ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
prove triangle ACD and BCE are congruent
Given:
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
To prove:
Triangle ACD and BCE are congruent.
Solution:
In triangle ACD and BCE,
[tex]AC=BC[/tex] (Given)
[tex]AC\cong BC[/tex]
[tex]\angle C\cong m\angle C[/tex] (Common angle)
[tex]CD=CE[/tex] (Given)
[tex]CD\cong CE[/tex]
In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.
[tex]\Delta ACD\cong \Delta BCE[/tex] (SAS congruence postulate)
Hence proved.
Answer:
Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD
Given AB=AC∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)
Given BE=CDThen BE−DE=CD−DE
ORBC=CE......................................(2)
In ΔABD and ΔACE
∠ABD=∠ACE ( From 1)
BC=CE (from 2)
AB=AC ( GIven)
∴ΔABD≅ΔACE
So AD=AE [henceproved]
g(x) = x2 – 2 (a) Identify the parent function f.
Answer:g(x) is flipped and 2 times as steep and shifted left 5
Step-by-step explanation:
Help please match with the words
Answer:
Perpendicular
Skew
Parallel
Step-by-step explanation:
First one : the lines intersect and they form right angles
The second one : they don't intersect and appear on separate planes
The last : they are both sides of a rectangle on the same plane
Answer:
1.) skew
2.) perpendicular
3.)parallel
Step-by-step explanation:
hope that helps:)
Please answer the question in order please.
Answer:
Step-by-step explanation:
WILL GIVE BRAINLIST! PUT THESE NUMBERS ON THE PLOT
Answer:
"fair" srry im only in 8th so im d.u.m
Step-by-step explanation:
What is the 8th term of a(n)=6•3^(n-1)
Answer:
13122
Step-by-step explanation:
a(n) = 6 * 3^(n -1)
a(8) = 6* 3^7
3^7 = 2187
a(8) =6 * 2187
a(8) = 13122
When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4 = C, where C is a constant. Suppose that at a certain instant the volume is 400 cm^3 and the pressure is 80 kPa and is decreasing at a rate of 10 kPa/min. At what rate is the volume increasing at this instant?
Answer:
The volume increases at 35.71cm^3/min
Step-by-step explanation:
Given
[tex]PV^{1.4} = C[/tex]
[tex]V = 400cm^3[/tex]
[tex]P =80kPa[/tex]
[tex]\frac{dP}{dt} =-10kPa/min[/tex]
Required
Rate at which volume increases
[tex]PV^{1.4} = C[/tex] [tex]V = 400cm^3[/tex] [tex]P =80kPa[/tex]
Differentiate: [tex]PV^{1.4} = C[/tex]
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]
By differentiating C, we have:
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]
Rewrite as:
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]
Solve for [tex]\frac{dV}{dt}[/tex]
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]
[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]
Substitute values
[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]
[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]
[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]
[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]
I would appreciate if someone could answer this for a brainlist :)
Answer:
x is 40° because it's same side interior angle
y is 140° because it's a corresponding angle with the 140° angle
z is 40° because it's a corresponding angle with x
Answer:
X=40, Y=140, Z=40 because total sum is 360
If f (x)
6x – 6 , find f (-1)
Answer:
-12
Step-by-step explanation:
f (x)=6x – 6
Let x= -1
f(-1) = 6(-1) -6
= -6-6
= -12
Find the measure of each angle listed below. Enter only numbers without space.
(1) ∠PTQ
(2) ∠QTR
(3) ∠PTS
9514 1404 393
Answer:
∠PTQ = 45°∠QTR = 15°∠PTS = 120°Step-by-step explanation:
Parallelogram PTSR is divided into two equilateral triangles by diagonal RT. All of the acute angles in that quadrilateral are 60°, and the obtuse angles are 120° (2×60° and also the supplement of 60°).
Triangle PTQ is an isosceles right triangle, so its acute angles are 45°.
∠PTQ = 45°
∠QTR = ∠PTR -∠PTQ = 60° -45°
∠QTR = 15°
∠PTS = 120° . . . . . . obtuse angle in PTSR; sum of ∠PTR and ∠RTS
how many matches are needed to form figure number 9 and 17? explain
Answer:
Please find the complete question in the attached file.
Step-by-step explanation:
For point 1:
At this point we make up triangles for the first one makes up by 3 matches figure 2 make up by 5 matches figure 3 makes up by 7 matches.
