Which two triangles are congruent by the AAS theorem? Complete the congruence statement.

Answer:

18.33

Step-by-step explanation:

f=-6

-6(x)=8-3(x-21)

-6x=8-3x-63

-6x+3x=8-63

-3x=-55

-3x/-3=-55/-3

x=18.33

hope it helps

The following conditions must be met in order to test hypotheses using proportions: np ≥ 5 and nq ≥ 5

To test hypotheses using proportions, the following requirements are necessary:

np ≥ 5 and nq ≥ 5: It is necessary to have a sufficient number of samples in each group being compared.

The rule of thumb is to have at least 5 observations in each group, where n is the sample size and p is the proportion in that group.

This ensures that the sampling distribution of the proportion is approximately normal, which is necessary for hypothesis testing.

Hence, the correct answer would be an option (A).

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The equation of the regression line is y = 4 + x and the regression analysis of the given data need not be done.

Straight line equation is y = a + bx.

The normal equations are

∑y = a·n + b ∑x ∑ xy = a ∑x + b∑x² Hence the regression analysis of the data :

The values are calculated using the following table

x y x²             x⋅y

58 62 3364 3596

47 51 2209 2397

84 88 7056 7392

62 66 3844 4092

57 61 3249 3477

72 76 5184 5472

69 73 4761 5037

hence :

∑x = 449

∑y = 477

∑x² = 29667

∑x⋅y = 31463

Substituting these values in the normal equations

7a+449b=477

449a+29667b=31463

Solving these two equations using Elimination method,

7a+449b=477

and 449a+29667b=31463

7a+449b=477→(1)

449a+29667b=31463→(2)

equation(1)×449

⇒3143a+201601b=214173

equation(2)×7

⇒3143a+207669b=220241

Substracting

⇒-6068b = -6068

⇒6068b = 6068

⇒b = 1

Putting b = 1 in equation (1), we have

7a+449(1) = 477

⇒7a = 477  - 449

⇒7a = 28 or a  = 4.

Now Estimate y for x=50

y = a + bx , we get

y = 4 + 1×50

y = 4 + 50

y = 54

At x equals 50 we get the value of y as 54 .

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1. This is not wrong at all, but there is a problem. In this case, the target parameter is not mentioned. Average in this case is not the most valid conclusion.

2. Not FALSE as in option #1, but the same problem occurs if the statement does not express a conclusion about the parameter of interest (mean) in this case.

3. This is not the case at all, as the statement refers to possible samples and not confidence levels or parameters of interest. So it's not the best option in this case.

4. true average number of chocolate chips per cookie.

This is the best interpretation, because confidence levels are used to construct the intervals. The most complete answer in this case, as the result is related to the parameter of interest.

Confidence Interval:

A confidence interval is "a range of values ​​that is likely to encompass the values ​​of a population with some degree of confidence. Often expressed as a percentage. The error bar is the range of values ​​above and below the sample statistic in the confidence interval

Normal Distribution:

"A probability distribution that is symmetric about the mean and indicates that data close to the mean are more common than data far from the mean."

X : represents sample mean

μ: population mean (variable of interest)

s : represents sample standard deviation

n : represents sample size

2) The mean confidence interval is given by the formula:

X ± [tex]t_{\alpha /2} \frac{s}{\sqrt{n} }[/tex]                    --------------------------- (1)

The 95% confidence interval obtained in this case is (18.6; 21.3)

Based on this, the statements can be analyzed individually as :

1: We are 95 years old We believe that each cookie from this brand contains approximately 18.6 to 21.3 chocolate chips.

This is not wrong at all, but there is a problem. In this case, the target parameter is not mentioned. Average in this case is not the most valid conclusion.

2: His 95% of cookies are expected to contain 18.6 to 21.3 chocolate his chips.

Not FALSE as in option #1, but the same problem occurs if the statement does not express a conclusion about the parameters of interest in this case.

3: About 95% of all possible sample means from this population are expected to be between 18.6 and 21.3 chocolate chips. This is not the case at all, as you are not referring to some parameter. So it's not the best option in this case.

4: 95% confident that the confidence interval of 18.6 to 21.3 contains the true average number of chocolate chips per cookie.

This is the best interpretation because of the confidence level used to construct the interval. The most complete answer in this case, as the result is related to the parameter of interest.

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By using proportions, it is discovered that 67% of voters who are female and vote for Candidate J to win.

A percentage is a component of a total amount, and the three-step rule is used to relate the measurements.

The percentage of voters who select Candidate J is:

60% of x are voters are female

30% of (1 - x), who vote are male

If the total of these percentages is larger than 50% = 0.5, Candidate J will be elected; therefore:

0.6x + 0.3(1 - x) > 0.5

0.6x + 0.3 - 0.3x > 0.5

0.3x > 0.2

x > 2/3

x > 0.667

x > 67%

By using proportions, it is discovered that 67% of voters who are female and vote for Candidate J to win.

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The value of the following expression x/19 when x=2 is 0.11.

An expression or mathematical expression is a finite arrangement of symbols that are well-formed in line with context-dependent criteria. To help define the logical grammar and order of operations, mathematical symbols can be used to represent variables, operations, functions, brackets, punctuation, and grouping. A sentence qualifies as a mathematical expression if it comprises one or more mathematical operations, at least two numbers, or variables. Mathematicians are proficient in addition, subtraction, multiplication, and division. An expression has the following components: an expression, a number or variable, and a mathematical operator.

Given expression is x/19

When x=2,

Then the value of the given expression is:

x/19=2/19

=0.105

≈0.11

Therefore, The value of the following expression x/19 when x=2 is 0.11.

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The two expressions are not equivalent when x = 3

What is expression ?

A mathematical expression is a phrase that has a minimum of two numbers or variables and at least one mathematical operation. It is possible to multiply, divide, add, or subtract in math.

A mathematical expression is as straightforward as 12 + 2. We might alter the (+) to create many mathematical equations, like 12 - 2, 12*2, and 12/2. Operations include multiplication, division, addition, and subtraction. A mathematical expression can make use of a great number of additional procedures.

when x = 3

8x + 40

8 * 3 + 40

= 24 + 40

= 64

when x = 3

5 (2x + 8)

10x + 40

10 * 3 + 40

= 30 + 40

= 70

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[tex]a_n = 11n + 91[/tex] is the nth term arithmetic progression for the following term.

The difference between any two successive integers in an arithmetic progression (AP) sequence of numbers is always the same amount. It also goes by the name Arithmetic Sequence.

For instance, the sequence 1, 2, 3, 4, 5, 6,... The standard progression in mathematics is a, (a + d), (a + 2d), and (a + 3d).

Given that,

the first five terms given in the table with position.

Denoted as: a₁ = 102, a₂ = 113, a₃ = 124, a₄ = 135, and a₅ = 146

Thus, the nth term for the arithmetic sequence is given as:

[tex]a_n = a_1 + (n-1)d[/tex]

here, d = (113-102) = 11

[tex]a_1 = 102[/tex]

d is the common difference

So, [tex]a_n = 102 + (n-1)11[/tex]

or, [tex]a_n = 102 +11n-11[/tex]

or, [tex]a_n = 11n + 91[/tex]

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Answer: NO

Step-by-step explanation:

This is not a function, since there are multiple outputs for ONE input.

Answer:

no

Step-by-step explanation:

to be a function, the x's can only have one partner. Here, 7 has two partners (7 goes to 20 and also to 18) and the 11 has two partners also. This relation is not a function.

The mean and standard deviation of the sampling distribution include the following: C. mean = 64, standard deviation = 2.5.

In Mathematics and statistics, the Central Limit Theorem states that the sampling distribution of means would always be normally distributed, as long as the sample size is large enough.

This ultimately implies that, the sampling distribution of means would always be normally distributed as the sample size gets larger in accordance with the Central Limit Theorem.

Mathematically, the standard deviation of a sampling distribution can be calculated by using this mathematical expression:

Standard deviation, σy = σ/√n

Where:

Substituting the given parameters into the formula, we have;

Standard deviation, σy = 10/√16

Standard deviation, σy = 10/4

Standard deviation, σy = 2.5.

In conclusion, the mean of an original population is expected to be equal to the mean of the sampling distribution of means i.e 64.

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The p-value for the z-distribution table is 0.4854.

What is  z-distribution?

A unique type of normal distribution with a mean of 0 and a standard deviation of 1 is known as the standard normal distribution, or z-distribution. By transforming the values of any normal distribution into z scores, it is possible to standardise it. Z scores provide the number of standard deviations from the mean that each value falls within.

Given that the z statistic to be 2.19 standard deviation above the population mean.

2.19 can be written as 2.1 + 0.09

Z₂.₁₉ = Z₂.₁₊₀.₀₉ =  0.4854

Therefore p-value is  0.4854.

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A) Yes, X is a binomial random variable because all of the requirements for a binomial distribution have been established

B) The mean and standard deviation are respectively; 1.2 and 0.6

C) The probability given as P(X ≥ 2) is 0.34464

The binomial probability is defined as the probability of exactly x successes on n repeated trials, with p probability.

The general formula of binomial probability distribution is;

P(X = x) = nCr * p^(x) * (1 - p)^(n - x)

where;

p = probability of "success"

n = number of trials, or the sample size

x = the number of "successes" in the probability we are trying to calculate.

A) We are told that 6 friends each buy one 12-ounce bottle of the soda at a local convenience store. Let X = the number who win a prize.

Probability of success; p = 1/5

Number of events; n = 6 which is the random variable being binomial random variable:

There are two types of accomplishments: successes and failures.

Candies are unrelated to one another.

There is a set number of buddies available.

In addition, the chance of success is fixed.

Because all of the requirements for a binomial distribution have been established, then it is a binomial probability distribution.

B) The formula for the mean here is;

μ = np

Plugging in the relevant values gives;

μ = 6(1/5) = 1.2

Formula for the standard deviation is;

σ = √(np(1 - p))

Thus;

σ = √(6 * 1/5)(1 - (1/5)))

σ = 0.6

C) The probability P(X ≥ 2) calculated with online binomial probability calculator gives;

P(X ≥ 2) = 0.34464

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Option a) 90% confidence interval for the population proportion of successes = 0.402

Option b) 90% confidence interval for the population proportion of failures = 0.598

According to the question given,

Critical values of Standard deviations are to be used to construct the proportions for the confidence interval.

The formula of a confidence interval that we will be using for the solution will be,

p = [tex]z_{a} * \sqrt{\frac{p(1-p)}{n} }[/tex]

In the above expression,

p = observed population.

n = sample size

[tex]z_{a}[/tex] = critical value of confidence interval

Now the given observations in question = 115

That result in success = 46

The resultant sample proportion = [tex]\frac{46}{115}[/tex]

⇒ 0.40 and it is for both success and failure

Here we can see that the answer for both parts will be identical.

The critical value of z at 90% confidence = 1.64

a) Lower bound = [tex]0.4 - 1.64 * \sqrt{\frac{0.4(1-0.4)}{90} }[/tex]

⇒ 0.402

b) Upper bound = [tex]0.4 + 1.64 * \sqrt{\frac{0.4(1-0.4)}{90} }[/tex]

⇒ 0.598

Confidence interval = 0.402 to 0.598

Therefore,

Option a) 90% confidence interval for the population proportion of successes = 0.402

Option b) 90% confidence interval for the population proportion of failures = 0.598

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The measures of angles x, y and z are 40°, 50° and 130° and measures of the segments are AY = 16, IY = 9, FG = 30, AP = 24

Centroid is the point in a triangle where all the medians of the triangle intersects.

Given are two triangles, in first we have to find the missing angles and in the second one we need to find the asked segments,

1) We know that, in a right triangle, one angle is 90° and the sum of other two sides is 90°,

Therefore, 40°+y = 90°

y = 50°

x+y = 90°

x = 90°-50°

x = 40°

z = 180°-50° (linear pair)

z = 130°

2) we know that, the centroid divides the medians into 2:1

AY = 2YP

AY = 16

IY = TY/2

IY = 9

FG = GY+YF   (segment addition postulate)

GY = YF/2

GY = 10

FG = 10+20 = 30

PA = AY+YP  (segment addition postulate)

PA = 8+16

PA = 24

Hence. the measures are x, y and z are 40°, 50° and 130° and  AY = 16, IY = 9, FG = 30, AP = 24

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The final answer of the problem is -0.75.

What is the order of operations?

The order of operations is also known as the hierarchy of operations. The order of operations tells us the order in which we should perform mathematical operations in order to get the correct result. The order of operations is usually represented by the acronym PEMDAS:

P: Parentheses first

E: Exponents (ie Powers and Square Roots, etc.)

MD: Multiplication and Division (left-to-right)

AS: Addition and Subtraction (left-to-right)

We have,

-1 - (-0.25)

Using the order of operations, we can solve this problem as follows:

Parentheses: The first step is to perform any calculations inside parentheses. In this case, there are no parentheses, so we can move on to the next step.

Exponents: There are no exponents in this problem, so we can move on to the next step.

Multiplication and Division: There is no multiplication or division in this problem, so we can move on to the next step.

Addition and Subtraction: Finally, we can perform addition and subtraction in the problem. We start from left to right, so we start with the first operation: -1 - (-0.25). To subtract a negative number, we can use the rule that subtracting a negative number is the same as adding a positive number.

Therefore, we have -1 + 0.25.

The final step is to simplify the expression by performing the addition: -1 + 0.25 = -0.75.

Therefore, the final result of the problem is -0.75.

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The height of the pile increasing when the pile is 16 feet high is 5/32 ft/min.

We are given dV/dt=10 cubic ft/min and we want to find dh/dt. Therefore, first we need to write a formula relating v and h.

V=pi*r^2*h/3  since d=h at any moment, we know that r=h/2 at any moment and if we substitute h/2 for r, we get

V=pi(h/2)^2*h/3 and if we simplify this,  we get

V=pi*(h^3)/12

Now we need to take the derivative of both sides with respect to t

dV/dt = pi * ( 3 * h^2 ) */12 * dh/dt

= pi * h^2 / 4 * dh/dt, substitute 40 for dV/dt and 16 for h and solve for dh/dt and we get

40 = pi * 16^2/4*dh/dt

dh/dt = 40 * 4 / ( 256 * pi )

= 40/(256*pi) ft/min,

= 10/64

= 5/32 ft/min

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Function 2 is the one with the fastest rate of change. It changes at a rate of six. Function 1 is the function with the smaller y-intercept. At a y value of 4, its y-intercept is located.

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The average amount of time it takes Bob to get his goods and pay if when he comes in there is one customer named Al with server 1 and no one at server 2 will be 16 minutes.

Let us assume that, T = the total amount of time Bob spends in the hardware store.

Let us assume that, T1 = the amount of time Bob spends waiting in line for Al to get his goods from server 1

Let us assume that, T2 = the amount of time it takes for Bob to get his goods from server 1

Let us assume that, T3 = the amount of time Bob spends waiting in line for Al to pay server 2 for his goods

Let us assume that,  T4 = the amount of time it takes for Bob to pay server 2 for his goods

So, the value of total time T will be

T = T1 + T2 + T3 + T4 and E[T] = E[T1] + E[T2] + E[T3] + E[T4]

Now, E[T1] = 6 min. because of the memoryless property of the exponential distribution

E[T2] = 6 min.

To find E[T3], the condition on the availability of server 2 after Bob is done with server 1

So, the value of E[T3] will be

E[T3] = E[T3 | Server 2 is free] P(​Server 2 is free) + E[T3 | Server 2 is not free] P(​Server 2 is not free)

= 0 + 3 . P(Bob is done with server 1 before AI is done with server 2)

[tex]$$=3 \cdot \frac{1 / 6}{1 / 6+1 / 3}$$[/tex]= 3(1/3) = 1 min. and E[T4] = 3 min.

So, E[T] = E[T1] + E[T2] + E[T3] + E[T4]

or, E[T] = 6+6+1+3= 16 minutes

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The line AC in the figure is the diameter of the circle also it is a chord.

The chord of a circle is a straight path that connects two locations on the circle's circumference. The chord is one of the line segments whose ends are on the perimeter of a circle that can be drawn.

As per the information obtained from the figure,

The line AC in the given diagram is the diameter of the circle, but it is also a chord of the circle because another definition of diameter is as a chord that runs across the center of the circle.

Note the point that every diameter can be said as a chord, but every chord cannot be the diameter of the circle.

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The number of hours it will take the student to complete the project is 5 / 6 hours.

A student completes ⅘ of a math project in ⅔ hour. If the student continues at the same rate,  the time it will take the student to complete the project can be calculated as follows:

Therefore,

let

x = time it will take the student to complete the project

Hence

if 4 / 5 x = 2 / 3 hours

x = ? hours

cross multiply

Therefore,

number of hours to complete the whole math project = x × 2 / 3 ÷ 4 / 5 x

number of hours to complete the whole math project = 2 / 3 x × 5 / 4x

number of hours to complete the whole math project = 10x / 12x

number of hours to complete the whole math project = 10 / 12

number of hours to complete the whole math project = 5 / 6 hours

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Eric typed 15 words more than Dae per minute.

Linear equations are equations whose highest power of the variables is 1. The graph of a linear equation is a straight line. A nonlinear equation is an equation whose highest power of the variables is not 1 and the graph is not a straight line.

To find the amount of words typed in 1 minute for both;

Dae = 333/9

Dae = 27 words per minute

Eric = 252/6

Eric = 42 words per minute

Therefore 42 - 27 = 15 words per minute

Eric typed 15 more words per minute.

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The points that have a distance of 6 units between them are A(-12, 2) and B(-6, 2); B(-6, 2) and C(-6, -4).

The distance between two points P(x₁, y₁) and Q(x₂, y₂) is given by  

Here we have

A (-12, 2) and B(-6, 2)

B (-6, 2) and C(-6, -4)

C (-6, -4) and D(6, 2)

D (6, 2) and E(6, 4)

E (6, 4) and F(-12, 4)  

Here we will find the distance between given points to find the point which has 6 units between them.

As we know Distance = [tex]\sqrt{(x_{2} -x_{1})^{2} +(y_{2} - y_{1})^{2} }[/tex]

For Option A

A (-12, 2) and B(-6, 2)

Distance = √(-6 + 12)² + (2 - 2)²

= √[(6)² + (0)²] = √36 = 6

For Option B

For  B (-6, 2) and C(-6, -4)

Distance = √(-6 - (-6))² + ( - 4 - 2)²

= √[(0)² + (-6)²] = √36 = 6  

For Option C

For C (-6, -4) and D(6, 2)

Distance =√(6 - (-6))² + (2 - (-4))²

= √(12)² + (6)² = √180 = 6√5

For Option D

For D (6, 2) and E(6, 4)

Distance = √(4 - 2)² + ( 6 - 6)²

= √[(2)² + (0)²] = √4 = 2      

For Option E

For E (6, 4) and F(-12, 4)  

Distance = √(-12 - 6)² + (4 - 4)²

= √[(18)² + (0)²] = √18² = 18

Therefore,

The points that have a distance of 6 units between them are A(-12, 2) and B(-6, 2); B(-6, 2) and C(-6, -4).

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Answer:

5x+x=90

Step-by-step explanation:

5 times the other = 5x

the other piece is x

Answer: the small pipe is 15 inches long

Step-by-step explanation: since the larger pipe is 5 times larger than the small pipe, the 90 inch pipe would have too be divided by 6 to make sure the 5 times of the large pipe and the 1 small pipe. so, you would do 90/6=15. so the small pipe is 15 inches long. the large pipe is 75 inches long.

Answer: 36.4

Step-by-step explanation:

Just convert the percentage to decimal and multiply.

70 x 0.52 = 36.4

The 2 3/4 is greater than 1 5/6, hence 1 1/4 × 2 1/5 > 5/6 × 2 1/5

An algebraic inequality is a mathematical statement that uses the inequality sign to connect an expression to a value, a variable, or another expression.

Relationships between two expressions that aren't equal to one another are known as inequalities. Inequalities are represented by the symbols, >,,, and. has the connotation "7 is greater than" (or "is less than 7," when read left to right).

Given the incomplete expression

1 1/4 × 2 1/5 _ 5/6 × 2 1/5

We are to fill it with the necessary inequality sign

For the expression:

1 1/4 × 2 1/5 = 5/4 * 11/5

1 1/4 × 2 1/5 = 55/20

1 1/4 × 2 1/5 = 2 3/4

For the expression 5/6 × 2 1/5

5/6 × 2 1/5 = 5/6 * 11/5

5/6 × 2 1/5 = 55/30

5/6 × 2 1/5 = 1 25/30

Since 2 3/4 is greater than 1 5/6, hence 1 1/4 × 2 1/5 > 5/6 × 2 1/5

The complete question is : Select the correct symbol to compare the expressions below.

1 1/4 × 2 1/5 _ 5/6 × 2 1/5

Symbols: <, >, =

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The independent variable in the following hypothesis: interstate migration in the united states lowers state poverty levels is IV (  Interstate migration ) and DV ( State poverty level ) .

Given :

identify the independent variable in the following hypothesis: interstate migration in the united states lowers state poverty levels.

Independent variable :

An independent variable is exactly what it sounds like. It is a variable that stands alone and isn't changed by the other variables you are trying to measure.

Here in the given statement the independent variable is :

IV = Interstate migration

DV = State poverty level

Unit of Analysis = U.S. states

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The model predicts that the net discharge will be -0.8 + 1.2 cos(24) billions of cubic feet from t = 0 to t = 12.

The net amount of water discharged from the Poudre river from t = 0 to t = 12 can be found using the Fundamental Theorem of Calculus, which states that the net change in a function over an interval is equal to the function evaluated at the endpoints of the interval minus the function evaluated at the beginning of the interval.

In this case, the net discharge from t = 0 to t = 12 can be calculated as follows:

Net discharge = F(12) - F(0)

= (1.5 + 1.2 cos(212)) - (1.5 + 1.2 cos(20))

= 1.5 + 1.2 cos(24) - 1.5 - 1.2

= -0.8 + 1.2 cos(24)

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