20 PTS PLEASE HELP!!!!

Select the correct answer from each drop-down menu.

The function below describes the number of students who enrolled at a university, where f(t) represents the number of students and t represents the time in years.


Initially, (1.03, 3, 19,055, 18,500) students enroll at the university. Every,(1years, t years, 2years, 3years) the number of students who enroll at the university increases by a factor of (1.03, 3, 19,055, 18,500).

Answer:

D. 40

Step-by-step explanation:

Interquartile range is the difference between the upper quartile value (Q3) and the lower quartile value (Q1).

In a box plot, Q1 is located at the beginning of the edge of the rectangular box from our left, while the Q3 is located at the end of the edge of the rectangular box to our right.

Interquartile range for City A = 70 - 40 = 30

Interquartile range for City B = 80 - 40

Therefore, city B has greater variability. The interquartile range is 40.

Answer:

A. linear, because it's growing the same amount each growing season

Step-by-step explanation:

Answer:

Step-by-step explanation: the answer is linear because it goes up by a constant every year

Answer:

5

Step-by-step explanation:

Answer:

5 is the answer to the question.

Step-by-step explanation:

(3² - 8) + 4

= (3×3×3 - 8) + 4

= (9 - 8) + 4

= 1 - 4

= 5

Answer:5

Step-by-step explanation:30/600×100

Answer:

Step-by-step explanation:

[tex]\frac{30}{600} \times 100\\\\= \frac{3000}{600}\\ \\= 5\%[/tex]

Answer:

Z=101

Step-by-step explanation:

A=2

B=3

C=5

D=7

E=11

F=13

From the above illustration, it can be deduced that A to Z represent prime numbers in ascending order.

Prime numbers are natural numbers that are greater than 1 and are only divisible by 1 and itself.

Therefore,

G=17

H=19

I=23

J=29

K=31

L=37

M=41

N=43

O=47

P=53

Q=59

R=61

S=67

T=71

U=73

V=79

W=83

X=89

Y=97

Z=101

3920|2

1960|2

980|2

490|2

245|5

49|7

7|7

1

[tex]3920=2^4\cdot5\cdot7^2=(2^2)^2\cdot5\cdot7^2[/tex]

It's 5

Answer:

[tex]\boxed{\mathrm{view \ explanation}}[/tex]

Step-by-step explanation:

The difference of two cubes formula is given as:

[tex]a^3-b^3 =(a-b)(a^2 +ab+b^2)[/tex]

Step-by-step explanation:

[tex] {(a - b)}^{3} = {(a - b)}^{2} (a - b)[/tex]

[tex] {a}^{3} - 3{a}^{2} b + 3a {b}^{2} - {b}^{3} = {(a - b)}^{2} (a - b)[/tex]

[tex] {a}^{3} - {b}^{3} + 3ab(a - b)= {(a - b)}^{2} (a - b)[/tex]

[tex] {a}^{3} - {b}^{3}= {(a - b)}^{2} (a - b) + 3ab(a - b)[/tex]

[tex] {a}^{3} - {b}^{3} = (a - b)(( {a}^{2} - 2ab + {b}^{2} ) - 3ab)[/tex]

[tex] {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )[/tex]

Answer:

Option (2)

Step-by-step explanation:

In the given circle,

[tex]m(\widehat{CBD})+m(\widehat{CED})[/tex] = 360°

Therefore, 212° + [tex]m(\widehat{CED})[/tex] = 360°

[tex]m(\widehat{CED})=360-212[/tex]

               = 148°

Tangent - chord theorem states,

"Angle between a chord and tangent measure the half of the angle measure of the intercepted minor arc."

m∠ACD = [tex]\frac{1}{2}(\widehat{CED})[/tex]

              = [tex]\frac{1}{2}(148)[/tex]  

              = 74°

Therefore, measure of ∠ACD is half the measure of arc CD or 74°.

Option (2) will be the correct option.

