A body is supported by a helical spring and causes an extension of 1.5 cm in the spring. If the mass is set into vertical oscillation, calculate the period of the oscillation.

Answers

Answer 1

Answer:

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Explanation:

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A Body Is Supported By A Helical Spring And Causes An Extension Of 1.5 Cm In The Spring. If The Mass

Related Questions

The _______ principle encourages us to resolve a set of stimuli, such as trees across a ridgeline, into smoothly flowing patterns

A.) depth perception.
B.) perception.
C.) similarity.
D.) continuity.

Answers

Answer:

C

Explanation:

Similarity

what's impulse of
force

Answers

Answer:

The impulse experienced by the object equals the change in momentum of the object. In equation form, F.t = m. Δv. In a collision, objects experience an impulse; the impulse causes and is equal to the change in momentum.

state any two effects of gravitational force​

Answers

Connection to Big Idea about energy: Gravity creates gravitational potential energy. Gravitational energy relies on the masses of two bodies and their distance.

Connection to Big Idea about the universe: Gravitational force is exerted by all objects with mass throughout the Universe. It is what keeps the Earth and the planets in orbit around the Sun, and our Solar System in orbit around the centre of the Milky Way. Gravity is one of the forces involved in the birth of stars, their evolution and finally their death.

Connection to Big Idea about Earth: The gravitational force is responsible for many physical properties of Earth and consequently it affects the existence and the properties of living creatures on it. For instance, the existence, the chemical composition and the structure of Earth’s atmosphere was determined by Earth’s gravitational force.

How does an airpump work? ​

Answers

The inlet and the outlet are used to direct the flow of air, while the piston is used to generate the flow of air. When the piston is pulled up, air gets sucked into the pump through the inlet. ... When the piston is forced down, the air becomes compressed and closes the inlet. Then the air flows out from the outlet.

A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediately after the impact, a 320-g piece moves along the x-axis with a speed of 2.00 m/s and a 355-g piece moves along the y-axis with a speed of 1.50 m/s. The third piece has a mass of 100 g. In what direction relative to the x-axis does the third piece move

Answers

Answer:

Explanation:

There will be conservation of momentum along horizontal plane because no force acts along horizontal plane.

momentum of first piece = .320 kg x 2 m/s

= 0.64 kg m/s along x -axis.

momentum of second piece = .355 kg x 1.5 m/s

= 0.5325 kg m/s along y- axis .

Let the velocity of third piece be v and it is making angle of θ with x -axis .

Horizontal component of its velocity = .100 kg x v cosθ = .1 v cosθ

vertical  component of its velocity = .100 kg x v sinθ = .1 v sinθ

For making total momentum in the plane zero

.1 v cosθ = 0.64 kg m/s

.1 v sinθ = 0.5325 kg m/s

Dividing

Tanθ = .5325 / .64 = .83

θ = 40⁰.

The angle will be actually 180 + 40 = 220 ⁰ from positive x -axis.

Answer:

8.3 m/s, 2196 degree from + X axis

Explanation:

m = 320 g , u = 2 m/s along X axis

m'  = 355 g, u' = 1.5 m/s along Y axis

m'' = 100 g, u'' = v

Let the speed of the third piece is v makes an angle A from the X axis.

use conservation of momentum along X axis

0 = 320 x 2 + 100 x v cos A

v cos A =  - 6.4 ..... (1)

Use conservation of momentum along Y axis

0 = 355 x 1.5 + 100 x v sin A

v sinA = - 5.3 ... (2)

Squaring and adding

[tex]v^2 = (-6.4)^2 +(-5.3)^2\\\\v= 8.3 m/s[/tex]

The angle is given by

[tex]tan A = \frac{-5.3}{-6.4}\\\\A = 219.6 degree[/tex] from + X axis

Which car has the greatest potential energy? What type of potential energy does the
car have? What characteristics or properties does potential energy depend on? Which
cars have the least potential energy? Explain.

