14. A professor records the number of class days (x) each student misses over the course of a semester and uses a frequency distribution to display the data. What is the probability a student missed exactly 1 day

9514 1404 393

Answer:

Step-by-step explanation:

Reflection over the x-axis changes the sign of the y-coordinate. Reflection over the y-axis changes the sign of the x-coordinate. We can summarize the transformations as ...

  preimage point ⇒ reflection over x ⇒ reflection over y

A(−8,−2) ⇒ A'(-8, 2) ⇒ A"(8, 2)

B(−4,−3) ⇒ B'(-4, 3) ⇒ B"(4, 3)

C(−2,−8) ⇒ C'(-2, 8) ⇒ C"(2, 8)

D(−10,−6) ⇒ D'(-10, 6) ⇒ D"(10, 6)

Answer:

c=80

Step-by-step explanation:

Based on my reading the critical damping occurs when the discriminant of the quadratic characteristic equation is 0.

So let's see that characteristic equation:

20⁢r^2+c⁢r+80⁢=0

The discriminant can be found by calculating b^2-4aC of ar^2+br+C=0.

a=20

b=c

C=80

c^2-4(20)(80)

We want this to be 0.

c^2-4(20)(80)=0

Simplify:

c^2-6400=0

Add 6400 on both sides:

c^2=6400

Take square root of both sides:

c=80 or c=-80

Based on further reading damping equations in form

a⁢y′⁢′+b⁢y′+C⁢y=0

should have positive coefficients with b also having the possibility of being zero.

Answer:

The answer is 890 . ...... :D

Answer:

1548.3 [tex]m^{2}[/tex]

Step-by-step explanation:

Answer:

A = 1548.3 m²

Step-by-step explanation:

Answer:

Hello,

5 s

Step-by-step explanation:

[tex]h(t)=-16t^2+48t+160\\=-16(t^2-3t-10)\\=-16(t^2-5t+2t-10)\\=-16(t(t-5)+2(t-5))\\=-16(t-5)(t+2)\\\\h(t)=0 \Longleftrightarrow\ t=-2\ or\ t=5\\\\Only\ t=5\ is \ a\ answer.(time\ must\ be\ positive)[/tex]

Answer:

(cosB-1)(cosB+6)

Step-by-step explanation:

use u substitution . u = cosB

u^2+5u-6

factor

(u-1)(u+6)

put cosB back in for u

(cosB-1)(cosB+6)

Answer: the radius is perpendicular to the chord.

If a radius of a circle bisects a chord which is not diameter, then the radius is perpendicular to the chord.

Answered by Gauthmath must click thanks and mark brainliest

The radius is perpendicular to the chord.

If the radius of the circle is perpendicular to the chord of the circle, the radius bisects the chord. The two strings are congruent only if they are equidistant from the center of the circle.

No, not all strings in a circle are diameters because the diameter passes through the center of the circle. Therefore, all the diameters of a circle are also strings, not all the strings of a circle.

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Answer:

125000000

Step-by-step explanation:

1.25 x 10^8

Move the decimal 8 places to the right

1.25

We can move it two places

125

We need to add 6 more zeros

125000000

Answer: 125,000,000

Step-by-step explanation:

Answer: I'm not Einstein sorry

Step-by-step explanation:

Have to be smart as Einstein.................Which I'm not

Answer:

All of area is πr²

Step-by-step explanation:

and we should write the area kind of radian. So if all area is π*(12)²= 144π - this for 360°- and 240° is 96π

but we must add area of the triangle which has two same side and has 6 high so it's area is 6*12√3/2 = 36✓3

our answer is 96π+ 36✓3

Answer:

There are three basic trigonometric ratios: sine , cosine , and tangent .

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

Part A

The slope is found by

m = ( y2-y1)/(x2-x1)

    = ( 1200-1500)/(4-0)

    = -300/4

    =-75

Part B

point slope  y-y1 = m(x-x1)  where m is the slope and (x1,y1) is a point on the line

y-1200 = -75(x-4)

slope intercept  y = mx+b  where m is the slope and b is the y intercept

y = -75x + 1500

standard form  Ax+By =C

75x + y = 1500

Part C

Change y to g(x) in the slope intercept form

g(x) = -75x + 1500

Part D

Let x = 5

g(5) = -75(5) + 1500

      =-375+1500

      =1125

[tex]\\ \sf\longmapsto A=πr^2[/tex]

[tex]\\ \sf\longmapsto A=3.14(5)^2[/tex]

[tex]\\ \sf\longmapsto A=3.14(25)[/tex]

[tex]\\ \sf\longmapsto A=78.5cm^2[/tex]

Answer:

20+(x+1) = 5x

x=21/4

x= 5.25

The entrance ticket per person can be calculated using algebraic equation. We have create the algebraic expression as per the question.

The entrance ticket per person is Rs. 5.25.

Given:

Total boys are 5

4 boys has 5 rupee each so total rupee are [tex]=5\times 4=20[/tex].

Let the entrance ticket per boy is [tex]x[/tex].

One boy had 1 rupee more than entrance ticket [tex](x+1)[/tex].

Write the algebraic expression to calculate the entrance ticket per person.

[tex]5x=20+(x+1)\\5x=20+x+1\\5x-x=20+1\\4x=21\\x=5.25[/tex]

Thus, the entrance ticket per person is Rs. 5.25.

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Answer:

statistics are when data analyzed in order to make decisions about the population behind the data.

The correct answer to the question is Statistics (Option D).

What is statistics?