Answer:

Step-by-step explanation:

[tex]3x+4\geq13\\\\3x\geq9\\\\x\geq3\\\\A=\big<3\,,\ \infty)[/tex]                         [tex]\frac12x+3\leq4\\\\\frac12x\leq1\\\\x\leq2\\\\B=(-\infty\,,\ 2\big>[/tex]

[tex]A\cup B\not=\varnothing\quad for\ all\ x\in(-\infty\,, 2\big>\cup\big<3\,,\ \infty)[/tex]

so:

     [tex]A\cup B=\varnothing\quad for\ x\in(\,2\,,\ 3\,)[/tex]

Answer:hi, the answer would be (a) or 2<x<3 hope this helps :)

Step-by-step explanation: i just took the test got em all correct

Let Length of each Plan A workout be [tex] a[/tex]

and Length of each Plan B workout be $b$

on Wednesday,

$5a+3b=7$

$2a+12b=19$

multiply equation one by $4$ and subtract equation two from it

to get,

$18a=9$ or $a=\frac12$

substitute $a$ in eq 2. to get $b$, $12b=18\implies b=\frac32$

Answer:

  x = {π/4, 7π/6, 5π/4, 11π/6} +2kπ . . . for any integer k

Step-by-step explanation:

  [tex]\dfrac{\sin^3{x}}{1+\cos{x}}+\dfrac{\cos^3{x}}{1+\sin{x}}=\cos{2x}+2\cos{x}-1\\\\\dfrac{\sin{x}(1-\cos^2{x})}{1+\cos{x}}+\dfrac{\cos{x}(1-\sin^2{x})}{1+\sin{x}}=\cos^2{x}-\sin^2{x}+2\cos{x}-1\\\\\sin{x}(1-\cos{x})+\cos{x}(1-\sin{x})=\cos^2{x}-\sin^2{x}+2\cos{x}-1\\\\\sin{x}+\cos{x}-2\sin{x}\cos{x}=2\cos{x}-2\sin^2{x}\qquad\text{use $1=s^2+c^2$}\\\\\sin{x}+2\sin^2{x}-\cos{x}-2\sin{x}\cos{x}=0\\\\\sin{x}(1+2\sin{x})-\cos{x}(1+2\sin{x})=0\\\\(\sin{x}-\cos{x})(1+2\sin{x})=0[/tex]

This will have solutions where the factors are zero.

sin(x) -cos(x) = 0

Dividing by cos(x), we have ...

  tan(x) -1 = 0

  x = arctan(1) = π/4, 5π/4

1 +2sin(x) = 0

  sin(x) = -1/2

  x = arcsin(-1/2) = 7π/6, 11π/6

The four solutions in the interval [0, 2π] are x = {π/4, 7π/6, 5π/4, 11π/6}. Solutions repeat every 2π radians.

_____

Additional comment

We have made use of the factoring of the difference of squares:

  (1 -a^2) = (1 -a)(1 +a)

and we have made use of the cosine double angle identity:

  cos(2x) = cos(x)^2 -sin(x)^2

The "Pythagorean" identity for sine and cosine was used several times:

  1 = sin(x)^2 +cos(x)^2

Answer:

A.) median; 1.5

Step-by-step explanation:

Hello!

The median is the number that is in the middle when the numbers are listed from least to greatest

0, 0, 1, 1, 2, 2, 2, 14

We can take one from both sides till there are one or two numbers left

0, 1, 1, 2, 2, 2

1, 1, 2, 2

1, 2

If there are two numbers left we add them then divide by 2 to get the median

1 + 2 = 3

3 / 2 = 1.5

The answer is A.) median; 1.5

Hope this helps!

Answer:

At x intercept, x = 0

2.8(0)+5.7y+5.8=0

y=-5.8/5.7

=-1.02

At y intercept, y=0

2.8x+5.7(0)+5.8=0

x=-5.8/2.8

=-2.07

Answer:

X ans y intercepts are

xintercept (s) : (-2.0,0) you can roud if necessary

y intercept(s) : (0,-1.01754385) you can round if nessecary

Step-by-step explanation:

to find the [tex]x[/tex] and [tex]y[/tex] intercepts simply plug in [tex]o[/tex] to replace [tex]x[/tex] then when you solve for [tex]x[/tex] plug in [tex]x[/tex]to solve for [tex]y[/tex]

Answer:

1

Step-by-step explanation:

Anything real number (except 0) to the zeroth power would be 1.

Therefore, 12 to the zeroth power would also be 1.

[tex]12^0=1[/tex]

Answer:

As you know everynumber raised to 0 is always 1 even if its x or infinity so the answer will be 12^0 will be 1

Step-by-step explanation:

any and every number raised to 0 is 1

Answer:

C....................

Answer:

(C) [tex]x=4[/tex]

Step-by-step explanation:

A line will be parallel to the y-axis if It’s x never changes.

In A, x is always being -y, so that’s going to change all the time.

In B, x is always becoming y, so that is changing too.

