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After completing the square the quadratic equation [tex]3x^{2} -12x-15=0[/tex] is equivalent to [tex](x-2)^2=3^2[/tex].

"It is a polynomial equation with degree two."

"It is a method that is used for converting a quadratic expression of the form [tex]ax^2 + bx + c[/tex] to [tex]a(x - h)^2 + k[/tex] "

For given example,

We have been given a quadratic equation.

[tex]3x^{2} -12x-15=0[/tex]

First we divide above quadratic equation by 3,

[tex]x^{2} -4x-5=0\\\\x^2-4x=5[/tex]                             ................(i)

Now for completing the square first find [tex](\frac{-b}{2a} )[/tex]

[tex]\frac{-b}{2a}\\=\frac{-(-4)}{(2)(1)}\\\\ =\frac{4}{2}\\\\ =2[/tex]

Add [tex](\frac{-b}{2a} )^2[/tex] on both the sides of equation (i),

[tex]x^{2} -4x+4=5+4\\\\(x-2)^2=9\\\\(x-2)^2=3^2[/tex]

Therefore, after completing the square the quadratic equation [tex]3x^{2} -12x-15=0[/tex] is equivalent to [tex](x-2)^2=3^2[/tex].

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Step-by-step explanation:

[tex] \frac{2}{4} + 5 \times 36 + 2 \frac{6}{3} [/tex]

[tex] = \frac{1}{2} + 180 + 2 \times \frac{2}{1} [/tex]

[tex] = \frac{1}{2} + 180 + 4[/tex]

[tex] = \frac{1 + 360 + 8}{2} [/tex]

[tex] = \frac{369}{2} [/tex]

[tex] = 184 \frac{1}{2} \: or \: 184.5(ans)[/tex]

Answer:

h²=p²+b²

(7√2)²=x²+x²

(49×2)=2x²

2x²=49ײ

x²=49×2/2

x²=49

x=√49=7

x=7

OAmalOHopeO

Answer:

Step-by-step explanation:

1 are = 100 m²

Assuming the ten squares are congruent, the area of each square is 160/10 = 16 are

16 are × 100 m²/are = 1600 m²

each side is √1600 = 40 m

The length of side of plot is 40 meters.

The total space occupied by a flat (2-D) surface or shape of an object is known as area.

Draw a square on a piece of paper with a pencil. It has two dimensions. The term "area" refers to the area that the shape occupies on the paper.

Now picture your square as being comprised of smaller unit squares. The number of unit squares required to cover a 2-D shape's total surface area is used to calculate its area.

Given the area of 10 square plot is 160 are,

here 1 are = 100 m²

area of 10 square plot = 160 x 100 = 16,000 m²

area of 1 square plot = 16000/10 = 1600 m²

area of square is "a²"

where a is side of square

area = a² = 1600 m²

a = √1600

a = 40 m

Hence the length of side of each plot is 40 meters.

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Answer:

failure to correctly define the problem

Step-by-step explanation:

He changes the menu without identify that the real problem was the service.

Answer:

The addition should be divided by 4 and not 3 since there are 4 meals.

Step-by-step explanation:

Answer:

30.10

Step-by-step explanation:

First find the amount of tax

28 * 7.5%

28 * .075

2.10

Add this to the price of the pants

28+2.10 =30.10

Answer:

12.04

Step-by-step explanation:

Find the number in the hundredth place  4  and look one place to the right for the rounding digit  1 . Round up if this number is greater than or equal to  5  and round down if it is less than  5 .

the answer is: combation

Answer:

f^-1 (x) = x+1

Step-by-step explanation:

f(x) = x-1

y = x-1

Exchange x and y

x = y-1

Solve for y

Add 1 to each side

x+1 = y-1+1

x+1 = y

The inverse is x+1

f^-1 (x) = x+1

Answer:

machine fed copies = 25, hand fed copies = 55

Step-by-step explanation:

let machine fed = x, hand fed = y

0.08x+0.2y = 13 (1)

x+y = 80

x= 80-y (2)

sub (2) into (1)

0.08(80-y)+0.2y=13

6.4-0.08y+0.2y=13

0.12y=6.6

y = 55

sub y=55 into eqn 2

x = 80-55 = 25

Answer:

1/(x^3 + 6x^2 + 12x + 8)

Step-by-step explanation:

The first thing we do is rationalize this expression. (2+x)^-3 is written as

1/(2+x)^3

Then from there we can foil out the denominator. It is easiest to foil (2+x)(2+x) first and then multiply that product by (2+x).

