You need friction created by your tires and the road ____
to control your speed and direction.

Answers

Answer 1

Answer:

surface

Explanation:

You need friction created by your tires and the road surface

to control your speed and direction.


Related Questions

Pause
He
When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be:
OA. 40 m/s
OB. 9.8 m/s2
OC 2.5 m/s2
OD. 0.40 m/s2

Answers

Answer:

C

Explanation:

a=f/m

10Kgm/s2/4kg

2.5m/s2

When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be 2.5 m/s².

What is acceleration?

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration. The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

Given in the question, force 10 N and mass 4.0 Kg the acceleration is,

a = 10/4 = 2.5 m/sec²

When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be 2.5 m/s².

To learn more about acceleration refer to the link:

brainly.com/question/12550364

#SPJ2

Two risks of exposure to High levels of UV radiation

Answers

Answer:

uv radiation cause cancer

uv radiation effect our eyes

Answer:

you can get

1:skin cancer

2:eye damage

3:skin damage

4:immune system suppression

choose which two u want

hope this helped

:)

Explanation:

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake withn a speed of 2m/s and a wavelength of 1.5m. When these waves move into a shallower part of the lake, their speed decreases to 1.6m/s, though their frequency remains the same. Find the wavelength of the wave in the shallower water.

Answers

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒  [tex]V=f\times \lambda[/tex]

or,

⇒  [tex]f=\frac{V}{\lambda}[/tex]

On substituting the values, we get

⇒      [tex]=\frac{2}{1.5}[/tex]

⇒      [tex]=1.33 \ Hz[/tex]

hence,

⇒  [tex]\lambda_1=\frac{V_1}{f}[/tex]

On substituting the values, we get

⇒       [tex]=\frac{1.6}{1.33}[/tex]

⇒       [tex]=1.2 \ m[/tex]

PLZ help 10 points!!! space question!

Answers

Answer:

B. They are smaller and made of rocky material

Explanation:

i think it's right??

What is the period of a wave with a speed of 20.0 m/s and a frequency of 10.0 Hz?

Answers

im confused hold on imma send you a link to the answerExplanation:

A right triangle has side lengths of 4 centimeters and 5 centimeters. What is the length of the hypotenuse?
O A. 3 cm
B. 4 cm
C. 5 cm
D. 41 cm

Answers

Answer D




Explanation:


Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings and has a moment of inertia of 1850 kgm2. The turntable is at rest initially, but when the person begins running at a speed of 3.8 m/s (with respect to the turntable) around its edge, the turntable begins to rotate in the opposite direction. Calculate the angular velocity of the turntable. (Hint: use what you know about relative velocity to help solve the problem

Answers

Answer:

[tex]0.3165\ \text{rad/s}[/tex]

Explanation:

m = Mass of person = 65 kg

d = Diameter of round table = 6.5 m

r = Radius = [tex]\dfrac{d}{2}=3.25\ \text{m}[/tex]

v = Velocity of person running = 3.8 m/s

[tex]I_t[/tex] = Moment of inertia of turntable = [tex]1850\ \text{kg m}^2[/tex]

Moment of inertia of the system is

[tex]I=I_t+mr^2\\\Rightarrow I=1850+65\times 3.25^2\\\Rightarrow I=2536.5625\ \text{kg m}^2[/tex]

As the angular momentum of the system is conserved we have

[tex]L_i=L_f\\\Rightarrow mvr=I\omega_f\\\Rightarrow \omega_f=\dfrac{mvr}{I}\\\Rightarrow \omega_f=\dfrac{65\times 3.8\times 3.25}{2536.5625}\\\Rightarrow \omega_f=0.3165\ \text{rad/s}[/tex]

The angular velocity of the turntable is [tex]0.3165\ \text{rad/s}[/tex].

0)
A-B-C-D-E
Describe the mass of the reactants and products given the balanced chemical reaction
A)
The mass of the products is 2/3 that of the reactants.
B)
The mass of the reactants equals the mass of the products.
C)
The mass of the reactants is less than the mass of the products.
D)
The mass of the reactants is greater than the mass of the products.

Answers

Answer:

D)

The mass of the reactants is greater than the mass of the products.

While flying at an altitude of 5.75 km, you look out the window at various objects on the ground. If your ability to distinguish two objects is limited only by diffraction, find the smallest separation between two objects on the ground that are distinguishable. Assume your pupil has a diameter of 4.0 mm and take ???? = 460 nm.

