Answer:
730 million in numbers = 730,000,000
730M in short form.
Instructions: Complete the following theorem.
"If m⊥t and n⊥t, then
∥
."
Answer:
m║n
Step-by-step explanation:
If two lines 'line m' and 'line n' are perpendicular to the 'line t', both the lines 'm' and 'n' will be parallel to each other.
If m ⊥ l and n ⊥ l, then m║n.
What is the volume of the cylinder below
Answer:
Option A, 80π
Step-by-step explanation:
4²×5π
= 80π
Which of the following is equivalent to the expression below?
Square root of -81
A. 9
B. -9
C. 9i
D. -9i
Answer:
C 9i
D -9i
Step-by-step explanation:
sqrt(-81)
sqrt(81) sqrt(-1)
we know that sqrt(-1) = i
±9i
0.45 0.40 0.11 This question uses the following probability model for the blood type of a randomly chosen person in the United States: Maria has type A blood. She can safely receive blood transfusions from people with blood types O and A. The probability that a randomly chosen American can donate blood to Maria is ______. (Give your answer to 2 decimal places.)
Answer:
[tex]P(O\ or\ A) = 0.85[/tex]
Step-by-step explanation:
Given
See attachment
Required
[tex]P(O\ or\ A)[/tex]
From the question, we understand that she can only get blood from O or A groups. So, the probability is represented as:
[tex]P(O\ or\ A)[/tex]
This is calculated as:
[tex]P(O\ or\ A) = P(O) + P(A)[/tex]
Using the American row i.e. the blood must come from an American.
We have:
[tex]P(O) = 0.45[/tex]
[tex]P(A) = 0.40[/tex]
So, we have:
[tex]P(O\ or\ A) = 0.45 + 0.40[/tex]
[tex]P(O\ or\ A) = 0.85[/tex]
What is the solution of this equation 5( x - 4) = 3x + 4
Three ounces of cinnamon cost $2.40. If there are 16 ounces in 1 pound, how much does cinnamon cost per pound?
20 students were asked “How many pets do you have in your household?” and the following data was collected:
2 1 0 3 1 2 1 3 4 0
0 2 2 0 1 1 0 1 0 1
Select the type of the data ?
Discrete
Continuous
Categorical
Qualitative
NO FAKE ANS
FRIST MARKED BRAINLIST
CHOOSE ONE ANS
Answer:
qualitative
Step-by-step explanation:
bcos the question is in quality format
Answer:
we are armysss!!!!\
hiiiiiiiiii
yoooooooo
heyyyyyy
brainlist meeee!
Safety regulations require that the time between airplane takeoffs (on the same runway) will be at least 2 minutes. When taking off, the run time of an airplane on the runway is 27 seconds. Planes are on average waiting 4 minutes and 21 seconds for take-off. On average there are 21 planes taking off per hour. How many planes are either on the runway or waiting to take off
Answer:
Number of planes on the runway or waiting to take off is approximately 2
Step-by-step explanation:
Given the data in the question;
On average there are 21 planes taking off per hour
rate of flow = frequency of take off = 21 planes / hr
= 21 planes per 60 minutes
= 0.35 planes/min
Now, we get the throughput time
throughput time = total time for take off = waiting time on runway + run time on runway
= (4 minutes and 21 seconds) + 27 seconds
= 4.35 minutes + 0.45 minutes
= 4.8 minutes
Now, using Little's law;
Number of planes on the runway or waiting to take off will be;
N = Rate of flow × throughput time
we substitute
N = ( 0.35 planes/min ) × 4.8 min
N = 1.68 planes ≈ 2 planes
Therefore, Number of planes on the runway or waiting to take off is approximately 2
Urgent need answer for this one.
Answer:
4th option
Step-by-step explanation:
6/sin(65) = 5/sin(x)
or, 6×sin(x) = 5×sin(65)
or, sin(x) = 5×sin(65)/6
or, x = arcsin(5×sin(65)/6)
x^{2}[(y'−x^{2})+3xy=cosx, (x>0)
The given differential equation is
x ² (y' - x ²) + 3xy = cos(x)
Expanding and rearranging terms, we get
x ² y' + 3xy = cos(x) + x ⁴
Multiply both sides by x, which is motivated by the fact that (x ³)' = 3x ².
x ³ y' + 3x ²y = x cos(x) + x ⁵
The left side is the derivative of a product:
(x ³y)' = x cos(x) + x ⁵
Integrate both sides with respect to x :
∫ (x ³y)' dx = ∫ (x cos(x) + x ⁵) dx
x ³y = cos(x) + x sin(x) + 1/6 x ⁶ + C
Solve for y. Since x > 0, we can safely divide both sides by x ³.
y = cos(x)/x ³ + sin(x)/x ² + 1/6 x ³ + C/x³
ents
Projectile Motion
Prog!
ons
Score: 0/1
0/1 answered
Question 1
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A rocket is launched at t = 0 seconds. Its height, in meters above sea-level, is given by the equation
h = - 4.9+2 + 112 + 395.
