5x
If f(x) = 5x and g(x)= 5x/3, find f(x) divided by g(x).

A. 1/3

B. 3

C. 3/25x^2

D. 25x^2/3

Answers

Answer 1

i think its b Step-by-step explanation:

Answer 2

[tex] \frac{5x}{ \frac{5x}{3} } = \frac{15x}{5x} = 3[/tex]

5xIf F(x) = 5x And G(x)= 5x/3, Find F(x) Divided By G(x). A. 1/3B. 3C. 3/25x^2D. 25x^2/3

Related Questions

On a Job application Doris gave her age as 32 years. Her actual age at the time was about 27. What is the relative error fo her age?

Answers

Answer:

Relative error = 0.19

Step-by-step explanation:

From the question given above, the following data were obtained:

Measured age = 32 years

Actual age = 27 years

Relative error =?

Next, we shall determine the absolute error. This can be obtained as follow:

Measured age = 32 years

Actual age = 27 years

Absolute error =?

Absolute error = | Measured – Actual |

Absolute error = | 32 – 27 |

Absolute error = 5 years

Finally, we shall determine the relative error. This can be obtained as follow:

Absolute error = 5 years

Actual age = 27 years

Relative error =?

Relative error = Absolute error / Actual years

Relative error = 5 / 27

Relative error = 0.19

Mrs. Kennedy is teaching an 8th grade class. She is standing 7 meters in front of Catherine. Davis is sitting to Catherine’s left. If Davis and Mrs. Kennedy are 12 meters apart, how far apart are Davis and Catherine?
13.90 meters
5 meters
9.75 meters
4.36 meters

Answers

Answer:

9.75 meters

Step-by-step explanation:

Davis and Catherine are approximately 13.90 meters apart.

How to determine distance apart

To find the distance between Davis and Catherine, we can use the concept of right triangles and apply the Pythagorean theorem.

Let's consider a right triangle where the distance between Davis and Mrs. Kennedy is the base, the distance between Mrs. Kennedy and Catherine is the height, and the distance between Davis and Catherine is the hypotenuse.

According to the given information, Mrs. Kennedy is 7 meters in front of Catherine, and Davis and Mrs. Kennedy are 12 meters apart.

Using the Pythagorean theorem, we have:

(Base)² + (Height)² = (Hypotenuse)²

Substituting the given values:

(12)² + (7)² = (Hypotenuse)²

Simplifying the equation:

144 + 49 = (Hypotenuse)²

193 = (Hypotenuse)²

Taking the square root of both sides:

√193 ≈ 13.89 = 13.90

Therefore, Davis and Catherine are approximately 13.90 meters apart.

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Check out this cube: 3 Find the surface area of the cube (above) using its net (below​

Answers

Answer:

54

Step-by-step explanation:

Surface area of a cube = 6a²

Where,

a = edge = 3

Surface area of a cube = 6a²

= 6 * (3)²

= 6 * (3 * 3)

= 6 * 9

= 54

Therefore,

The Surface area of the cube = 54

WILL MARK BRAINLIEST

picture included^^^^

need help asap please n thank you!


^^^^

Answers

Answer:

14

Step-by-step explanation:

The a value is from the center to the maximum

We want from minimum to max so we need 2 times the amplitude

a = 7

2 *7 = 14

What is the area of this polygon

Answers

Answer:

51

Step-by-step explanation:

1. Approach

One is given the polygon, (ABCDE); the problem asks one to find the area of this polygon. The most logical step to take is to divide this polygon into easier parts, find the area of each part, and then add up the area to find the total area of the figure.

One way to divide this figure up is to draw the line (AC). This will create the triangle (ABC) and rectangle (ACDE).

2. Find the area of (ABC)

The formula to find the area of a triangle is the following:

[tex]A=\frac{b*h}{2}[/tex]

Where (b) is the base of the triangle, and (h) is the height. The base of the triangle (ABC) is (AC), which has a measure of (6) units. The height of the triangle is the distance from the base of the triangle to the vertex opposite the base. This measurement is (3) units. Substitute these values into the formula and solve for the area:

[tex]A=\frac{b*h}{2}[/tex]

Substitute,

[tex]A=\frac{6*3}{2}\\\\A=\frac{18}{2}\\\\A=9[/tex]

3. Find the area of (ACDE)

The formula to find the area of a rectangle is as follows:

[tex]A=b*h[/tex]

The base of the rectangle is the segment (AE), with a measure of (7) units. The height of the rectangle is the segment (AC) with a measurement of (6) units. Substitute these values into the formula and solve for the area:

[tex]A=7*6\\\\A=42[/tex]

4. Find the area of the total figure

To find the area of the total figure, add up the area of the triangle, and the area of the rectangle:

[tex]9+42= 51[/tex]

A random sample of 13 teenagers were surveyed for a hypothesis test about the mean weekly amount spent on convenience goods. Researchers conduct a one-mean hypothesis test, at the 1% significance level, to test whether the average spent per week on convenience goods is greater than 50 dollars.

