a cube has edge length 2. suppose that we glue a cube of edge length 1 on top of the big cube so that one of its faces rests entirely on the top face of the larger cube. the percent increase in the surface area (sides, top, and bottom) from the original cube to the new solid formed is? express your answer as a common fraction a/b.

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Answer 1

The original cube has a surface area of 6*(2^2) = 24 square units. The smaller cube glued on top adds an additional surface area of 6*(1^2) = 6 square units.

To calculate the percent increase, we need to find the difference between the new surface area and the original surface area, which is 30 - 24 = 6 square units. The percent increase is then (6/24) * 100 = 25%. However, this only accounts for the increase in the sides and the top. Since the bottom face of the smaller cube is glued to the top face of the larger cube, it is not visible and does not contribute to the surface area increase. Therefore, the total surface area of the new solid is 24 + 6 = 30 square units.

Therefore, the percent increase in the surface area (sides, top, and bottom) is 25% + 8.33% (which represents the increase in the top face) = 33 1/3%.The percent increase in surface area, accounting for the sides, top, and bottom, is 33 1/3%.

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Related Questions

Express the integral as a limit of Riemann sums using endpoints. Do not evaluate the limit. root(4 x^2)

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The integral's Riemann sum is given by:

∫ √(4x²) dx ≈ lim(n->∞) Σ √(4([tex]x_i[/tex])²) * Δx,

To express the integral ∫ √(4x²) dx as a limit of Riemann sums using endpoints, we need to divide the interval [a, b] into smaller subintervals and approximate the integral using the values at the endpoints of each subinterval.

Let's assume we divide the interval [a, b] into n equal subintervals, where the width of each subinterval is Δx = (b - a) / n. The endpoints of each subinterval can be represented as:

[tex]x_i[/tex] = a + i * Δx,

where i ranges from 0 to n.

Now, we can express the integral as a limit of Riemann sums using these endpoints. The Riemann sum for the integral is given by:

∫ √(4x²) dx ≈ lim(n->∞) Σ √(4([tex]x_i[/tex])²) * Δx,

where the sum is taken from i = 0 to n-1.

In this case, we have the function f(x) = √(4x²), and we are approximating the integral using the Riemann sum with the function values at the endpoints of each subinterval.

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what is the difference between the pearson correlation and the spearman correlation? a. the pearson correlation uses t statistics, and the spearman correlation uses f-ratios. b. the pearson correlation is used on samples larger than 30, and the spearman correlation is used on samples smaller than 29. c. the spearman correlation is the same as the pearson correlation, but it is used on data from an ordinal scale. d. the spearman correlation is used when the sample variance is unusually high.

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The correct answer is: c. The Spearman correlation is the same as the Pearson correlation, but it is used on data from an ordinal scale.

The Pearson correlation measures the linear relationship between two continuous variables and is based on the covariance between the variables divided by the product of their standard deviations. It assumes a linear relationship and is suitable for analyzing data on an interval or ratio scale.

On the other hand, the Spearman correlation is a non-parametric measure of the monotonic relationship between variables. It is based on the ranks of the data rather than the actual values. The Spearman correlation assesses whether the variables tend to increase or decrease together, but it does not assume a specific functional relationship. It can be used with any type of data, including ordinal data, where the order or ranking of values is meaningful, but the actual distances between values may not be.

Option a is incorrect because neither the Pearson nor the Spearman correlation uses t statistics or f-ratios directly.

Option b is incorrect because both the Pearson and Spearman correlations can be used on samples of any size, and there is no strict cutoff based on sample size.

Option d is incorrect because the Spearman correlation is not specifically used when sample variance is unusually high. The choice between the Pearson and Spearman correlations is more about the nature of the data and the relationship being analyzed.

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Determine the convergence or divergence of the sequence with the given nth term. if the sequence converges, find its limit. (if the quantity diverges, enter diverges. ) an = 5 n 5 n 8

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The limit of the sequence as n approaches infinity is 1. Since the sequence converges to a specific value (1).

To determine the convergence or divergence of the sequence with the given nth term, let's examine the expression:

an = 5n / (5n + 8)

As n approaches infinity, we can analyze the behavior of the sequence.

First, let's simplify the expression by dividing both the numerator and denominator by n:

an = (5n/n) / [(5n + 8)/n]

= 5 / (5 + 8/n)

As n approaches infinity, the term 8/n approaches zero since n is increasing without bound. Therefore, we have:

an ≈ 5/5

an ≈ 1

Hence, the limit of the sequence as n approaches infinity is 1.

Since the sequence converges to a specific value (1), we can conclude that the sequence converges.

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Suppose Alex found the opposite of the correct product describe an error Alex could have made that resulted in that product

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It's important to double-check the signs and calculations during multiplication to ensure accuracy and avoid such errors.

If Alex found the opposite of the correct product, it means they obtained a negative value instead of the positive value that was expected. This type of error could arise due to various reasons, such as:

Sign error during multiplication, Alex might have made a mistake while multiplying two numbers, incorrectly applying the rules for multiplying positive and negative values.

Input error, Alex might have mistakenly used negative values as inputs when performing the multiplication. This could happen if there was a misinterpretation of the given numbers or if negative signs were overlooked.

Calculation mistake, Alex could have made a calculation error during the multiplication process, such as errors in carrying over digits, using incorrect intermediate results, or incorrectly multiplying specific digits.

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