Answer: D: The minimum value of A occurs 7 units lower than minimum of function B.
Step-by-step explanation: The minimum of function A is at (3,-2), while the minimum of function B would be at (-3,5). So, you do 5-(-2) to get 7.
The minimum value of A occurs 7 units lower than the minimum of function B.
We have given that,
Statement best compares the two functions
What is the minimum and maximum function?
The maxima and minima of a function, known collectively as extrema, are the largest and smallest value of the function, either within a given range, or on the entire domain.
The minimum of function A is at (3,-2), while the minimum of function B would be at (-3,5). So, you do 5-(-2) to get 7.
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A grinding stone completes 175 revolutions before coming to a stop. How many radians did the stone complete
Answer:
175 * 2 * [tex]\pi[/tex]
350[tex]\pi[/tex] radians
Step-by-step explanation:
The number of radians completed by the stone will be 350 radians.
What is an angle in radians?The angle subtended from a circle's centre that intercepts an arc with a length equal to the circle's radius is known as a radian.
Given that a grinding stone completes 175 revolutions before coming to a stop.
The number of the revolutions in radians will be calculated as:-
Multiply the number by 2π to convert it into the radians.
Number of revolutions = 175 x 2 x π
Number of revolutions = 350 radians
Therefore, the number of radians completed by the stone will be 350 radians.
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work out the area of this shape
Answer:
1000
Step-by-step explanation:
Frans paid R9600 as interest on a loan he took 5 years ago at 16% rate. What's was the amount he took as loan? Yeah
Answer:
5555 Lakh rupoes maybe hope it helps
The amount Frans took as loan = R12000
What is simple interest?"It is the interest that is only calculated on the initial amount of the loan."
Formula for simple interest:[tex]SI=\frac{P\times R\times T}{100}[/tex]
where, P: principal amount
T : period
R: rate of interest
For given question,
SI = 9600
T = 5 years
R = 16%
We need to find the principal amount.
Using simple interest formula,
[tex]\Rightarrow SI=\frac{P\times R\times T}{100}\\\\\Rightarrow P=\frac{SI\times 100}{R\times T}\\\\\Rightarrow P=\frac{9600\times 100}{5\times 16}\\\\\Rightarrow P=12000[/tex]
Therefore, the amount Frans took as loan = R12000
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What is the solution set of the equation x2+3*-4=6
Answer:
x=9
Step-by-step explanation:
I need help with this, please.
Answer:
it can not cleared clear but it can not cleared
What does it mean if a project has a Percent Spent of 90%, Percent Scheduled of 85%, and a Percent Complete of 95%
Answer:
It means that the project is in good shape, within budget an d it would finish early
Step-by-step explanation:
The answer to this question is pretty straight forward. If a project has the percent spent fine 90 percent, the scheduled has percentage of 85 percent and the complete is at the percentage of 95, what it means is that this project is in good shape, the project being carried out is still being done within the proposed budget and at 95% complete, it means that the project is going to finish early.
Previous Question Question 17 of 20 Next Question Based on the regression model, the expected daily production volume with 112 factory workers is 118,846 units. The human resource department noted that 123,415 units were produced on the most recent day on which there were 112 factory workers. What is the residual of this data point
Answer:
4,569 units
Step-by-step explanation:
Given :
Measured value = 123,415 units
Expected value = 118,846 units
Residual is the difference between the measured and expected value :
Residual = Measured value - Expected value
Residual = 123,415 units - 118,846 units
Residual = 4,569 units
The data on the box plot describes the weight of several students in sixth grade. Which of the following statements are true about the data set? Select all that apply.
One-fourth of the students weigh between 90 and 101 pounds.
One-half of the students weigh between 75 and 90 pounds.
The median weight of the sixth graders is 85 pounds.
One-fourth of the students weigh less than 75 pounds.
One-fourth of the students weigh more than 75 pounds.
The total range of weight is 40 pounds.
Answer:
Step-by-step explanation:
B
Will give brainliest answer
Answer:
A
Step-by-step explanation:
the proof of the answer is shown above
Identify the domain of the function shown in the graph.
A. -2 ≤ x ≤ 2
B. {-2,2}
C. x is all real numbers.
D. x > -2
Answer:
C. x is all real numbers
Step-by-step explanation:
Think of domain as how far the graph expands on the x-axis as asymptotes as the limits. So in this case, the graph extends infinitely on the x-axis; so it should be all real numbers.
