Zach's apparent weight before the elevator starts breaking is 686 N.
Zach's apparent weight while the elevator starts breaking is 966 N.
Given that, mass of Zach = 70 kg
His weight W = mg = 70* 9.8 = 686 N
If the elevator is going down at a constant velocity then, acceleration is zero and the apparent weight before braking is 686 N.
v = u + a * t
where,
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
Making a as subject from the above equation,
Acceleration a = (v - u)/t = (0-12)/3 = -4 m/s²
While the elevator is braking it has acceleration -4 m/s².
W = m ( g - a) = 70 (9.8 - (-4)) = 70(9.8 + 4 ) = 966 N
The apparent weight of Zach is 966 N.
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Which of the following statements are true?Check all that apply.Check all that apply.The path of the planets around the Sun is elliptical in shape.The Sun is located at the center of the of the planets' circular orbits.The Sun is located at one of the foci of the planets' elliptical orbits.The path of the planets around the Sun is circular in shape.
1.The Sun is located at one of the foci of the planets' elliptical orbits.
2.The path of the planets around the Sun is elliptical in shape. are the correct statement.
According to Kepler's law of planet motion, the sun must be located at one of the path's foci for all planets to rotate around it in an elliptical fashion.Consequently, every planet follows an ellipse course. The sun's position is constantly in the forefront.The orbits of planets around the Sun are described by Kepler's laws of planetary motion, which he published between 1609 and 1619.The laws replaced the circular orbits and epicycles of Nicolaus Copernicus' heliocentric theory with elliptical trajectories and provided an explanation for the variation in planetary velocities.For more information on Kepler's law kindly visit to
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a hohmann transfer is a fuel efficient transfer orbit to an outer planet. the process requires placing a spacecraft into an elliptical orbit about the sun, such that the perihelion, the point closest to the sun, is at the departure planet and the the aphelion, the point farthest from the sun, is at the arrival planet. the entire trajectory is depicted below.(a) Use Kepler's third law to calculate how long it would take to go from the Earth to Mars on such an orbit. (b) Can such a transfer be undertaken at any time? Explain.
A chemical rocket may launch a satellite into a Hohmann transfer orbit and maintain it there until it reaches the farthest point in the orbit by performing two very powerful burns.
These chemical rockets aren't very effective, though. They would have perished because it would have taken four weeks to return to Earth orbit.One (very powerful) engine burn is all that the Hohmann transfer orbit requires. But the interval between the two engine burns is nearly half an orbit, or 2 weeks in the event of an Earth to Moon transfer, as opposed to 3 days for the Apollo approach.That translates into four times as much food, oxygen, and cramping in the muscles, which results in increased mass and fuel. Apollo 13 remained on its orbit around the Moon after their oxygen tank exploded, depriving them of electrical power and heating, and returned to Earth after nearly 5 days.They would have perished if they had been in a Hohmann transfer orbit, which would have taken around 4 weeks to return to.
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A staging that weighs Wstaging supports a painter weighing 300 N. The reading on the left scale is 580 N and the reading on the right scale is 270 N. What is the weight of the staging?
The weight of the staging is 550N.
The weight of an object, the gravitational force caused by the presence of a large second object such as the Earth or the Moon.
The unit of measurement for weight is indeed a unit of force. This unit in the International System of Units (SI) is the Newton.
Given data : Weight of the painter ([tex]W_{p}[/tex]) = 300 N
Left scale's weight reading [tex](W_{L} )[/tex] = 580 N
Right scale's weight reading [tex](W_{R} )[/tex] = 270 N
To find the weight of the staging [tex](W_{s} )[/tex], we will set all the weight in the equilibrium.
Since the force of the staging and painter's weight is going downward we will denote them as negative. The opposite will be placed for the reading of weight on the left and right scale, which is positive.
[tex]-W_{p} -W_{s} +W_{L}+W_{R} = 0[/tex]
[tex]-300N-W_{s} +580N + 270N = 0\\[/tex]
[tex]W_{s}[/tex] [tex]= -300N+580N+270N[/tex]
[tex]W_{s}[/tex] [tex]= 550N[/tex]
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if you are in a car with a helium balloon in the middle of the back seat and you turn left, which way does the balloon move and why? physics.stackexchange
If you are in a car with a helium balloon in the middle of the back seat and you turn left, the balloon moves towards right.
A change in the air's surrounding density causes a helium-filled balloon to move.
The balloon operates in opposition to what your body would normally do. Therefore, if the automobile stops, the balloon will move to the back. The secret is that you are composed of materials that are significantly heavier than air and that the balloon is loaded with helium (He).
Turn left, the balloon goes right. When you turn right, the balloon moves to the left; when you stop, it moves to the right.
It has to do with the motion of the air in your car. When you start moving forward while stationary, all of the air in the car rushes to the back, where it builds up an area of higher air pressure.
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A car moving with a speed of 90km/hr was brought to rest by the application of the
Brakes in 10s How far did the car travel after the brakes were applied?
The distance travelled by the car after the brake was applied is 125 m.
What is the distance travelled by the car?
The distance travelled by the car is calculated by applying the following kinematic equation as shown below.
Mathematically, the distance travelled by the car at the given average speed is calculated as;
s = [ ( v + u ) / 2 ] t
where;
v is the final velocity of the car = 0u is the initial velocity of the car = 90 km/hr = 25 m/st is the time of motion of the car = 10 sThe distance travelled by the car is calculated as;
s = [ ( 0 + 25 m/s ) / 2 ] ( 10 s )
s = 125 m
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A point charge e moves along the x-axis with uniform velocity v, so that its position x at time t is given by x =v t . Derive an explicit expression for the potential φ(t ) at the point (0, b, 0). The differential equation obeyed by φ(x, t ) is ∇2φ− (1 /c2 )∂2φ /∂t 2 =−4πrho where rho is the charge density.
The potential at the point (0, b, 0) is given by: φ(t) = 0 This means that the potential at the point (0, b, 0) is constant in time and equal to zero.
The potential at a point in space is a measure of the electric potential energy per unit charge at that point. The potential at a point is affected by the presence of charges in the surrounding space. In this problem, a point charge e is moving along the x-axis with uniform velocity v, and we want to find the potential at the point (0, b, 0) at time t. To find the potential at this point, we used the differential equation for the potential: ∇2φ− (1 /c2 )∂2φ /∂t 2 =−4πrho. This equation relates the potential at a point to the charge density in the surrounding space. The charge density at any given time t is given by rho = eδ(x - vt), where δ is the Dirac delta function. This expression represents a point charge located at x = vt. Substituting this expression for the charge density into the differential equation for the potential, we obtained: ∇2φ− (1 /c2 )∂2φ /∂t 2 =−4πeδ(x - vt). However, the point (0, b, 0) is not on the x-axis, so it is not affected by the delta function. This means that the potential at the point (0, b, 0) is not influenced by the presence of the point charge, and is therefore constant in time and equal to zero.
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A certain 50.0-Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 13.0 kV/m. (a) What is the wavelength of this very low frequency electromagnetic wave? (b) What is its maximum magnetic field strength?
An electromagnetic wave radiating from a specific 50.0-Hz AC power line has a maximum electric field strength of 13.0 kV/m. This extremely low frequency electromagnetic pulse has a wavelength of 6.00 x [tex]10^{6}[/tex]m.
An electromagnetic wave is what?A sinusoidal graph illustrates electromagnetic waves. It is made up of time-varying electric and magnetic fields that are perpendicular to each other and to the direction that waves travel.
How do wavelength and frequency relate to one another?Inverse proportionality describes the relationship between frequency and wavelength. Longer wavelengths are correlated with lower frequency, and vice versa. The fact that a wave's speed is equal to the product of its frequency and wavelength helps to explain how these two properties are related.
Briefing:
Given that,
Frequency of the power line, f = 50.0 Hz
Value of maximum electric field strength of 13.0 kV/m
The wavelength of this very low frequency electromagnetic wave is given by using relation as:
[tex]c = f[/tex]λ
λ [tex]= \frac{c}{f}[/tex]
λ [tex]= \frac{3.8 * 10^{8} m/s }{50}[/tex]
λ = 6 x [tex]10^{6}[/tex] m
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A hippo's body is 4.0 m long with front and rear feet located as in (Figure 1). The hippo carries 60% of its weight on its front feet. Figure <1 of 1 Part A How far from its tail is the hippo's center of gravity? Express your answer with the appropriate units. S → ?
The distance of center of gravity from tail. now torque balance about center of gravity 1.58m
Let the total weight be w.
Then weight carried by front leg=60% of w
=0.6w
weight carried by back leg
=w-0.6w
=0.4w
Here d is the distance of center of gravity from tail. now torque balance about center of gravity.
The torque or moment is the result of the force and the perpendicular distance from the center of gravity for an open object or from the pivot for a closed item to the pivot. In the same way that a force causes a translation, a torque, which is also a vector variable, causes a rotation.
T1=T2
F1 X L1=F2 X L2
0.40(d-0.5)=0.6w(0.5+1.8-d)
2(d-0.5)=3(2.3 - d)
2d - 1= 6.9-3d
5d=7.9
d=7.9/5=1.58m
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crane lifts a 400 kg crate upward with an acceleration of 3.00 m/?. Determine the force on the crane.
The crane is under 5120 N of force. The crane touches the rock boulder and uses mechanical force to lift it.
What are the units of a force?Force is a physical phenomenon that can change an object's shape as well as its state of motion or rest. The SI unit of force is the Newton.
Cranes fall under which of the following three forces?Jib, gantry, and overhead cranes are the three pieces of machinery used most frequently in the industry. Depending on the type of item to be moved, either a chain or wire rope hoist will be used. In the shipbuilding sector, material handling is the main use of overhead cranes during the assembly process.
Briefing:
Mass (m) = 400kg
Acceleration (a) = 3.00 m/s^2
Gravitational acceleration (g) = 9.81 m/s^2
Force (F) = mg + ma
Force (F) = m (g + a)
Force (F) = 400 (9.81+3)
Force (F) = 5120 N
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A diffraction grating 20.0 mm wide has 6000 rulings. Light of wavelength 589 nm is incident perpendicularly on the grating. What are the (a) largest, (b) second largest, and (c) third largest values of theta at which maxima appear on a distant viewing screen?
6000 rulings are present on a 20.0 mm broad diffraction grating. The maximum value of theta at which maxima show on a distant viewing screen for light with a wavelength of 589 nm is 62.1 °, followed by 45.0 ° and 32.0 °.
Adjacent rulings are separated by a distance of d = 20.0mm/6000 = 0.00333mm = 3.33m. Let dsin equal m (0, 1, 2,...). The greatest value of corresponds to m=5, which results in = sin 1(m/d)= sin 1 (5(0.589m)/3.33m)=62.1 ° b) because m/d>1 for m6. The second-largest value of is equal to m=4, which results in the expression = sin 1 (m/d) = sin 1 (4(0.589 m)/ 3.33 m)= 45.0° c. When m=3—the third-largest value of —is used, the result is = sin 1 (m/d) = sin 1 (3(0.589 m)/3.33 m) = 32.0°.
Diffraction is the interference or bending of waves via an aperture or around an obstruction's corners into the region that is physically in its geometric shadow. In essence, the diffracting component or aperture becomes a second source of the wave. Francesco Maria Grimaldi, an Italian physicist, was the first to precisely record the occurrences of the phenomena in 1660 and also coined the name "diffraction".
An unlimited number of locations (three shown) along length d that project phase contributions from the wavefront cause a continuously varying intensity () to be created on the license plate.
The diffraction phenomenon is explained by the classical physics idea known as the Huygens-Fresnel principle, which views each point in a propagating wave front as a group of distinct spherical wavelets.
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One of the most controversial ideas to come out of instinct theories of aggression was Lorenz's proposal that society provide acceptable ways of permitting , or the process of discharging built-up aggressive energy.
The general instinct hypothesis, which contends that people are physiologically predisposed to or possess inclinations for violent behaviours, is known as the instinct theory of aggression in psychology.
This theory is more focused on aggression. The instinct theory of aggressiveness holds that human aggression is akin to sex and hunger, and that it can only be regulated rather than eradicated.In an effort to understand why we become aggressive and whether that behaviours can be altered, psychologists have developed three primary theories of aggression. Although many hypotheses have been put out, these three have proven most reliable and are crucial to comprehending the origins of violence. These hypotheses comprise as,
Adversity theory based on instinctTheory of Frustration and AggressionTheory of Social LearningTo know more about theory of aggression
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In a diffraction experiment, a coherent light source illuminates a pair of identical slits in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by 2.05 m. A student sketches the pattern that appears on the screen. The locations of the centers of the bright and dark fringes are accurate, but the shading is only qualitative. The color chosen may not be an ideal match to the actual light source. TITUTE THI HT -50.0 -40.0 -30.0 -20.0 -10.0 0.0 10.0 20.0 30.0 40.0 50.0 y (cm) * 25% Part (a) Enter the ratio of the slit separation, d, to the slit width, D, as a whole number. d = D TT 7 8 9 HOME E 4 5 6 sino cos tan cotano asin acos atan acotan sinh cosho tanh) cotanh O Degrees Radians 1 2 3 + 0 END . VO BACKSPACE DE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. A 25% Part (b) Calculate and enter the ratio of the slit width to the wavelength of the light source. A 25% Part (C) If the slit separation is 17 um, then calculate and enter the wavelength, in nanometers, of the light source. 25% Part (d) What is the slit width, in micrometers?
(a) The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width, in micrometers;
d = 20.5 µm
(a) We know that Fringe width is given by,
[tex]\beta =\frac{D\lambda}{d}[/tex]
Where,
D = slit to screen distance
λ = wavelength
d = slit width
Given in the question,
D = 2.05 m
[tex]\beta =4 cm=0.04m[/tex]
Now,
[tex]\frac{d}{D} =\frac{\lambda}{\beta } =\frac{400*10^{-9} }{0.04}[/tex]
d/D = 0.0001
Hence,
The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b) Ratio of d & λ,
[tex]\frac{d}{\lambda} =\frac{D}{\beta }[/tex]
[tex]\frac{d}{\lambda}=\frac{2.05}{0.04}[/tex]
[tex]\frac{d}{\lambda}=51.25[/tex]
Hence,
The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength of the light source,
[tex]\lambda=\frac{D\beta }{d}[/tex]
[tex]\lambda=\frac{17*10^{-6} *0.04}{2.05}[/tex]
[tex]\lambda=331.7nm[/tex]
Hence,
The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width,
[tex]d =\frac{D\lambda}{\beta }[/tex]
[tex]d=\frac{400*10^{-9} *2.05}{0.04}[/tex]
[tex]d=20.5 \mu m[/tex]
Hence,
The slit width, in micrometers;
d = 20.5 µm
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the two weights are released from rest. the coefficient of kinetic friction between the horizontal surface and the 5 lb weight is 0.18
The final velocity of the weights will be 3.31 m/s
Weight = 5 lb
Coefficient of kinetic friction (µ) = 0.18
let T be tension
[tex]m_{1}[/tex]*g-T =[tex]m_{1}[/tex]*a
[tex]m_{1}[/tex] =10 lb = 4.53 kg
T-(µ)[tex]m_{2}[/tex]g =[tex]m_{2}[/tex]a
Adding both equations, we have
([tex]m_{1}[/tex]-k[tex]m_{2}[/tex])g =[tex]m_{2}[/tex] a
a = (4.53-0.2*2.26)*10/2.26 =18.04 [tex]m/s^{2}[/tex]
Using the equation of motion, we have,
[tex]v^{2} -u^{2} =2as[/tex]
Since the body starts from rest, the initial velocity, that is, u is zero.
So, u = 0 m/s
Putting this value in the above equation to calculate the final velocity, we have,
[tex]v^{2}[/tex] = 2as
v = [tex]\sqrt{(2*18.04*0.304) }[/tex]= 3.31 m/s
Thus, the final velocity of the weights will be 3.31 m/s
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Analyze the motion of a rock dropped in water in terms of its speed and acceleration as it falls. Assume a resistive force is acting on the rock that increases as the velocity of the rock increases.
The acceleration of the rock would be constant as well as the velocity of the rock as it falls.
How does the rock move?We know that the motion of the rock would be in accordance to the principles of the motion of an object under gravity. If we drop the rock, we have to know that the rock would be acted upon by a system of forces. The system of the forces that act on the rock would determine the magnitude of the acceleration of the rock.
The forces that act on the rock as it is falling are as follows;
1) Weight of the rock
2) Drag force
We know that these two forces do actually act in the opposite direction to each other as the rock is falling. The velocity of the rock would change greatly as the rock falls. The velocity of the rock would be reducing gradually and this would continue until the rock would attain a constant terminal velocity.
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A(n) ____________________ is a dynamic variable on the free store without any pointer pointing to it.
A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.
How to find the height of an inaccessible object using sextant?Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.
How can heights and distances that are absent or unavailable be measured?The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.
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Answer:
dynamic variable
A string with one fixed end and an open end is observed to form a standing wave with a frequency of 250 Hz in its fundamental mode. It will also form a standing wave at frequency A) 500 Hz 650 Hz C)) 750 H:z 800 Hz E) 1000 Hz f 250
It will also form a standing wave at frequency C)) 750 H:z
What is frequency?The frequency of a repeating event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarity. Hertz, which equals one event per second, is the unit used to measure frequency.
The formula for standing wave frequency goes with the order nf (n=1,3,5,7,....) for one end of the string fixed at one point and the other at the open end.
Here in nf, f means the fundamental frequency that is when the order, n =1 . Here given that the fundamental frequency (n=1) as 250 Hz. Hence the other frequencies that can be formed according to the formula nf (n=1,3,5,7,....) are 750 Hz (n=3) , 1250 Hz (n=5), 1750 Hz (n=7) .. and so on.
The available frequency under the question is 750 Hz , when it comes to the options.
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applications of coherence
Coherence is a property of a system or text that refers to its internal consistency and the logical relationships between its parts. Coherence is important in many fields and contexts, as it allows people to understand and interpret information accurately and effectively. Some specific applications of coherence include:
Writing: Coherence is an important aspect of writing, as it helps to make text clear, logical, and easy to understand.Communication: Coherence is also important in communication, as it helps to ensure that messages are understood correctly and that there is a clear flow of information between people.Science: In scientific research, coherence is important to ensure that theories and hypotheses are based on logical and consistent evidence.Decision making: Coherent thinking is also important in decision-making, as it helps to ensure that decisions are based on sound reasoning and logic.Learning: In education, coherence is important for learning and understanding, as it helps to ensure that information is presented in a logical and coherent manner.If a 10.4kg block rests on a rough horizontal table with a coefficient or friction of u=0.15 then what is the resulting force of friction on the block ?
Mathematically, F is1.56 represents the resulting force of friction on the block. The Frictioval force's mathematical equation is typically represented as F is uN.
How can the force of friction be calculated?The resistive friction force (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), a numerical value. The formula fr = Fr/N is used to represent it.The block will now start to slide as P is increased continuously, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, and f staying constant after that as P is increased.The resistive friction force (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), a numerical value.Explanation:
Mathematically, F=1.56 represents the resulting force of friction on the block.
The Frictioval force's mathematical equation is typically represented as F=uN.
u equals the friction coefficient.