At what time does the rocket hit the ground? (Round answer to 2 decimal places.)
5
The rocket hits the ground after
seconds.
5
es
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what is the relationship and what does X equal?
help! :)
Answer:
4x + 3 = 59
x = 14
Step-by-step explanation:
The vertical angles theorem states that when two lines intersect, the angles opposite each other are congruent. One can apply this here by stating the following:
4x + 3 = 59
Solve for (x), use inverse oeprations:
4x + 3= 59
4x = 56
x = 14
Answer:
Relationship : Vertical angle
Step-by-step explanation:
(4x + 3) = 59
4x = 59 - 3
4x = 56
x = 56/4
x = 14
annual cost of 35,000 expected to save 40,000 during the first year how many months will the take to recover investment
Answer:
500000
Step-by-step explanation:
Analyse the table of values. The variable, T, represents the quantity (L) of gas in a tank and the variable, d, represents the distance travelled (km). What is the rate of change? Show calculations. Describe what this rate means in the real world? Graph this relation. Extrapolate to discover how far the vehicle travels before the tank is empty.
Answer:
The answer is below
Step-by-step explanation:
The equation of a straight line is given by:
y = mx + b;
where y, x are variables, m is the rate of change and b is the y intercept.
a) d is on the x axis and T is on the y axis, the rate of change is gotten using the points (0, 75) and (300, 37.5). Hence the rate of change (m) is:
[tex]m=\frac{y_2-y_1}{x_2-x_1} =\frac{37.5-75}{300-0} =-0.125[/tex]
b) The rate of change means that the quantity of gas in tank decreases by 0.125 for every km traveled.
c) The graph was plotted using geogebra online graphing tool.
d) Using the points (0, 75) and (300, 37.5), the equation of the line is:
[tex]T-T_1=\frac{T_2-T_1}{d_2-d_1}(x-x_1) \\\\T-75=\frac{37.5-75}{300-0}(d-0)\\\\T=-0.125d+75[/tex]
The tank is empty when T = 0, hence:
0 = -0.125d + 75
0.125d = 75
d = 600 km
The tank is empty at 600 km
Can someone please do these three and number them? -Numbers: 10,11,12-
Answer:
10. Option: c11. Option: a12. Option: aThe minimum number of parallel faces that a prism should have is
Answer:
The minimum number of parallel faces that a prism should have is three pairs
Answer:
The minimum number of parallel faces that a prism should have is three faces
Roll a pair of fair dice. Let X be the number of ones in the outcome and let Y be the number of twos in the outcome. Find E[XY].
Answer:
E(XY)=1/18
Step-by-step explanation:
x y P(x,y) xy*P(X,Y)
0 0 4/9 0
0 1 2/9 0
1 0 2/9 0
1 1 1/18 1/18
2 0 1/36 0
0 2 1/36 0
1 1/18
from above:
E(XY)=1/18
evaluate 2x-y when x=5 and when y=12
Answer:
-2
Step-by-step explanation:
GIVEN :-
x = 5 and y = 12
TO FIND :-
2x - y
SOLUTION :-
placing the values of x and y
(2 × 5) - 12
10 - 12
-2
Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form
Answer:
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}[/tex]
Step-by-step explanation:
Hi there!
Slope-intercept form: [tex]y=mx+b[/tex] where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept (the value of y when x is 0)
1) Determine the slope (m)
[tex]m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}[/tex] where two given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the given points (15,2.2) and (5,1.6):
[tex]m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}[/tex]
Therefore, the slope of the line is [tex]\frac{\displaystyle 3}{\displaystyle 50}[/tex]. Plug this into [tex]y=mx+b[/tex]:
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+b[/tex]
Plug in a given point and solve for b:
[tex]1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b[/tex]
Therefore, the y-intercept is [tex]\frac{\displaystyle 13}{\displaystyle 10}[/tex]. Plug this back into [tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+b[/tex]:
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}[/tex]
I hope this helps!