For point 2:
[tex]4 \ \ 5\ \ 6\ \ 7\ \ 8[/tex] you can try to
[tex]9 \ \ 11\ \ 13 \ \ 15 \ \ 17[/tex] draw to find values
For point 3:
number of matches[tex]= 1+2 \times \ figure\ number\\\\[/tex]
For point 4:
[tex]1+2 \times 9=19 \ \ (use \ law \ of\ (iii)) \\\\1+2 \times 17=35[/tex]
What is the probability of tossing a penny and landing on heads 3 times in a row
Answer:
Suppose you have a fair coin: this means it has a 50% chance of landing heads up and a 50% chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.
Identify the relationship between the graphs of these two equations. y = 5/6x + 5 y = 5/6x - 1
parallel
perpendicular
neither
Answer:
parallel
Step-by-step explanation:
the slope of each line is 5/6 which means the lines are parallel
What should my answer be?
Please help!!! Urgent ….
9514 1404 393
Answer:
ΔWZT ~ ΔWXY
Step-by-step explanation:
Angle XWY and angle ZWT are vertical angles, so congruent.
The sides on either side of those angles are proportional:
WZ/WX = WT/WY
11/22 = 10/20 = 1/2
so, we can claim similarity by the SAS Theorem.
ΔWZT ~ ΔWXY
At a basketball game, a vender sold a combined total of 200 sodas and hot dogs. The number of sodas sold was three times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.
Answer:
50 hot dogs
150 sodas
Step-by-step explanation:
set up a system of equations where 'h' = # hot dogs sold and '3h' = # sodas sold
h + s = 200
s = 3h
h + 3h = 200
4h = 200
h = 50
s = 200-50 or 150
I need help solving for x
Answer:
x = 25
Step-by-step explanation:
Given a line parallel to a side of the triangle and intersecting the other 2 sides then it divides those sides proportionally, that is
[tex]\frac{40}{24}[/tex] = [tex]\frac{x}{15}[/tex] ( cross- multiply )
24x = 600 ( divide both sides by 24 )
x = 25
Write the following expression in standard place-value form.
Answer:
3408
Step-by-step explanation:
The relationship between the actual air temperature x (in degrees Fahrenheit) and the temperature y adjust for wind chill (in degrees Fahrenheit, given a 20 mph wind) is given by the following formula:
y= -22 + 1.4x
Estimate the actual temperature if the temperature adjusted for wind chill is -15 degrees Fahrenheit.
The actual temperature is 5 degrees Fahrenheit if the temperature adjusted for wind chill is -15 degrees Fahrenheit.
What is a linear equation?It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.
If in the linear equation one variable is present then the equation is known as the linear equation in one variable.
We have the relationship between the actual air temperature x (in degrees Fahrenheit) and the temperature y adjust for wind chill (in degrees Fahrenheit, given by 20 mph wind) is given as:
y = -22 + 1.4x
When.
The temperature adjusted for wind chill, y = -15 degrees Fahrenheit
Put this value in the given linear equation, we get:
-15 = -22 + 1.4x
-15 + 22 = 1.4x (add 22 on both sides)
7 = 1.4x
x = 5 degrees Fahrenheit (divide by 1.4 on both sides)
Thus, the actual temperature is 5 degrees Fahrenheit if the temperature adjusted for wind chill is -15 degrees Fahrenheit.
Learn more about the linear equation here:
brainly.com/question/11897796
In ΔTUV, t = 7 inches, u = 9.4 inches and ∠V=18°. Find the area of ΔTUV, to the nearest 10th of a square inch.
Answer:
10 square inches
Step-by-step explanation:
that is the procedure above
Answer:
Area=10.167=10.2
Step-by-step explanation:
Area=1/2ab sin c
area= 1/2(7)(9.4)sin18
area = 10.167=10.2
this is for delta math
The population of a small town in central Florida has shown a linear decline in the years 2001-2012. In 2001 the population was 22200 people. In 2012 it was 13950 people.
A) Write a linear equation expressing the population of the town, P , as a function of t , the number of years since 2001. Include the entire equation as your answer. Answer: _________________
B) If the town is still experiencing a linear decline, what will the population be in 2014?
Answer:
Step-by-step explanation:
First of all, to keep our numbers manageable, we are going to let year 2001 = 0 so year 2012 = 11. The coordinates that result from these years/population numbers are (0, 22200) and (11, 13950). Since this linear, we can plug those 2 coordinate pairs into the slope equation to find the rate at which the population is decreasing in people per year:
[tex]m=\frac{13950-22200}{11-0}=\frac{-8250}{11}=-750\frac{people}{year}[/tex] That means that the town is losing people at the rate of 750 per year. We can use that slop along with one of the coordinate points to write the linear equation representing this situation:
[tex]y-22200=-750(x-0)[/tex] and
y = -750x + 22200. That answers part A.