N is normal force.
frictional force
As a result, the force of friction on the F=10.4*0.15 F=1.56
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the 30kg girl pushes the 20kg boy, and he moves away at a speed of 2.0m/s. if momentum is conserved, what is the girls speed?
The initial momentum of the girl is conserved with the equal final velocity for both of them . Hence, the momentum of the girl is 60 kg m/s.
What is momentum?Momentum of a moving body is the product of velocity and mass of the body. Momentum is a vector quantity and is characterized by its magnitude and direction. The unit of momentum is Kg m/s.
During collision, the total momentum of a body is conserved. Therefore, total initial momentum of the colliding bodies is equal to the final momentum where they both move in equal velocity.
Here, the boy moves in 2 m/s. The velocity of the girl will be the same.
Hence, her momentum = mass × velocity
= 30 Kg × 2 m/s = 60 Kg m/s.
Therefore, the momentum of the girl is 60 kg m/s.
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Aspace station has a mass M and orbits Earth in a circular orbit at a height above Earth's surface. Space Station Earth A payload of mass m, where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km farther away from Earth's surface than before. Which of the following best describes the effects of these changes on Earth's gravitational field strength at the space station's new location? The increase in mass of the space station has no effect on the field strength, and the increase in orbital radiun decreases the field strength A B The increase in mass increases the field strength, and the increase in orbital radius decreases the field strength, however, the field strength decreases overall A payload of mass m, where m
The increase in mass of the space station has no effect on the field strength, and the increase in orbital radium decreases the field strength
What is Earth's Gravitation Field?
Earth's gravitation field is the force any object experiences due to the gravitational pull by earth. It's formula is given below where G is the force, m is the mass of earth and r is radius of distance.
As seen through the formula, the gravitation field strength is only depend on earth's mass which is constant and radius of the distance. Hence, the increase in mass of the space station has no effect on the field strength, and the increase in orbital radium decreases the field strength.
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when the glass gob comes out of the oven, it is dangerously hot. What happens to the thermal energy of the gob between that time and when it is a bottle than can be touched?
Answer:
decreases
Explanation:
The thermal energy of the gob decreases by heating the air around the gob and the mold in which the bottle is made
A customer can choose one of six speaker systems, one of five DVD players, and one of six flat screen televisions to design a home entertainment system.
A customer can choose one of six speaker systems, one of five DVD players, and one of six flat-screen televisions to design a home entertainment system:
In order to determine the number of possible system configurations
A customer is a person or business that buys items or offerings from another business. clients are vital due to the fact they generate sales. without them, organizations might go out of business.
A client is commonly defined as someone who buys a terrific, product, or carrier. more, in particular, clients are human beings or agencies currently shopping, have bought, or maybe inquisitive about buying services or products from every other character or enterprise.
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if the sentence is true, write a response that would convince a classmate that the sentence is indeed true. If you think that the sentence is not true, write a response that would convince a classmate the sentence is not true
1.A 10 cm radius Styrofoam sphere is submerged in water. So is a 10 cm radius lead sphere. The buoyant force exerted by the water on the Styrofoam sphere is greater than the force exerted on the lead sphere
2.Hot air balloons could be improved by filling them with hydrogen instead of heated air.
A 10 cm radius Styrofoam sphere is submerged in water. So is a 10 cm radius lead sphere. The buoyant force exerted by the water on the Styrofoam sphere is greater than the force exerted on the lead sphere is true.
2.Hot air balloons could be improved by filling them with hydrogen instead of heated air is ta true statement.
How do you prove the statements above?Case I- Styrofoam sphere
The buoyant force exerted by a fluid on an object is equal to the weight of the fluid that the object displaces. This means that the buoyant force exerted on the Styrofoam sphere and the lead sphere will be determined by the amount of water that each sphere displaces when it is submerged.
The Styrofoam sphere has a lower density than water, so it will displace a greater volume of water than the lead sphere, which has a higher density than water. This means that the buoyant force exerted on the Styrofoam sphere will be greater than the force exerted on the lead sphere.