(2+x)(2+x) = 4 + 4x + x^2

(4+4x+x^2)(2+x) = 8+8x+2x^2+4x+4x^2+x^3.

Then we combine like terms and put them in order to get:

x^3 + 6x^2 + 12x + 8

And of course we can't forget that this was raised to the negative third power, so our answer is 1/(x^3 + 6x^2 + 12x + 8)

Answer:

Hello,

Step-by-step explanation:

[tex](a+x)^n=a^n+\left(\begin{array}{c}n\\ 1\end{array}\right)*a^{n-1}*x+\left(\begin{array}{c}n\\ 2\end{array}\right)*a^{n-2}*x^2+\left(\begin{array}{c}n\\ 3\end{array}\right)*a^{n-3}*x^3+\left(\begin{array}{c}n\\ 4\end{array}\right)*a^{n-4}*x^4+...+\left(\begin{array}{c}n\\ n\end{array}\right)*a^{n-n}*x^n[/tex]

[tex]with \\\\\left(\begin{array}{c}n\\ 1\end{array}\right)=n\\\\\left(\begin{array}{c}n\\ 2\end{array}\right)=\dfrac{n(n-1)}{2!} \\\\\left(\begin{array}{c}n\\3 \end{array}\right)=\dfrac{n(n-1)(n-2)}{3!} \\\\...\\[/tex]

[tex]\dfrac{1}{(2+x)^3} =\dfrac{1}{8} +3*\dfrac{x}{4}+3\dfrac{x^2}{2}+x^3\\\\[/tex]

Answer:

$500

Step-by-step explanation:

Intrest = P. A * Intrest Rate * Time

Time = 1 year, Intrest Rate = 9%, P. A. is what we need to find, Intrest is 45

45=x*9/100*1, x=500

Answer:

500

Step-by-step explanation:

I = PRT  where I is the interest, P is the amount invested, R is the rate and T is the time

We want 1 year at 9% to get 45 dollars in interest

45 = P ( .09) (1)

45 = .09P

Divide each side by .09

45/ .09 = P

500 =P

Answer:

0

Step-by-step explanation:

Answer:

Step-by-step explanation:

⅝ - 5/9 = 5/72

Answer:

4y+x-3=0

Step-by-step explanation:

The equation is y=mx+b

1) Use the coordinates from the first point

(-1,1)

1= -m+b

2) Use the coordinates frm the second point

(-5,2) (y=mx+b, use x=-5, y=2)

2=-5m+b

You have the system of equations

1=-m+b (multiply by -1)  -1= m-b

2=-5m+b

Add the first equation (multiplied by -1) and the second one

-1+2= m-b-5m+b

1= -4m

m=-0.25

2=1.25+b

b=0.75

y=-0.25x+0.75

4y= -x+3

4y+x-3=0

Step-by-step explanation:

the graph will be compressed vertically

A quadratic a function has a form of,

[tex]f(x)=ax^2+bx+c,a\neq0[/tex]

The first function has a term [tex]x^3[/tex] which doesn't fit the profile of a quadratic function. The highest exponent on x inside a quadratic function can be 2, but here we have 3 so this is not a quadratic function, but rather a cubic function.

The second function fits the form of a quadratic function perfectly.

The third function is a bit tricky. While technically the third function could be considered quadratic if the leading term would be something like [tex]0x^2[/tex] and we did't even see it written out because multiplying with 0. But when we specified the form of a quadratic function, we strictly said that the number before [tex]x^2[/tex] aka [tex]a[/tex] cannot equal to zero. So the last function is not a quadratic function but rather a linear function.

Hope this helps :)

Step-by-step explanation:

f(x) = 4x² + x - 3

[tex]f(x) = 4x {}^{2} + 3 - 2[/tex]

r3t40 is correct

Answer:

299.88 mi. !!!!!

you just multiple all of them together to get the area!!!