The 100th term of 8, 8^4, 8^7, 8^10, …
Answer:
[tex]8^{298} \\8^{3(n-1)+1}[/tex]
Step-by-step explanation:
Answer:
8^298
Step-by-step explanation:
n = 1, 8^(1 + 0 * 3)
n = 2, 8^(1 + 1 * 3)
n = 3, 8^(1 + 2 * 3)
n = 4, 8^(1 + 3 * 3)
The exponent of 8 is 1 added to product of 1 less than the term number multiplied by 3.
n = n, 8^(1 + [n - 1] * 3) = 8^(1 + 3n - 3) = 8^(3n - 2)
For n = 100, the exponent is
3n - 2 = 3(100) - 2 = 300 - 2 = 298
Answer: 8^298
write the following sets in the set builder form C={1,4,9,16,25}
C={ check example in book}
19.Find dy/dx
of the function y = f(x) definded by x²+xy-y2 = 4.
Answer:
2x + y
Step-by-step explanation:
x² + xy - y² = 4
→ Remember the rule, bring the power down then minus 1
2x + y
Find the maximum and the minimum value of the following objective function, and the value of x and y at which they occur. The function F=2x+16y subject to 5x+3y≤37, 3x+5y≤35, x≥0, y≥0
The maximum value of the objective function is ___ when x=___ and y=___
Answer:
The maximum value of the objective function is 112 when x = 0 and y = 7.
Step-by-step explanation:
Given the constraints:
5x+3y≤37, 3x+5y≤35, x≥0, y≥0
Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:
A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)
The objective function is given as E =2x+16y, therefore:
At point A(0, 7): E = 2(0) + 16(7) = 112
At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8
At point C(5, 4): E = 2(5) + 16(4) = 74
At point D(0, 0): E = 2(0) + 16(0) = 0
Therefore the maximum value of the objective function is at A(0, 7).
The maximum value of the objective function is 112 when x = 0 and y = 7.
a/b=2/5 and b/c=3/8 find a/c
Answer:
[tex]\frac{a}{c}[/tex] = [tex]\frac{3}{20}[/tex]
Step-by-step explanation:
[tex]\frac{a}{c}[/tex] = [tex]\frac{a}{b}[/tex] × [tex]\frac{b}{c}[/tex] = [tex]\frac{2}{5}[/tex] × [tex]\frac{3}{8}[/tex] = [tex]\frac{6}{40}[/tex] = [tex]\frac{3}{20}[/tex]
When P(x) is divided by (x - 1) and (x + 3), the remainders are 4 and 104 respectively. When P(x) is divided by x² - x + 1 the quotient is x² + x + 3 and the remainder is of the form ax + b. Find the remainder.
Answer:
The remainder is 3x - 4
Step-by-step explanation:
[Remember] [tex]\frac{Dividend}{Divisor} = Quotient + \frac{Remainder}{Divisor}[/tex]
So, [tex]Dividend = (Quotient)(Divisor) + Remainder[/tex]
In this case our dividend is always P(x).
