Which statement is true about figures ABCD and A'B'C'D'?
у
5
4
c
3/
D'
B
2
1 2 3 4 5
1
A
-5 -4 -3 -2 -1 0
AS - 1
-2
D
B
с
-41
-31

Answer:

Centre (0,0)

Radius √9 = 3

I've attached a graph if the circle with it

Answered by GAUTHMATH

Answer:

2

Step-by-step explanation:

4(a)+8-a

Combine like terms

4a-a +8

3a+8

Let a = -2

3(-2)+8

-6 +8

2

Answer:

ERROR

Step-by-step explanation:

Answer:i think its if the dots are open they arent closed but if they are filled in its closed same with () and [] if its (x,y) then its not able to be used but if its [x,y] then it is able to be used

Step-by-step explanation:

Answer:

The markup is 81.25%

Step-by-step explanation:

Take the new price and subtract the original price

58 - 32

26

Divide by the original price

26/32

.8125

Change to percent form

81.25%

The markup is 81.25%

Answer:

1.) Jill = 11 yrs & Jack = 14 yrs. | 2.) (x + 4)(x + 3)

Step-by-step explanation:

1.)

Let j = Jill's age.

[tex]j+(j+3)=25\\2j+3=25\\2j=22\\j=11\\\\\\(11)+3=14[/tex]

Therefore, Jill is 11 and Jack is 14.

2.)

[tex]x^2+7x+12\\(x+4)(x+3)[/tex]

Step-by-step explanation:

A

9×h - 2

B

the baseline of the triangle is 2 units less than 9 times the height long.

C

h = 1/3

9×1/3 - 2 = 3 - 2 = 1

Step-by-step explanation:

hope this helps to u......

Answer:

x = 63.9

Step-by-step explanation:

Since this is a right triangle, we can us trig functions

cos theta = adj/ hypotenuse

cos 35 = x/78

78 cos 35 =x

x=63.89385

Rounding to the nearest tenth

x = 63.9

Answer:

=X-2a

= 6- 2× (-7)

= 6 + 14

= 20

✌✌✌✌

Answer: 5sqrt2, 10sqrt2/2

Step-by-step explanation:

The isosceles triangle, or 45-45-90 rule states that the hypotenuse is x × square root of 2.

Divide the hypotenuse, 10, by sqrt 2 to get 5sqrt2

However , if you're looking to keep it in fraction form, you will need to rationalize the denominator. Multiply the numerator and denominator to get the fraction, 10sqrt2/2

Answer:

D 14

Step-by-step explanation:

Let x be the number

2(x-4) = 20

Divide each side by 2

2/2(x-4) = 20/2

x-4 = 10

Add 4 to each side

x-4+4 = 10+4

x = 14

Answer:

The number is 14

Step-by-step explanation:

Let's call this unknown number of x:

2×(x – 4) = 20

2x – 8 = 20

2x = 20 + 8

2x = 28

x = 28/2

x = 14

Answer:

SAS

43ft

Step-by-step explanation:

We know that two sides are equal

PQ = ST and QR = TU and the angle between them is equal Q = T

We can use the SAS (side angle side)

Since the triangles are congruent

PR = SU

6y+5 = 8y

Subtract 6y from each side

6y+5-6y = 8y-6y

5 = 2y

Divide by 2

5/2 = y

2.5 = y

PR = ST = 8y = 8(2.5) =20

The perimeter is 9+14+20 = 43

Answer:

B. =35ft

Step-by-step explanation:

The perimeter of a right angled triangle is a+b+c

which is 9+4+6y+5 =90

collect like terms

9+4+5+6y=90

18 + 6y = 90

6y = 90 - 18

6y= 72

divide both sides by 6

6y/6 = 72/6

y = 12

so therefore, the perimeter of ∆PQR is

9 + 12 + 14

= 35ft

Answer:

x²+ x = 0

x ( x +1 ) = 0

x = -1

x³-25x=0

x ( x² - 25 ) = 0

x² = 25

x = 5

x²=4x

x² - 4x = 0

x ( x- 4 ) = 0

x = 4

4x²-4x=1

4x²-4x - 1 = 0

4 x² - 2x - 2x - 1 = 0

2x ( 2x - 1 ) - 1 ( 2x- 1 ) = 0

2x- 1 ) ² = 0

2x = 1

x = 1/ 2

mark me as brainliest

Answer:-24(x-3) = -24x (-24)(-3)

Step-by-step explanation:

Answer:

eat my hand where the pic

Step-by-step explanation:

yeah

Answer:

Hello,

Step-by-step explanation:

[tex]\dfrac{x^{\frac{5}{6}} }{x^{\frac{1}{6}} } \\\\=x^{\frac{5}{6} -\frac{1}{6} }\\\\=x^{\frac{4}{6} }\\\\=x^{\frac{2}{3} }\\\\=\sqrt[3]{x^2}[/tex]

Hi there!

Look the picture for your answer.

Hope it helps!

Answer:

b

Step-by-step explanation:

cuz u add them all

Because all the angles are congruent (the same), this is an equilateral triangle. All equilateral triangles have congruent angles and congruent sides, so all sides has to be 14.

