Answer:
The cost of sending the telegram is $6.
Step-by-step explanation:
Since 3 St. Post Office charges for an ordinary telegram are $ 4 for the first 10 words and 40 cents for each extra word, to calculate the cost of sending this telegram: MR KAMAU ARRIVING AT 0630 EAST AFRICAN TIME ON BOARD KQ 46 INFORM THE WIFE must perform the following calculation:
The telegram has 15 words.
4 + ((15 - 10) x 0.40) = X
4 + (5 x 0.40) = X
4 + 2 = X
6 = X
Therefore, the cost of sending the telegram is $ 6.
The graph shown below expresses a radical function that can be written in
17
the form f(x) = a(x + k)!
C. What does the graph tell you about the
value of k in this function
Answer:
C. [tex]k[/tex] is greater than zero.
Step-by-step explanation:
We know that graph is obtained from the function of the form [tex]f(x) = a\cdot (x+k)^{1/n} + c[/tex]. According to the graph and if [tex]x + k = 0[/tex], we find that:
[tex]x = -k[/tex] (1)
[tex]x < 0[/tex] (2)
By (1) and (2):
[tex]-k < 0[/tex]
[tex]k > 0[/tex]
Hence, correct answer is C.
Please help!
It took Suki 127 minutes from start to finish to carve her pumpkin. Carving the pumpkin took her 13 fewer minutes than 10 times as long as it took her to pick the pumpkin out at the pumpkin patch. Write and solve an equation to find how long it took Suki to pick out her pumpkin.
9514 1404 393
Answer:
14 minutes
Step-by-step explanation:
Let t represent the time it took Suki to pick out her pumpkin. The given relation is ...
10t -13 = 127 . . . . . equation for minutes to carve
10t = 140 . . . . . . . . add 13
t = 14 . . . . . . . . . . divide by 10
It took Suki 14 minutes to pick out her pumpkin.
A rocket is fired upward with an initial velocity v of 100 meters per second. The quadratic function S(t)=-5t^2+100t can be used to find the height s of the rocket, in meters, at any time t in seconds. Find the height of the rocket 7 seconds after it takes off. During the course of its flight, after how many seconds will the rocket be at a height of 450 meters?
The rocket will be at the height of 450metres at 13.16secs and 6.84secs
Given the expression modeled by the height S(t)=-5t^2+100t where
t is the time taken by the rocket to take off
s is the height traveled by rocket
In order to find the height of the rocket 7 seconds after it takes off, we will substitute t = 7 into the equation
S(7) = -5(7)²+100(7)
S(7) = -5(49)+700
S(7) = -245+700
S(7) = 455metres
Hence the height of the rocket 7 seconds after it takes off is 455metres
Given that S = 450m, we can also get the time taken by the rocket at this height.
Recall that S(t)= -5t²+100t
450 = -5t²+100t
Rearrange
-5t²+100t - 450 = 0
5t²-100t + 450 = 0
Divide through by 5
t²-20t + 90 = 0
On factorizing above equation;
t= 10+√10 or t=10−√10
t = 10+3.1623 or 10 - 3.1623
t = 13.16 and 6.84secs
Hence the rocket will be at the height of 450metres at 13.16secs and 6.84secs
Learn more here: https://brainly.com/question/1063981
I will give a brainliest and 20pts to the person that can use the Pythagorean theorem to solve for x. Please help. I went over it several times and the answer I got doesn't match up with what the box says
Answer:
x = 48
Step-by-step explanation:
Pythagorean thm:
a² + b² = c²
Given:
a = x
b = 36
c = 60
Work:
a² + b² = c²
x² + 36² = 60²
x² + 1296 = 3600
x² = 3600 - 1296
x² = 2304
√x² = √2304
x = 48
A store is advertising a new DVD player for $189.00. If the sales tax rate is 7.25 percent,
Answer:
then what's the question???..
Consider the generic chemical equation:
2 A + 3 B ------> 3 C
If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed?
For this problem, you can see that a ratio exists between A, B, and C. Now you'll just have to find the constant k that satisfies this ratio using the proportional relationship formula.
After that, you can plug in the constant k to find the missing C value.