Answers

Answer:

the smallest separation between two objects is 0.8067 m

Explanation:

Given the data in the question;

Altitude h = 5.75 km = 5750 m

Diameter D = 4.0 mm = 0.004 m

λ = 460 nm = 4.6 × 10⁻⁷ m

Now, Using Rayleigh criterion for Airy disks resolution.

we know that, Minimum angular separation for resolving two points is;

θ = 1.22λ / D

so we substitute

θ = (1.22 × 4.6 × 10⁻⁷)  / 0.004

θ = 5.612 × 10⁻⁷ / 0.004

θ = 1.403 × 10⁻⁴ rad  

so minimum separation [tex]d_{min[/tex] =  θh

so we substitute

[tex]d_{min[/tex] = (1.403 × 10⁻⁴) × 5750 m

[tex]d_{min[/tex] = 0.8067 m

Therefore, the smallest separation between two objects is 0.8067 m

Can you please help me ?

Answers

Answer:

Distance is 300 and displacement is 100

Explanation:

Distance= 100+100+100=300

Displacement=100

plz mark me as brainliest.

The first extra-solar planet around a main sequence star (i.e., not a neutron star or white dwarf) was found around the star 51 Pegasi in 1995. The large planet causes a measureable motion of the star around the center of mass of the system. Pegasi 51's orbital motion had a period of 4 days indicating a very large planet very close to the star. A large planet of mass M around a small star of mass 4M. The distance between planet and star is L. Both the planet and star will orbit around the center of mass of the system (marked by the red X).

Required:
Where is the center of mass of the star-planet system?

Answers

Answer:

   [tex]r_{cm}[/tex]= 1/5 L

Explanation:

To find the center of mass of the system let's use

        [tex]r_{cm} = \frac{1}{M}[/tex] ∑ r_i x_i

where m is the total mass of the system

let's apply this expression to our case

       

Let's set the reference frame on the star

         [tex]r_{cm} = \frac{1}{M +4M} ( 4M 0 + M L)[/tex]

         r_{cm} = [tex]\frac{1}{5}[/tex] L

         [tex]r_{cm}[/tex]= 1/5 L

Hey, the breast center is 1/5 of the distance between the star and the planet.

pls help

What is the frequency range of UV light? Of infrared light?

Answers

Answer:

violet region (UV) is wavelength less than 400 nm, the most common is between 200 and 400 nm,

The infrared (IR) range wavelengths greater than 700 nm

Explanation:

The spectral region near the visible is what humans can see with our eyes.

The range of the ultra violet region (UV) is wavelength less than 400 nm, the most common is between 200 and 400 nm, this radiation is responsible for tanning and skin burns.

The infrared (IR) range is a very wide range that begins at wavelengths greater than 700 nm and continues up to approximately 25,000 nm (1012 Hz).

Model the Earth's atmosphere as 79% N2, 19% O2, and 2% Argon, all of which are in thermal equilibrium at 280 K. At what height is the density of O half its value at sea level

Answers

Answer:

[tex]9.495 \times 10^3\ m[/tex]

Explanation:

From the given information:

Using the equation of Barometric formula as related to density, we have:

[tex]\rho (z) = \rho (0) e^{(-\dfrac{z}{H})} \ \ \ \ --- (1)[/tex]

Here;

[tex]p(z) =[/tex] the gas density at altitude z

[tex]\rho(0) =[/tex] the gas density  at sea level

H = height of the scale

[tex]H = \dfrac{RT}{M_ag } \ \ \ --- (2)[/tex]

Also;

R represent the gas constant

temperature (T) a= 280 K

g = gravity

[tex]M_a =[/tex] molaar mass of gas; here, the gas is Oxygen:

[tex]M_a =[/tex] 15.99 g/mol

= 15.99 × 10⁻³ kg/mol

[tex]H = \dfrac{8.3144 \times 280}{15.99 \times 10^{-3} \times 9.8 }[/tex]

[tex]H =14856.43 \ m[/tex]

Now we need to figure out how far above sea level the density of oxygen drops to half of what it is at sea level.

This implies that we have to calculate z;

i.e. [tex]\rho(z) =\dfrac{\rho(0) }{(2)}[/tex]

By using the value of H and [tex]\rho(z)[/tex] from (1), we have:

[tex]\dfrac{\rho(0) }{(2)} = \rho (0) e^{(-\dfrac{z}{14856.43})}[/tex]

[tex]\dfrac{1}{2} = e^{(-\dfrac{z}{14856.43})} \\ \\ e^{(-\dfrac{z}{14856.43})} =\dfrac{1}{2}[/tex]

By rearrangement and taking the logarithm of the above equation; we have:

[tex]- z = 14856.43 \times \mathtt{In}\dfrac{1}{2} \\ \\ -z = 14856.43 \times (-0.6391) \\ \\ z = 9495 \ m \\ \\ z = 9.495 \times 10^3\ m[/tex]

As a result, the oxygen density at  [tex]9.495 \times 10^3\ m[/tex] is half of what it is at sea level.

