A chemist requires a large amount of 3-bromo-3-methyl-1-cyclohexene as starting material for a synthesis and decides to carry out the following NBS allylic bromination reaction in the presence of UV light. Draw the structures of all of the observed products.

Answer:

A (True)

Explanation:

Because ibuprofen has a chiral carbon center (carbon bonded to 4 distinct groups of atoms).

This means that a mixture of ibuprofen can rotate plane-polarized light equally in both the clockwise and counterclockwise direction.

Answer:true

Explanation: ibuprofen is commonly used for most pain, aches ect

From the question given above, the following data were obtained:

Oxygen = 45.2 Kg

Carbon = 12.6 Kg

Hydrogen = 7 Kg

Nitrogen = 2 Kg

Calcium = 1.3 Kg

Phosphorus = 0.78 Kg

Potassium = 0.25 Kg

Sulphur = 0.18 Kg

Others = 0.60 Kg

Total = 70 Kg

We can obtain the fraction of potassium of the mass of the body as follow:

Potassium = 0.25 Kg

Total = 70 Kg

Fraction of potassium = mass of potassium / Total

Fraction of potassium = 0.25 / 70

Therefore, the fraction of potassium in the body is 1/280

Learn more: https://brainly.com/question/14760859

Answer:

B

Explanation:

Answer:

10/3

Explanation:

Hope this helps

Answer:

The compound formula for the ammonia is

N

H

3

. It is a colorless gas. It is the result of the chemical reaction between nitrogen and hydrogen gas. The chemical reaction between the gases is shown below:

N

2

+

3

H

2

→

2

N

H

3

Answer:

d. All of the above

Explanation:

d. All of the above

Answer:

Answer: There are 1.53 moles present in   molecules of water in a beaker.

Explanation:

According to the mole concept, there are  molecules present in 1 mole of a substance.

So, number of moles present in  molecules are calculated as follows.

Thus, we can conclude that there are 1.53 moles present in   molecules of water in a beaker.

Explanation:

Answer:

67.0 L

Explanation:

Step 1: Given data

Step 2: Calculate the volume occupied by 2.99 moles of C₃H₈ at STP

C₃H₈ is a gas. If we assume ideal behavior, 1 mole of C₃H₈ at STP occupies 22.4 L.

2.99 mol × 22.4 L/1 mol = 67.0 L

Explanation:

Energy is essential to life and all living organisms. The sun, directly or indirectly, is the source of all the energy available on Earth. Our energy choices and decisions impact Earth's natural systems in ways we may not be aware of, so it is essential that we choose our energy sources carefully

Answer:

The given molecules are SO2 and BrF5.

Explanation:

Consider the molecule SO2:

The central atom is S.

The number of domains on S in this molecule is three.

Domain geometry is trigonal planar.

But there is a lone pair on the central atom.

So, according to VSEPR theory,

the molecular geometry becomes bent or V-shape.

Hybridization on the central atom is

[tex]sp^{2}[/tex].

Consider the molecule BrF5:

The central atom is Br.

The number of domains on the central atom is six.

Domain geometry is octahedral.

But the central atom has a lone pair of electrons.

So, the molecular geometry becomes square pyramidal.

The hybridization of the central atom is [tex]sp^{3} d^{2}[/tex].

The shapes of SO2 and BrF5 are shown below:

Answer:

For (a): The balanced net ionic equation is [tex]2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)[/tex] and the sum of coefficients is 4

For (b): The balanced net ionic equation is [tex]Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)[/tex] and the sum of coefficients is 4

For (c): The balanced net ionic equation is [tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex] and the sum of coefficients is

For (d): The balanced net ionic equation is [tex]Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)[/tex] and the sum of coefficients is 4

For (e): The balanced net ionic equation is [tex]Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)[/tex] and the sum of coefficients is 3

Explanation:

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation is:

[tex]Na_2S(aq)+2AgNO_3(aq)\rightarrow 2NaNO_3(aq)+Ag_2S(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+S^{2-}(aq)+2Ag^+(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ag_2S(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)[/tex]

Sum of the coefficients = [2 + 1 + 1] = 4

The balanced molecular equation is:

