WILL GIVE BRAINLIEST AND 20 POINTS!
Find the equation of the line which passes through the point (11,8) and is parallel to the given line. Express your answer in slope-intercept form. Simplify your answer.
6x+8y=15

Answer:

500000 cm2

Step-by-step explanation:

Answer:

Option B

Step-by-step explanation:

By applying the converse theorem of corresponding angles,

"If corresponding angles formed between two parallel lines and the transversal line are equal then both the lines will be parallel"

Angle between line B and Y = 90°

Angle between line B and Z = 90°

Therefore, corresponding angles are equal.

By applying converse theorem, line Y and line Z will be parallel.

Option B will be the answer.

Answer:

x = 2.2, y = -1.8, z = -1.6

Step-by-step explanation:

Put the coefficients of each variable and their constants into a matrix, as shown below.

1 1 -1 2

2 1 1 1

2 -1 2 3

Now use the rref( function to essentially "solve" the equation for all of its variables. You end up with the following matrix:

1 0 0 2.2

0 1 0 -1.8

0 0 1 -1.6

Remember that the first three columns are the coefficients on our variables, and the last column is the constant on the other side. That means that this matrix is essentially telling us the value of each variable.

x + 0y + 0z = 2.2

0x + y + 0z = -1.8

0x + 0y + z = -1.6

Answer:

x=6

Step-by-step explanation:

2x + 2y = 20

Let y=4

2x +2(4) = 20

Multiply

2x+8 = 20

Subtract 8 from each side

2x+8-8= 20-8

2x = 12

Divide by  2

2x/2 = 12/2

x = 6

Answer:

[tex]x=6\\[/tex]

Step-by-step explanation:

[tex]2x+2(4)=20[/tex]

[tex]2x+8=20[/tex]

Subtract both sides by 8

[tex]2x=12[/tex]

Divide both sides by 2 to get x alone

[tex]x=6[/tex]

Hope this is helpful

Answer:

[tex] \displaystyle - \frac{1}{2} [/tex]

Step-by-step explanation:

we would like to compute the following limit:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{1}{ \ln(x + \sqrt{ {x}^{2} + 1} ) } - \frac{1}{ \ln(x + 1) } \right) [/tex]

if we substitute 0 directly we would end up with:

[tex] \displaystyle\frac{1}{0} - \frac{1}{0} [/tex]

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

now notice that after simplifying we ended up with a rational expression in that case to compute the limit we can consider using L'hopital rule which states that

[tex] \rm \displaystyle \lim _{x \to c} \left( \frac{f(x)}{g(x)} \right) = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)} \right) [/tex]

thus apply L'hopital rule which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \dfrac{d}{dx} \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1} - \frac{1}{ \sqrt{x + 1} } }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2} + 1 } } + \frac{ \ln(x + \sqrt{x ^{2} + 1 } }{x + 1} } \right) [/tex]

simplify which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1 } - x - 1 }{ (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \sqrt{ {x}^{2} + 1 } - x - 1 }{ \dfrac{d}{dx} (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{x}{ \sqrt{ {x}^{2} + 1 } } - 1}{ \ln(x + 1) + 2 + \frac{x \ln(x + \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } } \right) [/tex]

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

[tex] \displaystyle \frac{ \frac{0}{ \sqrt{ {0}^{2} + 1 } } - 1}{ \ln(0 + 1) + 2 + \frac{0 \ln(0 + \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } } [/tex]

simplify which yields:

[tex] \displaystyle - \frac{1}{2} [/tex]

finally, we are done!

9514 1404 393

Answer:

  -1/2

Step-by-step explanation:

Evaluating the expression directly at x=0 gives ...

  [tex]\dfrac{1}{\ln(\sqrt{1})}-\dfrac{1}{\ln(1)}=\dfrac{1}{0}-\dfrac{1}{0}\qquad\text{an indeterminate form}[/tex]

Using the linear approximations of the log and root functions, we can put this in a form that can be evaluated at x=0.

The approximations of interest are ...

  [tex]\ln(x+1)\approx x\quad\text{for x near 0}\\\\\sqrt{x+1}\approx \dfrac{x}{2}+1\quad\text{for x near 0}[/tex]

__

Then as x nears zero, the limit we seek is reasonably approximated by the limit ...