The unit rate of the car that travels 5 2/5 km in 2 3/4 mins is: 1.96 km/min.

Unit rate can be defined as the ratio of one quantity in comparison to another.

Distance travelled by a car = 5 2/5 km = 5.4 km

Time travelled = 2 3/4 mins = 2.75 mins

Unit rate in km/min = 5.4/2.75

Unit rate in km/min = 1.96 km/min.

Learn more about the unit rate on:

https://brainly.com/question/19493296

#SPJ1

Answer:

210

Step-by-step explanation:

In a normal distribtuion mean=mode=median

so 210=median

Answer:

First, we apply the Distributive property and then we combine like terms,

To combine like terms, we add or subtract.

[tex]-(2x +y) - 2 ( -x - y)[/tex]

[tex]=-2x-y+2x+2y[/tex]

[tex]=(-2x+2x)+(-y+2y)[/tex]

[tex]=0+y[/tex]

[tex]=y[/tex]

OAmalOHopeO

Answer:

y is the simplest result here.

Step-by-step explanation:

Perform the indicated multiplication as a first step towards simplifying this expression:

-2x - y + 2x + 2y

-2x and 2x cancel each other out, leaving 2y - y, or just y

Answer:

cosA = 0.6

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract sin²A from both sides )

cos²A = 1 - sin²A ( take the square root of both sides )

cosA = ± [tex]\sqrt{1-sin^2A[/tex]

Since only the positive value is required , then

cosA = [tex]\sqrt{1-(0.8)^2}[/tex]

         = [tex]\sqrt{1-0.64}[/tex]

         = [tex]\sqrt{0.36}[/tex]

         = 0.6

Answer:

Answer:

Answer:x = 25°

Answer:x = 25°Step-by-step explanation:

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2}

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 2

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2}

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 2

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )x = 25°

A general cosine function (we could also use a sine function) is written as:

y = A*cos(k*x + p) + M

We will find that the function of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

Let's return to the general function:

y = A*cos(k*x + p) + M

A is the amplitude, it defines the distance between the value of a maximum and the value of the minimum, such that A is exactly half of that difference.

Here we can see that the maximum is 0, and the minimum is -4

The differene is: 0 - (-4) = 4

Then:

A = 4/2 = 2

f(x) = 2*cos(k*x + p) + M.

M is the midline, this is, the horizontal line that cuts the graph in two halves. Here we can see that the midline is x = -2, then:

M = -2

f(x) = 2*cos(k*x + p) - 2

p is the phase shift.

In the graph, we can see that f(0) = -3, so we have:

f(0) = 2*cos(0 + p) - 2 = -3

      cos(p) = -1/2

             p = Acos(-1/2) = 2.09

Then we have:

f(x) = 2*cos(k*x + 2.09) - 2

Finally, k is related to the frequency of the function.

We can see that the function does a complete cycle at x = pi

This means that:

f(x) = f(x + pi)

Knowing that the period of a cosine function is 2*pi, then:

k*(x + pi) = k*x + 2*pi

k = 2

Then the equation of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

If you want to learn more, you can read:

https://brainly.com/question/24372261

Answer(s):

[tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2 \\ y = 2cos\:(2x - 1\frac{1}{4}\pi) - 2[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{5}{8}\pi} \hookrightarrow \frac{-1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{5}{8}\pi} \hookrightarrow \frac{1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then by all means, go for it, but be careful and follow what is explained here. Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2sin\:(2x - 1\frac{1}{4}\pi) - 2,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex] which means the C-term will be negative. Now, BEFORE we go any further, we must remember that this particular cosine graph [thank goodness it is a cosine graph we are working with] ALREADY has a horisontal shift and does not have a single crest oscıllαtıng about any endpoint on the y-axis. So, in this case we need to figure out how far the FIRST oscıllαtıng crest is from the origin, and that obviously would be [tex]\displaystyle \frac{5}{8}\pi\:units.[/tex] Though, sinse we want the sine equation of this graph, it must be “negative”; so, by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{5}{8}\pi} = \frac{-1\frac{1}{4}\pi}{2},[/tex] in which the value of C is [tex]\displaystyle -1\frac{1}{4}\pi.[/tex] So, the sine equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [\frac{7}{8}\pi, -2],[/tex] from there to [tex]\displaystyle [-\frac{\pi}{8}, -2],[/tex] they are obviously [tex]\displaystyle \pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**As you can see, this is one of those moments where you will really need to be careful because if you notised, both equations have OPPOCITE horisontal shifts and C-values. Now, the ONLY TIME this occurs is when all crests in a SINUSOIDAL graph cycle half-way in between endpoints. Your best bet is to jot this down for when you see graphs like these in the future.

I am delighted to assist you at any time.

Answer:

right by 3 I think

Step-by-step explanation:

Answer: Right by 3 Units

Step-by-step explanation:

Right on edge 2021

Answer:

surface area of a square = 2 ( lb + bh + hl )

given that,

length = 8cm

breadth = 10cm

height = 15 cm

surface area = 2 ( 8* 10 + 10*15 + 15*8 )

                     = 2 ( 80 + 150 + 120 )

                     = 2 * 350

                     = 700 [tex]cm^{2}[/tex]

hope this answer helps you!!