Answers

Answer:

Please find the complete question and the graph in the attached file.

Step-by-step explanation:

On the basis of the data,

The level of importance is [tex]\alpha = 0.01[/tex]

Freedom levels [tex]= n -1 = 13 -1 = 12[/tex]

For the right-tailed test, the critical value is [tex]t_c = 2.681[/tex]

(Partially t-table permitted [tex]\alpha = 0.01 \ and\ df =12[/tex])

10 fracciones que generen decimales exactos 10 fracciones que generen decimales inexactos puros y 10 fraccionarios que generen decimales periódicos mixtos

Answers

Answer:

Un número decimal exacto es algo de la forma:

3.27

Para reescribir este número como una fracción, podemos ver que tiene dos dígitos luego del punto.

Entonces podemos multiplicar y dividir por 100 (misma cantidad de ceros que dígitos luego del punto decimal)

así obtenemos:

3.27*(100)/(100) = 327/100

Entonces la fracción 327/100 genera un decimal exacto.

Así, encontrar 10 fracciones es trivial, 10 ejemplos son:

7/10 = 0.7

314/100 = 3.14

27/10 = 2.7

27/100 = 0.27

2/10 = 0.2

25/100 = 0.25

31/10 = 3.1

12/10 = 6/5 = 1.2

131/10 = 13.1

142/100 = 1.42

Ahora, un decimal inexacto puro es algo de la forma:

3.33...

donde el 3 se repite infinitamente.

Tratemos de reescribir este número como una fracción:

primero debemos ver la cantidad de dígitos que se repiten, en este caso es uno solo, el 3, entonces multiplicamos por 10:

3.33*10 = 33.33...

Ahora, podemos restar el numero original:

33.333... - 3.333... = 30

Entonces tenemos que:

3.33*9 = 30

3.33 = 30/9

La fracción:

30/9 nos da in decimal inexacto puro.

Ahora que sabemos construirlas, 10 ejemplos pueden ser:

30/9 = 3.33....

1/3 = 0.33...

40/9 = 4.44...

50/9 = 5.55...

60/9 = 6.66...

70/9 = 7.77...

20/9 = 2.22...

55/9 = 6.11...

544/99 = 5.5959...

10/9 = 1.11...

Finalmente, un periódico mixto es algo de la forma:

1.2343434...

Es decir, el 34 se repite infinitamente, pero también tenemos un 2 luego del punto decimal, por lo que este número no es puramente periódico.

Para construirlos, podemos tomar una fracción exacta, como

1.1 y una periódica, como 1.11...

Si las sumamos, obtenemos:

1.1 + 1.11... = 2.211...

donde el uno se repetirá infinitamente.

Así, simplemente sumando las fracciones del primer caso con las del segundo, obtendremos decimales periódicos mixtos, por ejemplo:

7/10 + 55/9 = 613/90 = 0.7 +  6.11... = 6.8111....

7/10 +  10/9 = 163/90 = 0.7 + 1.11... = 1.811....

31/10 + 10/9 = 379/90 = 3.1 + 1.11... = 4.2111...

31/10 + 20/9 = 479/90 = 3.1 + 2.22... = 5.322...

31/10 + 30/9 = 579/90 = 3.1 + 3.33... = 6.4333...

27/10 + 20/9 =  443/90 = 2.7 + 2.22... = 4.922...

37/10 + 20/9 =  533/90 = 3.7 + 2.22... = 5.922...

4/10 +  10/9 = 136/90 = 0.4 + 1.11... = 1.511....

3/100 + 10/9 = 1027/900 = 0.03 + 1.11... = 1.14111...

4/10 +  20/9 = 236/90 = 0.4 + 2.22... = 2.622....

Solve the equation sine Ф=0.6792 for 0°≤Ф≤360

Answers

Answer:

42.78⁹, 137.22⁹.

Step-by-step explanation:

sine Ф=0.6792

Angle Ф in the first quadrant = 42.78 degrees.

The sine is also positive in the second quadrant so the second solutio is

180 - 42.78

= 137.33 degres.

b. Compare the similar triangle proof from question 3 with the inscribed square

proof. How are they different? Which method was easier for you to understand?

