Step By Step Explanation:
y = - 3/4× + 15/8Step 1Swap sides so that all variable terms are on the left hand side.[tex] - \frac{3}{4} x + \frac{15}{8} = y[/tex]Step 2Subtract [tex]\frac{15}{8}[/tex] from both sides.[tex] - \frac{3}{4} \times = y - \frac{15}{8} [/tex]Step 3Divide both sides of the equation by -[tex]\frac{3}{4}[/tex] which is the same as multiplying both sides by the reciprocal of the fraction.[tex] \frac{ - \frac{3}{4} \times}{- \frac{3}{4} } = \frac{y - \frac{15}{8} }{ - \frac{3}{4} } [/tex]Step 4Dividing by [tex]-\frac{3}{4}[/tex] undoes the multiplication by [tex]-\frac{2}{4}[/tex][tex]x = \frac{y - \frac{15}{8} }{ - \frac{3}{4} } [/tex]Step 5Divide [tex]y-\frac{15}{8}[/tex] by -\frac{3}{4} by multiplying [tex]y-\frac{15}{8}[/tex] by the reciprocal of [tex]-\frac{3}{4}[/tex][tex]\color{Green}x = \frac{ - 4y}{3} + \frac{5}{2} [/tex]If sally completed 6 laps around a circular track with the dimensions shown below, how many meters will she have run? Use 3.14 for up and round your answer to the nearest tenth
Answer/Step-by-step explanation:
The diagram of the circular track is missing, and so also its dimensions.
However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.
Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.
Circumference = πd
d = 20 m (we are assuming the diameter is 20 meters)
π = 3.14
Circumference of circular track = 3.14 × 20 = 62.8 m.
This means that 1 lap = 62.8 m that she would have to run.
Therefore,
6 laps would be = 6 × 62.8 = 376.8 m
Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.
which one of the following is product of(-3n)and(4mn-5n)
John owns shares in a mutual fund and shares of individual stocks in his brokerage account. The Form 1099-DIV from the mutual fund indicates $2,000 of capital gains distributions and the form from the brokerage firm indicates $6,000 of capital gains distributions. The brokerage statement also indicated a long term capital loss of $1,850 on a stock sale. How should John report the capital gains distributions?
Question options:
A. He should report them directly on form 1040
B. He should report them on form 8949 and then on schedule D
C. He should report them on schedule D
D. He is not required to report them until he sells the underlying securities
Answer:
B. He should report them on form 8949 and then on schedule D
Explanation:
John has shares which have capital gains from a mutual fund and a brokerage account. In order to report his taxes, he would need to use the Schedule D(form 1040) for his mutual fund capital gains and the form 8949 for his brokerage capital gains. The brokerage capital gains is then transferred to schedule D.
please help me, i need help quickkk-
x+y-z=2
2x+y+z=1
2x-y+2z=3
i got x=-11
y=18
z=5
but it’s probably wrong- HELP PLS
Answer:
x = 2.2, y = -1.8, z = -1.6
Step-by-step explanation:
Put the coefficients of each variable and their constants into a matrix, as shown below.
1 1 -1 2
2 1 1 1
2 -1 2 3
Now use the rref( function to essentially "solve" the equation for all of its variables. You end up with the following matrix:
1 0 0 2.2
0 1 0 -1.8
0 0 1 -1.6
Remember that the first three columns are the coefficients on our variables, and the last column is the constant on the other side. That means that this matrix is essentially telling us the value of each variable.
x + 0y + 0z = 2.2
0x + y + 0z = -1.8
0x + 0y + z = -1.6
Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?
A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the left.
A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right.
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the left.
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the right.
Answer:
3 < x
Step-by-step explanation:
3(8 – 4x) < 6(x – 5)
Divide each side by 3
3/3(8 – 4x) < 6/3(x – 5)
(8 – 4x) < 2(x – 5)
Distribute
8-4x < 2x-10
Add 4x to each side
8-4x+4x < 2x-10+4x
8 < 6x-10
Add 10 to each side
8+10 < 6x-10+10
18 < 6x
Divide by 6
18/6 < 6x/6
3 < x
The formula for the nth term of a sequence is 3n +7
What is the 6th term in the sequence?
Answer:
6th term = 25
Step-by-step explanation:
3n + 7
3 x (6) + 7
18 + 7 = 25
If this helps you, please mark brainliest!
Have a nice day!
Answer:
[tex]25[/tex]
Step-by-step explanation:
[tex] Tn_{n} = 3n + 7 \\Tn _{6} = 3 n + 7 \\ = 3 \times 6 + 7 \\ = 18 + 7 \\ = 25[/tex]
Hope this helps you
Have a nice day!
pls help in this
7.6x5.2
Answer:
39.52
Step-by-step explanation:
Answer:
Table multiplication:
7.6 times
5.2 =
15.2
38.0
—-
39.52
Circle A has a radius of 4 centimeters.