To calculate the buoyant force on each sphere, you can use the following formula:
Buoyant force = weight of displaced fluid
The weight of the displaced fluid is equal to the volume of the fluid displaced multiplied by the fluid's density. You can use the formula for the volume of a sphere (V = 4/3πr^³) to calculate the volume of water displaced by each sphere.
For example, if the density of water is 1 g/cm^³ and the radius of each sphere is 10 cm, the volume of water displaced by the Styrofoam sphere would be:
4/3π(10 cm)^³
= 4/3π1000 cm^³
= 4347.19 cm^³
The weight of the displaced water would be:
4347.19 cm^³ * 1 g/cm^³
= 4347.19 g.
The buoyant force on the Styrofoam sphere would therefore be 4347.19 g.
The volume of water displaced by the lead sphere would be the same as the Styrofoam sphere (4347.19 cm^3), but the weight of the displaced water would be greater, due to the higher density of lead.
The weight of the displaced water for the lead sphere would be:
4347.19 cm^³ * 11.34 g/cm^³
= 49359.93 g,
The buoyant force on the lead sphere would be:
49359.93 g.
Therefore, the buoyant force on the Styrofoam sphere would be less than the force on the lead sphere, as stated in the original statement.
Case 2-Hot air balloons
Hydrogen is a lighter-than-air gas, which means that it is less dense than air and has a lower molecular weight. This makes it a potential alternative to heated air as a lifting gas for hot air balloons.
One advantage of using hydrogen as a lifting gas is that it is more buoyant than air, so a hot air balloon filled with hydrogen would be able to lift a greater payload than a balloon filled with air. This could make it possible to design hot air balloons that are larger or carry more passengers or cargo.
However, there are also some significant drawbacks to using hydrogen as a lifting gas for hot air balloons. One concern is the flammability of hydrogen, which is highly explosive and can ignite easily. This makes it potentially dangerous to use in a hot air balloon, as any leaks or accidents could result in a fire or explosion.
Overall, while hydrogen has some potential advantages as a lifting gas for hot air balloons, the risks and costs associated with its use may make it less practical than other options.
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A uniform plane wave with parallel polarization is propagating in a lossless dielectric medium (l is € 1), and is incident obliquely onto a plane boundary with another lossless dielectric medium (u 2, E 2). (30%) (a) Derive the Snell's laws of reflection and refraction in terms of the refractive indices and angles. (b) Derive the general expressions for the reflection and the transmission coefficients of the EM field. Find such expressions in terms of the refractive indices if both media are nonmagnetic, i.e., M F M 240. (c) Derive the general expression for the Brewster angle. Find such an expression in terms of the refractive indices if both media are nonmagnetic. (d) Prove that, under the condition of no reflection, the sum of the Brewster angle and the angle of refraction is 90° if both media are nonmagnetic. (e) For total reflection to occur, find the condition for the medium property and the critical angle.
Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2
The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.
The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.
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Titan, the largest satellite of Saturn, has a thick nitrogen atmosphere. At its surface, the pressure is 1.5 Earth-atmospheres and the temperature is 94 K.
A) What is the surface temperature in ?
B) Calculate the surface density in Titan's atmosphere in molecules per cubic meter.
C) Calculate the density of Earth's atmosphere at 22 .
A) Surface temperature is the temperature at the surface.
B) The surface density in Titan's atmosphere in molecules per cubic meter is 1.17 x 10²¹ molecule/m³
C) The density of Earth's atmosphere is 0.0012 g/cm³
A) Surface temperature is the temperature at the surface, it can be defined differently for different surfaces:
Surface air temperature, air temperature near the earth's surface.
Sea surface temperature, the temperature of water near the surface of the ocean.
Global surface temperature, the combined global average of surface air temperature and sea surface temperature.
The surface temperature of the star, often the effective temperature.