(1 point)

Answers

Answer:

i might be wrong but this is what i put

Step-by-step explanation:

In question 3 it was comparing three triangles where now it is using the triangles to find the area of a square instead of proving that they are the same.

The length of a rectangle is 3 times the width. The perimeter of the rectangle is 64 cm. Show the equation that would be used to find the dimensions of the rectangle.

Answers

Answer:

64 = 2(3x + x)

Step-by-step explanation:

Perimeter of the rectangle = 64 cm

Width of the rectangle = x

Length of the rectangle = 3x

Perimeter of a rectangle = 2(length + width)

The equation is

64 = 2(3x + x)

64 = 6x + 2x

64 = 8x

x = 64/8

x = 8 cm

Width of the rectangle = x = 8 cm

Length of the rectangle = 3x

= 3(8 cm)

= 24 cm

What is the solution to this system of equations?
2x+y = 6
- - x - y = 2
0
0
(1, -1)
(0,8)
infinitely many solutions
no solution

Answers

Answer:

Step-by-step explanation:

{ 2/3 x+y=6

+

{ -2/3x-y=2

= 0=6

Hence,no solution.

What is the solution to this equation?
log_8 16 + 2log_8x =2

Answers

The awnser is I think x=2

The value of x for the given equation [tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2 will be 2 so option (B) must be correct.

What is a logarithm?

The exponent indicates the power to which a base number is raised to produce a given number called a logarithm.

In another word, a logarithm is a different way to denote any number.

Given the equation

[tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2

We know that,

xlogb = log[tex]b^{x}[/tex]

So,

2[tex]log_{8}[/tex](x) = logx²

For the same base

logA + logB = log(AB)

So,

[tex]log_{8}[/tex](16) + [tex]log_{8}[/tex](x)² = 2

[tex]log_{8}[/tex](16x²) = 2

We know that

[tex]log_{a}[/tex](b) = c ⇒ b = [tex]a^{c}[/tex]

so,

[tex]log_{8}[/tex](16x²) = 2 ⇒ 8² = 16x²

x = 2 hence x = 2 will be correct answer.

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-2/3a+5/6a-1/5a-1/6

Answers

Answer:

[tex]\frac{-1}{30} a - \frac{1}{6}[/tex]

Step-by-step explanation:

Give the order of symmetry from the fig 3
a)2
b)3
c)6
d)4

Answers

the order of symmetry is three as there are three of each repeated shape

This Venn diagram shows the pizza topping preferences for 9 students.
What elements are in A and B?
(Look at picture)

Answers

Answer:

I think the answer is C.

(8) The average daily temperatures in July of some cities in Texas are shown in the table. Which
of the following fiets the cities from greatest temperature to least temperatura
City
Average Daily
Temperature
Austin
84.52F
Dallas
85.9°F
San Antonio
85 F
Fort Worth
85.31°F
a. Dallas, Fort Worth, San Antonio, Austin
b. Austin, Dallas, San Antonio, Fort Worth
c. Austin, San Antonio, Fort Worth, Dallas
d. Dallas, San Antonio, Fort Worth, Austin

Answers

Answer:

A.

Step-by-step explanation:

85.9 > 85.31 > 85 > 84.52

Dallas, Fort Worth, San Antonio, Austin

Solve the equation for x: (4x+38) + (2x-18)=180

Answers

Answer:

80/3

Step-by-step explanation:

try mathw4y it helps alot.

Answer:

x = 80/3

Step-by-step explanation:

(4x+38) + (2x-18)=180

Combine like terms

6x +20 = 180

Subtract 20 from each side

6x+20 -20 = 180-20

6x = 160

Divide by 6

6x/6 = 160/6

x = 80/3

Finish the following table for the given function with x as the independent variable

Answers

Answer:

hi?

Step-by-step explanation:

choose the equation that satisfies the data in the table

Answers

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

See this attachment

option D is correct

plz help me to do this​

Answers

Answer: b

Explain: because that’s where they both meet

how many metres are there in ½ of ⅕ km​

Answers

Step-by-step explanation:

1/5=1/5×1000=200

1/2 of 200

1/2×200=100

PLZZZZ HELPPPP… IF NOT 100% SURE PLZZ DONT ANSWER! BRAINLIEST TO FIRST AND CORRECT ANSWER!

