Answer:
x = -3
Step-by-step explanation:
Answer:
x=-3
Step-by-step explanation:
You can just do +x on both sides so: 0=3+x and then -3 on both sides: -3=x.
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
The perimeter of a rectangular field is 312m. If the width of the field is 61m,what is the length.
Answer:
95m
Step-by-step explanation:
312 - 61 - 61 = 190
190/2 = 95
Help me plz i wanna make an an A
24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
A delivery company's charge for an overnight package weighing in excess of one pound is given by the formula c= 2.53w + 15, 16
where w is the weight of package in pounds. Find the following.
3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
i need help what is the answer
A classroom has 12 girls for every 4 boys. What is the ratio of boys to total students?
Question 7 options:
4 : 16
12 : 4
4 : 12
12 : 16
Answer:
I don't understand please elaborate more your given question.
Step-by-step explanation:
see question in attached photo.
Answer:
b = 2Step-by-step explanation:
We know that:
a/b + c/d = (ad + bc)/bdWe observe the denominator of the first expression is same as the product of the denominators of the second expression.
Compare the numerators and solve for b:
5(x - 1) - 4(x - b) = x + 35x - 5 - 4x + 4b = x + 3x - 5 + 4b = x + 34b - 5 = 34b = 8b = 21/2 divided by (-3) please help
Answer:
-1/6
Step-by-step explanation:
apply fraction rule to get 1/2(-3)
Multiply the numbers to get 1/-6
apply fraction rule to move negative to make
-1/6
1/2 divided by (-3) = -1/6 or -0.1666666667.
Answer all of the following questions. 3 Points a question. ALSO NO LINKS!
Is 2 a prime number?
Is 3 a prime number?
Is 11 a prime number?
Is 18 a prime number?
Is 20 a prime number?
Is 27 a prime number?
Answer:
no
yes
yes
no
no
yes
Step-by-step explanation:
a prime number cant be devided by any thing other than itself or one
Answer:
Step-by-step explanation:
Is 2 is 3 is 11 is 18 is 20 is 27
PLEASE READ THIS!!! Don't answer my questions with a link. Someone already answered this question, but they gave me a link and it was blocked on my school Chromebook, so it was an entirely useless answer. Thank you. If you answer this question without using a link I will give you an easy to earn 100 points. I just need to know how to turn this shape into as many triangles as possible. Thank you for reading this message.
Answer: 9 triangles
Step-by-step explanation:
Use the information given to find the equation of the line using the point-slope formula (y-y_1)=m(x-x_1)). Then convert your answer to slope-intercept form (y=mx+b).
y-intercept of 2 and (4,-1)
If it's possible please a explanation on how you solved it.
Answer:
y=[tex]-\frac{3}{4}[/tex]x+2
Step-by-step explanation:
y=sx+2;
-1=4s+2;
s=-3/4;
y=[tex]-\frac{3}{4}[/tex]x+2
Henry and his little brother made up a game using coins. They flip the coins towards a cup and receive points for every one that makes it in. Henry starts with 15 points, and his little brother starts with 20 points. Henry gets 3 points for every successful shot, and his brother, since he is younger, gets 2 points for each successful shot. Eventually, the brothers will have a tied score in the game. How many additional shots will each brother have made?
Write a system of equations, graph them, and type the solution.
Answer:
After 5 additional shots, the brothers will have a tied score.
Step-by-step explanation:
find equations
henry:
y-int is 15 because that is the starting number. the slope is 3 because that is how much his points are increasing for every successful shot. we can use this information to form this equation:
y = 3x + 15
brother:
y-int is 20 because that is the starting number. slope is 3 because that is how many points he gets for each successful shot. using this information, we can form the following equation:
y = 2x + 20
--
solve
y = 3x + 15
y = 2x + 20
3x + 15 = 2x + 20
x + 15 = 20
x = 5
--
graph
(just use desmos)
Y-2=-3(x-7) written in standard form
Which of the following is true?
|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5
Answer:
|-4| < |-5|
Step-by-step explanation:
because if modules is given sub sign will be deducate
Write down an example to show that each of the following two siatements is not correct
a) The factors of an even number are always even
Answer:
a) 2 * 3 = 6.
b) 123 is odd but contains an even digit (2).