Part 1
When the divisor is [tex](x - 1)[/tex], the remainder is [tex]4[/tex], so we can say [tex]P(x) = (Quotient)(x - 1) + 4[/tex]
In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x - 1) = 0[/tex]
When solving for [tex]x[/tex], we get
[tex]x - 1 = 0\\x - 1 + 1 = 0 + 1\\x = 1[/tex]
When [tex]x = 1[/tex],
[tex]P(x) = (Quotient)(x - 1) + 4\\P(1) = (Quotient)(1 - 1) + 4\\P(1) = (Quotient)(0) + 4\\P(1) = 0 + 4\\P(1) = 4[/tex]
--------------------------------------------------------------------------------------------------------------
Part 2
When the divisor is [tex](x + 3)[/tex], the remainder is [tex]104[/tex], so we can say [tex]P(x) = (Quotient)(x + 3) + 104[/tex]
In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x + 3) = 0[/tex]
When solving for [tex]x[/tex], we get
[tex]x + 3 = 0\\x + 3 - 3 = 0 - 3\\x = -3[/tex]
When [tex]x = -3[/tex],
[tex]P(x) = (Quotient)(x + 3) + 104\\P(-3) = (Quotient)(-3 + 3) + 104\\P(-3) = (Quotient)(0) + 104\\P(-3) = 0 + 104\\P(-3) = 104[/tex]
--------------------------------------------------------------------------------------------------------------
Part 3
When the divisor is [tex](x^2 - x + 1)[/tex], the quotient is [tex](x^2 + x + 3)[/tex], and the remainder is [tex](ax + b)[/tex], so we can say [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]
From Part 1, we know that [tex]P(1) = 4[/tex] , so we can substitute [tex]x = 1[/tex] and [tex]P(x) = 4[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]
When we do, we get:
[tex]4 = (1^2 + 1 + 3)(1^2 - 1 + 1) + a(1) + b\\4 = (1 + 1 + 3)(1 - 1 + 1) + a + b\\4 = (5)(1) + a + b\\4 = 5 + a + b\\4 - 5 = 5 - 5 + a + b\\-1 = a + b\\a + b = -1[/tex]
We will call [tex]a + b = -1[/tex] equation 1
From Part 2, we know that [tex]P(-3) = 104[/tex], so we can substitute [tex]x = -3[/tex] and [tex]P(x) = 104[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]
When we do, we get:
[tex]104 = ((-3)^2 + (-3) + 3)((-3)^2 - (-3) + 1) + a(-3) + b\\104 = (9 - 3 + 3)(9 + 3 + 1) - 3a + b\\104 = (9)(13) - 3a + b\\104 = 117 - 3a + b\\104 - 117 = 117 - 117 - 3a + b\\-13 = -3a + b\\(-13)(-1) = (-3a + b)(-1)\\13 = 3a - b\\3a - b = 13[/tex]
We will call [tex]3a - b = 13[/tex] equation 2
Now we can create a system of equations using equation 1 and equation 2
[tex]\left \{ {{a + b = -1} \atop {3a - b = 13}} \right.[/tex]
By adding both equations' right-hand sides together and both equations' left-hand sides together, we can eliminate [tex]b[/tex] and solve for [tex]a[/tex]
So equation 1 + equation 2:
[tex](a + b) + (3a - b) = -1 + 13\\a + b + 3a - b = -1 + 13\\a + 3a + b - b = -1 + 13\\4a = 12\\a = 3[/tex]
Now we can substitute [tex]a = 3[/tex] into either one of the equations, however, since equation 1 has less operations to deal with, we will use equation 1.
So substituting [tex]a = 3[/tex] into equation 1:
[tex]3 + b = -1\\3 - 3 + b = -1 - 3\\b = -4[/tex]
Now that we have both of the values for [tex]a[/tex] and [tex]b[/tex], we can substitute them into the expression for the remainder.
So substituting [tex]a = 3[/tex] and [tex]b = -4[/tex] into [tex]ax + b[/tex]:
[tex]ax + b\\= (3)x + (-4)\\= 3x - 4[/tex]
Therefore, the remainder is [tex]3x - 4[/tex].
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[tex]V = 864\pi[/tex]
Step-by-step explanation:
Since one of the boundaries is y = 0, we need to find the roots of the function [tex]f(x)=-2x^2+6x+36[/tex]. Using the quadratic equation, we get
[tex]x = \dfrac{-6 \pm \sqrt{36 - (4)(-2)(36)}}{-4}= -3,\:6[/tex]
But since the region is also bounded by [tex]x = 0[/tex], that means that our limits of integration are from [tex]x=0[/tex] (instead of -3) to [tex]x=6[/tex].
Now let's find the volume using the cylindrical shells method. The volume of rotation of the region is given by
[tex]\displaystyle V = \int f(x)2\pi xdx[/tex]
[tex]\:\:\:\:\:\:\:= \displaystyle \int_0^6 (-2x^2+6x+36)(2 \pi x)dx[/tex]
[tex]\:\:\:\:\:\:\:= \displaystyle 2\pi \int_0^6 (-2x^3+6x^2+36x)dx[/tex]
[tex]\:\:\:\:\:\:\:= \displaystyle 2\pi \left(-\frac{1}{2}x^4+2x^3+18x^2 \right)_0^6[/tex]
[tex]\:\:\:\:\:\:\:= 864\pi [/tex]
4
920
26°
?