In C, x is always being 4, so this never changes.

In D, x is always 4 times y, so this changes.

Hope this helped!

Answer/Step-by-step Explanation:

12. A. (1,299 + 3,563) ÷ 22 = 221

4,862 ÷ 22 = 221

221 = 221 (TRUE)

B. 16*(132 + 34)*12 = 32,872

16*166*12 = 32,872

31,872 = 32,872 (NOT TRUE)

C. (65 + 78)*(45 - 29) = 2,188

143*16 = 2,188

2,288 = 2,188 (NOT TRUE)

D. (1,444 - 349) ÷ (457 - 238) = 6

1,095 ÷ 219 = 6

5 = 6 (NOT TRUE)

The answer is A.

13. Let the missing number = X

Thus,

i. 25*(157 + x) = 8,850

[tex] 157 + x = \frac{8850}{25} [/tex]

[tex] 157 + x = 354 [/tex]

[tex] x = 354 - 157 [/tex]

[tex] x = 197 [/tex]

ii. x ÷ (453 - 425) = 135

x ÷ (28) = 135

x = 135*28

x = 3,780

14. (56 + 69) * (268 - 137)

125*131 = 256

15. 9,144 ÷ (2,784 - 2,784)

9,144 ÷ 0 = cannot divide

16.  (72 + 126) ÷ (687 - 654)

198 ÷ 33 = 6

17. 22*(562 + 733)

22*1,295 = 28,490

18. Let the missing number be x

48*(x - 239) = 4,272

[tex] x - 239 = \frac{4,272}{48} [/tex]

[tex] x - 239 = 89 [/tex]

[tex] x = 89 + 239 [/tex]

[tex] x = 328 [/tex]

The missing number is 328.

19. (794 + 718) ÷ (68 - 41)

1,512 ÷ 27 = 56

20. (58*89) + (192 ÷ 16)

5,162 + 12 = 5,174

Answer:

f(g(x)) = [tex]\sqrt{8x-22}[/tex]

Step-by-step explanation:

Substitute x = g(x) into f(x), that is

f(g(x))

= f(8x - 13)

= [tex]\sqrt{8x-13-9}[/tex]

= [tex]\sqrt{8x-22}[/tex]

Answer:

The expressión that represents the length:

a = 2w + 1

a = length of the rectangle

w = width of the rectangle

Answer:

its false

Step-by-step explanation:

Answer:

The answer is false

Step-by-step explanation:

Answer:

.6239 as a fraction is 6239/10000.

Answer:

Step-by-step explanation:

[tex]3 \times 19 \times 14 + 18 \div 2 \\ PEDMAS \\ (3 \times 19 \times 14 )+ 9 \\ = 798 + 9 \\ [/tex]

[tex] = 807[/tex]

Answer:

408

Step-by-step explanation:

3x19= 57

57x14= 798

798 + 18= 816

816/ 2= 408

Answer:

x = 19 1/3

Step-by-step explanation:

6/14 = 7/(x-3)

Using cross products

6 * (x-3) = 7*14

6x -18 = 98

Add 18 to each side

6x-18+18 =98+18

6x = 116

Divide each side by 6

6x/6 = 116/6

x =58/3

x = 19  1/3

Answer= 58/3

Step by Step

Step 1: Cross-multiply.

6*(x−3)=(7)*(14)

6x−18=98

Step 2: Add 18 to both sides.

6x−18+18=98+18

6x=116

Step 3: Divide both sides by 6.

6x /6 = 116 /6

x= 58 /3

Answer:

y=3

Step-by-step explanation:

7y-(5y+4)=10

7y-5y+4=10

         -4    -4

7y-5y=6

2y=6

÷2   ÷2

y=3

Answer:

$200,000 in bank A, $200,000 in bank B, $230,000 in bank C

Step-by-step explanation:

Meredith has $630,000

Limit per depositor, per bank, is $250,000

She needs to distribute her money between three Banks to guarantee that her money is insured.

A. $200,000 in bank A, $200,000 in bank B, $230,000 in bank C

It can be seen in A that her deposit per bank deposit didn't exceed the $250,000 limit in the three Banks.

