With the information that you gather from the summary tables, test the following (you can use excel when appropriate): Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance. Determine if there is sufficient evidence to conclude the average amount of deaths is equal to 6000 in the United States and territories at the 0.10 level of significance. Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 2500 in the United States and territories at the .05 level of significance. Determine if there is sufficient evidence to conclude the average amount of divorces is less than or equal to 4000 in the United States and territories at the 0.10 level of significance.

Answers

Answer 1

Answer:

Kindly check explanation

Step-by-step explanation:

A.)

H0 : μ = 5000

H0 : μ > 5000

xbar = 6671 ; s = 8185.21 ; n = 52 ; α = 0.05

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (6671 - 5000) ÷ (8185.21/√52)

T = 3.814

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at 3.814; 51 = 0.000185

Pvalue < α ; Reject H0 and conclude that average birth is greater than 5000

B)

H0 : μ = 6000

H0 : μ < 6000

xbar = 4187 ; s = 4386 ; n = 52 ; α = 0.01

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (4187 - 6000) ÷ (4386/√52)

T = - 2.981

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at - 2.981; 51 = 0.0022

Pvalue < α ; Reject H0 and conclude that average death is less than 6000

C.)

H0 : μ < 2500

H0 : μ ≥ 2500

xbar = 2744 ; s = 3134.41 ; n = 52 ; α = 0.05

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (2744 - 2500) ÷ (3134.41/√52)

T = 0.561

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at 0.561; 51 = 0.289

Pvalue > α ; Fail to Reject H0 and conclude that average marriage is not greater Tha or equal to 2500

D.)

H0 : μ = 4000

H0 : μ ≤ 4000

xbar = 1451 ; s = 1217 ; n = 52 ; α = 0.01

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (1451 - 4000) ÷ (1217/√52)

T = - 15.10

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at - 15.10; 51 = 0.000001

Pvalue < α ; Reject H0 and conclude that average divorce is less eqaul to 4000


Related Questions

The sum of two six-digit numbers is a seven-digit number

Answers

Answer

500,000 + 500,000 = 1,000,000

Step-by-step explanation:

Subtract and show work.

Answers

Answer:

[tex]31y^{3} -28y^{2}[/tex]+35y

Step-by-step explanation:

Answer is 31y ³ - 28y ² + 35y

what is the answer to this equation4
5
+ v =
41
20

Answers

Answer:

4075

Step-by-step explanation:

2 triangles are shown. The first triangle has side lengths 35, 20, and 20. The second triangle has side lengths x, 44, 44.
What value of x will make the triangles similar by the SSS similarity theorem?

15.9
59
77
96.8

Answers

Answer:

[tex]x = 77[/tex]

Step-by-step explanation:

Given

[tex]First \to Second[/tex]

[tex]35 \to x[/tex]

[tex]20 \to 44[/tex]

[tex]20 \to 44[/tex]

Required

Find x by SSS

Represent the triangle sides as a ratio

[tex]35 : x = 20 : 44[/tex]

Express as fraction

[tex]\frac{x}{35} = \frac{44}{20}[/tex]

Multiply by 35

[tex]x = \frac{44}{20} * 35[/tex]

[tex]x = \frac{44 * 35}{20}[/tex]

[tex]x = \frac{1540}{20}[/tex]

[tex]x = 77[/tex]

Answer:

ccccccccccccccccccccccccccc

Step-by-step explanation:

Which operation will solve the following word problem? Jaylene bought a blouse for $20.00. The next day she returned the blouse and got 90% of her money back, she was charged a restocking fee of 10%. How much money did she get back?


Division


Addition


Subtraction


Multiplication

Answers

Answer:

division is right i hope you understand

9514 1404 393

Answer:

  Multiplication

Step-by-step explanation:

The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.

Jaylene got back ...

  90% × $20 = $18

Find the size of angle XZY give your answer

Answers

The diagram or the shape

Answer:

yeah u forgot to add the picture ig

A display case of toy rings are marked 5 for $1. If Zach wants to buy 50 toy rings, how much will Zach spend (not including tax)

Answers

Answer:

$10

Step-by-step explanation:

5 toys = $1

Zach wants 50 of these

50 ÷ 5 = 10

10 x 1 = 10

= $10

Answer:

10 dollars

Step-by-step explanation:

We can use a ratio to solve

5 rings     50 rings

----------  = --------------

1 dollar         x dollars

Using cross products

5*x = 1 * 50

5x = 50

Divide by 5

5x/5 = 50/5

x = 10

Prove that the square of an odd number is always 1 more than a multiple of 4

Answers

Answer:

By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.