74°
find the missing angle.
9514 1404 393
Answer:
44°
Step-by-step explanation:
The sum of the marked angles on the right is equal to the sum of the marked angles on the left:
? + 74 = 92 + 26
? = 92 +26 -74 = 44
The missing angle is 44°.
_____
Additional comment
The vertical angles in the center of the figure are v = 62°, the measure required to bring the total to 180° in each triangle. We have shortcut the equation(s) ...
? + 74 + v = 180 = 92 + 26 + v
by subtracting v from both sides, giving ...
? +74 = 92 +26
Mrs Lee used 6 Meters of material to make 3 dresses. She used 4 ties as much material for a curtain as for a dress. How much material did she use for the curtain? (Dress)
Answer:
for each dress she used 6/3 of material
=2
then for a curtain =2x4=8 materials
For each of the following, assume that the two samples are obtained from populations with the same mean, and calculate how much difference should be expected, on average, between the two sample means. Each sample has n =4 scores with s^2 = 68 for the first sample and s^2 = 76 for the second. (Note: Because the two samples are the same size, the pooled variance is equal to the average of the two sample variances).
a) 4.24.
b) 0.24.
c) 8.48.
d) 6.00.
Next, each sample has n=16 scores with s^2 = 68 for the first sample and s^2 = 76 for the second.
a) 0.12.
b) 2.12.
c) 4.24.
d) 3.00.
Answer:
d)6.00
d)3.00
Step-by-step explanation:
We are given that
n=4 scores
[tex]S^2_1=68[/tex]
[tex]S^2_2=76[/tex]
We have to find the difference should be expected, on average, between the two sample means.
[tex]S_{M_1-M_2}=\sqrt{\frac{S^2_1}{n_1}+\frac{S^2_2}{n_2}}[/tex]
[tex]n_1=n_2=4[/tex]
Using the formula
[tex]S_{M_1-M_2}=\sqrt{\frac{68}{4}+\frac{76}{4}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{4}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{36}=6[/tex]
Option d is correct.
Now, replace n by 16
[tex]n_1=n_2=16[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68}{16}+\frac{76}{16}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{16}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{9}=3[/tex]
Option d is correct.
A film distribution manager calculates that 5% of the films released are flops. If the manager is right, what is the probability that the proportion of flops in a sample of 572 released films would be greater than 6%
Answer:
0.1357 = 13.57% probability that the proportion of flops in a sample of 572 released films would be greater than 6%
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
A film distribution manager calculates that 5% of the films released are flops.
This means that [tex]p = 0.05[/tex]
Sample of 572
This means that [tex]n = 572[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.05[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.05*0.95}{572}} = 0.0091[/tex]
What is the probability that the proportion of flops in a sample of 572 released films would be greater than 6%?
1 subtracted by the p-value of Z when X = 0.06. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.06 - 0.05}{0.0091}[/tex]
[tex]Z = 1.1[/tex]
[tex]Z = 1.1[/tex] has a p-value of 0.8643
1 - 0.8643 = 0.1357
0.1357 = 13.57% probability that the proportion of flops in a sample of 572 released films would be greater than 6%
Carly is the principal at a middle school and wants to know the average IQ of all the female, seventh-grade students. She does not know anything about what the population distribution looks like. She took a simple random sample of 31 seventh-grade girls in her school and found the average IQ score in her sample was 105.8 and the standard deviation was 15. Assume that all conditions are met, construct the 96% Confidence interval for the average IQ score of all seventh-grade girls in the school.
Answer:
The 96% confidence interval for the average IQ score of all seventh-grade girls in the school is (105, 111.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 31 - 1 = 30
96% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 30 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.96}{2} = 0.98[/tex]. So we have T = 2.15
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.15\frac{15}{\sqrt{31}} = 5.8[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 105.8 - 5.8 = 105.
The upper end of the interval is the sample mean added to M. So it is 105.8 + 5.8 = 111.6
The 96% confidence interval for the average IQ score of all seventh-grade girls in the school is (105, 111.6).
Which of the following statements provides the correct freezing and boiling points of water on the Celsius and Fahrenheit temperature scales?
The freezing point of water is 0°C or 32°F while the boiling point of water is 100°C or 212°F.
