why are metal containers not used for storing acids​

Answers

Answer 1
I’m pretty sure they are, but it depends on which acids. Some acids have a really high or low ph that can burn through items, like our stomach acid. Instead, something with a high melting point would be used.
Answer 2
Answer:

Metal containers are not used for storing acid because most of the time acid reacts with almost every metal and produces salts or oxides which alters the acid characteristics making it useless....


Related Questions

What is the basic difference between exergonic and endergonic reactions? Group of answer choices Exergonic reactions release energy; endergonic reactions absorb it. Exergonic reactions involve ionic bonds; endergonic reactions involve covalent bonds. Exergonic reactions involve the breaking of bonds; endergonic reactions involve the formation of bonds. In exergonic reactions, the reactants have less chemical energy than the products; in endergonic reactions, the opposite is true.

Answers

Answer: the basic difference is Exergonic reactions release energy and an endergonic reactions absorb energy .

HOPE THIS HELPS!!!

What is the balance equation for

_ Ba + _ HNO3 —> _ H2 + _ Ba(NP3)2


_ H3PO4 + _ NaOH —> _ H2O + _ Na3PO4

Answers

1st one

2_2_2

2nd one

3_1_1_3

i looked it up

Which has more mass, 2 kg of steel or 5 kg of feather.

Answers

Answer:

5 kg of feather

Explanation:

Suggest two ways Becky could make tea dissolve more quickly
NO FIlES OR REPORTED

Answers

Answer:

heat mixture/stir

Explanation:

these are factors of dissolving of solvent faster

What are the basic elements of selection of proffesion?describe any two​

Answers

Answer:

overall I think one answer

The mass of a neutron is

Answers

A milimter is the answebti this

An iron block of mass 18 kg is heated from 285 K to 318 K. If 267.3 kJ is required, what is the specific heat of iron?
A. 490.05
B. 158.77
C. 145.80
D. 450.00

Answers

Answer:

D. 450 J/kgK

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where:

Q = amount of heat absorbed/released (J)

m = mass of substance (g)

c = specific heat capacity

∆T = change in temperature (°C)

According to the information provided in this question:

Q = 267.3 kJ = 267300J

m = 18kg

∆T = 318K - 285K = 33K

c = ?

Q = m × c × ∆T

c = Q ÷ m∆T

c = 267300 ÷ 18 × 33

c = 267300 ÷ 594

c = 450 J/kgK

Diamond is an allotrope of :
a. carbon b. sillica
c. phosphorus c. Nitrogen​

Answers

Answer:

carbon

Explanation:

because it is an allotrope of carbon

Answer:

Carbon

Explanation:

its literaly carbon


For a reaction, AH = 176 kJ/mol and A SO = 0.285 kJ/(K•mol). At what
temperatures is this reaction spontaneous?
A. At no temperature
B. T< 50 K
C. T>617 K
D. T< 617 K

Answers

Answer:

C. T>617 K

Explanation:

We are given that

[tex]\Delta H=176KJ/mol[/tex]

[tex]\Delta S=0.285KJ/K\cdot mol[/tex]

We have to find the temperature at which the reaction is spontaneous.

When

[tex]\Delta H>0, \Delta S>0[/tex]

Therefore, the reaction is spontaneous at certain range of temperature.

Option A is not true.

[tex]\Delta G=\Delta H-T\Delta S[/tex]

When [tex]\Delta G[/tex] is negative, then  the reaction is spontaneous.

[tex]\Delta G=176-0.285T[/tex]

When T<50

Suppose T=49 K

[tex]\Delta G=176-49\times 0.285>0[/tex]

Therefore, [tex]\Delta G is positive[/tex].Hence, the  reaction is not spontaneous.

Option B is wrong.

C.T>617K

Suppose T=618 K

[tex]\Delta G=176-0.285\times 618=-0.13<0[/tex]

Therefore, [tex]\Delta G is negative[/tex].Hence, the  reaction is spontaneous.

So, option C is true.

D.T<617 K

Suppose T=616 K

[tex]\Delta G=176-0.285\times 616=0.44>0[/tex]

Therefore, [tex]\Delta G is positive[/tex].Hence, the  reaction is not spontaneous.

So, option D is not true.

If 250 grams of water is to be heated from 24.0°C to 100.0°C to make a cup of tea, how much
heat must be added? The specific heat of water is 4.18 J/g∙C

Answers

Answer:

[tex]\boxed {\boxed {\sf 79,420 \ J}}[/tex]

Explanation:

We are given the mass, a change in temperature, and the specific heat of water. We should use the following formula to solve this problem.

[tex]q=mc\Delta T[/tex]

In this formula, m is the mass, c is the specific heat, and ΔT is the change in temperature.

We know there are 250 grams of water and the specific heat of water is 4.18 J/g · °C.

We are given two temperature, so have to find the change in temperature. This is the difference between the initial temperature and final temperature. The water is heated from 24 °C to 100 °C. Therefore, the initial is 24 and the final is 100.

[tex]\bullet \ \Delta T= T_{final} - T_{initial} \\\bullet \ \Delta T=100 \textdegree C - 24 \textdegree C\\\bullet \Delta T= 76 \textdegree C[/tex]

Now we know all three of the variables and we can substitute them into the formula.

[tex]\bullet \ m= 250 \ g\\ \bullet \ c=4.18 \ J/g \textdegree C \\ \bullet \ \Delta T= 76 \textdegree C[/tex]

[tex]q= (250 \ g)( 4.18 \ J/g * \textdegree C)( 76 \textdegree C)[/tex]

Multiply the first two numbers together. The units of grams will cancel.

[tex]q= (1045 \ J/\textdegree C)(76 \textdegree C)[/tex]

Multiply again. This time, the units of degrees Celsius cancel.

[tex]q= 79420 \ J[/tex]

79, 420 Joules of heat must be added.

This is the chemical formula for calcium phosphate:
Ca3PO42.
Calculate the mass percent of oxygen in calcium phosphate. Round your answer to the nearest percentage

Answers

Answer:

This is the chemical formula for calcium phosphate:

[tex]Ca_3(PO_4)_2[/tex].

Calculate the mass percent of oxygen in calcium phosphate. Round your answer to the nearest percentage

Explanation:

The molar mass of calcium phosphate is: 310.18g/mol.

In one mole of calcium phosphate there are 8 moles of oxygen atoms.

The atomic mass of oxygen in calcium phosphate is: 128.0 g

Hence, the mass % of oxygen in the given compound is:

[tex]mass% of Oxygen =\frac{mass of oxygen}{mass of calcium phosphate}*100\\&=\frac{128.0g}{310.18g} *100\\&=41.3[/tex]

Hence,mass%of oxygen is 41.3.


Wood is made mostly of cellulose and has a chemical formula of C.H.00. Which of the following equations
represents the cellulose combustion reaction?

Answers

Answer:

Option B.

C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O

Explanation:

To know which option is correct, we shall write the balanced equation for the combustion of cellulose. This is illustrated below:

C₆H₁₀O₅ + O₂ —> CO₂ + H₂O

There are 6 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 6 before CO₂ as shown below:

C₆H₁₀O₅ + O₂ —> 6CO₂ + H₂O

There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:

C₆H₁₀O₅ + O₂ —> 6CO₂ + 5H₂O

There are a total of 7 atoms of O on the left side and a total of 17 atoms on the right side. It can be balance by writing 6 before O₂ as shown below:

C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O

Now, the equation is balanced.

Thus, option B gives the correct answer to the question.

The normal boiling point of ethanol is 78.4 oC. Its enthalpy of vaporization is 38.6 kJ/mol. Estimate the vapor pressure of ethanol at 26.3 oC.

Answers

Answer: The vapor pressure of ethanol at [tex]26.3^{o}C[/tex] is 238.3 torr.

Explanation:

Given: [tex]\Delta H_{vap}[/tex] = 38.6 kJ/mol

[tex]T_{1} = 26.3^{o}C = (26.3 + 273) K = 299.3 K[/tex]

[tex]T_{2} = 78.4^{o}C = (78.4 + 273) K = 351.4 K[/tex]

Formula used to calculate the vapor pressure of ethanol is as follows.

[tex]ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\[/tex]

Substitute the values into above formula as follows.

[tex]ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\ \\ln \frac{760 torr}{P_{1}} = \frac{38600 J}{8.314 J/mol K}[\frac{1}{299.3} - \frac{1}{351.4}]\\\frac{760}{P_{1}} = 3.18\\P_{1} = 238.3 torr[/tex]

Thus, we can conclude that the vapor pressure of ethanol at [tex]26.3^{o}C[/tex] is 238.3 torr.

True or false, If an atom is charged negative, it contains more electrons than protons.

Answers

False, it would contain more protons than electrons because of the negative charge

Answer:

True

Explanation:

An atom would carry more protons if positively charged, an equal amount of both protons and electrons if neutral, and more electrons if charged negative.

Which statement about biogeochemical cycles is true?
O A. Plants are a part of the nitrogen and carbon cycles, but not the
water cycle.
O B. Plants are a part of the nitrogen, carbon, and water cycles.
O c. Plants are a part of the water and carbon cycles, but not the
nitrogen cycle.
D. Plants are a part
carbon cycle.
the water and nitrogen cycles, but not the

Answers

Answer: The answer is D:

Answer:

The answer is Option D

Which describes the difference between a claim and a scientific claim?

Claims are based more on truth than scientific claims are.
Anyone can make a claim, but a scientific claim is backed by experimental evidence.
Claims are based on evidence and scientific claims are made by scientists.
Controlled experiments are used in claims, while scientific claims use multiple trials.

Answers

Answer:

B. Anyone can make a claim, but a scientific claim is backed by experimental evidence.

<3 Have a nice day!!

Answer:

the awnser is B i got it right

Explanation:

equator runs east and west all the way around the world,halfway between the south poles called the ______________and north poles called________________.

now na po plss....
then follow me☝​

Answers

Answer:

hanigin ng mga pule natin

Which of the following statements regarding diffusion is false? Group of answer choices Diffusion is a result of the thermal energy of atoms and molecules. Diffusion occurs even after equilibrium is reached and no net change is apparent. Diffusion requires no input of energy into the system. Diffusion occurs when particles spread from areas where they are less concentrated to areas where they are more concentrated.

Answers

Answer: The statement diffusion occurs when particles spread from areas where they are less concentrated to areas where they are more concentrated, is false.

Explanation:

When particles or atoms of a substance are able to move rapidly from one place to another then it is called diffusion.

During diffusion, particles tend to move apart from each other.

For example, spreading of dye molecules into water.

Thus, we can conclude that the statement diffusion occurs when particles spread from areas where they are less concentrated to areas where they are more concentrated, is false.

How to work out the amount of carbon dioxide that is released when fully combusted with 4kg of ethanol?

Answers

Answer:

There is 7642 grams of CO2 released

Explanation:

Step 1: Data given

carbon dioxide = CO2

Molar mass of carbon dioxide = 44.01 g/mol

Mass of ethanol = 4 kg = 4000 grams

Molar mass of ethanol = 46.07 g/mol

Step 2: The reaction

Combustion of ethanol means there is oxygen (O2) added. The products are CO2 and H2O.

C2H5OH + 3O2 → 2CO2 + 3H2O

Step 3: Calculate number of moles of ethanol

Moles ethanol = mass ethanol / molar mass ethanol

Moles ethanol = 4000 grams / 46.07 g/mol

Moles ethanol = 86.82 moles

Step 4: Calculate number of moles CO2

For 1 mol ethanol we need 3 moles to produce 2 moles CO2 and 3 moles H2O

For 86.82 moles of ethanol we'll have 2*86.82 = 173.64 moles CO2

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 173.64 moles * 44.01 g/mol

Mass CO2 = 7642 grams

There is 7642 grams of CO2 released

Which of these will form hydrogen bonds? a. CH2Br2 b. CH3OCH2CH3 c. H2NCH2COOH d. H2SO3 e. CH3CH2OH

Answers

Answer:

Which of these will form hydrogen bonds?

a. CH2Br2

b. CH3OCH2CH3

c. H2NCH2COOH

d. H2SO3

e. CH3CH2OH

Explanation:

A hydrogen bond is the weak electrostatic force of attraction that exists between a covalently bonded hydrogen atom and a highly electronegative atom like N,O, and F.

For example, water has a hydrogen bond between the hydrogen atoms of one molecule and the oxygen atom of another molecule.

Among the given molecules,

a. CH2Br2 does not have a hydrogen bond because it does not have N or O or F.

b. CH3OCH2CH3 does not have a hydrogen bond.

Due to the absence of -OH or -NH or H-F bonds.

c. H2NCH2COOH  shows hydrogen bonding.

d. H2SO3 has hydrogen bonding.

