Answer:
im litreally poor in maths
Answer:
Explanation:
a. (x +y , 1) = (3 , x -y)
compare the corresponding elements
x + y = 3
x = 3 -y equation(i)
substitute the value of x in equation
1 = x -y
1 = 3 - y -y
1 = 3 - y - y
1 - 3 = -2y
-2 = -2y
-2/-2 = y
1 = y
again substitute the value of x in equation (i)
x = 3 - y
x = 3 - 1
x = 2
b. (x + 5 , 3) = (2 , y - x)
compare the corresponding elements
x + 5 = 2
x = 2 - 5
x = -3
substitute the value of x in equation
3 = y - x
3 = y - (-3)
3 = y + 3
3 - 3 = y
0 = y
c. (y - 2 , x + 1) = (x - 1 , y + 2)
compare the corresponding elements
y - 2 = x - 1
y = x - 1 + 2
y = x +1 equation (i)
substitute the value of y in equation
x + 1 = y + 2
x + 1 = x + 1 + 2
x + 1 = x + 3
x = x + 3 -1
x = x +2
substitute the value of x in equation (i)
y = x + 1
y = x + 2 + 1
y = x + 3