A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has four identical components, each with a probability of .2 of failing in less than 1000 hours. The subsystem will operate if any two of the four components are operating. Assume that the components operate independently. Find the probability that a exactly two of the four components last longer than 1000 hours. b the subsystem operates longer than 1000 hours.
Answer:
a. 0.1536
b. 0.9728
Step-by-step explanation:
The probability that a component fails, P(Y) = 0.2
The number of components in the system = 4
The number of components required for the subsystem to operate = 2
a. By binomial theorem, we have;
The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) is given as follows;
P(Y = 2) = [tex]\dbinom{4}{2}[/tex] × 0.2² × 0.8² = 0.1536
The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) = 0.1536
b. The probability that the system last longer than 1,000 hours, P(O) = The probability that no component fails + The probability that only one component fails + The probability that two component fails leaving two working
Therefore, we have;
P(O) = P(Y = 0) + P(Y = 1) + P(Y = 2)
P(Y = 0) = [tex]\dbinom{4}{0}[/tex] × 0.2⁰ × 0.8⁴ = 0.4096
P(Y = 1) = [tex]\dbinom{4}{1}[/tex] × 0.2¹ × 0.8³ = 0.4096
P(Y = 2) = [tex]\dbinom{4}{2}[/tex] × 0.2² × 0.8² = 0.1536
∴ P(O) = 0.4096 + 0.4096 + 0.1536 = 0.9728
The probability that the subsystem operates longer than 1,000 hours = 0.9728
a. x ll y
b. y ll z
c. a ll b
d. x perpendicular to b
Answer:
Option B
Step-by-step explanation:
By applying the converse theorem of corresponding angles,
"If corresponding angles formed between two parallel lines and the transversal line are equal then both the lines will be parallel"
Angle between line B and Y = 90°
Angle between line B and Z = 90°
Therefore, corresponding angles are equal.
By applying converse theorem, line Y and line Z will be parallel.
Option B will be the answer.
What is the answer of (x+y÷x-y)÷(y+x÷y-x)
Answer:
[tex]{ \tt{ \frac{( \frac{x + y}{x - y}) }{( \frac{y + x}{y - x}) } }} \\ \\ { \tt{ = \frac{x + y}{x - y} \times \frac{y - x}{y + x} }} \\ \\ { \tt{ = \frac{-(x- y)}{x - y} }}[/tex]
Answer: = -1
Ivan and Tanya share £150 in the ratio 4 : 1
Work out how much more Ivan gets compared to Tanya.
Answer:
Step-by-step explanation:
120 : 30
ivans get £90 more
Can someone help me? Which of the following verifies that triangle YXZ is similar to triangle QPR?
Answer:
a
Step-by-step explanation:
Sarah buys a car for £23,000.
It depreciates at a rate of 3% per year.
How many years will it take to be worth less than £20,000?
Answer:
4.61 years
Step-by-step explanation:
hope it helped!
please find the result !
Answer:
[tex] \displaystyle - \frac{1}{2} [/tex]
Step-by-step explanation:
we would like to compute the following limit:
[tex] \displaystyle \lim _{x \to 0} \left( \frac{1}{ \ln(x + \sqrt{ {x}^{2} + 1} ) } - \frac{1}{ \ln(x + 1) } \right) [/tex]
if we substitute 0 directly we would end up with:
[tex] \displaystyle\frac{1}{0} - \frac{1}{0} [/tex]
which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:
[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]
now notice that after simplifying we ended up with a rational expression in that case to compute the limit we can consider using L'hopital rule which states that
[tex] \rm \displaystyle \lim _{x \to c} \left( \frac{f(x)}{g(x)} \right) = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)} \right) [/tex]
thus apply L'hopital rule which yields:
[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \dfrac{d}{dx} \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]
use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:
[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1} - \frac{1}{ \sqrt{x + 1} } }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2} + 1 } } + \frac{ \ln(x + \sqrt{x ^{2} + 1 } }{x + 1} } \right) [/tex]
simplify which yields:
[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1 } - x - 1 }{ (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]
unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:
[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \sqrt{ {x}^{2} + 1 } - x - 1 }{ \dfrac{d}{dx} (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]
use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:
[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{x}{ \sqrt{ {x}^{2} + 1 } } - 1}{ \ln(x + 1) + 2 + \frac{x \ln(x + \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } } \right) [/tex]
thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:
[tex] \displaystyle \frac{ \frac{0}{ \sqrt{ {0}^{2} + 1 } } - 1}{ \ln(0 + 1) + 2 + \frac{0 \ln(0 + \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } } [/tex]
simplify which yields:
[tex] \displaystyle - \frac{1}{2} [/tex]
finally, we are done!
