2x(5x-2)+(2x+1)(8-5x)

Answers

Answer 1
solution

STEP1: Equation at the end of step 1

(2x • (5x - 2)) + (2x + 1) • (8 - 5x)

STEP2: Equation at the end of step 2

2x • (5x - 2) + (2x + 1) • (8 - 5x)

..............................................................................

Final result :

7x + 8

Answer 2
I got 7x + 8 when solving it

Related Questions

you are renting a house in the seychelles for a week at $1500. What is the cost per day?

Answers

Step-by-step explanation:

cost per day

= $1500 / week

= $1500 / 7 days

= $1500 ÷ 7 / 7 ÷ 7

≈ $214,29 / day

Someone please help me answer this asap thank you x
(The empty box)

Answers

Two thirds is the answer! If you multiply it back by 100/1 you’ll get back 66.66

Express the tan G as a fraction in simplest terms.

Answers

Answer:

[tex]\frac{\sqrt{70} }{5}[/tex]

Please help! 15 points!! brainliest if right

Answers

Answer:

a)7x-3x

b)4+28y

Step-by-step explanation:

first one follow bidmas

2nd one just do 4 times 1 =4 and 7y times 4 equals 28y

C+X=G
what is X?
this is a literal equation.​

Answers

Answer:

x=g-c

Step-by-step explanation:

x= g - c
hope this helps!

For a company picnic, Nick ordered a box of fresh-baked gingerbread cookies and sugar cookies. The box included a total of 36 cookies, and 25% of them were gingerbread. How many gingerbread cookies did Nick get?

Answers

Answer: 9

Step-by-step explanation:

36 ÷ 4 = 9

which input value produces the same output value for the two funcions on the graphs
Rox) = x+1
9(x) = 3x-2

Answers

Answer: i solved on my channel

Step-by-step explanation: https://youtu.be/rTgj1HxmUbg

Which statement is true about the polynomial
–10m4n3 + 8m2n6 + 3m4n3 – 2m2n6 – 6m2n6 after it has been fully simplified?

Answers

Answer:

Below.

Step-by-step explanation:

–10m4n3 + 8m2n6 + 3m4n3  – 2m2n6 – 6m2n6

= 8m2n6 – 2m2n6 – 6m2n6 – 10m4n3 + 3m4n3

= 8m2n6 - 8m2n6 – 7m4n3

= –7m4n3.

It is a mononomial.

Jonah earns $3 an hour working after school and $4 an hour working on Saturdays. Last week he earned $43, working a total of 13 hours. How many hours did he work on Saturday?

Answers

Answer:

9 hours worked after school and 4 hours worked on saturday

Step-by-step explanation:

x = amount of hours worked after school

y = amount of hours worked on saturday

x + y = 13 or x = 13 - y

and

3x + 4y = 43

plug:

3 · (13 - y) + 4y = 43

39 - 3y + 4y = 43

y = 4

plug:

x = 13 - y

x = 13 - 4 = 9

9 hours worked after school and 4 hours worked on saturday

there are red blue and green ribbon on the tabel.there are a total of 36 ribbon.3/6 of the ribbon is red.how manny ribbon is red

Answers

Answer:

18

Step-by-step explanation:

3/6 =1/2

1/2 of 36 is 18

HELP D:

what is 70.4 divided by 11

show your work in partial quotient

Answers

Answer: 70.4÷11 = 6.4

Step-by-step explanation:

__6.4__

11/70.4

-66 |

04 4

- 4 4

_____

=0

Please I need help ASAP. Can someone help me?

Answers

Answer: The second bubble thing is correct you have picked the wrong one.

In 1963, Dr. Martin Luther King Jr. began his famous “I have a dream” speech with the words “Five score years ago, a great American, in whose symbolic shadow we stand, signed the Emancipation Proclamation.” The proclamation was signed by President Abraham Lincoln in 1863. Using the dates given, write and solve an equation that can be used to find the number of years in a score.

Answers

Answer:

The equation to represent number of years in score is 5x = 1005x=100,

The number of years in score is 20

Step-by-step explanation:

CAN YOU GIVE ME BRAINliEST

24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right

Answers

Answer:


It a acute

Hope this help you :)

labron has $15,300 of total liabilities and $52,580 of total assets.what is his net worth​

Answers

Answer:

.......................

please help me solve this will give brainliest

Answers

x=3/5 ………………………………….

What criterion statement accurately proves that triangle ABC is congruent to triangle DEF?

A. SSS criterion

B. AAS criterion

C. SAS criterion

D. ASA criterion



Need an answer ASAP​

Answers

Answer:

  D. ASA criterion

Step-by-step explanation:

Two angles are marked congruent as is the side between them. The criterion involving angle - side - angle is abbreviated ASA.

