Answer:
Kinetic energy = 90.98 J
Explanation:
Given that,
The mass of a hammer, m = 2.2 kg
At a distance of 4.50 m above the ground, the hammer's total mechanical energy is 188 J.
We need to find the kinetic energy of the hammer at this height.
We know that,
Mechanical energy = kinetic energy + potential energy
[tex]188=K_E+mgh\\\\K_E=188-mgh\\\\K_E=188-2.2\times 9.8\times 4.5\\\\K_E=90.98\ J[/tex]
So, the kinetic energy of the hammer at this height is equal to 90.98 J.
5. A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 6400 m away?
Answer:
8.89 secs
Explanation:
720m = 1 sec
6400m = ?
6400/720 = 8.89 secs
An object with a mass of 20 kg has a net force of 80 N acting on it. What is the acceleration of the object?
Answer:
the answer is 4m/ s²
hope this helps love!! <3
The sun is located in
the Crab Nebula.
the Andromeda Nebula.
the Milky Way Galaxy.
the Snickers Galaxy.
Answer:
The sun is located in the Milky Way Galaxy.
An atom with 9 protons, 11 electrons, and 10 neutrons has a net charge of
ASAP
A light wave travels through glass (n=1.50) at an angle of 35°. What angle
does it have when it passes from the glass into the air (n = 1.0)?
A. 59.4
B. 0.860
C. 22.5
D. 0.382
Answer:
A. 59.4
Explanation:
The refractive index of the glass, n₁ = 1.50
The angle of incidence of the light, θ₁ = 35°
The refractive index of air, n₂ = 1.0
Snell's law states that n₁·sin(θ₁) = n₂·sin(θ₂)
Where;
θ₂ = The angle of refraction of the light, which is the angle the light will have when it passes from the glass into the air
Therefore;
θ₂ = arcsin(n₁·sin(θ₁)/n₂)
Plugging in the values of n₁, n₂ and θ₁ gives;
θ₂ = arcsin(1.50 × sin(35°)/1.0) ≈ 59.357551° ≈ 59.4°
The angle the light will have when it passes from the glass into the air, θ₂ ≈ 59.4°.
Answer:
A. 59.4
Explanation:
got it right, trust
What is the answer to this question?
Answer:
Explanation:
In a velocity/time (aka acceleration) graph, the slope of a line indicates the value of the acceleration in m/s/s. Acceleration is the change in velocity over the change in time. From 0 - 2 seconds, there is no change in velocity, so the acceleration during this interval is 0 (which is the same as the slope of the line). From 2 - 4 seconds, the slope of the line is -2, so the acceleration during the time interval from 2 to 4 seconds is -2 (negative because David is slowing down but is still going the same direction: to the right).
Question 2 of 10
A wave has a wavelength of 0.05 m and a wave speed of 10 m/s. What is the
frequency of the wave?
O A. 5.0 Hz
B. 200 Hz
C. 2.0 Hz
O D. 0.50 Hz
Explanation:
everything can be found in the picture
A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the car? (ii) what is the the distance cover ded by the car?
Answer: [tex]3.5\ km[/tex]
Explanation:
Given
Car starts from the state of rest and acquires a velocity of [tex]70\ km/hr[/tex] in 6 minutes
Final velocity in m/s is [tex]v=70\approx 19.44\ m/s[/tex]
Using equation of motion
[tex]v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2[/tex]
Distance covered in 360 s
[tex]\Rightarrow v^2-u^2=2as\\\Rightarrow 19.44^2-0=2\times 0.054\times s\\\Rightarrow s=3500.64\ m\approx 3.5\ km[/tex]
How does the "lollipop moment", exemplify for us the opportunity we all have to exercise leadership on a normal everyday basis?
Answer:
WHat do you mean by that
Explanation:
I dont get what you re asking
what will happen to satellite if the linear speed is reduced?. give a reason for your answer
Explanation:
If the satellite is moving too quickly then the gravitational attraction between the Earth and the satellite is too weak to keep it in orbit. If this is the case, the satellite will move off into space. This occurs at speeds around or above 11,200 metres per second (m/s).
You lift a 44 N box from the floor and place it on a shelf that is 1.5 m above the ground . How much work did you use in lifting the box ?
Answer:
W = 66 J
Explanation:
Given that,
The weight of the box, W = 44 N
It is placed on a shelf that is 1.5 m above the ground.
We need to find the work done in lifting the box.
We know that,
Work done, W = Fd
So,
W = 44 N × 1.5 m
= 66 J
So, the required work done is equal to 66 J.
Which of the following types of stars is cooler that an orange main sequence?
Answer:
Not sure but, I think C
Hopefully this helps
What are the positives and negatives of friction?