Use the following graph to evaluate f’(-5) and f’(-1).
Answer:
Bonsoir,
f'(-5)=-4/3
f'(-1) =3/4
Step-by-step explanation:
f'(-5) = ?
2 points : (-6,9) and (-3,5)
f'(-5)=(9-5)/(-6-(-3))=-4/3
f'(-1) = ?
2 points : (-3,5) and (1,8)
f'(-1)=(5-8)/(-3-1)=3/4
The lines are perpendicular
The derivative at the points -5 and -1 are:
f’(-5) = -4/3
f’(-1) = 3/4
What is derivative at a point on line?The slope of the tangent line to the graph of a function at a point is called the derivative of the function at that point.
We consider the line on which where the x coordinate -5 lies.
It is the line with points (-3, 5) and (-6, 9).
Slope of the line = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] = [tex]\frac{9-5}{-6+3} = \frac{-4}{3}[/tex]
f'(-5) = -4/3
We consider the line on which where the x coordinate -1 lies.
It is the line with points (-3, 5) and (1, 8).
Slope of the line = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] = [tex]\frac{8-5}{1+3} = \frac{3}{4}[/tex]
f'(-1) = 3/4
Learn more about derivative at a point here
https://brainly.com/question/1111011
#SPJ2
Need help with precalc please! Thank you!
que es eso ._ .wooooooooo .
Solve
0.9(7x + 14) = 1.5 - (x + 2)
[tex]\\ \sf\longmapsto 0.9(7x+14)=1.5-(x+2)[/tex]
[tex]\\ \sf\longmapsto 6.3x+12.6=1.5-x-2[/tex]
[tex]\\ \sf\longmapsto 63x+12.6=-x-0.5[/tex]
[tex]\\ \sf\longmapsto 63x+x=-0.5-12.6[/tex]
[tex]\\ \sf\longmapsto 64x=-13.1[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-13.1}{64}[/tex]
[tex]\\ \sf\longmapsto x=0.2[/tex]
Fill in this blank spaces (1,3,5,7,9 , 11, 13, 15) _+_+_=30
Step-by-step explanation:
Just till the number 9 upside down to make it 6 then
6+11+13=30
The sum of three odd numbers can never be even. so I did it in that way.
I HOPE THIS WILL HELP U
STAY SAFE, STAY HAPPY
Carlos is an administrative assistant at an insurance agency. He wants to gather feedback from customers on their service. He doesn't have a lot of time, and he wants to have some data to share with his supervisor. What is the best way for Carlos to gather feedback? O a) Individual interviews O b) Survey O c) Focus group d) Phone calls
Answer: b) Surveys
When a person does not have enough time he must should take the faster and effective route in this case carlos does not have time for individual interviews or phone calls. Focus group is not used to get feedback it is to discuss about data before a item is launched. Therefore it should be survey because it is used to collect feedback from large amount of people.
Must click thanks and mark brainliest
Find the value of x.
A. 6
B. 3
C. 5
D. 2
[tex]\\ \sf\longmapsto \dfrac{AK}{DK}=\dfrac{CK}{BK}[/tex]
[tex]\\ \sf\longmapsto \dfrac{14}{12}=\dfrac{4x+1}{3x+3}[/tex]
[tex]\\ \sf\longmapsto \dfrac{7}{6}=\dfrac{4x+1}{3x+3}[/tex]
[tex]\\ \sf\longmapsto 7(3x+3)=6(4x+1)[/tex]
[tex]\\ \sf\longmapsto 21x+21=24x+6[/tex]
[tex]\\ \sf\longmapsto 24x-21x=21-6[/tex]
[tex]\\ \sf\longmapsto 3x=15[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{15}{3}[/tex]
[tex]\\ \sf\longmapsto x=5[/tex]
[tex]3^n^+^1+9/3^n^-^1+1[/tex]
how do i solve it?
Answer:
Hello,
Step-by-step explanation:
[tex]\dfrac{3^{n+1}+9}{3^{n-1}+1} \\\\=\dfrac{9*(3^{n-1}+1)}{3^{n-1}+1}\\\\=9\\[/tex]
What are the values of (-2)4 and -24?