Step-by-step explanation:

For examples,

Let's consider squares of 3, 11, 25, 37 and 131.

[tex] {3}^{2} = 9[/tex]

8 is a multiple of 4, and 9 is more than 8.

[tex] {11}^{2} = 121[/tex]

120 is a multiple of 4 and 121 is one more than it.

[tex] {25}^{2} = 625[/tex]

624 is a multiple of 4 and 625 is one more than it.

[tex] {37}^{2} = 1369[/tex]

1368 is a multiple of 4 and 1369 is one more than 1368.

[tex] {131}^{2} = 17161[/tex]

17160 is a multiple of 4.

Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.5 customers arrive each hour. One design consultant is available to answer customer questions and make product recommendations. The consultant averages 10 minutes with each customer. Compute the operating characteristics of the customer waiting line, assuming Poisson arrivals and exponential service times. Round your answers to four decimal places. Do not round intermediate calculations.

Answers

Answer:

the operating characteristics have been solved below

Step-by-step explanation:

we have an average of 10 minutes per customers

μ = mean service rate = 60/10 = 6 customers in one hr

the average number of customers that are waiting in line

mean arrival λ = 2.5

μ = 6

[tex]Lq = \frac{2.5^{2} }{6(6-2.5)} \\[/tex]

= 6.25/21

= 0.2976

we calculate the average number of customers that are in the system

[tex]L=Lq+\frac{2.5}{6}[/tex]

= 0.2976+0.4167

= 0.7143

we find the average time that a customer spends in waiting

[tex]Wq=\frac{0.2976}{2.5}[/tex]

= 0.1190 hours

when converted to minutes = 0.1190*60 = 7.1424 minutes

[tex]0.1190+\frac{1}{6}[/tex]

=0.2857

probability that arriving customers would wait for the service

= 2.5÷6 = 0.4167

number of bald eagles in a country a discrete random​ variable, a continuous random​ variable, or not a random​ variable?

Answers

Answer:

Discrete random variable.

Step-by-step explanation:

Discrete variable:

Countable numbers(0,1,2,3,...)

Continuous variable:

Can assume decimal values, such as 0.5, 2.5,...

Number of bald eagles:

Number of bald eagles is a countable value, either there a 0, 100, 1000,... so it is a discrete random variable.

Answer:

Discrete random variable.

Step-by-step explanation:

help with this question pleaseee !

Answers

Answer:

Add equations A and C to eliminate y and add B and C to eliminate y

Step-by-step explanation:

From the equation given, we can see that the coefficient of y in A and C are alternating values 5 and  -5 which cancels out on adding same for B and C. Hence t eliminate y, we will add B and C and A and C

Therefore the correct answer will be to eliminate add equations A and C to eliminate y and add B and C to eliminate y

a. The first five terms of n^2 + 5 are


Answers

Given:

The nth term of a sequence is:

[tex]n^2+5[/tex]

To find:

The first five terms of the given sequence.

Solution:

The given sequence is:

[tex]a_n=n^2+5[/tex]

For n=1,

[tex]a_1=1^2+5[/tex]

[tex]a_1=1+5[/tex]

[tex]a_1=6[/tex]

For n=2,

[tex]a_2=2^2+5[/tex]

[tex]a_2=4+5[/tex]

[tex]a_2=9[/tex]

For n=3,

[tex]a_3=3^2+5[/tex]

[tex]a_3=9+5[/tex]

[tex]a_3=14[/tex]

For n=4,

[tex]a_4=4^2+5[/tex]

[tex]a_4=16+5[/tex]

[tex]a_4=21[/tex]

For n=5,

[tex]a_5=5^2+5[/tex]

[tex]a_5=25+5[/tex]

[tex]a_5=30[/tex]

Therefore, the first five terms of the given sequence are 6, 9, 14, 21, 30.

the mean of 5 numbers is 198. the numbers are in ratio 1:2:3:4:5 find the smallest number​

Answers

Answer:  13.2

In fraction form, this is 66/5

=============================================================

Explanation:

The five values are in the ratio 1:2:3:4:5 which scales up to 1x:2x:3x:4x:5x for some positive number x.

