex]a^b=b^a\\\\\text{ We can replace a by 2b.}\\\\(2b)^b=2^b\cdot b^b=b^{2a}=b^2\cdot b^b\\\\\text{ Let's assume that b is different from 0 and we can divide by }b^b \\ \\ \text{ both sides of the equation, and it come.}\\\\2^b=b^2\\\\\text{ We find b = 2 and then a = 4, So}\\\\a^2+b^2=4^2+2^2=16+4=20[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Step-by-step explanation:

Here,

radius (r)= 2cm

height(h)=5cm

now,

according to the question we must find the surface area of cylinder so,

by formulae ,

a= 2.pi.r(r+h)

now,

a= 2×3.14×2(2+5)

by simplifying it we get,

The surface area of cylinder is 87.92 cm^2.

Hope it helps

Answer:

13.6

Step-by-step explanation:

tan(45)=x÷8.5

1.6=x/8.5

x=13.6

Use the law of sines

x/sin(45) = 8.4/sin(85)

x = sin(45)*8.4/sin(85)

x = 5.96238563941842

x = 6.0

Answer:

196

Step-by-step explanation:

Surface area of a cuboid:

2 ( lw + wh + hl)

L = Length

W = Width

H = Height

Area of the base = 30 = lw; So we could take the length as 15 cm and width as 2 cm.

Volume = lwh; 15 x 2 x (4); So 4 is the height

So, 2 ( lw + wh + hl)

= 2 (15 x 2 + 2 x 4 + 4 x 15)

= 2 (30 + 8 + 60)

= 2 (98)

= 196 is the surface area of cuboid

Answer:

-x^2 - 3

Step-by-step explanation:

SO we know f(x); x^2

when you place a (-), it flips teh image across the x-axis.

Finally, we see that the line is at (0,-3). To get it there, we need to go down 3, which gives us the -3 in the equation.

So we have -x^2-3

(rember the - sign is to flip it across the x-axis, and the -3 is to move the line 3 down the y-axis)        

I checked my answer on a calculator btw lol.

Step-by-step explanation:

Hi, there!!

Here according to the question we must find the cost of 1 kg sugar.

Given that:

17/4 kg of sugar cost £68.

then 1 kg sugar costs,

=[tex] \frac{68}{ \frac{17}{4} } [/tex]

after reciprocal we get,

= £68×4/17

=£16

The answer would come £16.

Therefore, The cost of 1 kg sugar is £. 16.

Hope it helps....

Answer:

£ 16

Step-by-step explanation:

Cost of 4 1/4 kg sugar = £ 68

4 1/4 = 17/4

Cost of 17/4 kg of sugar = 68

Cost of 1 kg of sugar =68 ÷ (17/4)

                                  [tex]= 68* \frac{4}{17}\\\\=4*4\\[/tex]

                                  = £ 16​

Answer:

SSS

Step-by-step explanation:

Answer:

SSS

Step-by-step explanation:

Option c or "SSS"

Answer:

  4/5

Step-by-step explanation: