Answer:
a. Local user profile.
Explanation:
Local user profile is a type of user profile which is stored in the C:\Users folder and is automatically created when a user logs on to the computer for the first time and it is being stored on the local hard disk of the computer.
Generally, in Microsoft windows any change made to the local user profile is peculiar to the user and the host computer on which the change is made.
Hence, local user profiles avails several users the opportunity of sharing a single computer with their respective user settings and data.
what are the morals and ethics of computer
Answer:
Computer ethics is a part of practical philosophy concerned with how computing professionals should make decisions regarding professional and social conduct. Margaret Anne Pierce, a professor in the Department of Mathematics and Computers at Georgia Southern University has categorized the ethical decisions related to computer technology and usage into three primary influences:
The individual's own personal code.
Any informal code of ethical conduct that exists in the work place.
Exposure to formal codes of ethics.
Explanation:
A machine on a 10 Mbps network is regulated by a token bucket algorithm with a fill rate of 3 Mbps. The bucket is initially filled to capacity at 3MB. How long can the machine transmit at the full 10 Mbps capacity
what are three ways to add receipts to quick books on line receipt capture?
Answer:
1) Forward the receipt by email to a special receipt capture email
2) You can scan, or take a picture of the receipt and upload it using the QuickBooks mobile app.
3) You can also drag and drop the image, or upload it into QuickBooks Online receipt center.
Explanation:
1) Th first process is simply done using the email address
2) On the app, tap the Menu bar with icon ≡. Next, tap Receipt snap., and then
tap on the Receipt Camera. Yo can then snap a photo of your receipt, and tap on 'Use this photo.' Tap on done.
3) This method can be done by simply navigating on the company's website.
Write an INSERT statement that adds this row to the Categories table:
CategoryName: Brass
Code the INSERT statement so SQL Server automatically generates the value for the CategoryID column.
Answer:
INSERT INTO categories (CategoryName)
VALUES ('Brass Code');
Explanation:
The SQL refers to the Structured Query Language in which the data is to be designed and maintained that occurred in the relational database management system i.e it is to be used for maintaining and query the database
Now the INSERT statement should be written as follows
INSERT INTO categories (CategoryName)
VALUES ('Brass Code');
Write a method named coinFlip that accepts as its parameter a string holding a file name, opens that file and reads its contents as a sequence of whitespace-separated tokens. Assume that the input file data represents results of sets of coin flips. A coin flip is either the letter H or T, or the word Heads or Tails, in either upper or lower case, separated by at least one space. You should read the sequence of coin flips and output to the console the number of heads and the percentage of heads in that line, rounded to the nearest whole number. If this percentage is 50% or greater, you should print a "You win!" message; otherwise, print "You lose!". For example, consider the following input file: H T H H T Tails taIlS tAILs TailS heads HEAds hEadS For the input above, your method should produce the following output: 6 heads (50%) You win!
Answer:
Here is the JAVA program:
import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args) throws FileNotFoundException{ //the start of main() function body, it throws an exception that indicates a failed attempt to open the file
Scanner input = new Scanner(new File("file.txt")); //creates a Scanner object and a File object to open and scan through the file.txt
coinFlip(input); } //calls coinFlip method
public static void coinFlip(Scanner input) { //coinFlip method that accepts as its parameter a string input holding a file name
while(input.hasNextLine()) { //iterates through the input file checking if there is another line in the input file
Scanner scan = new Scanner(input.nextLine()); //creates a Scanner object
int head = 0; // stores count of number of heads
int count = 0; //stores count of total number of tokens
while(scan.hasNext()) { //iterates through the sequence checking if there is another sequence in the input file
String token= scan.next(); // checks and returns the next token
if (token.equalsIgnoreCase("H")||token.equalsIgnoreCase("Heads")) { //compares H or Heads with the tokens in file ignoring lower case and upper case differences
head++; } //if a token i.e. any form of heads in file matches with the H or Heads then add 1 to the number of heads
count++; } //increment to 1 to compute total number of counts
double result = Percentage(head, count); //calls Percentage method passing number of heads and total counts to compute the percentage of heads
System.out.println(head + " heads " + "(" + result +"%)"); // prints the number of heads
if(result >= 50.00) { //if the percentage is greater or equal to 50
System.out.println("You win!");} //displays this message if above if condition is true
else //if the percentage is less than 50
{System.out.println("You lose!");} } } //displays this message if above if condition is false
public static double Percentage(int h, int total) { //method to compute the percentage of heads
double p = (double)h/total* 100; // divide number of heads with the total count and multiply the result by 100 to compute percentage
return p; } } //returns result
Explanation:
The program is well explained in the comments mentioned with each line of the above code. I will explain how the method coinFlip works.
Method coinFlip accepts a string holding a file name as its parameter. It opens that file and reads its contents as a sequence of tokens. Then it reads and scans through each token and the if condition statement:
if (token.equalsIgnoreCase("H")||token.equalsIgnoreCase("Heads"))
checks if the each token in the sequence stored in the file is equal to the H or Heads regardless of the case of the token. For example if the first token in the sequence is H then this if condition evaluates to true. Then the head++ statement increments the count of head by 1. After scanning each token in the sequence the variable count is also increased to 1.
If the token of the sequence is HeAds then this if condition evaluates to true because the lower or upper case difference is ignored due to equalsIgnoreCase method. Each time a head is found in the sequence the variable head is incremented to 1.
However if the token in the sequence is Tails then this if condition evaluates to false. Then the value of head variable is not incremented to 1. Next the count variable is incremented to 1 because this variable value is always incremented to 1 each time a token is scanned because count returns the total number of tokens and head returns total number of heads in the tokens.
Percentage method is used to return the percentage of the number of heads in the sequence. It takes head and count as parameters (h and total). Computes the percentage by this formula h/total* 100. If the result of this is greater than or equal to 50 then the message You win is displayed otherwise message You lose! is displayed in output.
(Process scores in a text file) Suppose that a text file contains an unspecified number of scores. Write a program that reads the scores from the file and displays their total and average. Scores are separated by blanks. Your program should prompt the user to enter a filename. Here is a sample run:
Answer:
Here is the Python program:
def scores(file): # method scores that takes a file name as parameter and returns the sum and average of scores in a file
with open(file, 'r') as infile: # open the file in read mode
lines = [score.split() for score in infile] # split the scores into a list
print("The scores are:",lines) #print the scores
for line in lines: # loops through each score
total= sum(int(score) for score in line) # adds the scores
average =total/len(line) # computes average by taking sum of scores and dividing by number of scores in file
print("The sum is:", total) #prints the sum of scores
print("The average is:", "{:.2f}".format(average)) #prints the average
filename = input("Enter name of the file: ") #prompts user to enter name of file
scores(filename) #calls scores method by passing the file name to it in order to compute sum and average of file contents i.e. scores
Explanation:
It is assumed that the scores in the file are separated by a blank space.
The scores() method takes a file name as parameter. Then it opens that input file in read mode using object infile.
split() method is used to split the scores in a file into a list. Suppose the scores are 1 2 3 4 5 6 . So after the split, they become ['1', '2', '3', '4', '5', '6']
The loop iterates through each score in the file, splits them into a list and stores this list in lines. The next print statement prints these scores in a list.
The second loop for line in lines iterates through each score of the list and the statements: total= sum(int(score) for score in line) and average =total/len(line) computes the total and average of scores.
total= sum(int(score) for score in line) statement works as follows:
for loop iterates through each element of list i.e. each score
int() converts that string element into integer.
sum() method adds the integers to compute their total.
So if we have ['1', '2', '3', '4', '5', '6'] each element i.e. 1,2,3,4,5,6 is converted to integer by int() and then added together by sum method. So this becomes 1+2+3+4+5+6 = 21. This result is stored in total. Hence
total = 21.
average = total/len(line) works as follows:
The computed sum of scores stored in total is divided by the number of scores. The number of scores is computed by using len() method which returns the length of the line list. So len() returns 6. Hence
average = total/len(line)
= 21 / 6
average = 3.5
The next two print statement prints the value of sum and average and "{:.2f}".format(average)) prints the value of average up to 2 decimal places.
The screenshot of the program along with its output is attached.
What is the quick key to highlighting a column?
Ctrl + down arrow
Ctrl + Shift + down arrow
Right-click + down arrow
Ctrl + Windows + down arrow
The quick key to highlighting a column is the Ctrl + Shift + down arrow. Thus, option (b) is correct.
What is column?The term column refers to how data is organized vertically from top to bottom. Columns are groups of cells that are arranged vertically and run from top to bottom. A column is a group of cells in a table that are vertically aligned. The column is the used in the excel worksheet.
The quick key for highlighting a column is Ctrl + Shift + down arrow. To select downward, press Ctrl-Shift-Down Arrow. To pick anything, use Ctrl-Shift-Right Arrow, then Ctrl-Shift-Down Arrow. In the Move/Highlight Cells, the was employed. The majority of the time, the excel worksheet was used.
As a result, the quick key to highlighting a column is the Ctrl + Shift + down arrow. Therefore, option (b) is correct.
Learn more about the column, here:
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Answer:
its (B) ctrl+shift+down arrow
hope this helps <3
Explanation:
Develop a CPP program to test is an array conforms heap ordered binary tree. This program read data from cin (console) and gives an error if the last item entered violates the heap condition. Use will enter at most 7 numbers. Example runs and comments (after // ) are below. Your program does not print any comments. An output similar to Exp-3 and Exp-4 is expected.
Exp-1:
Enter a number: 65
Enter a number: 56 // this is first item (root,[1]) in the heap three. it does not violate any other item. So, no // this is third [3] number, should be less than or equal to its root ([1])
Enter a number: 45 // this is fourth number, should be less than or equal to its root ([2])
Enter a number: 61 // this is fifth number, should be less than or equal to its root ([2]). It is not, 61 > 55. The 61 violated the heap.
Exp-2:
Enter a number: 100
Enter a number: 95 1/ 95 < 100, OK
Enter a number: 76 // 76 < 100, OK
Enter a number: 58 // 58 < 95, OK
Enter a number: 66 1/ 66 < 95, OK
Enter a number: 58 // 58 < 76, OK
Enter a number: 66 // 66 < 76, OK
Exp-3:
Enter a number: -15
Enter a number: -5
-5 violated the heap.
Exp-4:
Enter a number: 45
Enter a number: 0
Enter a number: 55
55 violated the heap.
Answer:
Following are the code to this question:
#include<iostream>//import header file
using namespace std;
int main()//defining main method
{
int ar[7];//defining 1_D array that stores value
int i,x=0,l1=1,j; //defining integer variable
for(i=0;i<7;i++)//defining for loop for input value from user ends
{
cout<<"Enter a Number: ";//print message
cin>>ar[i];//input value in array
if(l1<=2 && i>0)//using if block that checks the array values
{
x++;//increment the value of x by 1
}
if(l1>2 && i>0)//using if block that checks the array values
{
l1=l1-2;//using l1 variable that decrases the l1 value by 2
}
j=i-x;//using j variable that holds the index of the root of the subtree
if(i>0 && ar[j]>ar[i])// use if block that checks heap condition
{
l1++; //increment the value of l1 variable
}
if(i>0 && ar[j]<ar[i])// using the if block that violate the heap rule
{
cout<<ar[i]<<" "<<"Violate the heap";//print message with value
break;//using break keyword
}
}
return 0;
}
Output:
1)
Enter a Number: -15
Enter a Number: -5
-5 Violate the heap
2)
Enter a Number: 45
Enter a Number: 0
Enter a Number: 55
55 Violate the heap
Explanation:
In the above-given C++ language code, an array "ar" and other integer variables " i,x,l1, j" is declared, in which "i" variable used in the loop for input values from the user end.In this loop two, if block is defined, that checks the array values and in the first, if the block it will increment the value of x, and in the second if the block, it will decrease the l1 value by 2.In the next step, j variable is used that is the index of the root of the subtree. In the next step, another if block is used, that checks heap condition, that increment the value of l1 variable. In the, if block it violate the heap rule and print its values.Consider the following Stack operations:
push(d), push(h), pop(), push(f), push(s), pop(), pop(), push(m).
Assume the stack is initially empty, what is the sequence of popped values, and what is the final state of the stack? (Identify which end is the top of the stack.)
Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m
What are the constraints for designing small and large files and how these are resolved in different file system
Answer:
space management and buffering speed.
Explanation:
There are different types of file management systems in a computer system, examples of which are NTFS, FAT, WAFL, etc, and are governed by protocols like NFS, TFTP, FTP, etc.
These file systems are used in storages like the hard disk drive, CD and DVD, solid-state drive, etc, to organize or manage the files from boot setup, device drivers to permission-seasoned user files.
Files in storage range from small to large files, for which the schema of the file system must adjust to manage and allocate free space to other files in the future. The file system is also able to index the location of a file for retrieval to a cache memory, making buffering faster.
Consider the following calling sequences and assuming that dynamic scoping is used, what variables are visible during execution of the last function called? Include with each visible variable the name of the function in which it was defined.a. Main calls fun1; fun1 calls fun2; fun2 calls fun3b. Main calls fun1; fun1 calls fun3c. Main calls fun2; fun2 calls fun3; fun3 calls fun1d. Main calls fun3; fun3 calls fun1e. Main calls fun1; fun1 calls fun3; fun3 calls fun2f. Main calls fun3; fun3 calls fun2; fun2 calls fun1void fun1(void);void fun2(void);void fun3(void);void main() {Int a,b,c;…}void fun1(void){Int b,c,d;…}void fun2(void){Int c,d,e;…}void fun3(void){Int d,e,f;…}
Answer:
In dynamic scoping the current block is searched by the compiler and then all calling functions consecutively e.g. if a function a() calls a separately defined function b() then b() does have access to the local variables of a(). The visible variables with the name of the function in which it was defined are given below.
Explanation:
In main() function three integer type variables are declared: a,b,c
In fun1() three int type variables are declared/defined: b,c,d
In fun2() three int type variables are declared/defined: c,d,e
In fun3() three int type variables are declared/defined: d,e,f
a. Main calls fun1; fun1 calls fun2; fun2 calls fun3
Here the main() calls fun1() which calls fun2() and fun2() calls func3() . This means first the func3() executes, then fun2(), then fun1() and last main()
Visible Variable: d, e, f Defined in: fun3
Visible Variable: c Defined in: fun2 (the variables d and e of fun2
are not visible)
Visible Variable: b Defined in: fun1 ( c and d of func1 are hidden)
Visible Variable: a Defined in: main (b,c are hidden)
b. Main calls fun1; fun1 calls fun3
Here the main() calls fun1, fun1 calls fun3. This means the body of fun3 executes first, then of fun1 and then in last, of main()
Visible Variable: d, e, f Defined in: fun3
Visible Variable: b, c Defined in: fun1 (d not visible)
Visible Variable: a Defined in: main ( b and c not visible)
c. Main calls fun2; fun2 calls fun3; fun3 calls fun1
Here the main() calls fun2, fun2 calls fun3 and fun3 calls fun1. This means the body of fun1 executes first, then of fun3, then fun2 and in last, of main()
Visible Variable: b, c, d Defined in: fun1
Visible Variable: e, f Defined in: fun3 ( d not visible)
Visible Variable: a Defined in: main ( b and c not visible)
Here variables c, d and e of fun2 are not visible
d. Main calls fun3; fun3 calls fun1
Here the main() calls fun3, fun3 calls fun1. This means the body of fun1 executes first, then of fun3 and then in last, of main()
Visible Variable: b, c, d Defined in: fun1
Visible Variable: e, f Defined in: fun3 ( d not visible )
Visible Variable: a Defined in: main (b and c not visible)
e. Main calls fun1; fun1 calls fun3; fun3 calls fun2
Here the main() calls fun1, fun1 calls fun3 and fun3 calls fun2. This means the body of fun2 executes first, then of fun3, then of fun1 and then in last, of main()
Visible Variable: c, d, e Defined in: fun2
Visible Variable: f Defined in: fun3 ( d and e not visible)
Visible Variable: b Defined in: fun1 ( c and d not visible)
Visible Variable: a Defined in: main ( b and c not visible)
f. Main calls fun3; fun3 calls fun2; fun2 calls fun1
Here the main() calls fun3, fun3 calls fun2 and fun2 calls fun1. This means the body of fun1 executes first, then of fun2, then of fun3 and then in last, of main()
Visible Variable: b, c, d Defined in: fun1
Visible Variable: e Defined in: fun2
Visible Variable: f Defined in: fun3
Visible Variable: a Defined in: main
what makes''emerging technologies'' happen and what impact will they have on individuals,society,and environment
Answer:
Please refer to the below for answer.
Explanation:
Emerging technology is a term given to the development of new technologies or improvement on existing technologies that are expected to be available in the nearest future.
Examples of emerging technologies includes but not limited to block chain, internet of things, robotics, cognitive science, artificial intelligence (AI) etc.
One of the reasons that makes emerging technology happen is the quest to improving on existing knowledge. People want to further advance their knowledge in terms of coming up with newest technologies that would make task faster and better and also address human issues. For instance, manufacturing companies make use of robotics,design, construction, and machines(robots) that perform simple repetitive tasks which ordinarily should be done by humans.
Other reasons that makes emerging technology happens are economic benefit, consumer demand and human needs, social betterment, the global community and response to social problems.
Impact that emerging technology will have on;
• Individuals. The positive effect of emerging technology is that it will create more free time for individuals in a family. Individuals can now stay connected, capture memories, access information through internet of things.
• Society. Emerging technology will enable people to have access to modern day health care services that would prevent, operate, train and improving medical conditions of people in the society.
• Environment. Before now, there have been global complains on pollution especially on vehicles and emission from industries. However, emerging technology will be addressing this negative impact of pollution from vehicles as cars that are currently being produced does not use petrol which causes pollution.
what makes ''emerging technologies'' happen is the necessity for it, the need for it in the society.
The impact they will have on individuals ,society,and environment is that it will improve areas of life such as communication, Transportation, Agriculture.
What is Emerging technologies?Emerging technologies can be regarded as the technologies in which their development as will as practical applications are not yet realized.
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Cloud computing gives you the ability to expand and reduce resources according to your specific service requirement.
a. True
b. False
Answer:
a. True
Explanation:
Cloud computing can be defined as a type of computing that requires shared computing resources such as cloud storage (data storage), servers, computer power, and software over the internet rather than local servers and hard drives.
Generally, cloud computing offers individuals and businesses a fast, effective and efficient way of providing services.
In Computer science, one of the most essential characteristics or advantages of cloud computing is rapid elasticity.
By rapid elasticity, it simply means that cloud computing gives you the ability to expand and reduce resources according to your specific service requirement because resources such as servers can be used to execute a particular task and after completion, these resources can then be released or reduced.
Some of the examples of cloud computing are Google Slides, Google Drive, Dropbox, OneDrive etc.