Now for B we need to find y when x = 13 (remember we let year 2001 = 0, so year 2014 = 13):
y = -750(13) + 22200 so
y = 12450 people in the year 2014
hey can some one help with this plz
9514 1404 393
Answer:
21 September
Step-by-step explanation:
Since Alicia is 12 days older, her birthday was 12 days before October 3rd. If we think of October 3rd as equivalent to September 33rd, then 12 days previous is the 33 -12 = 21st day of September.
Alicia's birthday is September 21st.
Jom!
06 PM
What is the slope of the line that passes through the points (-4, 4) and (-6, 6)?
Write your answer in simplest form.
Answer:
Step-by-step explanation:
On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?
(2, 3)
(–2, 3)
(3, 2)
(3, –2)On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?
(2, 3)
(–2, 3)
(3, 2)
(3, –2)
Answer:
the coordinates of pre - image point H is (3,2)
Answer:
c time for learning
Step-by-step explanation:
Each sample of water has a 30% chance of containing a particular organic pollutant. Assume that the samples are independent with regard to the presence of the pollutant. Find the probability that, in the next 10 samples, two or less contain the pollutant. (Hint: using the tables in Appendix A will be faster than doing it by hand!)
a) 0.678
b) 0.028
c) 0.041
d) 0.383
Answer:
d) 0.383
Step-by-step explanation:
For each sample, there are only two possible outcomes. Either they contain the pollutant, or they do not. The probability of a sample containing the pollutant is independent of any other sample. Thus, the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
30% chance of containing a particular organic pollutant.
This means that [tex]p = 0.3[/tex]
Next 10 samples
This means that [tex]n = 10[/tex]
Probability that two or less contain the pollutant.
This is:
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.028[/tex]
[tex]P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.121[/tex]
[tex]P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.233[/tex]
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.028 + 0.121 + 0.233 = 0.382[/tex]
A little rounding difference, but the correct answer is given by option d.
Which choice shows (40+10)+30 correctly rewritten using the associative property and then correctly simplified?
40 + (10 + 30) = 40 + 40 = 80
40 + 30 + 10 = 70 + 10 = 80
40 + (10 +30) = 50 + 30 =80
(10 +40) + 30 = 50 + 30 =80
I need help anyone please
Answer:
Base: 7
Height:10
BH divided by two so
7 times 10 = 70 divided by two 35
Base: 7 yd
Height: 10 yd
Area: 35 square yd
([tex]A=\frac{h_{b}b }{2}[/tex] = [tex]\frac{10*7}{2}[/tex] = 35)
hope this helps....
why is the mean of the set of data is always greater than it's median?
Answer:
One of the basic tenets of statistics that every student learns in about the second week of intro stats is that in a skewed distribution, the mean is closer to the tail in a skewed distribution. So in a right skewed distribution (the tail points right on the number line), the mean is higher than the median.
Step-by-step explanation:
The distribution is said to be right-skewed. In such a distribution, usually (but not always) the mean is greater than the median, or equivalently, the mean is greater than the mode; in which case the skewness is greater than zero.
The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May it cost her $420 to drive 500 mi and in June it cost her $444 to drive 620 mi. (a) Express the monthly cost C as a function of the distance driven d, assuming that a linear relationship gives a suitable model. C(d)
Answer:
[tex]C(d) = \frac{1}{5}d + 320[/tex]
Step-by-step explanation:
Given
[tex]d \to miles[/tex]
[tex]C \to cost[/tex]
So:
[tex](d_1,C_1) = (500,420)[/tex] --- May
[tex](d_2,C_2) = (620,444)[/tex] --- June
Required
Express as a function
Start by calculating the slope (m)
[tex]m = \frac{\triangle C}{\triangle d}[/tex]
[tex]m = \frac{444-420}{620-500}[/tex]
[tex]m = \frac{24}{120}[/tex]
Simplify
[tex]m = \frac{1}{5}[/tex]
The equation is:
[tex]C(d) = m(d - d_1) +C_1[/tex]
[tex]C(d) = \frac{1}{5}(d - 500) +420[/tex]
[tex]C(d) = \frac{1}{5}d - 100 +420[/tex]
Take LCM
[tex]C(d) = \frac{1}{5}d + 320[/tex]
Can someone help me solv for x?
Answer:
AB=AC
X²+8 =33
X²=33-8
X²=25.
X=√25
X=5