The density of 1 kilogram of gold is

Answers

Answer:

0.02 kg/cm³

Explanation:

The fictional rocket ship Adventure is measured to be 65 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c. As rocket ship Adventure passes by the space dock, the ship's captain flashes a flashlight at 1.20-s intervals as measured by space-dock personnel.

Required:
How often does the flashlight flash relative to the captain?

Answers

Answer:

1.04 s

Explanation:

The computation is shown below:

As we know that

t = t' × 1 ÷ (√(1 - (v/c)^2)

here

v = 0.5c

t = 1.20 -s

So,

1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)

1.20 = t' × 1 ÷ (√(1 - (0.5)^2)

1.20 = t' ÷ √0.75

1.20 = t' ÷ 0.866

t' = 0.866 × 1.20

= 1.04 s

The above formula should be applied

A bucket of water of mass 14.6 kg is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.320 m with mass 11.1 kg . The cylinder pivots on a frictionless axle through its center. The bucket is released from rest at the top of a well and falls a distance 11.0 m to the water. You can ignore the weight of the rope.

Required:
a. What is the tension in the rope while the bucket is falling?
b. What is the time of fall?
c. While the bucket is falling, what is the force exerted on the cylinder by the axle?

Answers

Answer:

a. T = 39.41 N

b. t = 1.76s

c. 150.78 N

Explanation:

Given:

Mass of bucket of water, Mb = 14.6 kg

Mass of cylinder, Mc = 11.1 kg

Diameter of cylinder, D =  0.320 m, or radius, r = D/2 = 0.16m

Displacement of the bucket from the top, that is the vertical displacement , y = 11.0 m

a. The tension in the rope while the bucket is falling is:

F = mg - T = ma

Where F= The force

m= mass

g= Acceleration due to gravity

T = tension in the rope

a = acceleration

T= m(g - a)

Then, calculating the angular acceleration of the pulley system in relation to its radial acceleration

T= 1/2Ma

Merging the two final equation so as to solve for a

M(g - a) = 1/2Ma

Make a the subject of the formula

Mg - Ma = 1/2Ma

1/2Ma + Ma = Mg

a (1/2 M + M) = Mg

Divide both side by (1/2 M + M)

a = Mg ÷ (1/2 M + M)

Inputing the given value in the formula above

g= 9.8m/s2

a = (14.6 kg) (9.8m/s2) ÷ 1/2 (11.1 kg) + 14.6 kg

a = 7.1007m/s2

Now it is easy to input the value into T= 1/2Ma

T = 1/2 (11.1 kg) (7.1007m/s2) = 39.41 N

B. Time of fall is:

Using one of the equation of motion

s = ut + 1/2 at^2

U = Initial velocity

t = time

a = acceleration

s= distance in this case displacement y

making t the subject of the formula

t = √(2s ÷ a)

u is 0 since the bucket starts from rest

so, t = √((2)(11.0 m) ÷ 7.1007m/s2)

t = 1.76s

c.  the force exerted on the cylinder by the axle = T + Mg

  = 42 N + (11.1 kg) (9.8m/s2)

= 150.78 N

An object’s
✔ mass
will remain constant throughout the universe, but its
can change from planet to planet.

If you increase the mass of a planet, what happens to its gravity?

If the gravity on a planet decreases, what happens to the weight of an object on that planet?

Answers

Answer:

mass, weight, strength of gravity increases, weight decreases

Explanation:

got it on edge

Answer:

An object’s

✔ mass

will remain constant throughout the universe, but its

✔ weight

can change from planet to planet.

If you increase the mass of a planet, what happens to its gravity?

✔ strength of gravity increases

If the gravity on a planet decreases, what happens to the weight of an object on that planet?

✔ weight decreases

Explanation:

right on edge 22

what is friction and the types withe examples.​

Answers

Explanation:

The answer is In the picture. Thanks.

Why does Marx’s workers’ paradise resolve the problems of capitalism?

A. Everything is free, and no one has to work.
B. Workers are divided into three classes, much like in Plato’s ideas.
C. There is no currency in the paradise so no economic problems.
D. People work for their own good instead of a factory owner’s.

Answers

we need the story or article

What type of force is F-?

Answers

Answer:

Frictional Force

Explanation:

i think so

the answer is F- is fractional force

If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 15.0 km ? Take the mass of the sun to be ms = 1.99×1030 kg , the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , and the free-fall acceleration at the earth's surface to be g = 9.8 m/s2 . Express your weight wstar in newtons.

Answers

Answer:

W' = 1.66 x 10¹⁴ N

Explanation:

First, we will calculate the mass:

[tex]W = mg[/tex]

where,

W = weight on earth = 690 N

m = mass = ?

g = acceleration due to gravity on earth = 9.8 m/s²

Therefore,

[tex]m = \frac{W}{g} = \frac{690\ N}{9.8\ m/s^2}\\\\m = 70.4\ kg[/tex]

Now, we will calculate the value of g on the neutron star:

[tex]g' = \frac{GM}{R^2}[/tex]

where,

g' = acceleration due to gravity on the surface of the neutron star = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of the Neutron Star = 1.99 x 10³⁰ kg

R = Radius of the Neutron Star = 15 km/2 = 7.5 km = 7500 m

Therefore,

[tex]g' = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{(7500\ m)^2}\\\\g' = 2.36\ x\ 10^{12}\ m/s^2[/tex]

Therefore, the weight on the surface of the neutron star will be:

[tex]W' = mg'\\W' = (70.4\ kg)(2.36\ x\ 10^{12}\ m/s^2)[/tex]

W' = 1.66 x 10¹⁴ N

If a runner is running at 100 meters per minute at the exact moment they cross the finish line of a race, it is the
instantaneous speed.

O True
O False

Answers

Answer:

Hello! Your answer would be, O False

Explanation:

Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby

Answer:

False is the correct answer.

Explanation:

plz mark me as brainliest.

Explain the meaning of the constant of proportionality ​

Answers

Answer:

The constant of proportionality is the ratio between two directly proportional quantities. Two quantities are directly proportional when they increase and decrease at the same rate. The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other.

Explanation:

Imagine you are on a space mission and you are 6 AU's from the Sun and you use a light sensor to measure the brightness of the Sun. The amount of sunlight received per square centimeter would be different by what factor compared to the same measurement on Earth at AU

Answers

Answer:

36 times less.

Explanation:

The distance from you to the sun is 6AU's, and from the sun to the earth is 1 AU.

Therefore,

At Earth sunlight received per unit cm² is:

[tex]I_{earth} = \dfrac{I_o}{4 \pi \times (1)^2}[/tex]

[tex]I_{earth} = \dfrac{I_o}{4 \pi}[/tex]

[tex]I_{me} =\dfrac{I}{4 \pi (6)^2}[/tex]

[tex]I_{me} = \dfrac{I_o}{36(4 \pi)}[/tex]

Thus, [tex]I_{earth} = 36 \times I_{me}[/tex]

Thus, the right answer is 36 times less.

What does it mean if the reflected beam is above the incident beam? What does it mean if reflected beam is below the incident beam?

Answers

Answer:

aim at prisma and will have all colors

Explanation:

Answer:

If the vision position is above the actual image location then the light travel from the object in such a way that the angle of incidence is less than the angle of reflected ray which means that the reflected beam is above the incident beam.

Explanation:

A cold block of metal feels colder than a block of wood at the same temperature. Why? A hot block of metal feels hotter than a block of wood at the same temperature. Again, why? Is there any temperature at which the two blocks feel equally hot or cold? What temperature is this?

Answers

: In general, metals feel colder or hotter to the touch than other materials at the same temperature because they're good thermal conductors. This means they easily transfer heat to colder objects or absorb heat from warmer objects

It is because the metal conducted heat faster than it feels colder than the wood, which conducted heat slower. Even tho they are similar temperatures. The metal will feel colder than the wood because of the thermal conductivity of the metal, compared to the wood.  

A heating coil operates on 220 V if it draws 15.0 A. Find it's resistance

Answers

Answer:

R ≈ 15 ohms

Explanation:

Using ohm's law equation,

I = V/R, to solve for the resistance of the heating coil.

R = V/I

Known:

V = 220 v = 220 kgm^2s^-3A^-1

I = 15 A

Unknown:

R =?

Solution:

R = (220 kgm^2s^-3A^-1)/ 15.0 A

R = 14.6 kgm^2s^-3A^-2

R ≈ 15 kgm^2s^-3A^-2

R ≈ 15 ohms

two bodies of masses 10 kg and 4 kg are moving in opposite direction with the same velocity of 5 m per second if they Collide and stick together after the impact calculate their velocities​

Answers

Answer:

dasd

Explanation:

dsdas

Student Exploration: Energy Conversion in a SystemNCVPS Chemistry Fall 2014Vocabulary: energy, gravitational potential energy, heat energy, kinetic energy, law of conservation of energy, specific heat capacityPrior Knowledge Questions (Do these BEFORE using the Gizmo.)A battery contains stored energy in the form of chemical energy.1. What are some examples of devices that are powered by batteries? ____________________________________________________________________________________________2. What different forms of energy are dmonstrated by these devices? ___________________ _________________________________________________________________________Gizmo Warm-upEnergy constantly changes from one form to another, but in a closed system, the total amount of energy always remains the same. This concept is known formally as the law of conservation of energy.The Energy Conversion in a System Gizmo™ allows you to observe the law of conservation of energy in action. In the Gizmo, a suspended cylinder has gravitational potential energy. When the cylinder is released, the

Answers

Answer:

a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights

b) ed lights and flashlights transform into light energy and thermal energy

c)  Em₀ = U = m gh,  Em_f = K = ½ m v²

Explanation:

In this exercise ask to complete the sentences

a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights

   

b) These devices transform the chemical energy stored in the batteries into other forms of energy.

Led lights and flashlights transform into light energy and thermal energy

Keyboards transform into electromagnetic energy that is emitted

clocks transform to mechanical energy from the movement of the needles

Electronic weights transforms the chemical energy of the baria into gravitational potential energy that prevents the movement of the plate and this translates into the reading of the body weight

c) The total energy of the cylinder mechanical energy when sustained is

          Em₀ = U = m gh

it is transformed as it descends into kinetic energy, at any point

          Emₙ = K + U = 1/2 m v² + m g y

at the lowest point of the trajectory all energy is transformed

           Em_f = K = ½ m v²

what is force,momentum,and velocity.​

Answers

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object.

Momentum is force or speed of movement.

Velocity defines the path of the motion of the frame or the object

Other Questions
ASAPPPP18. The steps used to solve the equation 2x + 8 = 20 for x are shown below.2x + 8 = 20Step I: 2x = 12Step II: x = 6Which property makes Step I true?A. Division property of equalityB. Reflexive property of equalityC. Subtraction property of equalityD. Symmetric property of equality 3. Which of the following is often written in chronological order?memoirbiographyautobiographynovel A man has Rs 1900. he lent some of it at 5% p.a and rest at9% p.a. The total amount of interest which he got after4 years was Rs 580.Wwhat was the sumans= Rs650,Rs 1250 The Brown vs. Board of Education Supreme Court decision stated that segregation is not legal becauseSegregation can be equalit does not separate all races.Segregation cannot ever truly be equal. The third quartile value for thedata set shown in the box plotbelow is:657075808590 How quickly did Germany advance in the beginning of the Second World War ill choose brainliest if bestt Explain some of the different practices of feudalism between Europe and Japan? Which of the following recent presidential candidates is considered to be aprogressive?O A. John McCainB. Barack ObamaC. George W. BushD. Mitt Romney Since the standardization of Christian beliefs, which change has most affected the practice of Christianity? Explain the difference between Bias and Slanters? . Which of the following best describes the protocols used on the Internet?The protocols of the Internet are designed by government agencies to ensure they remain free to useThe protocols of the Internet are secret to maintain the privacy and security of people using themEach device connected to the Internet will use a protocol designed by the company that manufactured itThe protocols of the Internet are open and used by all devices connected to the network Marcy can walk 12 blocks in 5 minutes. If each block is 50 feet long, how many feet will she walk during the 30 minutes that she walks each dog? Please i need help..... again what is equivalent to (3x+1)(4x-1) Please help. Thank you!! Review graph I and graph II. On a coordinate plane, a parabola labeled Graph 2 opens down. It goes through (negative 2, 0), has a vertex at (negative 2, 7), goes through open circle (negative 4, 5), and goes through (negative 6, 0).On a coordinate plane, a parabola labeled Graph 1 opens down. It goes through (negative 2, 0), has a vertex at (negative 2, 7), goes through open circle (negative 4, 5), and goes through (negative 6, 0). An open circle is at (negative 4, 8).Which statement compares the limit as x approaches 4 for the two graphs?In both graph I and graph II, the limit is 5.In both graph I and graph II, the limit does not exist.In graph I, the limit does not exist, but in graph II, the limit is 5.In graph I, the limit is 8, but in graph II, the limit does not exist. Which point does not pass through?10 Points What is the range of fat grams for the five sandwiches?A. 15B. 16O c. 21D. 21.2.O E. 24 The ability of an ecosystem to support life declines sharply after a population crashamong some of the organisms. A population crash among organisms with whichcharacteristic could have caused the sharpest decline?A hibernation during the winterB mobility on land and in the airC conversion of sunlight into food energyD different fur coloring in summer and winter