Statistics is a field of study in mathematics which deals with raw data. It is a tool which refines the data to produce meaningful results and a pathway to better understanding of it.

Some examples of raw data can be population sample which loves to see a particular TV show or a sample of students getting so and so marks in Math test.

Data is analyzed mainly by three different measure of central tendency that is mean, median and mode.

Therefore, Statistics the correct answer.

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Answer:

3/4

Step-by-step explanation:

To find the common ratio, take the second term and divide by the first term

3/4

Check with the third and second terms

9/4 ÷3

9/4 *1/3= 3/4

The common ratio is 3/4

Answer:

The sequence has first term 7 and common difference is 8.

So the sequence is f(n)=7 + 8(n-1)

Step-by-step explanation:

Let a be the first term.

Let a+d be the second term where d is the common difference.

Then a+2d is the third....

And a+(n-1)d is the nth term.

Adding these terms we get:

an+(n-1)(n)/2×d

For the first term of this sum I seen we had n amount of a's and for the second term I used the well known identity sum of the first n positive integers is n(n+1)/2.

Let's simplify:

an+(n-1)(n)/2×d

Distribute:

an+(n^2d/2)-(nd/2)

Find common denominator:

(2an/2)+(n^2d/2)-(nd/2)

Combine terms into one:

(2an+n^2d-nd)/2

Reorder terms:

(n^2d+2an-nd)/2

Regroup terms:

(n^2d+(2a-d)n)/2

We want the following sum though:

4n^2+3n

This means d/2=4 (so d=8) and (2a-d)/2=3.

So plug d=8 into second equation to solve for a.

(2a-8)/2=3

2a-8=6

2a=14

a=7

The sequence has first term 7 and common difference is 8.

So the sequence is f(n)=7 + 8(n-1).

Answer:

See pic below.

Answer: C. 380°

Step-by-step explanation:

Answer:

0.0009765625

Step-by-step explanation:

This is what i got its probally incorrect

Given:

The given values are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

[tex]r^2=0.9435996398[/tex]

[tex]r=0.9713905701[/tex]

To find:

The exponential regression equation for the given values (Rounded to three decimal places).

Solution:

The general form of exponential regression equation is:

[tex]y=a\cdot b^x[/tex]          ...(i)

Where, a is the initial value and b is the growth/decay factor.

We have,

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

Round these numbers to three decimal places.

[tex]a\approx 0.209[/tex]

[tex]b\approx 2.507[/tex]

Substitute [tex]a=0.209, b=2.507[/tex] in (i) to find the exponential regression equation.

[tex]\hat{y}=0.209\cdot 2.507^x[/tex]

Therefore, the correct option is C.

Step-by-step explanation:

7 times a certain number :

Let the unknown number be x

[tex]7 \times x[/tex]

is less four times that same number -2 is 58 :

7x - 4x -2 = 58

Collect like terms

7x-4x = 58+2

3x = 60

3x/3 = 60/3

x = 20

Let the number be x

ATQ

[tex]\\ \sf\longmapsto 7x-4x-2=58[/tex]

[tex]\\ \sf\longmapsto 3x-2=58[/tex]

[tex]\\ \sf\longmapsto 3x=58+2[/tex]

[tex]\\ \sf\longmapsto 3x=60[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{60}{3}[/tex]

[tex]\\ \sf\longmapsto x=20[/tex]

Answer:

1 + 7n

Step-by-step explanation:

7-(3n+6)+10n​

7 - 3n - 6 + 10 n

1 - 7n

Answered by Gauthmath

Answer:

base-2 base-10

110011 = 51

110100 = 52

110101 = 53

110110 = 54

21 more rows

Answer:

Reflection

Step-by-step explanation:

Because reflecting yourself in a mirror means pre image to image

Answer:

Step-by-step explanation:

dilation

GIVEN -> Triangles r similar

so sides r in ratio

[tex] \frac{2.4}{3} = \frac{2.8}{x} \\ 0.8 = \frac{2.8}{x} \\ x = \frac{2.8}{0.8} \\ x = \frac{28}{8} \\ x = 3.5 \: \: ans[/tex]

Answer:

3.5

Step-by-step explanation:

We can write a ratio to solve

2.4      2.8

----- = --------

3         x

Using cross products

2.4x = 3(2.8)

2.4x =8.4

Divide each side by 2.4

2.4x /2.4 = 8.4/2.4

x = 3.5

Answer: y = x - 7

Slope intercept form: y = mx + b

[tex]2x-2y=14\\\\-2y=-2x+14\\\\y=\frac{-2x+14}{-2} =\frac{-2(x-7)}{-2} =x-7[/tex]

Answer:

the average number of cars waiting in line L[tex]q[/tex] is 0.45

Step-by-step explanation:

Given the data in the question;

Cars arrive at an automatic car wash system every 10 minutes on average.

Car arrival rate λ = 1 per 10 min = [ 1/10 × 60 ]per hrs = 6 cars per hour

Washing time for each is 6 minutes per car

Car service rate μ = 6min per car = [ 1/6 × 60 ] per hrs = 10 cars per hour

so

P = λ/μ = 6 / 10 = 0.6

Using the length of queue in M/D/1 system since there is only one service bay;

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ P² / ( 1 - P ) ]

so we substitute

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ (0.6)² / ( 1 - 0.6 ) ]

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ 0.36 / 0.4 ]

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ 0.9 ]

L[tex]q[/tex] = 0.45

Therefore, the average number of cars waiting in line L[tex]q[/tex] is 0.45