  [tex]\displaystyle\lim_{x\to0}\left(\dfrac{1}{x+\dfrac{x^2}{2}}-\dfrac{1}{x}\right)=\lim_{x\to0}\left(\dfrac{x-(x+\dfrac{x^2}{2})}{x(x+\dfrac{x^2}{2})}\right)\\\\=\lim_{x\to0}\dfrac{-\dfrac{x^2}{2}}{x^2(1+\dfrac{x}{2})}=\lim_{x\to0}\dfrac{-1}{2+x}=\boxed{-\dfrac{1}{2}}[/tex]

_____

I find a graphing calculator can often give a good clue as to the limit of a function.

Answer:

The total amount paid is $ 27.5.

Step-by-step explanation:

MAGALI BUY 15 CHOCOLATES AT $ 0.75 EACH ONE, AND 13 PACKAGES OF COOKIES AT $ 1.25 EACH, HOW MUCH SHOULD I PAY?

Number of chocolates = 15

Cost of a chocolate = $ 0.75

Packet of cookies = 13

cost of one packet of cookie = $ 1.25

The total amount paid is

= 15 x $ 0.75 + 13 x $ 1.25

= $ 11.25 + $ 16.25

= $ 27.5

Answer:

the answer is 2.8

Step-by-step explanation:

Answer:

[tex]x=4[/tex]

Step-by-step explanation:

Given:

[tex]\frac{3x}{5} -0.5=1.9[/tex]

Add 0.5 to both sides

[tex]\frac{3x}{5} =2.4[/tex]

Multiply 5 from both sides

[tex]3x=12[/tex]

Divide both sides by 3

[tex]x=4[/tex]

Hope this helps

Answer:

a. 0.1536

b. 0.9728

Step-by-step explanation:

The probability that a component fails, P(Y) = 0.2

The number of components in the system = 4

The number of components required for the subsystem to operate = 2

a. By binomial theorem, we have;

The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) is given as follows;

P(Y = 2) = [tex]\dbinom{4}{2}[/tex] × 0.2² × 0.8² = 0.1536

The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) = 0.1536

b. The probability that the system last longer than 1,000 hours, P(O) = The probability that no component fails + The probability that only one component fails + The probability that two component fails leaving two working

Therefore, we have;

P(O) = P(Y = 0) + P(Y = 1) + P(Y = 2)

P(Y = 0) = [tex]\dbinom{4}{0}[/tex] × 0.2⁰ × 0.8⁴ = 0.4096

P(Y = 1) = [tex]\dbinom{4}{1}[/tex] × 0.2¹ × 0.8³ = 0.4096

P(Y = 2) = [tex]\dbinom{4}{2}[/tex] × 0.2² × 0.8² = 0.1536

∴ P(O) = 0.4096 + 0.4096 + 0.1536 = 0.9728

The probability that the subsystem operates longer than 1,000 hours = 0.9728

Answer:

8.

a) f'x means you find the derivative.

2 * d/dx x^2 -b * d/dx x + d/dx c

use power rule x^2 = 2x^1

2*2x = 4x.  the derivative of the differentiation variable, x is 1 and the derivative of a constant, c is 0

4x-b+0

4x-b is our derivative

(I am still figuring out b and c, I will edit this answer and put the solution for b and c.)

Step-by-step explanation:

Answer:

60009=hh

Step-by-step explanation:

Answer:

Step-by-step explanation:

120 : 30

ivans get £90 more

Answer/Step-by-step explanation:

The diagram of the circular track is missing, and so also its dimensions.

However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.

Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.

Circumference = πd

d = 20 m (we are assuming the diameter is 20 meters)

π = 3.14

Circumference of circular track = 3.14 × 20 = 62.8 m.

This means that 1 lap = 62.8 m that she would have to run.

Therefore,

6 laps would be = 6 × 62.8 = 376.8 m

Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.

Answer:

39.52

Step-by-step explanation:

Answer:

Table multiplication:

7.6 times

5.2 =

15.2

38.0

—-

39.52

Answer:

4.61 years

Step-by-step explanation:

hope it helped!

Answer:

[tex]{ \tt{ \frac{( \frac{x + y}{x - y}) }{( \frac{y + x}{y - x}) } }} \\ \\ { \tt{ = \frac{x + y}{x - y} \times \frac{y - x}{y + x} }} \\ \\ { \tt{ = \frac{-(x- y)}{x - y} }}[/tex]

Answer: = -1

Answer:

a

Step-by-step explanation:

Answer:

[tex]7,500[/tex]

Step-by-step explanation:

Let's solve this problem step-by-step. The library had 1,500 books in 2011. The ratio of books in 2011 and in 2012 is 1:2. Therefore, let the number of books in 2012 be [tex]x[/tex].

