Answer:
Kindly check explanation
Step-by-step explanation:
A.)
H0 : μ = 5000
H0 : μ > 5000
xbar = 6671 ; s = 8185.21 ; n = 52 ; α = 0.05
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (6671 - 5000) ÷ (8185.21/√52)
T = 3.814
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at 3.814; 51 = 0.000185
Pvalue < α ; Reject H0 and conclude that average birth is greater than 5000
B)
H0 : μ = 6000
H0 : μ < 6000
xbar = 4187 ; s = 4386 ; n = 52 ; α = 0.01
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (4187 - 6000) ÷ (4386/√52)
T = - 2.981
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at - 2.981; 51 = 0.0022
Pvalue < α ; Reject H0 and conclude that average death is less than 6000
C.)
H0 : μ < 2500
H0 : μ ≥ 2500
xbar = 2744 ; s = 3134.41 ; n = 52 ; α = 0.05
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (2744 - 2500) ÷ (3134.41/√52)
T = 0.561
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at 0.561; 51 = 0.289
Pvalue > α ; Fail to Reject H0 and conclude that average marriage is not greater Tha or equal to 2500
D.)
H0 : μ = 4000
H0 : μ ≤ 4000
xbar = 1451 ; s = 1217 ; n = 52 ; α = 0.01
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (1451 - 4000) ÷ (1217/√52)
T = - 15.10
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at - 15.10; 51 = 0.000001
Pvalue < α ; Reject H0 and conclude that average divorce is less eqaul to 4000
12
х
8
6
Find the value of x.
A) 9
B) 16
C) 14
D) 10
Answer:
The answer is 10, hope this helps!
Step-by-step explanation:
Factorize 5b2-11b+6=0
Answer:
5b^2-(5+6)b+6=0
5b^2-5b-6b+6=0
5b(b-1)-6(b-1)=0
(5b-6)(b-1)=0
either
(5b-1)=0
5b=1
b=1/5
or
b-1=0
b=1
Step-by-step explanation:
firstly find out the mid term factor i e in above qn 11 should be break down so that its multiple should be coefficient of b and constant and additiqn should be equals to 11 .so we find out 5 and 6
Geometry Oddsseseyware
a. The first five terms of n^2 + 5 are
Given:
The nth term of a sequence is:
[tex]n^2+5[/tex]
To find:
The first five terms of the given sequence.
Solution:
The given sequence is:
[tex]a_n=n^2+5[/tex]
For n=1,
[tex]a_1=1^2+5[/tex]
[tex]a_1=1+5[/tex]
[tex]a_1=6[/tex]
For n=2,
[tex]a_2=2^2+5[/tex]
[tex]a_2=4+5[/tex]
[tex]a_2=9[/tex]
For n=3,
[tex]a_3=3^2+5[/tex]
[tex]a_3=9+5[/tex]
[tex]a_3=14[/tex]
For n=4,
[tex]a_4=4^2+5[/tex]
[tex]a_4=16+5[/tex]
[tex]a_4=21[/tex]
For n=5,
[tex]a_5=5^2+5[/tex]
[tex]a_5=25+5[/tex]
[tex]a_5=30[/tex]
Therefore, the first five terms of the given sequence are 6, 9, 14, 21, 30.
the mean of 5 numbers is 198. the numbers are in ratio 1:2:3:4:5 find the smallest number
Answer: 13.2
In fraction form, this is 66/5
=============================================================
Explanation:
The five values are in the ratio 1:2:3:4:5 which scales up to 1x:2x:3x:4x:5x for some positive number x.
Add up the pieces of the second ratio and set that sum equal to 198. Then solve for x.
1x+2x+3x+4x+5x = 198
15x = 198
x = 198/15
x = 66/5
x = 13.2 is the smallest number since 1x = 1*13.2 = 13.2 was the smallest value of the ratio 1x:2x:3x:4x:5x.
number of bald eagles in a country a discrete random variable, a continuous random variable, or not a random variable?
Answer:
Discrete random variable.
Step-by-step explanation:
Discrete variable:
Countable numbers(0,1,2,3,...)
