Answers
Answer:
Answer is E but not 100%
Step-by-step explanation:
Answer:
A is correct
E shows an error as the first two values are identical so one cannot be greater than the other.
Step-by-step explanation:
A shows 2.69 is equal to 2.696 which is more than 2.696 which is more than 2.696 which is more than 2.696
As when;
2.696 repeats in bold = 2.696969696 1st greatest
2.696 repeats in bold = 2.696696696 2nd in highest value so 2nd in order.
2.696 repeats in bold = 2.696666666 3rd in highest value so 3rd in order.
2.696 does not repeat = 2.696 so is the least greatest from the list.
Related Questions
What is the shape of
its bases?
A. Circle
B. Heptagon
C. Rectangle
D. Triangle
Answers
Answer:
C. Rectangle
Step-by-step explanation:
Hope it helps you in your learning process.
An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blends of gasoline:
88.5 98.8 89.6 92.2 92.7 91.8 91.0 91.0 94.7 88.3 90.4 83.4 87.9 88.4 87.5 90.9 84.3
90.4 91.6 91.0 93.0 92.6 87.8 89.9 90.1 91.2 90.7 88.2 94.4 93.7 88.3 91.8 89.0 90.6
88.6 88.5 90.4 96.5 89.2 89.7 89.8 92.2 88.3 93.3 91.2 84.3 92.3 92.2 91.6 87.7 94.2
87.4 91.2 93.2 88.9 90.3 91.1 85.3 91.1 86.7 88.6 89.8 90.0 86.7 90.1 90.5 94.2 88.7
92.7 91.5 93.4 89.3 100.3 90.8 92.7 93.3 89.9 96.1 91.1 87.6 90.1 89.3 86.7
Required:
Construct a stem-and-leaf display for these data. Calculate the median and quartiles of these data.
Answers
Answer:
[tex]Median = 90.4[/tex]
[tex]Q_1 = 88.6[/tex]
[tex]Q_3 = 92.2[/tex]
Step-by-step explanation:
Given
The above data
Required
- A stem and leaf display
- The median
- The quartiles
First, determine the range of the data
[tex]Smallest = 83.4[/tex]
[tex]Highest = 100.3[/tex]
Next, group each dataset base on common whole numbers.
So, we have:
[tex]83.4[/tex]
[tex]84.3\ 84.3[/tex]
[tex]85.3[/tex]
[tex]86.7\ 86.7\ 86.7[/tex]
[tex]87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9[/tex]
[tex]88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9[/tex]
[tex]89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9[/tex]
[tex]90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9[/tex]
[tex]91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8[/tex]
[tex]92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7[/tex]
[tex]93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7[/tex]
[tex]94.2\ 94.2\ 94.4\ 94.7[/tex]
[tex]96.1\ 96.5[/tex]
[tex]98.8[/tex]
[tex]100.3[/tex]
Next, we construct the stem and leaf plot.
The whole numbers will be the stem while the decimal parts will be the leaf.
So, we have:
[tex]\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}[/tex]
[tex]\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}[/tex]
From the above plot,
[tex]n = 83[/tex]
The median is calculated as:
[tex]Median = \frac{n+1}{2}th[/tex]
[tex]Median = \frac{83+1}{2}th[/tex]
[tex]Median = \frac{84}{2}th[/tex]
[tex]Median = 42nd[/tex]
i.e. the median is at the 42nd position.
From the above stem and leaf plot.
The 42nd position is at stem 90 and the leaf .4
So the median is:
[tex]Median = 90.4[/tex]
The lower quartile (Q) is calculated as:
[tex]Q_1 = \frac{n+1}{4}th[/tex]
[tex]Q_1 = \frac{83+1}{4}th[/tex]
[tex]Q_1 = \frac{84}{4}th[/tex]
[tex]Q_1 = 21st[/tex]
i.e. the lower quartile is at the 21st position.
From the above stem and leaf plot.
The 42nd position is at stem 88 and the leaf .6
So the lower quartile is:
[tex]Q_1 = 88.6[/tex]
The upper quartile (Q3) is calculated as:
[tex]Q_3 = 3 * \frac{n+1}{4}th[/tex]
[tex]Q_3 = 3 * \frac{83+1}{4}th[/tex]
[tex]Q_3 = 3 * \frac{84}{4}th[/tex]
[tex]Q_3 = 3 * 21th[/tex]
[tex]Q_3 = 63rd[/tex]
i.e. the upper quartile is at the 63rd position.