[tex]2NaCl(aq)+Pb(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+PbCl_2(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+2Cl^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+PbCl_2(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)[/tex]

Sum of the coefficients = [2 + 1 + 1] = 4

The balanced molecular equation is:

[tex]K_2CO_3(aq)+Ca(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+CaCO_3(s)[/tex]

The complete ionic equation follows:

[tex]2K^{+}(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2K^+(aq)+2NO_3^-(aq)+CaCO_3(s)[/tex]

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex]

Sum of the coefficients = [1 + 1 + 1] = 3

The balanced molecular equation is:

[tex]2NaOH(aq)+Ba(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Ba(OH)_2(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+2OH^{-}(aq)+Ba^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ba(OH)_2(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions

The net ionic equation follows:

[tex]Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)[/tex]

Sum of the coefficients = [2 + 1 + 1] = 4

The balanced molecular equation is:

[tex]NaCl(aq)+AgNO_3(aq)\rightarrow NaNO_3(aq)+AgCl(s)[/tex]

The complete ionic equation follows:

[tex]Na^{+}(aq)+Cl^{-}(aq)+Ag^{+}(aq)+NO_3^{-}(aq)\rightarrow Na^+(aq)+NO_3^-(aq)+AgCl(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)[/tex]

Sum of the coefficients = [1 + 1 + 1] = 3

Answer:

The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), butanoic acid (C3H7COOH), and sodium bromide (NaBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive.

Explanation:

The given substances are:

barium chloride(BaCl2),

glucose(C6H12O6),

butanoic acid (C3H7COOH) which is a weak acid,

sodium bromide (NaBr).

The conductivity of a solution is proportional to the number of ions present in a particular solution.

1mol. of BaCl2 in water produces a total three mol. of ions.

[tex]BaCl_2 (aq) -> Ba^2^+(aq) + 2Cl^-(aq)[/tex]

Gluocse is a covalent compound and it does not dissociate into ions in water.

So, it does not conduct electricity.

Butanoic acid is a weak acid. But due to the release of H+ ions it can conduct a very less amount of electricity.

NaBr is an ionic compound and in 1mol. of NaBr in water gives two mol. of ions.

NaBr (aq)  -> Na+ (aq)  + Br- (aq)

Hence, the order of conductivity among the given substances in aqueous solution is:

BaCl2 > NaBr > butanoic acid > glucose

Answer:

C. 2.70 g/mL

Explanation:

Density is the ratio between the mass of a substance and the volume it occupies. Based on Archimedes' volume, the displaced volume of the aluminium is the volume it occupies. To solve this question we must find the difference in volume between initial volume of water = 30mL and final volume of water + aluminium = 39.26mL. This difference is the volume of the aluminium. With its mass we can find density:

39.26mL - 30mL = 9.26mL

Density = 25.00g / 9.26mL =

2.70g/mL

Right answer is:

Answer:

For a chemical reaction, the enthalpy of reaction (ΔHrxn) is the difference in enthalpy between products and reactants; the units of ΔHrxn are kilojoules per mole

Answer:

[tex]1.74molNO_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:

[tex]80g*\frac{1mol}{46g}\\\\1.74molNO_2[/tex]

Regards!

Answer:

Hi, there the answer is D.

Explanation:

Answer: B

Explanation: im pretty sure my teacher mentioned something about N--h bonds are non polar

Answer:

C

Explanation:

Answer:

pH = 11.3

Explanation:

From the question given above, the following data were obtained:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

The pH of a solution is defined by the following equation:

pH = –Log [H₃O⁺]

Thus, with the above formula, we can obtain the pH of the solution as follow:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

pH = –Log [H₃O⁺]

pH = –Log 4.950×10¯¹²

pH = 11.3

The question is incomplete, the complete question is;

49.9 g per day of a certain industrial waste chemical P arrives at a treatment plant settling pond with a volume of 300 m^3. P is destroyed by sunlight, and once in the pond it has a half-life of 3.4 h. Calculate the equilibrium concentration of P in the pond. Round your answer to 2 significant digits.