Answer:

3/56

Step-by-step explanation:

Probability is the ratio of the number of possible outcome to the number of total outcome.

Given that two marbles are drawn without replacement from a box with 1 blue, 3 white, 2 green, and 2 red marbles.

The total number of marbles in the box

= 1 + 3 + 2 + 2

= 8 marbles

The probability that the first marble is white and the second marble is blue

= 3/8 * 1/7

= 3/56

Answer:

C

Step-by-step explanation:

r=1+2sin(theta)

r^2=r+2*r*sin(theta)

x^2+y^2=±sqrt(x^2+y^2)+2y

Answer:

3

Step-by-step explanation:

3 - 3/x

----------------

1 - 1/x

Multiply the top and bottom by x

x(3 - 3/x)

----------------

x(1 - 1/x)

3x -3

------------

x-1

Factor the numerator

3(x-1)

-------

x-1

Cancel like terms

3

-----

1

3

Answer:

y = 1/3x - 7/3

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - (-3) / 4 - (-2)

2/6

= 1/3

y = 1/3x + b

-1 = 1/3(4) + b

-1 = 4/3 + b

-7/3 = b

This value is approximate.

=============================================================

Explanation:

To find the perimeter, we simply add up the lengths of the three external sides.

The horizontal side from D to E is 16 units long since |-10-6| = 16. I subtracted the x coordinates of the points and applied absolute value. You could also count out the spaces and you should count 16 spaces from D to E.

Unfortunately, the diagonal lengths aren't as straight forward. We have two options here: The pythagorean theorem, or the distance formula.

I'll go with the distance formula.

Let's find the distance from C to D, aka the length of side CD

[tex]C = (x1,y1) = (-1,-2)\\\\D = (x2,y2) = (-10,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-10))^2 + (-2-0)^2}\\\\d = \sqrt{(-1+10)^2 + (-2-0)^2}\\\\d = \sqrt{(9)^2 + (-2)^2}\\\\d = \sqrt{81 + 4}\\\\d = \sqrt{85}\\\\d \approx 9.2195\\\\[/tex]

Side CD is roughly 9.2195 units long.

Repeat this idea to find the length of CE

[tex]C = (x1,y1) = (-1,-2)\\\\E = (x2,y2) = (6,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-6)^2 + (-2-0)^2}\\\\d = \sqrt{(-7)^2 + (-2)^2}\\\\d = \sqrt{49 + 4}\\\\d = \sqrt{53}\\\\d \approx 7.2801\\\\[/tex]

Side CE is roughly 7.2801 units long

The perimeter of triangle CDE is approximately...

P = DE+CD+CE

P = 16 + 9.2195 + 7.2801

P = 32.4996

This then rounds to 32.5 units. The answer is choice C.

Answer:

8/17

Step-by-step explanation:

The sine of an angle is defined as the opposite side to the reference angle divided by the hypotenuse.

The side opposite the angle is always the side not connected to the reference angle. In this case the opposite side = ZY

The hypotenuse = XZ

Sin(X) = ZY/XZ

Sin(X) = 1634 = 8 / 17

Answer:

-1.87 (B)

865.93 - [968-3.34(30)] = -1.87

ED2021

The average weekly allowance of a 5th grade student as calculated using direct variation with the information provided by Fidelity Investment Vision Magazine is 5.367 dollars per week.

The question given is a direct variation problem:

Let:

• Average weekly allowance = [tex]a[/tex]

• Grade level = [tex]g[/tex]

If Average weekly allowance varies directly as grade level , then , then the direct variation between the variables can be expressed as :

[tex]a = k * g[/tex]

Where ,  [tex]k[/tex] = constant of proportionality

We can obtain the value of k from the given values of a and g

[tex]9.66 = k * 9\\9.66 = 9k\\k = 9.66/9[/tex]

Our equation becomes:

[tex]a = (9.66/9) * g[/tex]

[tex]a = (9.66/9) * 5\\a = 5.367[/tex] (rounded to 3 decimal places)

Hence, using proportional relationship, the average weekly allowance for a 5th grade student is [tex]5.367[/tex] per week

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