From the above stem and leaf plot.
The 63rd position is at stem 92 and the leaf .2
So the upper quartile is:
[tex]Q_3 = 92.2[/tex]
Meatball subs used to cost $5.40 at Mike's Sub Shop, but he just increased the price by $0.54.
How much do subs cost now?
Answers
Answer:
Step-by-step explanation: $5.40 + $0.54 now equals $5.94
choose the expression that represents the fraction as a product of a whole number and a unit fraction 4/10
Answers
Answer:
69
Step-by-step explanation:
trust me
A Solve each problem.
1. Henry flies his plane at 240 mph for 3 hours. How far does he travel?
Answers
Distance = speed x time
Distance = 240 x 3 = 720 miles
Answer:
henry doesn't travel but plane travel
Step-by-step explanation:
240m×3hour240m×60×60sec2592000m/sMrs Mills buys 4 packs of treats for her cats, Fluff and tigger
she gives Fluff 1/6 of a pack each day
She gives tigger 1/5 of a pack each day
for how many complete days will the 4 packs of treats last
Answers
Answer: 10 days
Step-by-step explanation:
1/6 + 1/5 = 5/30 + 6/30 = 11/30 (total for the day)
4 / (11/30) = 10.90909091 (divide the total amount of packages by the daily total)
So 10 complete days.
Represent the greatest common factor of 36 and 8 using the distributive property
36 + 8 =
0 4x(9+2)
O2 x (18+4)
O 8x (5+2)
0 11 x (3+1)
Answers
36/2=18, 8/2= 4 b is correct however wrong because it is the simplest distribution
36/8= 4.5, 8/8= 1 c is incorrect
36/11= 3.27, 8/11= .73 d is incorrect.
Answer is 4x(9+2)
Suzanne collected data on the weight of her classmates. She found that the range of the data she collected was 17
Which of the following BEST explains what a range of 17 indicates?
A
The average distance of each point from the mean is 17.
.
B
The distance between the minimum and the maximum is 17.
С
The distance between the lower quartile to the upper quartile is 17.
D
The distance between the mean and the median in a skewed data set is 17
Answers
Answer:
the answer is A.
Step-by-step explanation:
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 : Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective. Using the data, construct the 80% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places.
Answers
Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that [tex]n = 1067, \pi = \frac{74}{1067} = 0.069[/tex]
80% confidence level
So [tex]\alpha = 0.2[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.2}{2} = 0.9[/tex], so [tex]Z = 1.28[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079[/tex]
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
How can you isolate the variable in this equation? x + 6 = 13 A Add 6 to 13. B Add 6 to both sides. C Subtract x from both sides. D Subtract 6 from both sides.
Answers
Answer:
the answer is D, im doiing the flocab rn
Step-by-step explanation:
The catapults are 14.5 m, end text apart, as shown. From catapult A, there is a 96 degree angle between catapult B and the target. From catapult B, there is a 58°degree angle between catapult A and the target.
How far should catapult B throw the snowball to reach the target?
Do not round during your calculations. Round your final answer to the nearest tenth of a meter.
Thank you very much.
Answers
Answer:32.9 m
Step-by-step explanation:
HELP PLEASE ILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
50%
- Animals
Home
Economics -
20%
30%
- Farm Mechanics
There were 2500 entries at the county fair. The circle graph tells what types of entries were made.
How many were Farm Mechanics entries?
Answers
Answer:
750 were Farm Mechanics.
Step-by-step explanation:
30% of 2500 is 750.
Hope this helps
Using the product of the means equals the product of the extremes, solve for x, to the nearest tenth. 4:9=x:6
Answers
Cross multiply:
4 x 6 = 9x
24 = 9x
Divide both sides by 9
X = 24/9
X = 2.7 ( rounded to the nearest tenth)
If a rectangle has an area of 48 cm², what would be the area of a similar rectangle if
the dimensions are doubled?
A) 2304 cm^2
B) 192 cm^2
C)96 cm^2
D)216 cm^2
Answers
B)192cm^2
Step by step exploration
what is a easier way to solve fractions
Answers
Answer: hewo, there! I hope I Made it easier to Understand
the first method is to equally divide the top and bottom of the fraction by whole numbers larger than 1 until you cannot go any further. As an example, let's take the fraction 24/108: Divide each number by 2 to get 12/54. Divide by 2 again to get 6/27
Step-by-step explanation:
To work out a fraction of a number, all you need to do is divide that number by the denominator of the fraction, then multiply your result by the numerator of the fraction
Hope this helps you!!