Answer:
Positives (advantages) of Friction:
Friction is responsible for many types of motion -
It helps us walk on the groundBrakes in a car make use of friction to stop the carAsteroids are burnt in the atmosphere before reaching Earth due to friction.It helps in the generation of heat when we rub our hands.Negatives (disadvantages) of Friction:
Friction produces unnecessary heat leading to the wastage of energy.The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects.Forest fires are caused due to the friction between tree branches.A lot of money goes into preventing friction and the usual wear and tear caused by it by using techniques like greasing and oiling.What is the process of combining the sperm and egg cell called and what does it produce? Anyone know the answer ?
Answer:
fertilization and it produces a Zygote
Two forces that make up 3rd law of motion can: 1)Act on the same object 2)do not act on same time 3)Act on different objects 4)Do not act oppositely
Answer:
3) Act on different objects
Explanation:
Newton's third law of motion states that for every action there is an equal and opposite reaction.
Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move, etc.
Basically, action-reaction force pairs are characterized by the following statements;
I. The forces are the same type such as magnetic force, contact force or gravitational force.
II. The forces are equal in magnitude but opposite in direction.
III. They act up on two different bodies.
Hence, the two forces that make up 3rd law of motion can act on different objects.
For example, while driving down the road, a bug strikes the windshield of a vehicle (Action) and makes a quite obvious mess in front of the face of the driver of the vehicle (Reaction) i.e the bug hit the vehicle and the vehicle hits the bug.
5
Which equation represents a line with a slope of
2
and a y-intercept of
- ?
3
Coordinates of y-intercept : (0,3)
Slope = 2
Another coordinate = 2 steps of rise and 1 step of run = (1,5)
Verification
Slope = (3-5) / (0-1) = -2 / -1 = 2
A constant force (3,0,4)N moves a body from point (-5,3,1)m to the point (4,3,3)m. If the initial velocity of the body is (6,1,1)m/s, determine the work done by the force and the angle between the force and the initial velocity of the body
The net displacement of the body is
∆x = (4, 3, 3) m - (-5, 3, 1) m = (9, 0, 2) m
so the work done by F = (3, 0, 4) N in the direction of ∆x is
F • ∆x = (3, 0, 4) • (9, 0, 2) N•m = (27 + 0 + 8) N•m = 35 J
The angle between the force and initial velocity v₀ is θ, such that
F • v₀ = ||F|| ||v₀|| cos(θ)
(3, 0, 4) • (6, 1, 1) N•m/s = √(3² + 0² + 4²) √(6² + 1² + 1²) cos(θ) N•m/s
==> cos(θ) = (18 + 0 + 4) / (√25 × √38) = 22/(5√38)
==> θ = arccos(22/(5√38)) ≈ 44.5°
Please help with the page below
Explanation:
I think a) Waste product and b) 80%
A) Which of the balloons shown below is under greater pressure? Give reason for your choice.
B) When John placed an inflated balloon inside freezer, what do you think would happen to the balloon? Explain a possible reason why this might happened.
Explanation:
I think number has the greater pressure because the molecules are seen tightly packed
Answer:
I think part A) is b because there's more matter(molecules) inside the second so it has more tension
and to part b) I think it would deflated because the air molecules decrease when the temperature does I think.
If a wire with current 5.0A has 12 coulombs of charge pass through it how much has passed
Answer:
2.4 secs.
Explanation:
Current (A) = Charge (coulomb)/Time(sec)
We are looking for time. So:
Time (sec) = Charge (coulomb)/Current (A)
↓
12coulombs/5.0A = 2.4 secs
An observer standing near a window 5 m high observe that an object falling downwards is passing across the window in 0.5 s. Find at what height above the window the object was dropped. (g = 10 m/s2).
Answer:
Explanation:
An object in free fall, NOT experiencing parabolic motion, has an equation of
[tex]h(t)=\frac{1}{2} gt^2+h_0[/tex] which says:
The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.
For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;
g = 10 m/s/s, and
t = .5sec
[tex]5=\frac{1}{2}(-10)(.5)^2[/tex]+h and
5 = -5(.5)² + h and
5 = -5(.25) + h and
5 = -1.25 + h so
h = 6.25
That's how high the window is above the ground.
Height above the window object was dropped is 6.25 m
Given:
Height of window = 5 m
Time taken to drop object = 0.5 sec
Gravitational acceleration = 10 m/s²
Find:
Height above the window object was dropped
Computation:
We know that;
[tex]H(T) = \frac{1}{2}(g)(t^2) + H(S)\\\\5 = \frac{1}{2}(10)(0.5^2) +H(S)\\\\5 = (5)(0.5^2)+H(S)\\\\H(S) = 6.25[/tex]
So,
Height above the window object was dropped = 6.25 m
Learn more:
https://brainly.com/question/13704950?referrer=searchResults
Match each description to one of the graphs below.