Add up the pieces of the second ratio and set that sum equal to 198. Then solve for x.

1x+2x+3x+4x+5x = 198

15x = 198

x = 198/15

x = 66/5

x = 13.2 is the smallest number since 1x = 1*13.2 = 13.2 was the smallest value of the ratio 1x:2x:3x:4x:5x.

Please help me.I tryed to solve

Answers

Answer:

[tex]x \ge 1[/tex]

Step-by-step explanation:

Given

The number line

Required

Interpret

On the number, we have the following observations;

(1) The thick line starts from 1

(2) The line points to the right; this means greater than or/equals to

(3) The dot on 1 is a closed circle; this means greater than or equal to

So, the inequality is:

x greater than or equal to 1

i.e.

[tex]x \ge 1[/tex]

In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC?

Answers

Answer:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

Step-by-step explanation:

Given

[tex]\triangle ABD \cong \triangle CBD[/tex]

Required

The congruent segments by CPCTC

From the question, we have:

[tex]\angle ADB \cong \angle CDB[/tex] --- given

[tex]\angle DBA \cong \angle DBC[/tex] --- given

Both triangles share a common side (length BD);

So, we have:

[tex]BD = BD[/tex]

Hence, the congruent segments are:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

Instructions: Solve the following linear
equation
4(n + 5) – 2(5 + 7n) = -70
n =

Answers

Answer:

Step-by-step explanation:

4*(n +5) - 2*(5 + 7n) = -70

4*n + 4*5 + 5*(-2) + 7n*(-2) = -70

4n + 20 - 10 - 14n = -70

4n - 14n + 20 - 10 = -70

- 10n + 10 = -70

Subtract 10 from both sides

-10n = -70 - 10

-10n = -80

Divide both sides by (-10)

n = -80/-10

n = 8

Step-by-step explanation:

sjbsbsbeekejebebheebebejekek

A circle has a circumference of 2cm. Which statement about the circumference and area is true?
A comparison of the area and circumference is not possible since the area cannot be determinec
The numerical values of the circumference and area of the circle are equal.
The numerical value of the circumference is greater than the numerical value of the area.
The numerical value of the circumference is less than the numerical value of the area.
ОО

Answers

Answer:

The numerical values of the circumference and area of the circle are equal.

PLEASE I NEED HELP!!!!!



Find the volume of this sphere.
Use 3 for TT.
L-r=3ft
V [?]ft3
V = Tr3

Answers

Answer:

113.1 =VOLUME , 4/3 X 3.14 (3) ^3 = 113.1

Omgg please help right now

Answers

Answer:

64in^3

Step-by-step explanation:

6×3 = 18

18×2 = 36

4×7 = 28

36+28 = 64

Hope this helps! :)


12
х
8
6
Find the value of x.
A) 9
B) 16
C) 14
D) 10

Answers

Answer:

The answer is 10, hope this helps!

Step-by-step explanation:

Find the probability that when a couple has ​children, at least one of them is a . ​(Assume that boys and girls are equally​ likely.)

Answers

Answer:

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Step-by-step explanation:

Given

[tex]n = 3[/tex]

[tex]B \to boys[/tex]

[tex]G \to girls[/tex]

[tex]P(G) = P(B) = 0.5[/tex] --- equal probability

See comment for complete question

Required:

[tex]P(At\ least\ one\ girl)[/tex]

To do this, we make use of complement rule:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

The event that there is no girl out of the 3 children is: B B B

And the probability is:

[tex]P(No\ Girl) = P(B) * P(B) * P(B)[/tex]

[tex]P(No\ Girl) = 0.5*0.5*0.5[/tex]

[tex]P(No\ Girl) = 0.125[/tex]

So:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

[tex]P(At\ least\ one\ girl) = 1 - 0.125[/tex]

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Use the expression 9(7 + 2x) to answer the following:

Part A: Describe the two factors in this expression. (4 points)

Part B: How many terms are in each factor of this expression? (4 points)

Part C: What is the coefficient of the variable term? (2 points)

Answers

Step-by-step explanation:

Part A:

The two factors in 9(7+2x) are 9 and 7+2x

Part B:

First term: 9

Second term: 7+2x

Part C:

9(7+2x)

Open bracket

63+18x

The coefficient is 18x

A. The two factors are 9 and (7+2x).

B. In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.

C. The coefficient of the variable term is 18.

Algebraic expression:

Given expression is;

                         [tex]9(7+2x)[/tex]

In given expression, there are two factors fist is 9 and second one is [tex](7+2x)[/tex]

In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.