Answers

Answer is 7/10 because you need the same denominator so you multiply 1/2 by 5 both top and bottom then multiply 1/5 by 2 both top and bottom and then add numerator

Answer:

7/10

Step-by-step explanation:

½ of a cup of cheddar=½ x 1=½

⅕ of a cup of parmesan=⅕ x 1=⅕

all cheese used=½ + ⅕= 7/10

A parallelogram is cut out of a 12 inch by 8 inch sheet of paper there are four right triangles remnats two have the dimensions 2 inches by 9 inches and the other two have the dimensions 3 inches by 6 inches

Answers

Answer:

96 in²

36 in²

60 in²

6.51 in

Step-by-step explanation:

Given that :

Dimension of paper = 12 in by 8 in

Dimension of right triangles :

2 in by 9 in ; 3 in by 6 in

Area of sheet of paper = 12 in * 8 in = 96 in²

Area of triangle = 1/2 base * height

Therefore, area of remnant right triangle :

2 * 1/2 * 2 * 9 = 18 in²

2 * 1/2 * 3 * 6 = 18 in²

Combined area of triangle left = 18in + 18in = 36 in²

Area of parallelogram = Area of sheet - Area of triangles left

Area of parallelogram = 96in² - 36in² = 60 in²

Base, b of parallelogram = 9.22 in

Area of parallelogram = base * altitude,h

60in² = 9.22h

h = 60 / 9.22 = 6.51 in

please anyone help no wrong asnwers plss ------

Answers

(-1/4, 2 1/4)

I graphed the equations and that was the other solution. See the attached photo to view the graph.

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

please help



yuffytdgtutidrysryrdf

Answers

Answer:

19 + 1 + 9 + 1

put any of those in the slots

Answer:

19 + 1 + 9 + 1

peace

Choose the graph that correctly corresponds to the equation y = −4

Answers

Answer:

e

Step-by-step explanation:

the graph should look something like this

Which of the following statements does not prove that ABCD is a parallelogram.
Given: A(-4, 7), B(3,0), C(2,-5) and D(-5, 2).

Answers

Answer:

answer A

Step-by-step explanation:

A=(-4,7)

C=(2,-5)

midpoint = U=((-4+2)/2, (7+(-5))/2)=(-1,1))

B=(3,0)

D=(-5,2)

midpoint = V=((3+(-5))/2,(0+2)/2)=( -1,1)

Diagonals have the same middle, the quadrilater is a parallogram.

Help me plss I’m lost ☺️❤️

Answers

Answer:

there is only one way to to roll a 3

1/36 = .044 = 4.4%

Step-by-step explanation:

4.4?
I hope that works if not sorry.

Can someone please help

Answers

Answer:

[tex]162.07[/tex]

Step-by-step explanation:

An image that creates represents this situation has been attached to this answer. As one can see, the diagram models the situation, the angle of depression represents the angle between the horizon line and the line of sight. The horizon line and the tower form a right angle (a (90) degree angle). This means that the angle of depression is complementary to the angle of sight. Therefore, one can state the following:

[tex](angle\ of\ depression) + (angle\ of \ sight)=90[/tex]

Substitute,

[tex](angle\ of\ depression) + (angle\ of \ sight)=90[/tex]

[tex](m<ABD)+(m<DBC)=90[/tex]

[tex]42+(m<DBC)=90[/tex]

Inverse operations,

[tex]42+(m<DBC)=90[/tex]

[tex]m<DBC=48[/tex]

Now one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are a series of ratios that describe the relationship between the sides and angles in a right triangle. These ratios are as follows:

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}[/tex]

Bear in mind, the terms (opposite) and (adjacent) are subjective, and change depending on the reference angle. However, the term (hypotenuse) refers to the side opposite the right angle and is constant regardless of the reference angle.

In this case, one has found an angle in the triangle, one is given the measure of the side opposite this angle, and one is asked to find the side adjacent to this angle. Therefore, it would make the most sense to use the ratio tangent (tan).

[tex]tan(\theta)=\frac{opposite}{adjacnet}[/tex]

Substitute,

[tex]tan(48)=\frac{180}{adjacent}[/tex]

Inverse operations,

[tex]tan(48)=\frac{180}{adjacent}[/tex]

[tex]adjacent=\frac{180}{tan(48)}[/tex]

[tex]adjacent=162.07[/tex]

Which angles are adjacent to each other?

• Angle KGD and Angle AEB
• Angle BEC and Angle AEB
• Angle AEB and Angle ECU
• Angle JCI and Angle KGD​

Answers

Answer:

Step-by-step explanation:

adjacent angles have a common vertex and a common ray

∠BEC and ∠AEB (common vertex E common ray EB)

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