TemperatureTemperature is the measure of the degree of hotness or coldness of a substance or place. It is usually expressed Fahrenheit and Celsius scale. Temperature indicates the direction of heat flow.
The freezing point of water is 0°C or 32°F while the boiling point of water is 100°C or 212°F.
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What does p(B/A) represent?
Answer:
I believe you're asking about P(B|A).
Step-by-step explanation:
So,
P(B|A) represents the probability of event B occurring after it is assumed that event A has already occurred.
P(B|A) means "Event B given Event A" . In other words, event A has already happened, now what is the chance of event B? P(B|A) is also called the "Conditional Probability" of B given A.
Each side of a square is increasing at a rate of 4 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 25 cm2
Answer:
The area of the square is increasing at a rate of 40 square centimeters per second.
Step-by-step explanation:
The area of the square ([tex]A[/tex]), in square centimeters, is represented by the following function:
[tex]A = l^{2}[/tex] (1)
Where [tex]l[/tex] is the side length, in centimeters.
Then, we derive (1) in time to calculate the rate of change of the area of the square ([tex]\frac{dA}{dt}[/tex]), in square centimeters per second:
[tex]\frac{dA}{dt} = 2\cdot l \cdot \frac{dl}{dt}[/tex]
[tex]\frac{dA}{dt} = 2\cdot \sqrt{A}\cdot \frac{dl}{dt}[/tex] (2)
Where [tex]\frac{dl}{dt}[/tex] is the rate of change of the side length, in centimeters per second.
If we know that [tex]A = 25\,cm^{2}[/tex] and [tex]\frac{dl}{dt} = 4\,\frac{cm}{s}[/tex], then the rate of change of the area of the square is:
[tex]\frac{dA}{dt} = 2\cdot \sqrt{25\,cm^{2}}\cdot \left(4\,\frac{cm}{s} \right)[/tex]
[tex]\frac{dA}{dt} = 40\,\frac{cm^{2}}{s}[/tex]
The area of the square is increasing at a rate of 40 square centimeters per second.
Find the missing number?
Answer:
65 solve theprob
Step-by-step explanation:
sinolove ko po yan paki brainly
PLEASE HELP!!! WILL GIVE BRAINLIEST!!!!!
Step-by-step explanation:
[tex]g(x) = 3^{\frac{x}{2}}[/tex]
For [tex]x = -2[/tex], we get
[tex]g(-2) = 3^{\frac{-2}{2}} = 3^{-1} = \frac{1}{3}[/tex]
Overige
1) IF A = {2,3, 5, 7, 11 OR Write four subdivisions of this set.
2) A set of sub-sets of any set from the figure below.
с
5
25
35
D
15
10
30
20
3) Find out which of the following sets is a subset of which set of figures.
1
с
B
A
1) X = A set of self-contained lines
U
Y- set of all the elements above line AB
Answer:
the answae is D THEN C THE. 1
What is the median of the following set of values? 7, 21, 19, 15, 19, 14, 15, 19
The median of the following set of values is equals to 17.
What are median?Median represents the middle value of the given data when arranged in a particular order. The mean is the average value which can be calculated by dividing the sum of observations by the number of observations
We are given that the median of the following set of values
7, 21, 19, 15, 19, 14, 15, 19
Line them up in order first.
7, 14, 15, 15, 19, 19, 19, 21
Here the middle value are 15 and 19.
The median is 15 and 19. OR 17,
Therefore, 15 + 19 = 34/2 which equals to 17.
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what are the coordinates of the point that is 1/6 of the way from a(14 -1) to b(-4 23)
9514 1404 393
Answer:
(11, 3)
Step-by-step explanation:
That point is ...
P = a + (1/6)(b -a) = (5a +b)/6
P = (5(14, -1) +(-4, 23))/6 = (70-4, -5+23)/6 = (11, 3)
The point of interest is (11, 3).
Answer:
The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)
Step-by-step explanation:
Let's look first at the x coordinates of the two given points: 14 and -4. From 14 to -4 is a decrease of 18. Similarly, from y = -1 to y = 23 is an increase of 24.
Starting at a(14, -1) and adding 1/6 of the change in x, which is -18, we get the new x-coordinate 14 + (1/6)(-18), or 14 - 3, or 11. Similarly, adding 1/6 of the increase in y of 24 yields -1 + 4, or 3.
The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)