B. $200,000 in bank A, $170,000 in bank B, $260,000 in bank C

Here, her deposit in bank C exceeds $250,000, so there is no guarantee for insurance in bank C

C. $160,000 in bank A, $180,000 in bank B, $290,000 in bank C

Her deposit in bank C is $290,000 which exceeds the $250,000 limit. Therefore, no guarantee for insurance of her money in bank C

D. $160,000 in bank A, $200,000 in bank B, $270,000 in bank C

you

Also, her deposit in bank C exceeds $250,000, so there is no guarantee for insurance in bank C

The way her money can be distributed between three Banks and guarantee insurance is

A. $200,000 in bank A, $200,000 in bank B, $230,000 in bank C.

That way, her deposit per bank is less than the $250,000 limit

Answer:

Climax:  11,560. Calipatria: 185 Calipatra is closer by 11,375ft

Step-by-step explanation:

Climax is 11,560ft above sea level, which means it is 11,560ft away from sea level. Calipatria 185ft away from sea level by the same logic. The one whih is closer to sea level would be the smaller number, which would be 185, and how much closer would be 11,560-185= 11,560.

If you're wondering why the 185 isn't negative, it's because the question is asking how far away from zero the numbers are, so you would take the absolute value of -185 which would be 185.

Answer:

see explanation (please confirm if I read you problem correctly)

Step-by-step explanation:

150 kilometers

60 kph

tank is 20 liters

6 km/l

150/6 = 25 liters needed

$60/l

you will need to get 5 more liters of fuel

total cost 25 x .60 =  $15

Answer:

AHHHHH I think its two hours

Step-by-step explanation:

she...? can drive 120 Kilometers before she runs out of fuel since the car's tank has 20 liters of fuel at the beginning of the drive, and its fuel efficiency is 6 kilometers per liter. and that means she can drive 2 hours

Answer:

[tex]6b[/tex]

Step-by-step explanation:

We know that the distance formula is [tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]. We already have the x values, which are [tex]5a[/tex] and [tex]-a[/tex], subtracting [tex]-a[/tex] from 5a gets us [tex]6a[/tex].

Same concept for the y values, let's subtract the first y value from the second.

The second y value is [tex]b[/tex], while the first is [tex]-5b[/tex]

[tex]b - (-5b) = b + 5b = 6b[/tex]

Hope this helped!

Answer:

6b is your answer!

Step-by-step explanation:

I wish ALL ACELLUS USERS LUCK

Answer:

(a) ∠EFH =  68°

(b) ∠EGF = 21°

Step-by-step explanation:

(a) The given parameters are;

The diameter of the circle = Segment [tex]\overline{EG}[/tex]

Arc [tex]m\widehat{FG}[/tex] = 138°

∠GFH = 22°

∠ EFG = (Angle subtended by the diameter EG at the center)

Arc mEG = 180° (Arc subtended by the diameter of a circle = 180°)

∠ EFG is subtended by the diameter EG at the center

∴ ∠ EFG = 90° (Angle at the center = 2 times angle at the circumference)

∠EFG = ∠EFH + ∠GFH  (Angle addition postulate)

∴ ∠EFH = ∠EFG - ∠GFH = 90° - 22° = 68°

∠EFH =  68°

(b) ∠EGF

Arc GH = 44°

Arc mFE + Arc [tex]m\widehat{FG}[/tex] + Arc mEHG = 360 (Sum of angles at the center of a circle)

Arc mFE = 360 - ( Arc [tex]m\widehat{FG}[/tex] + Arc mEHG )

Arc mFE  =  360 - 180 - 138 = 42°

∠EGF = Arc mFE/2 (Angle at the center = 2 times angle at the circumference)

∠EGF = 42/2 = 21°

∠EGF = 21°

Answer:

Charlie is the right person.

Step-by-step explanation:

The right person is Charlie because he was sure of what he was saying. Others were not sure making them mention two textbooks while Danny didn't answer the question Tony asked because he was talking about the one that doesn't have the solution.

Answer:

x=0

Step-by-step explanation:

in the quadratic formula to only have one solution

[tex]b^{2} -4ac=0[/tex] for [tex]ax^2+bx+c=0[/tex]

so we have

[tex]ax^2+b=c[/tex]

[tex]ax^2+(b-c)=0[/tex]

if we insert in the formula we have

[tex]0^2-4(a)(b-c)=0\\\\-4ab+4ac=0\\\\4ac=4ab\\\\\frac{4ac}{4a} = \frac{4ab}{4a}\\\\c=b[/tex]

[tex]ax^2+b=c\\\\ax^2=b-b\\\\ax^2=0[/tex] since a≠0

[tex]\frac{ax^2}{a}=\frac{0}{a} \\\\x^2=0\\\\x=0[/tex]