Have a great day!!!
Someone PLease help me
Answers
What is sec 0 when cot 0 = -4/2?
Answers
Answer:
[tex]sec 0=\frac{\sqrt{66} }{8}[/tex]
Step-by-step explanation:
[tex]Cot0=-4\sqrt{2}[/tex]
[tex]sec0=\frac{\sqrt{33} }{4\sqrt{2} }[/tex]
[tex]=\frac{\sqrt{33} }{4\sqrt{4} } *\frac{4\sqrt{2} }{4\sqrt{2} }[/tex]
[tex]=\frac{4\sqrt{66} }{32}[/tex]
[tex]=\frac{\sqrt{66} }{8}[/tex]
--------------------
hope it helps...
have a great day!!
Question 9 of 10
True or False? A circle could be circumscribed about the quadrilateral below.
Answers
Answer:
t
Step-by-step explanation:
A circle can be circumscribed about the given quadrilateral, the answer is: A. True.
We know that,
To circumscribe a circle about a quadrilateral means to place the quadrilateral inside the circle, such that the four vertices of the quadrilateral touches the circumference of the circle.
Opposite angles of a circumscribed polygon are supplementary.
Therefore, a circle can be circumscribed about the given quadrilateral, the answer is: A. True.
Learn more about circumscribed polygon on:
brainly.com/question/1423054
#SPJ7
Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x
Answers
Answer:
[tex]Period = \pi[/tex]
Step-by-step explanation:
Given
[tex]y = -\frac{1}{3} * \sin(2x)[/tex]
Required
The period
A sine function is represented as:
[tex]y =A \sin(Bx + C) + D[/tex]
Where
[tex]Period = \frac{2\pi}{B}[/tex]
By comparing:
[tex]y =A \sin(Bx + C) + D[/tex] and [tex]y = -\frac{1}{3} * \sin(2x)[/tex]
[tex]B = 2[/tex]
So, we have:
[tex]Period = \frac{2\pi}{2}[/tex]
[tex]Period = \pi[/tex]
Hence, the period of the function is [tex]\pi[/tex]
Sin 0= 8/17 determine the value of tan?
Answers
Answer:
tan theta = 8/15
Step-by-step explanation:
Sin is equal to opposite over hypotenuse. So it means that the side opposite from theta is 8, and the hypotenuse is 17.
To find the value of the adjacent side from theta, use the Pythagorean Theorem.
a^2 + b^2 = c^2
8^2 + b^2 = 17^2
64 + b^2 = 289
Subtract 64.
b^2 = 225
Take the square root.
b = 15.
So that means:
the side opposite from theta is 8,
the side adjacent from theta is 15,
the hypotenuse is 17.
Now we take tan, opposite over adjacent, and use the values from the triangle.
tan = opposite / adjacent
tan = 8/15.
Can someone seriously help me!!!!!
Answers
Answer:
Step-by-step explanation:
This should help I hope
Which expression is equivalent to 3m(x) - 5n(x), if m(x) = 6x2 + 3x - 5 and n(x) = 2x2 + 7x - 1?
Answers
Answer:
8x^2 - 26x - 10
Step-by-step explanation:
3(6x2 + 3x - 5 ) = 18x^2 + 9 -15
5(2x2 + 7x - 1) = 10x^2 + 35 - 5
18^2 - 10x^2 = 8x^2
9x - 35x = - 26x
-15 -(-5) = -10
final answer = 8x^2 - 26x - 10
I need to know the answer!
Answers
Answer:
As it says he is incorrect.
Step-by-step explanation:
To start, if you were to multiply something such as 5*1, then you would get the same number. Another example would be 8*0. Anything multiplied by 0 IS zero. He does give some valid answers, but there are also ones with smaller numbers. That is why Jackson is incorrect.
