30 points plz help
Use the draggable points to graph the equation
1
y=
2x+3

Answer:

the answer is 29

Step-by-step explanation:

good luck! <33

Answer:

The answer is  203

Step-by-step explanation:

 I  started off by dividing 609 by 3 and your answer is on the top. You're welcome!!

Answer:

Step-by-step explanation:

here is an example in the shown file

Answer:

y= -3x+1

Step-by-step explanation:

Answer:

The other end of the line segment is at (-8, 3)

Step-by-step explanation:

Since we know one end point and the midpoint, all we need to do is take the vector from the end point to the midpoint, and add it again to the midpoint to find the other end point:

dx = -5 - (-2) = -3

dy = -1 - (-5) = 4

-5 + dx = -8

-1 + dx = 3

So the other end of the line segment is at (-8, 3)

If a segment has an endpoint at (-2, -5) and a midpoint at (-5, -1), the coordinates of the other endpoint are (-8, 3)

The midpoint of a line segment is given as:

[tex]a=\frac{x_1+x_2}{2} \\\\b=\frac{y_1+y_2}{2}[/tex]

One of the endpoints of the line segment is (-2, -5)

That is, [tex]x_1=-2, y_1=-5[/tex]

Let the coordinates of the other endpoint be [tex](x_2, y_2)[/tex]

Solving for [tex]x_1[/tex] and [tex]y_1[/tex] in  the equation:

[tex]a=\frac{x_1+x_2}{2} \\\\b=\frac{y_1+y_2}{2}[/tex]

[tex]-5=\frac{-2+x_2}{2} \\\\-2+x_2=-5(2)\\\\x_2=-10+2\\\\x_2=-8[/tex]

Solve for [tex]y_2[/tex]

[tex]b=\frac{y_1+y_2}{2} \\\\-1=\frac{-5+y_2}{2} \\\\-2=-5+y_2\\\\y_2=-2+5\\\\y_2=3[/tex]

The coordinates of the other endpoint are (-8, 3)

Learn more here: https://brainly.com/question/20696453

Answer: 1) y=1/3x-1

2) y=-2/5x+0

3) y=1x+8

4) y=-3/6x+3

5) y=5/2x+1

6) y=-8/2x-5

7) y=1x+2

8) y=-2/3x-4

9) y=6/5x

Step-by-step explanation: For the graph: if the line is pointing to the right Mx from the equation Y=Mx+B it’s going to be POSITIVE for example: Y=7x+4 If it’s pointing to the left it’s NEGATIVE for example: Y=-6x+2. If want to know the Y-INTERCEPT = B you have to find the point that is connected to the (0,0) on the graph

Answer:

3 1/2 is the closest

Step-by-step explanation:

Theres 3 that are full and 2/5

Answer:

its 3 1/2 or c

Step-by-step explanation:

Answer:

Answer is (-1,-2) As where 2 lines bisect, that point be the answer. And in given scenario, both the lines bisected at (-1,-2)

Step-by-step explanation:

Answer:

System of Equations is given as:

c = 2h - 1...... Equation 1

1.8c + 3h = 288.60....Equation 2

Step-by-step explanation:

Let us represent

The number of Cold lunch = c

The number of Hot lunch = h

The number of cold lunches the teacher bought was 1 fewer than twice the number of hot lunches the teacher bought.

Hence:

c = 2h - 1

At a school cafeteria a cold lunch costs $1.80, and a hot lunch costs $3.00. During one school year a school year a teacher spent a total of $288.60 on cold lunches and hot lunches.

Hence:

$1.80 × c + $3.00 × h = $288.60

1.8c + 3h = 288.60....Equation 2

The system of equations can be used to find c, the number of cold lunches, and h, the number of hot lunches, the teacher taught during the school year is given as:

c = 2h - 1...... Equation 1

1.8c + 3h = 288.60....Equation 2

The system of equations that can be used to calculate the number of hot and cold lunches is [tex]\mathbf{1.80c +3.00h = 288.60}[/tex] and [tex]\mathbf{c = 2h - 1}[/tex]

Let h represents hot lunch, and c represents cold lunch.

So, we have:

[tex]\mathbf{1.80c +3.00h = 288.60}[/tex]

[tex]\mathbf{c = 2h - 1}[/tex]

Substitute [tex]\mathbf{c = 2h - 1}[/tex] in [tex]\mathbf{1.80c +3.00h = 288.60}[/tex]

[tex]\mathbf{1.80(2h -1) +3.00h = 288.60}[/tex]

Expand

[tex]\mathbf{3.60h -1.80 +3.00h = 288.60}[/tex]

Collect like terms

[tex]\mathbf{3.60h +3.00h = 288.60 + 1.80}[/tex]

[tex]\mathbf{6.60h = 290.4}[/tex]

Divide both sides by 6.60

[tex]\mathbf{h = 44}[/tex]

Substitute 44 for h in [tex]\mathbf{c = 2h - 1}[/tex]

[tex]\mathbf{c = 2(44) - 1}[/tex]

[tex]\mathbf{c = 83}[/tex]

Hence, the system of equations that can be used to calculate the number of hot and cold lunches is [tex]\mathbf{1.80c +3.00h = 288.60}[/tex] and [tex]\mathbf{c = 2h - 1}[/tex]

Read more about simultaneous equations at:

https://brainly.com/question/16763389

Answer:

A. Infity and B. is 1

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

Conjugate of z = -3-5i

Therefore the expression is equivalent to (-3+5i)(-3-5i).