To find the coefficient of variable term, we have to to expand given expression.

             [tex]9(7+2x)=63+18x[/tex]

The coefficient of the variable term is 18.

Learn more about the algebraic expression:

https://brainly.com/question/4344214

What is the probability that something with a 2.18% chance of occurring happens 3 times out of 194 events

Answers

Answer:

0.18431525 = 18.4%

Step-by-step explanation:

General Formula :

total trials Cn⋅p(success)^n⋅p(fail)^total−n

1198144* (.0218)^3 * (1-.0218)^191

simplify 6 x + 3y /3​

Answers

Answer:

6x + y

Step-by-step explanation:

6x + 3y/3​

6x + y

Answer:

6x + y

Step-by-step explanation:

6x + 3y / 3

cancel 3y by 3

6x + y

Geometry Oddsseseyware

Answers

Geometry Oddsseseyware

Factorize 5b2-11b+6=0​

Answers

Answer:

5b^2-(5+6)b+6=0

5b^2-5b-6b+6=0

5b(b-1)-6(b-1)=0

(5b-6)(b-1)=0

either

(5b-1)=0

5b=1

b=1/5

or

b-1=0

b=1

Step-by-step explanation:

firstly find out the mid term factor i e in above qn 11 should be break down so that its multiple should be coefficient of b and constant and additiqn should be equals to 11 .so we find out 5 and 6

Find the volume of the composite solid. Round your answer to the nearest hundredth. A. 22.5mm^3 B. 22.19mm^3 C. 22.53mm^3 D. 22.54mm^3

Answers

I think that it would have to be A if I did it right

What is the value of y?

Answers

Answer:

y=0

Step-by-step explanation:

1. Make variable y as subject for the first equation, which is y= -2x +10

2. substitute the first eq to the second one

3. x - (-2x+10) -5=0

4. solve x, which x = 5

5. substitute in eq 1 which is y= -2x +10

6. solve the eq, the possible solution is y=0

40 points! Need help finding.

Answers

The cordent plan of the answer is 2

Answer:

The scale factor will just be 2

Step-by-step explanation:

The length of PQ is twice as larger than the length of AB.

so from 12 to 6 or 6 to 12, we multiply 6 by 2 which equals to 12

A town has a current population of 4,000. The population increased 4 percent per year for the past four years, Emergency response professionals
make up 3 percent of the town's population.
Part A
Write a function that represents the population (p) of the town in terms of the number of years (1) for the last four years.

Answers

Answer:

p=c(1+r)^t so the population will be 4679.43424 or rounded to 4679

Step-by-step explanation:

p=c(1+r)^t

p=4,000(1+.04)^t

p=4,000(1.04)^t

p=4,000(1.04)^4

p=4679.43424

p= the population you are solving for

c= the initial amount of the population

(1+r)= the rate of change

t= the period of time

The exponential equation that represents the population of the town in terms of the number of years : [tex]p=4000 (1+0.4)^{t}[/tex]

What is an exponential equation?

An exponential equation is an equation with exponents where the exponent (or) a part of the exponent is a variable.

It is similar to the amount received after investing a certain amount compounded annually.

Given,

Initial population = 4000

Rate of increase = 4%

Let current population be p.

Let number of years passed be t.

The exponential equation will be: [tex]p=4000 (1+0.4)^{t}[/tex]

(The population of the town has grown exponentially. This means that:

Initial population = 4000

Population in year I = 4000 + 4% of 4000 = 4000(1 + 0.4)

Population in year II = 4000 + 4% of 4000(1 + 0.4) = 4000(1 + 0.4)(1+0.4)

and this goes on.)

Learn more about exponential equation here

https://brainly.com/question/23729449

#SPJ2

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