9514 1404 393
Answer:
-1/2
Step-by-step explanation:
Evaluating the expression directly at x=0 gives ...
[tex]\dfrac{1}{\ln(\sqrt{1})}-\dfrac{1}{\ln(1)}=\dfrac{1}{0}-\dfrac{1}{0}\qquad\text{an indeterminate form}[/tex]
Using the linear approximations of the log and root functions, we can put this in a form that can be evaluated at x=0.
The approximations of interest are ...
[tex]\ln(x+1)\approx x\quad\text{for x near 0}\\\\\sqrt{x+1}\approx \dfrac{x}{2}+1\quad\text{for x near 0}[/tex]
__
Then as x nears zero, the limit we seek is reasonably approximated by the limit ...
[tex]\displaystyle\lim_{x\to0}\left(\dfrac{1}{x+\dfrac{x^2}{2}}-\dfrac{1}{x}\right)=\lim_{x\to0}\left(\dfrac{x-(x+\dfrac{x^2}{2})}{x(x+\dfrac{x^2}{2})}\right)\\\\=\lim_{x\to0}\dfrac{-\dfrac{x^2}{2}}{x^2(1+\dfrac{x}{2})}=\lim_{x\to0}\dfrac{-1}{2+x}=\boxed{-\dfrac{1}{2}}[/tex]
_____
I find a graphing calculator can often give a good clue as to the limit of a function.
Express 5m2 in cm2 please answer fast!
Answer:
500000 cm2
Step-by-step explanation:
The formula sa
SA
6 gives the length of the side, s, of a cube with a surface area, SA. How much longer is the side
of a cube with a surface area of 180 square meters than a cube with the surface area of 120 square meters?
o
30-45 m
O V30-2V5
o 10 m
215 m
Answer:
The correct option is (b).
Step-by-step explanation:
The formula for the side of a cube of surface area SA is as follows :
[tex]s=\sqrt{\dfrac{SA}{6}}[/tex]
When SA = 180 m²
[tex]s=\sqrt{\dfrac{180}{6}}\\\\s=\sqrt{30}[/tex]
When SA = 120 m²
[tex]s=\sqrt{\dfrac{120}{6}}\\\\s=\sqrt{20}\\\\=2\sqrt5[/tex]
Difference,
[tex]=30-2\sqrt5[/tex]
So, the correct option is (b).
please give answer of 6 number
Answer:
[tex]7,500[/tex]
Step-by-step explanation:
Let's solve this problem step-by-step. The library had 1,500 books in 2011. The ratio of books in 2011 and in 2012 is 1:2. Therefore, let the number of books in 2012 be [tex]x[/tex].
We have the following proportion:
[tex]\frac{1}{1,500}=\frac{2}{x},\\x=2\cdot 1,500=3,000[/tex]
Therefore, there were 3,000 books in 2012. The ratio of books in 2012 and in 2013 is 2:5. Let the number of books in 2013 be [tex]y[/tex].
We have:
[tex]\frac{2}{3,000}=\frac{5}{y},\\2y=5\cdot 3,000,\\2y=15,000\\y=\boxed{7,500}[/tex]
Therefore, there were 7,500 books in 2013.
Answer:
7,500 books
Step-by-step explanation:
Write a quadratic equation that has the solutions: 4 and -7
Answer:
y = ( x-4)(x+7)
Step-by-step explanation:
When we know the zeros of the equation, we can write the equation in the form
y= a(x-z1) (x-z2) where a is a constant and z1 and z2 are the zeros (solutions)
y = a( x-4)(x--7)
y =a( x-4)(x+7)
Since its says write an equation, we can pick a and I will let a=1
y = ( x-4)(x+7)
A rectangle has a length that is 8 less than it’s width w the perimeter is 52 which equation can be used to determine length
Answer:
width?
8-W-52
2(w-8) +2w=52
(W-8)+W=52
2(8-W) +2w=52
please help asap!!
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SOLVE URGENT CORRECT ANSWER WILL GET BRAINLIEST
Answer:
8.
a) f'x means you find the derivative.
2 * d/dx x^2 -b * d/dx x + d/dx c
use power rule x^2 = 2x^1
2*2x = 4x. the derivative of the differentiation variable, x is 1 and the derivative of a constant, c is 0
4x-b+0
4x-b is our derivative
(I am still figuring out b and c, I will edit this answer and put the solution for b and c.)