You have been given the task of designing a study concerning the lifetimes of five different types of electric motor. The initial question to be addressed is whether there are differences in mean lifetime among the five types. There are 20 motors, four of each type, available for testing. A maximum of five motors can be tested in a day. The ambient temperature differs from day to day, and this can affect motor lifetime.
a. Describe how you would choose the five motors to test each day. Would you use a completely randomized design? Would you use any randomization at all?
b. If X;j represents the measured lifetime of a motor of type i tested on day j, express the test statistic for testing the null hypothesis of equal lifetimes in terms of the Xir
Answers
Answer:
a-As the only factor of interest is type of electric motor, thus instead of using 1-factor randomization, a randomized block design is used where at maximum one motor of each type is tested every day.
b- The test statistic is given as
[tex]F_{I-1,(I-1)(J-1)}=\dfrac{12\left(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}\right) }{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}[/tex]
Step-by-step explanation:
a-
This is done such that the days are considered as blocks and the randomization is only occuring within the block. The order of testing is random. However the condition is implemented such that one motor of each type is tested each day.
b-
The F-Value is given as
[tex]F-Value=\dfrac{MSA}{MSAB}[/tex]
Here MSA is given as
[tex]MSA=\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex]Similarly MSAB is given as
[tex]MSAB=\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{.j}[/tex] is the column-wise mean which is given as [tex]\bar{X}_{.j}=\dfrac{1}{I}\Sigma^I_{i=1}X_{ij}[/tex][tex]X_{ij}[/tex] is the any motor j of type iBy putting these values and simplifying, equation becomes:
[tex]F-Value=\dfrac{MSA}{MSAB}\\\\F-Value=\dfrac{\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}}{\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}}\\\\F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{5-1}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(5-1)(4-1)}}\\\\[/tex]
This is further simplified as
[tex]F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{4}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\[/tex]
The numerator can be written as
[tex]F-Value=\dfrac{\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{12(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..})}{{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}}\\[/tex]
Convert 400 meters (m) to feet (ft). Round your answer to two decimal places. (1 metre = 3.28084 feet)
Answers
Answer:
1m----------3.28084ft
400m---------xft
x=(400*3.28084)/1
x=1,312.33 ft
Step-by-step explanation:
Help ASAP
What is the highest common factor of 180 and 168
Answers
Answer:
Its 12
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
make a factor tree, find the product of the prime factors, it will be 12.
hey I need help with my coordinates
Answers
Ok send the picture so I can help you.
Answer:
what is the question? I can help
Step-by-step explanation:
what its 600+600 pls help
Answers
Answer:
1200 hope this helps you;)
Answer:
1200 lol
Step-by-step explanation:
14. On Monday, a work group eats at Ava's café,
where a lunch special is $8 and a dessert is
$2. The total is $108. On Friday, the group
eats at Bo's café, where a lunch special Is
$6 and a dessert is $3. The total is $90. Each
time, the group orders the same number of
lunches and the same number of desserts.
How many lunches and desserts are
ordered?
what the x and y value.
Answers
Answer:
no. who eat lunch special = 12
no. who eat dessert = 6
Step-by-step explanation:
Let x = no. who eat lunch special
y = no. who eat dessert
(1) 8x + 2y = 108 (2) 6x + 3y = 90
Divide thru by 2 Divide thru by 3
4x + y = 54 2x + y = 30
-2x - y = -30
2x = 24
x = 12 2(12) + y = 30
24 + y = 30
y = 6
Rosalind made 969 donuts and put 8 donuts into each box. How many boxes of donuts were made
Answers
Answer:
121 donuts in each box
Step-by-step explanation:
969 divided by 8 = 121.125
(Ignore the remainder)
Step by step solution:
We know that there are 969 doughnuts, and there are 8 doughnuts per box. What we need to find out is how many boxes of doughnuts were made.
Step 1:
Set up an equation for Number of doughnuts (969) / Number of doughnuts per box (8) = Number of boxes made (x), which would look like this:
969/8 = x
Step 2:
Doing this, we can get 121.125, which leaves us with
121.125 = x
121.125 = 121.125
Which gives us the answer of 121.125, which we can shorten to 121, as the decimal is not necessary.
Checking our answer:
We can check our answer simply be rewording our 1st equation to solve for the number of doughnuts made. This would give us the equation Number of doughnuts per box (8) * Number of boxes made (121.125) = x. Solving this equation would look like
8 * 121.125 = x
969 = x
969 = 969
Answer: By completing the steps above we get 121, and we can check our work by rewording the problem to solve for the number of Doughnuts. Good Luck!