PLEASE HELP
Complete the table to find the different combinations of coin quantities that have a sum of $2.41. (See photo above)
Answer:
1st row 56 pennies
2nd row 36 pennies
3rd row 14 dimes
4th row 4 quarters
5th row 5 nickels
Step-by-step explanation:
1st row $1.85 + 56 cents = $2.41
2nd row $2.05 + 36 cents = $2.41
3rd row is $1.01 + $1.40 = $2.41
4th row $1.41 + $1.00 = 2.41
5th row $2.16 + 25 cents = $2.41
Does anyone know these?
Answer:
1 = - 4 - 14 √3
2 = 9 - 11 √3
Step-by-step explanation:
Question 1
(-4√3 + 2)(√3 + 4)
Apply FOIL method
= (-4√3) √3 + (-4√3) . 4 + 2 √3 + 2 . 4
Apply minus-plus rules: + (-a) = -a
= -4 √3 √3 - 4 . 4 √3 + 2 √3 + 2 . 4
Simplify
= - 4 - 14 √3
Question 2
(-3 + √3)(1 + 4 √3)
Apply FOIL method
= (-3) . 1 + (-3) . 4 √3 + √3 . 1 + √3 . 4 √3
Apply minus-plus rules: + (-a) = -a
= -3 . 1 - 3 . 4 √3 + 1 . √3 + 4 √3 √3
Simplify
= 9 - 11 √3
Suppose f"(x) = -9 sin(3x) and f'(0) = -4, and f(0) = -2
Find f(pi/4)
Answer:
9sin (3)and f,(0)=4,AND f(0)=2
If the common difference of an ap is 3/2 and its 20 th term 35×1/2 find first term and 15 th term
Answer:
Step-by-step explanation:
d = 3/2
a₂₀ = a₁+19d
35/2 = a₁ + 19×3/2
a₁ = 35/2 - 19×3/2 = -11
a₁₅ = a₁+14d = -11 + 14×3/2 = 10
Match each equation with its number of unique solutions.
y = 3x2-6x+3
y = -x2 - 4x + 7
y = -2x2+9x-11
Two Real Solutions
One Real Solution
One Complex Solution
Two Complex Solutionse de
Answer:
y = 3x^2-6x+3 one real solution
y = -x^2 - 4x + 7 two real solution
y = -2x^2+9x-11 two complex solutions
Step-by-step explanation:
b^2-4ac = 0 1 repeated real solution
b^2-4ac > 0 2 distinct real solutions
b^2-4ac < 0 2 complex solutions
The quadratic functions have the following solutions:
y = 3x²-6x+3 has two real solutions.
y = -x² - 4x + 7 has one real solution.
y = -2x²+9x-11 has one complex solution.
The given quadratic functions are y = 3x²-6x+3, y = -x² - 4x + 7 and y = -2x²+9x-11.
What is the discriminant of a quadratic equation?The discriminant of a quadratic equation ax² + bx + c = 0 is in terms of its coefficients a, b, and c. i.e., Δ OR D = b² − 4ac.
Now, with the function y = 3x²-6x+3, we get
b² − 4ac=(-6)²-4×3×3=36-36=0
Since b=0 it has two real solutions.
Now, with the function y = -x² - 4x + 7, we get
b² − 4ac= (-4)²-4×(-1)×7=16+28=44
Since b>0 it has one real solutions.
Now, with the function y = -2x²+9x-11, we get
b² − 4ac= (9)²-4×(-2)×(-11)=81-88=-7
Since b<0 it has one complex solution.
Therefore, the quadratic functions have the following solutions:
y = 3x²-6x+3 has two real solutions.
y = -x² - 4x + 7 has one real solution.
y = -2x²+9x-11 has one complex solution.
To learn more about the quadratic function solutions visit:
https://brainly.com/question/1687230.
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Write the equation of a line, in slope-intercept form
(1,1);(-2,-11)
Y =
Answer:
Y =4X -3
Step-by-step explanation:
x1 y1 x2 y2
1 1 -2 -11
(Y2-Y1) (-11)-(1)= -12 ΔY -12
(X2-X1) (-2)-(1)= -3 ΔX -3
slope= 4
B= -3
Y =4X -3
Answer:
y=4x-3
Step-by-step explanation:
Hi there!