Step-by-step explanation:
HELP ME PLEASE RNNN FASTTT
Answer:
The first three are functions
Step-by-step explanation:
4th one fails the Vertical line test.
(2x+y)2-y2 if x=-3 y=4 and z=-5
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
Question 4 options:
y=47x−4
y=56x+1
y=−56x−4
y=−47x+1
Please help!
Answer: i think it is y=−56x−4
Step-by-step explanation:
The equation in the slope intercept form which passes through the points ( 0, -4 ) and ( 6 , 9 ) is y = (-5 / 6)x - 4.
The correct answer is Option C.
Given data:
To find the equation of a line in slope-intercept form (y = mx + b) that passes through the points (0, -4) and (6, -9), we need to determine the slope (m) and the y-intercept (b).
First, calculate the slope (m):
m = (change in y) / (change in x)
m = (-9 - (-4)) / (6 - 0)
m = (-9 + 4) / 6
m = -5 / 6
Now that we have the slope, we can use one of the given points (let's use (0, -4)) to solve for the y-intercept (b):
-4 = (-5 / 6) * 0 + b
-4 = b
So, the y-intercept (b) is -4.
Now, we can write the equation of the line in slope-intercept form:
y = (-5 / 6)x - 4
Hence, the equation of the line is y = (-5 / 6)x - 4.
To learn more about equation of line, refer:
https://brainly.com/question/14200719
#SPJ3
The complete question is attached below:
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
A) y = ( 4/7 )x - 4
B) y = ( 5/6 )x + 1
C) y = ( -5/6 )x - 4
D) y = ( -4/7 )x + 1
If f (x) = 3x + 1 and g(x) = 2x + 1, what is the value of f (g(2))?
Step-by-step explanation:
= f( g(2) )
= 3(2x + 1) + 1
= 6x + 3 + 1
= 6x + 4
= 6(2) + 4
= 12 + 4
= 16
f(g(2)) = 16
PLEASE HELP ME!!! jacky starts biking to meet up with her friend. she knows that if she bikes at a speed of 10 mph, she will be 3 minutes late. jacky also know that if she bikes at a speed of 12 mph, she will be there 2 minutes before they agree to meet. how much time does she have left before the appointed time?
Answer:
27s
Step-by-step explanation:
d = distance to rendezvous point in miles
t = time of arrival at 10mph, i.e. 3 mins later than appointed time
10 mph = 10 miles per hour = ¹/₆ miles per min
12 mph = ¹/₅ miles per min
t = d/(¹/₆)
t = 6d
5 min = ¹/₁₂ hr
t - ¹/₁₂ = d/(¹/₅)
t = 5d + ¹/₁₂
Elimination of t:
6d = 5d + ¹/₁₂
d = ¹/₁₂ mi
t = 6(¹/₁₂)
t = ¹/₂ min
Time left to appointed time = ¹/₂ - ³/₆₀
= ¹⁰/₂₀ - ¹/₂₀
= ⁹/₂₀.min → 27 seconds
Answer:
27 min
Step-by-step explanation:
rsm
fill in the blank with the letter of the description that best matches the term for the verb porter, match the subject pronoun with the correct form of the verb. i'll mark Brainliest if the answers are correct.
A. portons
B. porte
C. portez
D. portes
E. portent
FILL IN THE BLANK
je ____
tu ____
nous ____
vous ____
ils ____
Step-by-step explanation:
je........porte
tu.......portes
nous.......portons
vous........portez
ils......portent
If the sum of a number and two is tripled, the result is one less than twice the number. Find the number.
Answer:
z
Step-by-step explanation:
hqvqhqvw karrar ras wallah a part
Please I need help ASAP. Can someone help me?
Answer: The second bubble thing is correct you have picked the wrong one.
combine like the like terms
34w - 4g + 4g - 36w
the answer is -2w (i have the write at least 20 words to dont worry about this)
Answer:
-2w
Step-by-step explanation:
Like terms have same variable.
34w - 4g + 4g - 36w = 34w - 36w - 4g + 4g
= - 2w + 0 = -2w
what is the percentage discount when a stereo is reduced from $258 to $199?
Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage rate of increase or decrease.
y=14(1.21)^x
Answer:
r:its a growth by 51%
Step-by-step explanation:
np
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