We have the following proportion:

[tex]\frac{1}{1,500}=\frac{2}{x},\\x=2\cdot 1,500=3,000[/tex]

Therefore, there were 3,000 books in 2012. The ratio of books in 2012 and in 2013 is 2:5. Let the number of books in 2013 be [tex]y[/tex].

We have:

[tex]\frac{2}{3,000}=\frac{5}{y},\\2y=5\cdot 3,000,\\2y=15,000\\y=\boxed{7,500}[/tex]

Therefore, there were 7,500 books in 2013.

Answer:

7,500 books

Step-by-step explanation:

- 9 3 x 7 5

To get the combination that would yield the greatest result if the true number are multiplied,

i. multiply each given combination

73 x 95 = 6935

79 x 53 = 4187

97 x 35 = 3395

93 x 75 = 6975

ii. get the largest result from the results calculated above in (i)

The greatest of the results is 6975, therefore the digits should be placed like so;

9   3

7   5

Answer:

6th term = 25

Step-by-step explanation:

3n + 7

3 x (6) + 7

18 + 7 = 25

If this helps you, please mark brainliest!

Have a nice day!

Answer:

[tex]25[/tex]

Step-by-step explanation:

[tex] Tn_{n} = 3n + 7 \\Tn _{6} = 3 n + 7 \\ = 3 \times 6 + 7 \\ = 18 + 7 \\ = 25[/tex]

Hope this helps you

Have a nice day!

Question options:

A. He should report them directly on form 1040

B. He should report them on form 8949 and then on schedule D

C. He should report them on schedule D

D. He is not required to report them until he sells the underlying securities

Answer:

B. He should report them on form 8949 and then on schedule D

Explanation:

John has shares which have capital gains from a mutual fund and a brokerage account. In order to report his taxes, he would need to use the Schedule D(form 1040) for his mutual fund capital gains and the form 8949 for his brokerage capital gains. The brokerage capital gains is then transferred to schedule D.

Answer:

width?

8-W-52

2(w-8) +2w=52

(W-8)+W=52

2(8-W) +2w=52

Answer:

y = ( x-4)(x+7)

Step-by-step explanation:

When we know the zeros of the equation, we can write the equation in the form

y= a(x-z1) (x-z2)   where a is a constant and z1 and z2 are the zeros (solutions)

y = a( x-4)(x--7)

y =a( x-4)(x+7)

Since its says write an equation, we can pick a and I will let a=1

y = ( x-4)(x+7)

Given:

Bananas are $2.40 per pound.

To find:

The graph and unit rate on the graph.

Solution:

Let y be the total cost of x pounds of bananas.

Cost of 1 pound of banana = $2.40

Cost of x pound of bananas = $2.40x

So, the required equation for the given situation is:

[tex]y=2.4x[/tex]

The graph of [tex]y=2.4x[/tex] describes the proportional relationship between the two quantities.

The graph of [tex]y=2.4x[/tex] is a line passing through (0, 0) with a slope of 2.4; the slope 2.4 is the unit rate of each pound of bananas.

Therefore, the correct option is (b).

Answer:

a

Step-by-step explanation:

Answer:

3 < x

Step-by-step explanation:

3(8 – 4x) < 6(x – 5)

Divide each side by 3

3/3(8 – 4x) < 6/3(x – 5)

(8 – 4x) < 2(x – 5)

Distribute

8-4x < 2x-10

Add 4x to each side

8-4x+4x < 2x-10+4x

8 < 6x-10

Add 10 to each side

8+10 < 6x-10+10

18 < 6x

Divide by 6

18/6 < 6x/6

3 < x

Answer:

87 minutes

Step-by-step explanation:

Let the total number of minutes = m

Our equation is given as:

$20.21 = $14.99 + 0.06m

20.21 = 14.99 + 0.06m

Collect like terms

0.06m= 20.21 - 14.99

0.06m = 5.22

m = 5.22/0.06

m = 87

Therefore, the total number rod minutes used is 87 minutes

Answer:

The correct option is (b).

Step-by-step explanation:

The formula for the side of a cube of surface area SA is as follows :

[tex]s=\sqrt{\dfrac{SA}{6}}[/tex]

When SA = 180 m²

[tex]s=\sqrt{\dfrac{180}{6}}\\\\s=\sqrt{30}[/tex]

When SA = 120 m²

[tex]s=\sqrt{\dfrac{120}{6}}\\\\s=\sqrt{20}\\\\=2\sqrt5[/tex]

Difference,

[tex]=30-2\sqrt5[/tex]

So, the correct option is (b).

Answer:

timely, timely,measurable

Step-by-step explanation:

Answer:

specific, timely, measurable

Step-by-step explanation:

i took the test on plato