Due to the presence of -OH bond.

e. CH3CH2OH has hydrogen bonding.

Due to the presence of -OH bond.

alguien que me pase una pagina para mirar nopor

Answers

Answer:

no pues nadie te pasa la pagina

¿Qué características distinguen a los coloides de otras mezclas?

Answers

Colloids is the correct answer

Zinc oxide + carbon =

Answers

Answer:

carbondioxe and zinc as solid

Makes carbon monoxide

what is the formulas for Calcium Chloride,Aluminium Sulphate and Sodium hydroxide. *

Answers

Answer:

Explanation:

Why is there a star * behind the question.

CaCl2

Al2(SO4)3

NaOH

2. Find the slope of the line that passes between the points (12,5) and (2,3).
Write your formula for Slope

Answers

m=y2 −y1/x2-x1

Explanation:

3-5/2-12=1/5

plant growth is chemical change or physical change




Answers

Answer:

its a chemical change.

hope it helps.

stay safe healthy and happy...

Answer: it is a chemical change because it involves chemical process

Explanation:

the molar mass of oxygen(O2) is 32g. what is the mass of 1.05*10^25 molecules of O2

Answers

Answer:

3.36×10²⁶ g

Explanation:

Molar mass ( O2) = 32g/mol

mole(O2) = 1.05×10²⁵mol

Mass(O2) = ?

mole(n)= mass(m)/Molar mass(M)

n×M = m

1.05×10²⁵ mol × 32g/mol = mass

mass= 3.36×10²⁶ g

Please can someone answer quickly this do tomorrow morning

Which of the five signs should not be used by themselves?

Precipitate
Temperature change
Color change
Odor
Bubbles

Answers

Answer

Temperature change

Pls corret my answer if its wrong ●~●#CarryOnLearning

A mechanical wave starts when matter is disturbed by a source
of_______ I NEED ANSWER ASAP

Answers

Answer:

i believe energy is your answer here

which of the following pairs are ionic compounds ( Al,Cl),(Na,O),(Al,F)​

Answers

Answer:

This answer I think it is Al,F

Other Questions
. My typing speed isn't as fast as I would like, but this position doesn't require me to use the computer. b. To tell the truth, I become frustrated with lazy coworkers who don't pull their own weight. c. I've worked hard to eliminate every weakness, and I am confident you will find me the perfect employee for this position. d. Some people complain that I'm a workaholic with nearly too much passion for this field. Eric receives a portion of his income from his holdings of interest-bearing U.S. government bonds. The bonds offer a real interest rate of 4.5% per year. The nominal interest rate on the bonds adjusts automatically to account for the inflation rate. The government taxes nominal interest income at a rate of 10%. The following table shows two scenarios: A low-inflation scenario and a high- inflation scenario. Given the real interest rate of 4.5% per year, find the nominal interest rate on Eric's bonds, the after-tax nominal interest rate, and the after-tax real interest rate under each inflation scenario. Inflation Rate Real Interest Nominal Interest After-Tax After-Tax (Percent) Rate Rate Nominal Interest Rate Real Interest (Percent) (Percent) (Percent) (Percent)2.0 4.5 7.0 4.5Compared with higher inflation rates, a lower inflation rate will_________ nominal interest income. This tends to_________ the after-tax real interest rate when the government taxes saving, thereby________ the quantity of investment in the economy and________ the economy's long-run growth rate. Ashley has average technical skills but her real strengths lay in visualizing the benefits of other's ideas and in finding financial and political support for these ideas. Ashley is an excellent example of a(n) _____. Suppose the nominal annual interest rate on a two-year loan is 8 percent and lenders expect inflation to be 5 percent in each of the two years. The annual real rate of interest is Annenbaum Corporation uses the weighted-average method in its process costing system. This month, the beginning inventory in the first processing department consisted of 2,200 units. The costs and percentage completion of these units in beginning inventory were: Cost Percent Complete Materials costs $ 7,500 65% Conversion costs $ 8,600 45% A total of 10,100 units were started and 7,700 units were transferred to the second processing department during the month. The following costs were incurred in the first processing department during the month: Cost Materials costs $ 127,300 Conversion costs $ 208,800 The ending inventory was 50% complete with respect to materials and 35% complete with respect to conversion costs. 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