1. 8 and -8
2. -8 and -8
3. 16 and -16
4. 16 and 16
Answer:
2.
Step-by-step explanation:
(-2)×4=-8
-2×4=-8
~~~~~~~~
Answer:
16 and 16 is the correct answer
If 3x+2=5/9, what is the value of −3x+8?
Group of answer choices
Answer:
= 4
Step-by-step explanation:
first lets find the value of x in 3x+2=5/9
3x+2=5/9
3x = [tex]\frac{5}{9}[/tex] -2
3x = [tex]\frac{3}{9}[/tex]
3x = [tex]\frac{1}{2}[/tex]
x = [tex]\frac{1}{2 * 3\\ }[/tex]
x = [tex]\frac{1}{6}[/tex]
[tex]\frac{1}{6}[/tex] can also be written as [tex]6^{-1}[/tex]
−3x+8
-3 ([tex]\frac{1}{6}[/tex]) +8
[tex]\frac{-3}{6}[/tex] +8
= 4
Find F(-3).
F(x) = 2x^2- 5x-8
Answer:
25
Step-by-step explanation:
F(x) = 2x^2- 5x-8
Let x=-3
f(-3) = 2 (-3)^2 -5(-3) -8
=2(9) +15 -8
=18+15-8
=25
If a runner jogs 3 miles west and then jogs 8 miles
north, how far is the runner from her starting point
if she plans to run straight back? Remember to
simplify your answer.
If they run 3 miles west then 8 miles north, it forms a right triangle. So just use the Pythagorean Theorum.
A^2+B^=C^2
3^2+8^3=C^2
9+64=C^2
Square root 73=C or 8.54=C (Miles)
The runner is 8.54 miles from her starting point if she plans to run straight back.
From the question, a runner jogs 3 miles west and then jogs 8 miles north.
An illustrative diagram for the journey is shown in the attachment below.
In the diagram, S is the starting point. That is, the runner jogs 3 miles west to a place R and then 8 miles north to a place E.
The cardinal points (North, East, West and South) are indicated beside the diagram.
Now, to calculate how far she is from her starting point if she plans to run straight back, we will determine the length of /ES/ in the diagram.
The diagram is a right-angled triangle and /ES/ can be determined using the Pythagorean theorem.
The Pythagorean theorem states that, in a right-angled triangle, the square of the longest side ( that is hypotenuse) equals sum of the squares of the other two sides.
In the diagram, hypotenuse = /ES/
∴ /ES/² = /SR/² + /RE/²
/SR/ = 3 miles
/RE/ =8 miles
/ES/² = 3² + 8²
/ES/² = 9 + 64
/ES/² = 73
/ES/ = [tex]\sqrt{73}[/tex]
/ES/ = 8.54 miles
Hence, the runner is 8.54 miles from her starting point if she plans to run straight back.
Learn more here: https://brainly.com/question/20327506
what is the sign of x/y times 7y^3 when x<0 and y>0? A. Positive B. Negative C. Zero
X <0 means x would be negative.
For x/y, a negative divided by a positive would give a negative answer.
A negative multiplied by a positive would result in a negative.
The answer would be B. Negative
Reduce 20/60 to its lowest common denominator
Answer:
it is 1/4
Step-by-step explanation:
20/60=10/30=1/3
Answer:
20/60=1/3
Step-by-step explanation:
20/60
HCF=20,
20*1=20, 20*3=60
1/3
or,
Remove the zeros,
2/6
Divide by 2 on both,
1/3
or divide by any common factor on both and keep dividing until u cant no more
20/60=1/3
I can’t solve plz help me ...
Your answer is in the attachment.
In a food preference experiment, 80 lizards were given the opportunity to choose to eat one of three different species of insects. The results showed that 33 of the lizards chose species A, 12 chose species B, and 35 chose species C. They conducted a Chi-squared analysis to test for equal preference. What are the Null and Alternate hypothesis for this test
Answer:
H0 : The variables are independent
H1 : The variables are not independent
Step-by-step explanation:
In a Chisquare test ; The null hypothesis is used to lay claim that the variables are independent, that is no relationship exists between the categorical variables in the population while the alternative hypothesis negates the null thus claiming that the variables aren't independent.