Answer:

0.034 g/m³

Explanation:

From the question, mass of industrial waste = 49.9 g

It takes 24 hours to complete a day.

Mass per hour;

Mass in = (49.9 g / day) * (1 day /24 hr )

= 2.079 g/hr

Mass out = 0

Mass leaving due to sunlight = k CA V

Half life of the industrial waste = 3.4 h

This is a first order reaction;

Hence;

k = ln2/t1/2

Where, t1/2 = half life

k = 0.693 / 3.4 = 0.2038 hr⁻¹

Mass leaving due to sunlight = k CA V

CA = Mass per hr / kV

= 2.079 g/hr / ( 0.2038 hr⁻¹ x 300 m³ )

= 0.034 g/m³

Answer:

a. NADH and FADH₂ donate electrons to the electron transport chain

b. Molecular oxygen, O₂, is the final electron acceptor

c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP

Explanation:

The citric cycle oxidize acetylCoA molecules to carbon dioxide and in the process produce the reduced coenzyme NADH and FADH₂. These reduced coenzymes then are able to donate their electrons to various complexes in the electron transport chain. The flow of these electrons through the electron transport chain is coupled to proton pumping out of the mitochondrial matrix into the intermembrane space. Ultimately, the energy of the proton motive force is used to drive synthesis of ATP from ADP and inorganic phospahte and the electrons are accepted by molecular oxygen to produce water. This process is known as oxidative phosphorylation.

Therefore, the answers to the given questions a, b and c are as follows:

a. NADH and FADH₂ donate electrons to the electron transport chain

b. Molecular oxygen, O₂, is the final electron acceptor

c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP

Answer:

(a): The theoretical yield of silicon is 72.33 kg.

(b): The percent yield of the reaction is 91.25 %.

Explanation:

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]       .....(1)

For [tex]SiO_2[/tex]:

Given mass = 155.0 kg = 155000 g          (Conversion factor: 1 kg = 1000 g)

Molar mass = 60 g/mol

Putting values in equation 1:

[tex]\text{Moles of }SiO_2=\frac{155000g}{60g/mol}=2583.3mol[/tex]

For carbon:

Given mass = 78.2 kg = 78200 g

Molar mass = 12 g/mol

Putting values in equation 1:

[tex]\text{Moles of carbon}=\frac{78200g}{12g/mol}=6516.67mol[/tex]

The chemical equation for the reaction of silicon dioxide and carbon follows:

[tex]SiO_2+2C\rightarrow Si+2CO[/tex]

By stoichiometry of the reaction:

1 mole of [tex]SiO_2[/tex] reacts with 2 moles of carbon

So, 2583.3 moles of [tex]SiO_2[/tex] will react with = [tex]\frac{2}{1}\times 2583.3=5166.4mol[/tex] of carbon

As the given amount of carbon is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, [tex]SiO_2[/tex] is considered a limiting reagent because it limits the formation of the product.

By stoichiometry of the reaction:

1 mole of [tex]SiO_2[/tex] produces 1 mole of silicon

So, 2583.3 moles of [tex]SiO_2[/tex] will produce = [tex]\frac{1}{1}\times 2583.3=2583.3mol[/tex] of silicon

Since the molar mass of silicon = 28 g/mol

Putting values in equation 1:

[tex]\text{Mass of Si}=2583.3mol\times 28g/mol=72332.4g=72.33 kg[/tex]

Hence, the theoretical yield of silicon is 72.33 kg.

The percent yield of a reaction is calculated by using an equation:

[tex]\% \text{yield}=\frac{\text{Measured value}}{\text{Theoretical value}}\times 100[/tex]              ......(2)

Given values:

Measured value of silicon = 66.0 kg

Theoretical value of silicon  = 72.33 kg

Putting values in equation 1:

[tex]\% \text{yield}=\frac{66.0kg}{72.33kg}\times 100\\\\\% \text{yield}=91.25 \%[/tex]

Hence, the percent yield of the reaction is 91.25 %.