Answers

Explanation:

*car A has the greatest PE

*gravitational potential energy

*mass and height

*car D has the least PE

A police car travels towards a stationary observer at a speed of 15m/s. the siren on the car emits a sound of frequency 250Hz. Calculate the observer frequency. the speed of sound is 340m/s​

Answers

Observer Frequency = sound frequency x ( speed of sound / speed of sound - speed of car)

= 250 x (340/( 340-15))

= 261.54 Hz

An astronaut weighs 202 lb. What is his weight in newtons?

Answers

202 lb is 898.541newtons
The answer would be 898.541 newtons

An inductive circuit contains resistance of 20 ohm and an inductance of 20 H. If an ac voltage of 120 V and frequency 60 Hz is applied to this circuit, the current would be
A 0.0159
A 0.017
A 0.02
A 0.16

Answers

Answer:

answer : option (b) 0.016 amp

explanation : resistance of resistor , R = 10 Ω

inductance of inductor , X_LX

L

= 20H

voltage of AC circuit , V = 120volts

frequency, ff =60Hz

so, angular frequency, \omega=2\pi fω=2πf = 2 × π × 60 = 120π rad/s

now, current , i=\frac{V}{\sqrt{R^2+\omega^2L^2}}i=

R

2

2

L

2

V

= 120/√{10² + (120π)² × 20²}

= 120/√{100 + 14400π² × 400}

after solving this we get, i = 0.016 amp

Compare and contrast how sound waves behave when they

encounter solid (hard) surfaces
encounter soft surfaces
pass through an opening
encounter a barrier

Compare and contrast how light waves are

reflected from concave and convex mirrors
reflected/absorbed in black, red, blue and white paper
refracted in concave and convex lenses
transmitted in opaque, translucent, and transparent materials

Answers

Answer:

As sound waves move (or more accurately, when they travel by transferring their energy) they interact with physical objects. Soft surfaces will absorb sound while hard surfaces will reflect it. .Hard surfaces reflect sound and soft surfaces absorb sound.

The convex mirror has a reflecting surface that curves outward, resembling a portion of the exterior of a sphere. Light rays parallel to the optical axis are reflected from the surface in a direction that diverges from the focal point, which is behind the mirror

Explain why it takes much more effort to stop a freight train compared with a car?

Answers

Answer:

Train wheels and rails are both made of steel, and the steel-steel friction coefficient is around 0.25. As a result, the stopping time and distance will be three to four times that of a car.

a fixed mass of gas occupies a volume of 1000 CM3 at 0 degree celsius if it is heated at constant pressure of 100 degree celsius calculate the new volume ​

Answers

Answer:

P V = N R T       ideal gas equation

V1 = k * T1        if P is constant and also N and R will be constant

V2 = k * T2      where k is some constant

Or     V2 = (T2 / T1) * V1      also known as "Charles Law"  for expansion at    

 constant pressure

V2 = (373 / 273) * 1000 cm^3 = 1366 cm^3     where T is absolute temperature

A car of mass 2100 kg collides with a motorcycle of mass 290 kg. After the collision, the car and motorcycle stick and slide together. The car's velocity just before the collision was<30,-10>m/s , and that of the motorcycle was <10,10>m/s. Determine the velocity of the stuck-together car and motorcycle just after the collision.

Answers

Answer:

V = 29.49 m/s

Explanation:

Given that,

The mass of a car,[tex]m_c=2100\ kg[/tex]

The mass of a motorcycle, [tex]m_m=290\ kg[/tex]

The initial velocity of the car,[tex]v_c=30i-10j[/tex]

[tex]|v_c|=\sqrt{30^2+(-10)^2} =31.62\ m/s[/tex]

The initial velocity of the motorcycle,[tex]v_m=10i+10j[/tex]

[tex]|v_m|=\sqrt{10^2+10^2} =14.14\ m/s[/tex]

As they stick together. Let V is the speed. So, using the conservation of momentum,

[tex]m_cv_c+m_mv_m=(m_c+m_m)V\\\\V=\dfrac{m_cv_c+m_mv_m}{(m_c+m_m)}\\\\V=\dfrac{2100\times 31.62+290\times 14.14}{(2100+290)}\\\\V=29.49\ m/s[/tex]

So, the velocity of the stuck together car and the motorcycle after the collision is 29.49 m/s.

your neighbour is throttling his recent bought motorbike to show off. the sound intensity measured at your window 16m away is 0.25W/m^2. what is the sound intensity level in dB at your friend's house, a distance of 28m away from the noisy bike?