Continuous variable:
Can assume decimal values, such as 0.5, 2.5,...
Number of bald eagles:
Number of bald eagles is a countable value, either there a 0, 100, 1000,... so it is a discrete random variable.
Answer:
Discrete random variable.
Step-by-step explanation:
Which operation will solve the following word problem? Jaylene bought a blouse for $20.00. The next day she returned the blouse and got 90% of her money back, she was charged a restocking fee of 10%. How much money did she get back?
Division
Addition
Subtraction
Multiplication
Answer:
division is right i hope you understand
9514 1404 393
Answer:
Multiplication
Step-by-step explanation:
The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.
Jaylene got back ...
90% × $20 = $18
A display case of toy rings are marked 5 for $1. If Zach wants to buy 50 toy rings, how much will Zach spend (not including tax)
Answer:
$10
Step-by-step explanation:
5 toys = $1
Zach wants 50 of these
50 ÷ 5 = 10
10 x 1 = 10
= $10
Answer:
10 dollars
Step-by-step explanation:
We can use a ratio to solve
5 rings 50 rings
---------- = --------------
1 dollar x dollars
Using cross products
5*x = 1 * 50
5x = 50
Divide by 5
5x/5 = 50/5
x = 10
Subtract and show work.
Answer:
[tex]31y^{3} -28y^{2}[/tex]+35y
Step-by-step explanation:
Please help me.I tryed to solve
Answer:
[tex]x \ge 1[/tex]
Step-by-step explanation:
Given
The number line
Required
Interpret
On the number, we have the following observations;
(1) The thick line starts from 1
(2) The line points to the right; this means greater than or/equals to
(3) The dot on 1 is a closed circle; this means greater than or equal to
So, the inequality is:
x greater than or equal to 1
i.e.
[tex]x \ge 1[/tex]
What is the value of y?
Answer:
y=0
Step-by-step explanation:
1. Make variable y as subject for the first equation, which is y= -2x +10
2. substitute the first eq to the second one
3. x - (-2x+10) -5=0
4. solve x, which x = 5
5. substitute in eq 1 which is y= -2x +10
6. solve the eq, the possible solution is y=0
Use the expression 9(7 + 2x) to answer the following:
Part A: Describe the two factors in this expression. (4 points)
Part B: How many terms are in each factor of this expression? (4 points)
Part C: What is the coefficient of the variable term? (2 points)
Step-by-step explanation:
Part A:
The two factors in 9(7+2x) are 9 and 7+2x
Part B:
First term: 9
Second term: 7+2x
Part C:
9(7+2x)
Open bracket
63+18x
The coefficient is 18x
A. The two factors are 9 and (7+2x).
B. In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.
C. The coefficient of the variable term is 18.
Algebraic expression:Given expression is;
[tex]9(7+2x)[/tex]
In given expression, there are two factors fist is 9 and second one is [tex](7+2x)[/tex]
In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.
To find the coefficient of variable term, we have to to expand given expression.
[tex]9(7+2x)=63+18x[/tex]
The coefficient of the variable term is 18.
Learn more about the algebraic expression:
https://brainly.com/question/4344214
what is the answer to this equation4
5
+ v =
41
20
Answer:
4075
Step-by-step explanation:
Instructions: Solve the following linear
equation
4(n + 5) – 2(5 + 7n) = -70
n =
Answer:
Step-by-step explanation:
4*(n +5) - 2*(5 + 7n) = -70
4*n + 4*5 + 5*(-2) + 7n*(-2) = -70
4n + 20 - 10 - 14n = -70
4n - 14n + 20 - 10 = -70
- 10n + 10 = -70
Subtract 10 from both sides
-10n = -70 - 10
-10n = -80
Divide both sides by (-10)
n = -80/-10
n = 8
Step-by-step explanation:
sjbsbsbeekejebebheebebejekek
simplify 6 x + 3y /3
Answer:
6x + y
Step-by-step explanation:
6x + 3y/3
6x + y
Answer:
6x + y
Step-by-step explanation:
6x + 3y / 3
cancel 3y by 3
6x + y
A town has a current population of 4,000. The population increased 4 percent per year for the past four years, Emergency response professionals
make up 3 percent of the town's population.