Step-by-step explanation:
Solve for x when y = 4
2x + 2y = 20
Answer:
x=6
Step-by-step explanation:
2x + 2y = 20
Let y=4
2x +2(4) = 20
Multiply
2x+8 = 20
Subtract 8 from each side
2x+8-8= 20-8
2x = 12
Divide by 2
2x/2 = 12/2
x = 6
Answer:
[tex]x=6\\[/tex]
Step-by-step explanation:
[tex]2x+2(4)=20[/tex]
[tex]2x+8=20[/tex]
Subtract both sides by 8
[tex]2x=12[/tex]
Divide both sides by 2 to get x alone
[tex]x=6[/tex]
Hope this is helpful
Describe the graph of the proportional relationship between the two quantities and describe how the unit rate is represented on the graph. Bananas are $2.40 per pound.
a
The graph of y = 24x , which is a line passing through (0, 0) with a slope of 24; the slope 24 is the unit rate of each pound of bananas.
b
The graph of y = 2.4x , which is a line passing through (0, 0) with a slope of 2.4; the slope 2.4 is the unit rate of each pound of bananas.
c
The graph of y = 5.8x , which is a line passing through (0, 0) with a slope of 5.8; the slope 5.8 is the unit rate of each pound of bananas.
d
The graph of y = 2.4 + x , which is a line passing through (0, 0) with a slope of 2.4; the slope -2.4 is the unit rate of each pound of bananas.
Given:
Bananas are $2.40 per pound.
To find:
The graph and unit rate on the graph.
Solution:
Let y be the total cost of x pounds of bananas.
Cost of 1 pound of banana = $2.40
Cost of x pound of bananas = $2.40x
So, the required equation for the given situation is:
[tex]y=2.4x[/tex]
The graph of [tex]y=2.4x[/tex] describes the proportional relationship between the two quantities.
The graph of [tex]y=2.4x[/tex] is a line passing through (0, 0) with a slope of 2.4; the slope 2.4 is the unit rate of each pound of bananas.
Therefore, the correct option is (b).
Answer:
a
Step-by-step explanation:
MAGALI COMPRAR 15 CHOCOLATES A $0,75 CADA UNA , Y 13 PAQUETES DE GALLETAS A $ 1,25 CADA UNO ¿CUANTO DEBBE PAGAR?
Answer:
The total amount paid is $ 27.5.
Step-by-step explanation:
MAGALI BUY 15 CHOCOLATES AT $ 0.75 EACH ONE, AND 13 PACKAGES OF COOKIES AT $ 1.25 EACH, HOW MUCH SHOULD I PAY?
Number of chocolates = 15
Cost of a chocolate = $ 0.75
Packet of cookies = 13
cost of one packet of cookie = $ 1.25
The total amount paid is
= 15 x $ 0.75 + 13 x $ 1.25
= $ 11.25 + $ 16.25
= $ 27.5
A cell phone company offers a contract that costs $14.99 plus $0.06 per minute. Find the total number of minutes used if the bill for October was $20.21.
Answer:
87 minutes
Step-by-step explanation:
Let the total number of minutes = m
Our equation is given as:
$20.21 = $14.99 + 0.06m
20.21 = 14.99 + 0.06m
Collect like terms
0.06m= 20.21 - 14.99
0.06m = 5.22
m = 5.22/0.06
m = 87
Therefore, the total number rod minutes used is 87 minutes
Mary's bicycle tire has a radius of 40 cm. How far has Mary travelled if her tire has made 50 complete rotations?
Answer:
60009=hh
Step-by-step explanation:
Play the four digit 3,5,7,and 9 into the boxes pure in the position that would give the greatest results in the true numbers are multiplied
- 73X95
- 79X53
-97X35
-93X75
- 9 3 x 7 5
Step-by-step explanation:To get the combination that would yield the greatest result if the true number are multiplied,
i. multiply each given combination
73 x 95 = 6935
79 x 53 = 4187
97 x 35 = 3395
93 x 75 = 6975
ii. get the largest result from the results calculated above in (i)
The greatest of the results is 6975, therefore the digits should be placed like so;
9 3
7 5
Devons current financial goals are to reduce his credit card debt start a retirement plan and save for a down payment on a house which smart goal attribute in the table applies to each of devons financial goals
Answer:
timely, timely,measurable
Step-by-step explanation:
Answer:
specific, timely, measurable
Step-by-step explanation:
i took the test on plato
Please help quickly!
Answer:
the answer is 2.8
Step-by-step explanation:
Answer:
[tex]x=4[/tex]
Step-by-step explanation:
Given:
[tex]\frac{3x}{5} -0.5=1.9[/tex]
Add 0.5 to both sides
[tex]\frac{3x}{5} =2.4[/tex]
Multiply 5 from both sides
[tex]3x=12[/tex]
Divide both sides by 3
[tex]x=4[/tex]
Hope this helps