Answers

Answer:

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Two people, who have the same mass, throw two different objects at the same velocity. If the first object is heavier than the second, compare the velocities gained by the two people as a result of recoil.

a. The first person will gain more velocity as a result of recoll.
b. The second person will gain more velocity as a result of recoll.
c. Both people will gain the same velocity as a result of recoll.
d. The velocity of both people will be zero as a result of recoil

Answers

Answer:

The first person will gain more velocity as a result of recoil.

Explanation:

Let us recall that from Newton's third law of motion, action and reaction are equation and opposite. A consequence of this law is the proposition that ''momentum can neither be created nor destroyed.''

Hence, when two people who have the same mass, throw two different objects at the same velocity but the first object is heavier than the second, the first object possesses greater momentum than the second object hence the first person will gain more velocity as a result of recoil.

15. Calculate the resistive forces acting on a sports car if it is travelling at a steady speed of 25 m/s when the engine is providing 200 kW. gnt V 10X50 - soot Grade 9



Answers

Answer:

8000 N

Explanation:

Applying

P = F×V.............. Equation 1

Where P = Power of the sport car, F = resistive force acting on the sport car, V  = Speed of the sport car.

make F the subject of the equation

F = P/V............ Equation 2

From the question,

Given: P = 200 kW = 200000 W, V = 25 m/s

Substitute these values into equation 2

F = 200000/25

F = 8000 N

A vehicle is used to transport material down a straight aisle. The max acceleration of the vehicle is 1 m/s/s and the max speed of the vehicle is 5m/s. The vehicle starts at the beginning of the aisle. How long does it take to move down the aisle and come to a stop at the other end if:
a) the aisle is 100 meters long?
b) the aisle is 9 meters long?

Answers

Answer:

(a) 14.14 s

(b) 4.24 s

Explanation:

maximum acceleration, a =  1 m/s^2

maximum speed, v = 5 m/s

initial speed, u = 0 m/s

(a) distance, s = 100 m

Let the time is t.

Use second equation of motion

[tex]s = u t 0.5 at^2\\\\100 = 0 + 0.5 \times 1 \times t^2\\\\t = 14.14 s[/tex]

(b) distance, s = 9 m

Let the time is t'.

Use second equation of motion

[tex]s = u t + 0.5 at^2\\\\9= 0 + 0.5 \times 1 \times t'^2\\\\t' = 4.24 s[/tex]

What process provides the sun with its energy

Answers

Answer:

nuclear fusion

The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom. During the fusion process, radiant energy is released.

Answer:

nuclear fusion

Explanation:

The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom.

gAn optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be

Answers

Answer:

d = 68.5 x 10⁻⁶ m = 68.5 μm

Explanation:

The complete question is as follows:

An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is  1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?

The answer can be given by using the formula derived from Young's Double Slit Experiment:

[tex]y = \frac{\lambda L}{d}\\\\d =\frac{\lambda L}{y}\\\\[/tex]

where,

d = slit separation = ?

λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m

L = distance from screen (detector) = 1.7 m

y = distance between bright fringes = 15.7 mm = 0.0157 m

Therefore,

[tex]d = \frac{(6.33\ x\ 10^{-7}\ m)(1.7\ m)}{0.0157\ m}\\\\[/tex]

d = 68.5 x 10⁻⁶ m = 68.5 μm

A mass of 5 kg stretches a spring 20 cm. The mass is acted on by an external force of 10 sint4 N (newtons) and moves in a medium that imparts a viscous force of 4 N when the speed of the mass is 2 cm/s. If the mass is set in motion from its equilibrium position with an initial velocity of 7 cm/s.