Part A
Write a function that represents the population (p) of the town in terms of the number of years (1) for the last four years.
Answer:
p=c(1+r)^t so the population will be 4679.43424 or rounded to 4679
Step-by-step explanation:
p=c(1+r)^t
p=4,000(1+.04)^t
p=4,000(1.04)^t
p=4,000(1.04)^4
p=4679.43424
p= the population you are solving for
c= the initial amount of the population
(1+r)= the rate of change
t= the period of time
The exponential equation that represents the population of the town in terms of the number of years : [tex]p=4000 (1+0.4)^{t}[/tex]
What is an exponential equation?An exponential equation is an equation with exponents where the exponent (or) a part of the exponent is a variable.
It is similar to the amount received after investing a certain amount compounded annually.
Given,
Initial population = 4000
Rate of increase = 4%
Let current population be p.
Let number of years passed be t.
The exponential equation will be: [tex]p=4000 (1+0.4)^{t}[/tex]
(The population of the town has grown exponentially. This means that:
Initial population = 4000
Population in year I = 4000 + 4% of 4000 = 4000(1 + 0.4)
Population in year II = 4000 + 4% of 4000(1 + 0.4) = 4000(1 + 0.4)(1+0.4)
and this goes on.)
Learn more about exponential equation here
https://brainly.com/question/23729449
#SPJ2
In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC?
Answer:
[tex]\angle ADB \cong \angle CDB[/tex]
[tex]\angle DBA \cong \angle DBC[/tex]
[tex]BD = BD[/tex]
Step-by-step explanation:
Given
[tex]\triangle ABD \cong \triangle CBD[/tex]
Required
The congruent segments by CPCTC
From the question, we have:
[tex]\angle ADB \cong \angle CDB[/tex] --- given
[tex]\angle DBA \cong \angle DBC[/tex] --- given
Both triangles share a common side (length BD);
So, we have:
[tex]BD = BD[/tex]
Hence, the congruent segments are:
[tex]\angle ADB \cong \angle CDB[/tex]
[tex]\angle DBA \cong \angle DBC[/tex]
[tex]BD = BD[/tex]
2 triangles are shown. The first triangle has side lengths 35, 20, and 20. The second triangle has side lengths x, 44, 44.
What value of x will make the triangles similar by the SSS similarity theorem?
15.9
59
77
96.8
Answer:
[tex]x = 77[/tex]
Step-by-step explanation:
Given
[tex]First \to Second[/tex]
[tex]35 \to x[/tex]
[tex]20 \to 44[/tex]
[tex]20 \to 44[/tex]
Required
Find x by SSS
Represent the triangle sides as a ratio
[tex]35 : x = 20 : 44[/tex]
Express as fraction
[tex]\frac{x}{35} = \frac{44}{20}[/tex]
Multiply by 35
[tex]x = \frac{44}{20} * 35[/tex]
[tex]x = \frac{44 * 35}{20}[/tex]
[tex]x = \frac{1540}{20}[/tex]
[tex]x = 77[/tex]
Answer:
ccccccccccccccccccccccccccc
Step-by-step explanation:
Find the size of angle XZY give your answer
Answer:
yeah u forgot to add the picture ig
PLEASE I NEED HELP!!!!!
Find the volume of this sphere.
Use 3 for TT.
L-r=3ft
V [?]ft3
V = Tr3
Answer:
113.1 =VOLUME , 4/3 X 3.14 (3) ^3 = 113.1
The sum of two six-digit numbers is a seven-digit number
Answer
500,000 + 500,000 = 1,000,000
Step-by-step explanation:
A circle has a circumference of 2cm. Which statement about the circumference and area is true?
A comparison of the area and circumference is not possible since the area cannot be determinec
The numerical values of the circumference and area of the circle are equal.
The numerical value of the circumference is greater than the numerical value of the area.
The numerical value of the circumference is less than the numerical value of the area.
ОО
Answer:
The numerical values of the circumference and area of the circle are equal.
Prove that the square of an odd number is always 1 more than a multiple of 4
Answer:
By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.