We are given the points (1,1) and (-2, -11) and we want to write the equation of the line in slop-intercept form
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
So let's find the slope of the line
The formula for the slope calculated from two points is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points
We have everything we need to calculate the slope, let's just label the points to avoid confusion
[tex]x_1=1\\y_1=1\\x_2=-2\\y_2=-11[/tex]
Now substitute those values into the formula
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{-11-1}{-2-1}[/tex]
Subtract
m=[tex]\frac{-12}{-3}[/tex]
Divide
m=4
So the slope of the line is 4
Here is the equation of the line so far:
y=4x+b
We need to find b
As the equation passes through both (1,1) and (-2, -11), we can plug either one of them into the equation to solve for b
Taking (1,1) will give us this:
1=4(1)+b
Multiply
1=4+b
Subtract 4 from both sides
-3=b
Substitute -3 as b into the equation
y=4x-3
Hope this helps!
convert decimal into fraction 17.38
Answer:
869/50
Step-by-step explanation:
17.38
= 1738/100
= 869/50
The length of a rectangle is 7cm less than 3 times it's width. It's area is 20 square cm. Find the dimensions of the rectangle
Answer:
4 cm by 5 cm (4 x 5)
Step-by-step explanation:
The area of a rectangle with length [tex]l[/tex] and width [tex]w[/tex] is given by [tex]A=lw[/tex]. Since the length of the rectangle is 7 less than 3 times its width, we can write the length as [tex]3w-7[/tex]. Therefore, substitute [tex]l=3w-7[/tex] into [tex]A=lw[/tex]:
[tex]A=lw,\\20=(3w-7)w[/tex]
Distribute:
[tex]20=3w^2-7w[/tex]
Subtract 20 from both sides:
[tex]3w^2-7w-20=0[/tex]
Factor:
[tex](w-4)(3w+5)=0,\\\begin{cases}w-4=0, w=\boxed{4},\\3w+5=0, 3w=-5, w=\boxed{-\frac{5}{3}}\end{cases}[/tex]
Since [tex]w=-\frac{5}{3}[/tex] is extraneous (our dimensions cannot be negative), our answer is [tex]w=4[/tex]. Thus, the length must be [tex]20=4l, l=\frac{20}{4}=\boxed{5}[/tex] and the dimension of the rectangle are 4 cm by 5 cm (4 x 5).
Based on the graph, what is one solution to the equation f(x) = g(x)?
x= -4
x = 2.5
x= -5.1
x = 2.75
Answer:
x= -5.1
Step-by-step explanation:
The solution to f(x) = g(x) is where to two graphs intersect
The graphs meet at
about x=2 and x = -5
The best answer listed is x = -5.1
Answer:
x = −5.1
Step-by-step explanation:
I took the practice test
find m∠H
What does m∠H happened to equal
Answer:
[tex]m\angle H = 30^o[/tex]
Step-by-step explanation:
Given
See attachment
Required
Find [tex]m\angle H[/tex]
To calculate [tex]m\angle H[/tex], we make use of:
[tex]\cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]
So, we have:
[tex]\cos(H) = \frac{GH}{HI}[/tex]
This gives:
[tex]\cos(H) = \frac{10\sqrt3}{20}[/tex]
[tex]\cos(H) = \frac{\sqrt3}{2}[/tex]
Take arccos of both sides
[tex]m\angle H = cos^{-1}(\frac{\sqrt3}{2})[/tex]
[tex]m\angle H = 30^o[/tex]
83
EDFN 1090/1092
Assignment 4
1. From statistics grades, John has a mean of 70 and Sx(standard deviation) of 15, Jane
has a mean of 70 and Sx(standard deviation) of 5. Hint: create a 68% Range)
Describe the two students in terms of consistency of their grades and give reason.
Answer:
68% of the time, John's grades will be between 55 and 85, while for Jane, 68% of the time, her grades will be between 65 and 75. They have the same mean grade, however, due to the lower standard deviation, Jane is more consistent, while John has the higher upside.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
John:
Mean of 70, standard deviation of 15.
70 - 15 = 55
70 + 15 = 85
68% of the time, John's grades will be between 55 and 85.
Jane:
Mean of 70, standard deviation of 5.
70 - 5 = 65
70 + 6 = 75.
68% of the time, Jane's grades will be between 65 and 75.
Describe the two students in terms of consistency of their grades and give reason.
68% of the time, John's grades will be between 55 and 85, while for Jane, 68% of the time, her grades will be between 65 and 75. They have the same mean grade, however, due to the lower standard deviation, Jane is more consistent, while John has the higher upside.