The question is incomplete, the complete question is:

A solution of permanganate is standardized by titration with oxalic acid. To react completely with 0.0018 mol of oxalic acid required 28.18 mL of permanganate solution. The unbalanced chemical equation for the reaction in acidic solution is:

[tex]\mathrm{MnO}_{4}^{-}(aq)+\mathrm{H}_{2}\mathrm{C}_{2}\mathrm{O}_{4}(aq)\stackrel{\mathrm{Acidic}}{\longrightarrow}\mathrm{Mn}^{2+}(aq)+\mathrm{CO}_{2}(\mathrm{g})[/tex]

Determine the concentration of the permanganate solution in molarity.

Answer: The molarity of permanganate solution is 0.026 M

Explanation:

The balanced chemical equation follows:

[tex]2MnO_4^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow 2Mn^{2+}+8H_2O(l)+10CO_2(g)[/tex]

Given values:

Moles of oxalic acid = 0.0018 moles

By the stoichiometry of the reaction:

If 5 moles of oxalic acid reacts with 2 moles of permanganate solution

So, 0.0018 moles of oxalic acid will react with = [tex]\frac{2}{5}\times 0.0018mol=0.00072mol[/tex] of permanganate solution

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)

Given values:

Moles of permanganate solution = 0.00072 moles

Volume of solution = 28.18 mL

Putting values in equation 1, we get:

[tex]\text{Molarity of permanganate solution}=\frac{0.00072\times 1000}{28.18}\\\\\text{Molarity of permanganate solution}=0.026M[/tex]

Hence, the molarity of permanganate solution is 0.026 M

Answer:

Decanitrogen is molecular

Explanation:

Answer:

Dec a nitrogen is Molecular

Explanation:

hey mate i hope it will help you...!

Answer:

1.40M = [N2O4]

Explanation:

Based on the reaction:

2NO2(g) ⇄ N2O4(g)

Kc is defined as:

Kc = 5.0 = [N2O4] / [NO2]²

Where [] are the concentrations in equilibrium of each gas

As the equilibrium concentration of NO2 is 0.53M:

5.0 = [N2O4] / [0.53]²

5.0 = [N2O4] / [0.2809]

5.0*0.2809 = [N2O4]

Answer:

Well, they are very durable unlike other packaging food materials, they can be recycled. But, the internet says allumninum cans are much better. and it could be better because you can keep the canned milk cool (cold) for a long lasting time. (keep it in the fridge if you want it to stay cold even longer)

Explanation:

First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.

For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.

Answer:

Number of moles : Mass (g) ÷ relative atomic mass

Answer:

oxygen is add to ATP providing energy to the cell

Answer:

The given molecules are:

CH2Br2

CH3NH2

LiF

C3H8

CF4.

Which compound consists of the hydrogen bond as the strongest intermolecular force.

Explanation:

The hydrogen bond is the electrostatic force of attraction that exists between the covalently bonded H-atom of one molecule and a high electronegative atom (N, O, F) of another molecule.

For example, H-bonding in water is represented below:

Among the given molecules,

CH2Br2 does not have H-bond because there is no either N or O or F atom in it.

In LiF also there is no H-atom and no hydrogen bond.

C3H8 also does not have H-bond in it.

CF4 also does not have H-atom or hydrogen bond in it.

The answer is CH3NH2(methylamine).

It has an intermolecular hydrogen bond in it as shown in the attachment.

The dashed line represents the H-bond.

Answer:

[tex]m_{CO_2}=75.6gCO_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out mandatory for us to calculate the reacting moles of both C and O2 because we are given grams and pressure, temperature and volume, respectively:

[tex]n_C=36gC*\frac{1molC}{12gC}=3.0molC \\\\n_{O_2}=\frac{3.0atm*14L}{0.08206\frac{atm*L}{mol*K}*298K}=1.72molO_2[/tex]

Thus, since C and O2 react in a 1:1 mole ratio, we infer C is in excess, and the grams of CO2 can be calculated with the moles of O2:

[tex]m_{CO_2}=1.72molO_2*\frac{1molCO_2}{1molO_2}*\frac{44.01gCO_2}{1molCO_2} \\\\ m_{CO_2}=75.6gCO_2[/tex]

Best regards!

Answer:

[tex]CH _{3}CH _{3}[/tex]

Ethane