Required:
Formulate the initial value problem describing the motion of the mass. Assume that g = 9.8 m/s^2.

Answers

Answer:Answer:

Initial value problem is:

u'' + 10u' + 98u = (2 sin(t/2) N for u(0) = 0

u'(0) = 0.03m/s

Explanation:

The directions of Fd(t*) and U'(t*) are not specified in the question, so we'll take Fd(t*) to be negative and U'(t*) to be positive. This is due to the fact that the damping factor acts in the direction opposite the direction of the motion of the mass.

M = 5kg; L= 10cm or 0.1m;

F(t) = 10 sin(t/2) N ; Fd(t*) = - 2N

U'(t*) = 4cm/s or 0.04m/s

u(0) = 0

u'(0) = 3cm/s or 0.03m/s

Now, we know that W = KL.

Where K is the spring constant.

And L is the length of extension.

So, k = W/L

W= mg = 5 x 9.81 = 49.05N

So,k = 49.05/0.1 = 490.5kg/s^(2)

Now from spring damping, we know that; Fd(t*) = - γu'(t*)

Where,γ = damping coefficient

So, γ = - Fd(t*)/u'(t*)

So, γ = 2/0.04 = 50 Ns/m

Therefore, the initial value problem which describes the motion of the mass is;

5u'' + 50u' + 490u = (10 sin(t/2) N

Divide each term by 5 to give;

u'' + 10u' + 98u = (2 sin(t/2) N for u(0) = 0

u'(0) = 0.03m/s

Explanation:

The upward normal force exerted by the floor is 710 N on an elevator passenger who weighs 720 N . You may want to review (Pages 107 - 110) . For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Weighing yourself in an elevator. Part A What is the reaction force to the upward normal force exerted by the floor

Answers

Answer:

If the person is to remain the floor the reaction force will be equal to the normal force exerted by the floor.

F(normal) - F(reaction) = 0

That means the person is not moving with respect to the elevator.

Expanding the applied forces we have:

Fw - Fn = 720 - 710 = 10 N   where the positive direction is chosen as down

Fw is the weight of the person and Fn the force exerted on the person by the elevator,

The acceleration of the person the becomes F = m a = m * 10 N and will be downward agreeing with our choice of coordinate axes.

describe the movement of the man when the resultant horizontal force is 0 N
can anyone help in both questions please

Answers

Answer:

Force A newton Law first law

F = M.A which Force in 0 N as you Questions Above

Force B

Newton Law 3

Action = -Reaction

Hope you can explain this formula as you want to scribe to explaining

Catching a wave, a 77-kg surfer starts with a speed of 1.3 m>s, drops through a height of 1.65 m, and ends with a speed of 8.2 m>s. How much nonconservative work was done on the surfer

Answers

Answer:

W = 2523.67 J

Explanation:

Given that,

The mass of surfer, m = 77 kg

He starts with a speed of 1.3 m/s

It drops through a height of 1.65 m and ends with a speed of 8.2 m/s.

We know that, the work done is equal to the change in kinetic energy. So,

[tex]W=\dfrac{1}{2}m(v_2^2-v_1^2)\\\\=\dfrac{1}{2}\times 77\times (8.2^2-1.3^2)\\W=2523.67\ J[/tex]

So, the required work done is equal to 2523.67 J.

A CD is spinning on a CD player. In 12 radians, the cd has reached an angular speed of 17 r a d s by accelerating with a constant acceleration of 3 r a d s 2 . What was the initial angular speed of the CD

Answers

Answer:

The initial angular speed of the CD is equal to 14.73 rad/s.