The null hypothesis, H0 : The variables are independent, A = B = C
The alternative hypothesis ; H1 : The variables are not independent, A ≠ B ≠ C
A coffee pot holds 3 3/4 quarts of coffee. How much is this in cups.
Answer: 15 cups
Step-by-step explanation:
The measure of one of the small angles of a right triangle is 45 less than twice the measure of the other small angle. Find the measure of both angles.
Answer:
Step-by-step explanation:
A right triangle has one right angle and two acute angles.
A and B are the acute angles.
A+B = 90°
One acute angle is 45 less than twice the other acute angle.
A = 2B-45°
(2B-45°) + B = 90°
3B = 135°
B = 45°
A = 45°
You have 2 5 sided dice, what's the probability the addition of rolling both
Answer:
7
Step-by-step explanation:
Find the length of AB
Answer:
C. 44.98
Step-by-step explanation:
Hi there!
We are given the right triangle ABC, m<B=12°, and CB =44
We want to find the length of AB
We can use trigonometry to do it
Let's find the ratio in reference to angle B, as that angle is given.
In reference to angle B the opposite angle is AC, the adjacent side is CB, and the hypotenuse is AB
Now let's recall the 3 most commonly used functions:
[tex]sine=\frac{opposite}{hypoptenuse}[/tex]
[tex]cosine=\frac{adjacent}{hypotenuse}[/tex]
[tex]tangent=\frac{opposite}{adjacent}[/tex]
Let's find the cosine of angle B, as it uses CB and AB, which are the given side and the side we need to find
In that case,
cos(12)=[tex]\frac{CB}{AB}[/tex]
cos(12)=[tex]\frac{44}{AB}[/tex]
Multiply both sides by AB
[tex]AB[/tex]*cos(12)=44
Divide both sides by cos(12)
AB=[tex]\frac{44}{cos(12)}[/tex]
Now plug [tex]\frac{44}{cos(12)}[/tex] into your calculator. Make sure your calculator is on degree mode
AB≈44.98
So the answer is C
Hope this helps!
The produce of three and the sum of a number and eight
Answer:
3(x + 8)
Step-by-step explanation:
"The product of three and the sum of a number and eight".
First, note that:
1) Product means multiply.
2) Sum means addition.
With that in mind, also note the order of operations. The order of operations is defined as PEMDAS, or:
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
Also, let "a number" be denoted as the variable, x.
~
Firstly, "the sum of a number and eight": x + 8
Next, "The product of...": 3 *
Putting the two parts together will generate: 3(x + 8)
3(x + 8) is your answer.
~
The perimeter of a rectangular garden is 120 feet The garden is two times as long as it’s why the system of equation can be used to find the width in the length what is the length
Answer:
Step-by-step explanation:
Garden is two times as long as it is wide.
L = 2W
Perimeter is 120 feet
2L + 2W = 120
L +W = 60
(2W) + W = 60
3W = 60
W = 20 feet
L = 2W = 40 feet
I need help in math please, if you can
Answer:
Step-by-step explanation:
400*e^(.09*3)
$523.97
answer is b
Answer: Option B
$523.97
Explanation:
= 400×e^(0.09×3)
= $523.97
Must click thanks and mark brainliest
[tex]\lim_{x\to \ 0} \frac{\sqrt{cos2x}-\sqrt[3]{cos3x} }{sinx^{2} }[/tex]
Answer:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}[/tex]
General Formulas and Concepts:
Calculus
Limits
Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
L'Hopital's Rule
Differentiation
DerivativesDerivative NotationBasic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
We are given the limit:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}[/tex]
When we directly plug in x = 0, we see that we would have an indeterminate form:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}[/tex]
This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}[/tex]
Plugging in x = 0 again, we would get:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}[/tex]
Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}[/tex]
Substitute in x = 0 once more:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}[/tex]
And we have our final answer.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
What are the solutions of the equation (x + 2)2 + 12(x + 2) – 14 = 0? Use u substitution and the quadratic formula to
solve.
..... Here
This is the answer