A) A child runs at a constant speed for 40 s before stopping.
B)A panda moves slowly at a constant speed for 40 s before stopping.
C)A cheetah stalks his prey, moving slowly, stopping occasionally.
D)A rabbit runs away from a farmer, not stopping for anything!
Answer:
I) the correct one is A
II) the alternatives C
III) corresponds to option D
IV) alternative B
Explanation:
Various information can be obtained from the speed versus time graphs
* If the graph is an inclined line, the speed is constant
* if the graph is a horizontal line the velocity is zero
In this case, the first graph (I) has two parts: an inclined line that corresponds to a uniform movement with speed and a second one, so that it is a horizontal line that indicates that the body is stopped.
If we see the different alternatives, the correct one is A
The second graph (II) has a movement with constant speed second period of being stopped
This graph corresponds to the alternatives C
The third graph (III) the body moves at constant speed without stopping
This corresponds to option D
The fourth graph (IV) the body moves with a slow speed and after 40 s it stops
This graph is associated with alternative B
How does a valve cause a pressure drop in terms of the individual molecules in the liquid?
A battery provides a potential difference of 20 V. What size current will flow through a 5 ohm resistor in
this circuit
If an object of mass 70kg falls from a height of 500 m, what is the maximum velocity of the object?
Answer:
H = 1/2 * g * t^2 since initial velocity is zero
v = g * t where v is the final velocity
t = v / g
H = 1/2 g * v^2 / g^2 = 1/2 v^2 / g
v = (2 * H * g)^1.2
v = (2 * 500 * 9.8)^1/2 = 99 m/s
Check: t = v / g = 99 / 9.8 = 10.1 sec
H = 1/2 * 9.8 * 10.1^2 = 500 m
A cyclist traveling at 30.0m/s along a straight road comes uniformly to stop in 5.00s. Determine the stopping acceleration, the stopping distance.
Answer:
I. Stopping acceleration = 6 m/s²
II. Stopping distance, S = 75 meters
Explanation:
Given the following data;
Final velocity = 30 m/s
Time = 5 seconds
To find the stopping acceleration;
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Substituting into the equation;
[tex]a = \frac{30 - 0}{5}[/tex]
[tex]a = \frac{30}{5}[/tex]
Acceleration = 6 m/s²
II. To find the stopping distance, we would use the third equation of motion;
[tex] V^{2} = U^{2} + 2aS [/tex]
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
30² = 0² + 2*6*S
900 = 12S
S = 900/12
S = 75 meters
A sled drops 20 mts in height on a hill. The rider is going 20 m/s at the bottom of the hill. Where can you find kinetic and potential energy? In which moments?
Explanation:
Potential energy is the energy occupied by an object or substance due to its position.
For example, a sled drops 20 meters in height on a hill shows that a decrease in height is taking place.
Hence, potential energy is involved there.
Kinetic energy is the energy acquired by an object due to its motion.
For example, a rider is going 20 m/s at the bottom of the hill shows that rider is in motion due to which it has kinetic energy.
¿cuantos colores existen?
Answer:
Los 11 colores básicos (negro, azul, marrón, gris, verde, naranja, rosa, púrpura, rojo, blanco y amarillo) y los 28 adicionales (turquesa, verde oliva, verde menta, borgoña, lavanda, magenta, salmón, cian, beige, rosado, verde oscuro, verde oliva, lila, amarillo pálido, fucsia, mostaza, ocre, trullo, malva, púrpura
hope that helps bby<3
Answer:
10 millones
Explanation:
En primer lugar, los científicos han determinado que en el laboratorio podemos ver unos 1.000 niveles de luz oscura y unos 100 niveles de rojo-verde y amarillo-azul. Eso es alrededor de 10 millones de colores ahí mismo.
Balance the following equations:
1) AI + MnO2
2) Ga + H2SO4
3) Mg + HCI
→ Mn + Al2O3
→ Gaz(SO )3 + H2
→ MgCl2 + H2
Answer:
[tex]1) \: \: \: 4Al+ 3MnO _{2}→ 3Mn + 2Al _{2} O _{3} \\ 2) \: \: \:2Ga + 3H _{2}SO _{4} → Ga _{2} (SO _{4}) _{3} +3 H _{2} \\ 3) \: \: \: Mg + 2HCI→ MgCl _{2}+ H _{2}[/tex]
write down the relation between energy and power
Answer:
Energy is what makes change happen and can be transferred form one object to another. Energy can also be transformed from one form to another. Power is the rate at which energy is transferred. It is not energy but is often confused with energy.
Explanation:
Answer:
when u have energy u will have power n u can work as power is the capacity to do the work