Step-by-step explanation:
For examples,
Let's consider squares of 3, 11, 25, 37 and 131.
[tex] {3}^{2} = 9[/tex]
8 is a multiple of 4, and 9 is more than 8.
[tex] {11}^{2} = 121[/tex]
120 is a multiple of 4 and 121 is one more than it.
[tex] {25}^{2} = 625[/tex]
624 is a multiple of 4 and 625 is one more than it.
[tex] {37}^{2} = 1369[/tex]
1368 is a multiple of 4 and 1369 is one more than 1368.
[tex] {131}^{2} = 17161[/tex]
17160 is a multiple of 4.
Omgg please help right now
Answer:
64in^3
Step-by-step explanation:
6×3 = 18
18×2 = 36
4×7 = 28
36+28 = 64
Hope this helps! :)
Find the volume of the composite solid. Round your answer to the nearest hundredth. A. 22.5mm^3 B. 22.19mm^3 C. 22.53mm^3 D. 22.54mm^3
help with this question pleaseee !
Answer:
Add equations A and C to eliminate y and add B and C to eliminate y
Step-by-step explanation:
From the equation given, we can see that the coefficient of y in A and C are alternating values 5 and -5 which cancels out on adding same for B and C. Hence t eliminate y, we will add B and C and A and C
Therefore the correct answer will be to eliminate add equations A and C to eliminate y and add B and C to eliminate y
What is the probability that something with a 2.18% chance of occurring happens 3 times out of 194 events
Answer:
0.18431525 = 18.4%
Step-by-step explanation:
General Formula :
total trials Cn⋅p(success)^n⋅p(fail)^total−n
1198144* (.0218)^3 * (1-.0218)^191
40 points! Need help finding.
The cordent plan of the answer is 2
Answer:
The scale factor will just be 2
Step-by-step explanation:
The length of PQ is twice as larger than the length of AB.
so from 12 to 6 or 6 to 12, we multiply 6 by 2 which equals to 12
Find the probability that when a couple has children, at least one of them is a . (Assume that boys and girls are equally likely.)
Answer:
[tex]P(At\ least\ one\ girl) = 0.875[/tex]
Step-by-step explanation:
Given
[tex]n = 3[/tex]
[tex]B \to boys[/tex]
[tex]G \to girls[/tex]
[tex]P(G) = P(B) = 0.5[/tex] --- equal probability
See comment for complete question
Required:
[tex]P(At\ least\ one\ girl)[/tex]
To do this, we make use of complement rule:
[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]
The event that there is no girl out of the 3 children is: B B B
And the probability is:
[tex]P(No\ Girl) = P(B) * P(B) * P(B)[/tex]
[tex]P(No\ Girl) = 0.5*0.5*0.5[/tex]
[tex]P(No\ Girl) = 0.125[/tex]
So:
[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]
[tex]P(At\ least\ one\ girl) = 1 - 0.125[/tex]
[tex]P(At\ least\ one\ girl) = 0.875[/tex]
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.5 customers arrive each hour. One design consultant is available to answer customer questions and make product recommendations. The consultant averages 10 minutes with each customer. Compute the operating characteristics of the customer waiting line, assuming Poisson arrivals and exponential service times. Round your answers to four decimal places. Do not round intermediate calculations.
Answer:
the operating characteristics have been solved below
Step-by-step explanation:
we have an average of 10 minutes per customers
μ = mean service rate = 60/10 = 6 customers in one hr
the average number of customers that are waiting in line
mean arrival λ = 2.5
μ = 6
[tex]Lq = \frac{2.5^{2} }{6(6-2.5)} \\[/tex]
= 6.25/21
= 0.2976
we calculate the average number of customers that are in the system
[tex]L=Lq+\frac{2.5}{6}[/tex]
= 0.2976+0.4167
= 0.7143
we find the average time that a customer spends in waiting
[tex]Wq=\frac{0.2976}{2.5}[/tex]
= 0.1190 hours
when converted to minutes = 0.1190*60 = 7.1424 minutes
[tex]0.1190+\frac{1}{6}[/tex]
=0.2857
probability that arriving customers would wait for the service
= 2.5÷6 = 0.4167