(-3+5i)(-3-5i)

=(-3)^2-(5i)^2

=9-(-25)

=36

Answer:

z (the conjugate of z) = 34

Answer:

Q) (-2, 2)

V) (2, 2)

Step-by-step explanation:

Answer:

(-5*m)-(-5*2)

Step-by-step explanation:

Here, we want to use the distributivity property to evaluate the expression

We have this as;

(-5*m)-(-5*2)

ANSWER:

2.) There are 5 students absent on day 3 because the dot is in the line of 5 in day 3.

3.) The 2 day is the greatest number of students absent beacause on that 2 day, 10 students were absent

I obviously know this is the answer

Answer:

6ft

Step-by-step explanation:

Answer:

sorry dude

Step-by-step explanation:

Answer:

13.50200 or 13

Step-by-step explanation:

you use c = 3.14 (which is pie) x d to get the full sphere, hopefully this is correct

Answer:

[tex]Probability = 0.2975[/tex]

Step-by-step explanation:

Giving:

Swimming

[tex]P(Win[Swim])= 65\%[/tex]

Running

[tex]P(Win[Run])= 85\%[/tex]

Required

Determine the probability of winning at running and losing at swimming

First, we calculate the probability of losing at swimming using

[tex]P(Win) + P(Lose) = 1[/tex]

Substitute 65% for P(Win)

[tex]65\% + P(Lose[Swim]) = 1[/tex]

Collect Like Terms

[tex]P(Lose[Swim]) = 1 - 65\%[/tex]

[tex]P(Lose[Swim]) = 35\%[/tex]

The required probability is then calculated using:

[tex]Probability = P(Win[Run]) * P(Lose[Swim])[/tex]

[tex]Probability = 85\% * 35\%[/tex]

Convert to decimal

[tex]Probability = 0.85 * 0.35[/tex]

[tex]Probability = 0.2975[/tex]

Answer is 0.0005164x

9514 1404 393

Answer:

  v(t) = 30000×0.82^t . . . value in dollars after t years

  v(10) ≈ 4123 . . . . dollars

Step-by-step explanation:

The general form of the decay model is ...

  f(t) = f(0)×(1 -decay rate)^time

where the decay rate is a fraction between 0 and 1, and the time is expressed in the same time units as the decay rate. The multiplier f(0) is the initial value that is decaying.

In this problem, the initial value is $30,000 and the decay rate is 18% per year. So, we can write a function v(t), where v is the car's value in dollars, and t is the number of years after it starts depreciating.

  v(t) = 30,000×(1 -0.18)^t

  v(t) = 30,000×0.82^t

__

The car's value in 10 years is ...

  v(t) = 30,000×0.82^10 ≈ 4123.44

The value of the car after 10 years is about $4,123.

Answer:627.072

Step-by-step explanation:

Step-by-step explanation:

(4x-3)(3x+6)

4x(3x+6)-3(3x+6)

12x+24-9x-18

12x-9x+24-18

3x+6

x=6/3

x=2

Answer:

The production cost is Rs 12,500

Step-by-step explanation:

Let the production cost be $x

At any point in time

sales price = cost price +( profit percentage* cost price)

Manufacturer gaining 6%

That would be;

x + 6% of x

x + 0.06x

= 1.06x

Wholesaler gaining 8%

= 1.06x + 8% of 1.06x

1.06x + 0.08(1.06x)

= 1.06x + 0.0848x

= 1.1448x

The for the retailer

= 1.1448x + 10% of 1.1448x

= 1.1448x + 0.11448x

= 1.25928x

1.25928x = 15,741

x = 15,741/1.25928

x = 12,500

Answer:

81,00000000

Step-by-step explanation:

Hope this Helps! :)

Answer: Lucy pays $ 492.58  back altogether.

Step-by-step explanation:

Formula : Interest = Principal x Rate x Time

Given: Principal  = $425  , rate = 5.3% = 0.053 , time = 3 years

Interest = 425 x 0.053 x 3 ≈ $ 67.58

Total amount need to pay back = Principal + Interest

= $ (425+67.58)

= $ 492.58

Hence, Lucy pays $ 492.58  back altogether.

Answer:

24 blue beads

Step-by-step explanation:

The number of blue beads is calculated as:

Percentage of blue beads × Total number of beads

Total number of beads = 40 beads

Hence:

= 60% × Total number of beads

= 60% × 40

= 60/100 × 40

= 24 blue beads

Joel received 24 blue beads.

Answer:

50

Step-by-step explanation:

Answer:

[tex]\sin \alpha = \frac{5}{13}[/tex], [tex]\cos \alpha = \frac{12}{13}[/tex], [tex]\tan \alpha = \frac{5}{12}[/tex], [tex]\cot \alpha = \frac{12}{5}[/tex], [tex]\sec \alpha = \frac{13}{12}[/tex], [tex]\csc \alpha = \frac{13}{5}[/tex]

Step-by-step explanation:

The angle [tex]\alpha[/tex] is the angle opposite to the side of length 5 and adjacent to the side of length 12. From Trigonometry we remember the following relationships:

[tex]\sin \alpha = \frac{5}{\sqrt{5^{2}+12^{2}}}[/tex]

[tex]\sin \alpha = \frac{5}{13}[/tex]

[tex]\cos \alpha = \frac{12}{\sqrt{5^{2}+12^{2}}}[/tex]

[tex]\cos \alpha = \frac{12}{13}[/tex]

[tex]\tan \alpha = \frac{5}{12}[/tex]

[tex]\cot \alpha = \frac{12}{5}[/tex]

[tex]\sec \alpha = \frac{\sqrt{5^{2}+12^{2}}}{12}[/tex]

[tex]\sec \alpha = \frac{13}{12}[/tex]

[tex]\csc \alpha = \frac{\sqrt{5^{2}+12^{2}}}{5}[/tex]

[tex]\csc \alpha = \frac{13}{5}[/tex]