Explanation:

Given that,

Angular displacement, [tex]\theta=12\ rad[/tex]

Final angular speed, [tex]\omega_f=17\ rad/s[/tex]

The acceleration of the CD,[tex]\alpha =3\ rad/s^2[/tex]

We need to find the initial angular speed of the CD. Using third equation of kinematics to find it such that,

[tex]\omega_f^2=\omega_i^2+2\alpha \theta\\\\\omega_i^2=\omega_f^2-2\alpha \theta[/tex]

Put all the values,

[tex]\omega_i^2=(17)^2-2\times 3\times 12\\\\\omega_i=\sqrt{217}\\\\\omega_i=14.73\ rad/s[/tex]

So, the initial angular speed of the CD is equal to 14.73 rad/s.

During the Moment of Inertia experiment, a group of students decided to mount a solid sphere on the top of the horizontal disk. The sphere and disk have the same mass, M, and radius, R. They recorded the values for the initial and final positions for the falling mass, and the height above the floor when falling mass is at its lowest position. These values are respectively 90cm, 68.5 cm, and 23.5cm. The radius of the pulley, r, was 1/10 of the radius of the sphere. Furthermore, the mass of the disk, M, was 1.4kg, what was the mass, m, for the falling mass

Answers

Answer:

u are the very good person I know if u will do itself u will becam3 a rising star

An oscillating dipole antenna 1.73 m long with a maximum 36.0 mV potential creates a 500 Hz electromagnetic wave. (a) What is the maximum electric field strength created

Answers

Answer:

[tex]E_0=0.021v/m[/tex]

Explanation:

From the question we are told that:

Length [tex]l=1.73m[/tex]

Voltage [tex]V=36.0mV[/tex]

Frequency [tex]F=500Hz[/tex]

Generally the equation for maximum Electric Field  is mathematically given by

 [tex]E_0=\frac{\triangle}{r}[/tex]

 [tex]E_0=\frac{36*10^{-3}}{1.73}[/tex]

 [tex]E_0=0.021v/m[/tex]

question 1+1677-789909​

Answers

Answer:

your answer is -788231

Explanation:

1+1677=1678

1678-789909=-788231

What is the electric field strength between two parallel conducting plates separated by 10 cm and having a potential difference between them of 2000 V?

a.
2000 V/m

b.
200 V/m

c.
20 kV/m

d.
200000 V/m

Answers

Answer:

• Potential Difference (V) = 2000 V

• Distance b/w the two parallel plates (d) = 10 cm = 10/100 = 1/10 = 0.1 m

• Electric field (E) = ?

[tex]\implies V = E.d[/tex]

[tex]\implies E = \dfrac{V}{d} [/tex]

[tex]\implies E = \dfrac{2000}{0.1} [/tex]

[tex]\implies E = \dfrac{2000}{ {10}^{ - 1} } [/tex]

[tex]\implies E = 2000 \times {10}^{1} [/tex]

[tex]\implies\bf E = 20000 \:V/m[/tex]

[tex]\implies\bf E = 20\:kV/m[/tex]

Hence, option C) the correct answer.

A horizontal rod (oriented in the east-west direction) is moved northward at constant velocity through a magnetic field that points straight down. Make a statement concerning the potential induced across the rod.

a. The east end of the rod is at higher potential than the west end.
b. The bottom surface of the rod is at higher potential than the top surface.
c. The top surface of the rod is at higher potential than the bottom surface.
d. The west end of the rod is at higher potential than the east end.
e. The potential is uniform.

Answers

Answer:

a. The east end of the rod is at higher potential than the west end.

Explanation:

The horizontal rod is oriented in the east-west direction. This means that applying right hand rule, the current will flow from the east to the west. Now, if we assume tat it is a closed loop, we know from polarity of voltage that current usually flows positive to negative terminal within a circuit.

This means the east is at a largely positive terminal while the west is at a largely negative terminal.

Thus, we can say that the east end of the rod is at higher potential than the west end of the rod.

When several forces act on an object, the forces combine to act as a

Answers

Answer:

Net force

Explanation:

When several forces act on an object, the forces combine to act as a net force.

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