B) According to the Gas equation, PV = nRT
P: pressure = 1.5 Earth-atmospheres = 1.5 atm
R: ideal gas constant = 8.205 m^3.atm.mol^-1.K^-1
T: temperature in Titan = 94K
n: number of moles
So as to calculate no. of moles per cubic meter N = (n/v) = (P/RT)
N' = N*A = (AP/RT)
A: Avogadro's number = 6.022*109^23 molecules/mol
N': molecules per cubic meter
By putting all the values in the formula,
N' so obtained is 1.17 x 10²¹ molecule/m³
C) The density of Earth's atmosphere 0.0012 g/cm³ or 1.217 kg/m³.
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two loops of wire are arranged so that a changing current in one will induce a current in the other. if the current in the first is increasing clockwise by one amp every second, the current in the second loop will? a. be increasing counterclockwise. b. stay constant. c. increase clockwise also. d. stay zero
Answer:
An induced current in a changing magnetic field will be in such a direction as to oppose the magnetic field causing the induced current.
Thus, the current in the second loop must be increasing in a counterclockwise direction (a)
The induced current must produce magnetic field that opposes the field producing the change or perpetual motion could occur.
The half-life for a 200 gram sample of radioactive element X is 5 days. How much of element X remains after 15 days have passed?
A. 200 g - no change
B. 25 g
C. 50 g
D. 12.5 g
Answer:
B.) 25g
Explanation:
The easiest way to solve this problem is to realize that the sample has gone through three half-lives (15÷5=3).
Use this information to calculate how much of the original 200g sample is left after the three half-lives:
[tex](\frac{1}{2})(200g)=100g\\(\frac{1}{2})(100g)=50g\\(\frac{1}{2})(50g)=25g[/tex]
So, after three half-lives, the remaining sample has a mass of 25g.
for the circuit below all values are rms with a source frequency of 60 hertz. the generator impedance is negligible (0 w). calculate the value of ib and and determine the value of vb-n. now, calculate the rms values of apparent, real and reactive power of zb. (show units for all)
The reactive power of the branch (Qb) can be calculated from its voltage and current 676.16 VA.
What is reactive power?Reactive power is the power in an AC circuit that is required to establish and maintain a voltage across a load. It is associated with the storage and release of energy in the form of electric and magnetic fields. Reactive power does not contribute to the actual work output of a system and is measured in Volt-amperes reactive (VARs). Power factor is a measure of reactive power relative to the total power in a system.
Source frequency = 60 Hz
Generator impedance = 0 W
Circuit:
Vg = 170 V
R1 = 10 Ω
R2 = 20 Ω
Zb = 20 + j10 Ω
The current flowing through the generator (Ig) and the branch (Ib) can be calculated from Ohm's Law:
Ig = Vg/R1 + Vg/R2 = 170/10 + 170/20 = 17 A
Ib = Ig - Vg/Zb = 17 - 170/(20 + j10) = 17 - 16.4 + j4.4 = 0.6 + j4.4 A
Since Ib is a complex number, we can find its magnitude (|Ib|) and angle (θ):
|Ib| = √(0.6² + 4.4²) = 4.46 A
θ = tan⁻¹(4.4/0.6) = 80.16°
The voltage across the branch (Vb-n) can be calculated using Ohm's Law:
Vb-n = Ib × Zb = (0.6 + j4.4) × (20 + j10) = -8.4 + j74.4 V
The apparent power of the branch (Sb) can be calculated from its voltage and current:
Sb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = -45.48 + j367.04 VA
The real power of the branch (Pb) can be calculated from its voltage and current:
Pb = Vb-n × Ib = (-8.4 + j74.4) × (0.6 + j4.4) = -45.48 - j367.04 W
The reactive power of the branch (Qb) can be calculated from its voltage and current:
Qb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = 676.16 VA
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Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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Page 69 Section Review 3-1,3-) When an acrobat reaches the equilibrium position, the net force acting along the direction of motion is zero. Why does the acrobat swing past the equilibrium position?
According to the 1st law of motion (the law of inertia), the acrobat past the equilibrium position because he/she is initially in motion.
(or it gains momentum as approaching to equilibrium position and pass there with that momentum)