PLEASE HELP!!! I NEED THIS DONE AS SOON AS POSSIBLE 20 points Make a table of order pairs for the equation y=-1/3+4 then plot two points to graph the equation

Answers

Answer:

ok so.u grit da he on 40/ rock cause u got a andriodnh on gf

Make x the subject, 2x + y = s

Answers

Answer:

2x+y=s

2x\2+y\2=s\2

therefore x= s\2-y\2

What is the value of x+y in this question and what’s the equation?

Answers

Answer:

Step-by-step explanation:x

Which of the following values are in the range of the function graphed below? Check all that apply. ​

Answers

Answer:

-5,3

Step-by-step explanation:

find the middle of it and simplify until you reach the point

Which of the following is true?

|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5

Answers

Answer:

|-4| < |-5|

Step-by-step explanation:

because if modules is given sub sign will be deducate

Which integer can you multiply by itself to get 400 as the square number?

a. 10
b. 20
c. 30
d. 40.

Answers

Answer:

20

Step-by-step explanation:

20*20 = 400

OR

[tex]20 {}^{2} = 400[/tex]

what is 2/5 divided by 1/3

Answers

Answer:

6/5

Step-by-step explanation:

(2/5)/(1/3) ⇔ (2/5)(3) = 6/5

Answer:

6/5 or 1 and 1/5

Step-by-step explanation:

To divide fractions use KFC

Keep the first fraction the sameFlip the second fractionChange the sign from ÷ to ×

Using KFC, 2/5 ÷ 1/3 becomes 2/5 × 3/1.

We can now multiply the numerators and multiply the denominators:

2 × 3 = 65 × 1 = 5

Answer: 6/5 or 1 and 1/5

Hope this helps!

Reduce answers to their lowest
terms and mixed forms.
2 4
5
2/
+
f

Answers

Answer:

10 + 28 / 35

= 38 / 35

= 1.0875

2/7 + 4/5 = 38/35
38/35 is already reduced to it’s lowest term.
38/35’s mixed term is 1, 3/35

9 DNG AKUM
Solve for x :
N
M
5
U7
X+7
D 8 G
K 35 J

Answers

Answer:

x = 49

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are in proportion, that is

[tex]\frac{DN}{KJ}[/tex] = [tex]\frac{DG}{KM}[/tex] , substitute values

[tex]\frac{5}{35}[/tex] = [tex]\frac{8}{x+7}[/tex] ( cross- multiply )

5(x + 7) = 280 ( divide both sides by 5 )

x + 7 = 56 ( subtract 7 from both sides )

x = 49

please answer it is related to square root​

Answers

Answer:

Step-by-step explanation:

[tex]2\sqrt{8}+3\sqrt{50}=2\sqrt{2*2*2} + 3\sqrt{5*5*2}\\\\= 2*2\sqrt{2}+3*5\sqrt{2}\\\\=4\sqrt{2}+15\sqrt{2}\\\\= 19\sqrt{2}[/tex]

[tex]3\sqrt{12}+4\sqrt{27}=3\sqrt{2*2*3}+4\sqrt{3*3*3}\\\\=3*2\sqrt{3}+4*3\sqrt{3}\\\\=6\sqrt{3}+12\sqrt{3}\\\\=(6+12)\sqrt{3}\\\\= 18\sqrt{3}[/tex]

If f (x) = 3x + 1 and g(x) = 2x + 1, what is the value of f (g(2))?

Answers

Step-by-step explanation:

= f( g(2) )

= 3(2x + 1) + 1

= 6x + 3 + 1

= 6x + 4

= 6(2) + 4

= 12 + 4

= 16

f(g(2)) = 16

This is a graphing problem and I am trying to find the x-intercepts and the y-intercepts. Please show me the full steps. I really appreciate it thank you.

Answers

Answer:

y-intercept: y = 3/4no x-intercepts

Step-by-step explanation:

To find the y-intercept, set x=0 and evaluate the function.

  f(0) = -3/(0 -4) = 3/4

The y-intercept is (0, 3/4).

__

To find the x-intercept(s), set f(x) = 0 and solve for x.

  0 = -3/(x^2 -4)

  0 = -3 . . . . . . . . . . multiply by (x^2 -4), x ≠ ±2

There are no values of x that will make this true. There are no x-intercepts.

_____

Additional comments

In general, you find the x-intercepts of a rational function by finding the zeros of the numerator. Here, the numerator is -3, so cannot ever be zero.

I find a graphing calculator to be a useful tool for showing where to look for x-and y-intercepts. The attached graph shows y=0 (the x-axis) is a horizontal asymptote, so there are no x-intercepts.

(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme​

Answers

Step-by-step explanation:

[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]

[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

We can write as :

27 = 3 × 3 × 3 = 3³

8 = 2 × 2 × 2 = 2³

243 = 3 × 3 × 3 × 3 × 3 = 3⁵

32 = 2 × 2 × 2 ×2 × 2 = 2⁵

[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now, we can write as :

(3³/2³) = (3/2)³

(3⁵/2⁵) = (3/2)⁵

[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now using law of exponent :

[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]

[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]

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