A cubical water tank can contain 1000/125 cubic meters of water. Find the length of a side of the water tank.

Answer:

1026

Step-by-step explanation:

Common difference = d = 2nd term  - first term

 d = -3 - (-11) = -3 +11 = 8

First term = a = -11

First we need to find the number of terms in this series

[tex]a_{n} = 125\\\\a + (n- 1)d = a_{n}\\\\[/tex]

-11 + (n- 1) * 8 = 125

 (n-1)*8 = 125 + 11

 (n-1) * 8 = 136

n -1 = 136/8

n -1 = 17

  n = 17+1

 n = 18

[tex]S_{n} =\frac{n}{2}(a+a_{n})\\\\S_{18} =\frac{18}{2}(-11+125)\\\\[/tex]

   = 9 * 114

   = 1026

Answer:

41

Step-by-step explanation:

Answer:

they exceeded their goal by 668 cans.

Step-by-step explanation:

multiplying 524 by 7 you get 3668, then subtracting 3,000 from that you get 668.

solution :-

here,

We know that interior opposite angles are equal.

So,

110° = 50° + x (being interior opposite angles)

110° - 50° = x

60° = x

the value of x =60°

hope it is helpful to you ☺️

Answer:

x = -1

Step-by-step explanation:

If you input -1 to both functions, you get 3.

Answer:

Fourth term of given arithmetic progression a(4) = 30

Step-by-step explanation:

Given incomplete information:

a(n) = 7n - 1 9

Assume Correct information:

a(n) = 7(n - 1) + 9

Find:

Fourth term of given arithmetic progression

Computation:

Fourth term of given arithmetic progression = a(4)

So,

Number of term (n) = 4

So,

a(n) = 7(n - 1) + 9

a(4) = 7(4 - 1) + 9

a(4) = 7(3) + 9

a(4) = 21 + 9

a(4) = 30

Fourth term of given arithmetic progression a(4) = 30

Answer:

10 and 10

Step-by-step explanation:

This is because of the triangle having all sides with the same angle. This is a equilateral triangle

Answer:

See explanation

Step-by-step explanation:

The given options are not properly formatted; so, I will give a general explanation instead

An equation is said to be radical if its variable is in a radicand sign.

For instance, the following equation is a radical;

[tex]\sqrt x + 2 = 4[/tex]

In the above equation, x is the variable, and it is in [tex]\sqrt[/tex] sign

However, the following equation is not a radical equation

[tex]x + \sqrt 4 = 2[/tex]

Because the variable is not in a radicand

Answer:

Step-by-step explanation:

you can divide 11/30 and get 0.37

0.37%/ 100*11 =

Multiply:

0.37*11 =

add the 100 to the product you multiplied and divide them together:

4.07/100=

your quotient:

0.0407

round by 2 decimals:

0.04

your final answer is :

0.04

Answer:

z=4x

=14y10

Step-by-step explanation:

this is the answer

Answer:

the answer is gonna be

6x^2+1

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\huge\textsf{Just do PEMDAS}\\\\\\\huge\textsf{Parentheses}\\\\\huge\textsf{Exponents}\\\\\huge\textsf{Multiplication}\\\\\huge\textsf{Division}\\\\\huge\textsf{Addition}\\\\\huge\textsf{Subtraction}[/tex]

[tex]\large\textsf{18 }\div\large\textsf{ 3 }\times\large\textsf{ 2 + 1}\\\\\\\large\textsf{18 }\div\large\textsf{ 3 = \bf 6}\\\\\\\large\textsf{6 }\times\large\textsf{ 2 + 1}\\\\\\\large\textsf{6 }\times\large\textsf{ 2 = \bf 12}\\\\\\\large\textsf{12 + 1}\\\\\\\large\textsf{= \bf 13}\\\\\\\boxed{\boxed{\huge\textsf{Answer: \bf 13}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Or you could if your equation is: }\\\\\large\textsf{18}\div\large\textsf{3x}\mathsf{^2}\large\textsf{ + 1}[/tex]

[tex]\large\textsf{18}\div\large\textsf{3x}\mathsf{^2}\large\textsf{ + 1}\\\\\large\textsf{18}\div\large\textsf{3x}\mathsf{^2}\large\textsf{ = \bf 6x}\mathsf{\bf ^2}\\\\\large\textsf{= \bf 6x}\mathsf{\bf ^2 \ + }\large\textsf{ \bf 1}\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \bf 6x}\mathsf{\bf ^2}\large\textsf{ \bf + 1}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

both lines have the same slope, hence they are parallel to each other

Step-by-step explanation:

The equation of a straight line is given by:

y = mx + b;

where y, x are variables, m is the slope of the line and b is the y intercept.

Two lines are said to be parallel to each other if they have the same slope, whereas two lines are perpendicular to each other if the product of their slopes is -1.

Given a line with an equation:

y = (2/3)x - 17

From the equation of the line with can see that the slope of the line is 2/3 and the y intercept is -17.

Also the other line has an equation of 4x - 6y = -6

6y = 4x + 6

y = (2/3)x + 1

Hence this line has a slope of 2/3 and a slope of 1.

Since both lines have the same slope, hence they are parallel to each other

Answer:

Step-by-step explanation:

1) nth therm = dn + (a - d)

-10n + (11+10)

-10n + 21

t11 = -110 + 21 = -89

2) nth therm = 3n + (-66 - 3)

3n - 69

t16 = 48 - 69 = -21

Answer:

x = [tex]\frac{3}{20}[/tex]

Step-by-step explanation:

Given

x + [tex]\frac{3}{2}[/tex] + (x - 1) = [tex]\frac{4}{5}[/tex]

Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions

10x + 15 + 10(x - 1) = 8

10x + 15 + 10x - 10 = 8

20x + 5 = 8 ( subtract 5 from both sides )

20x = 3 ( divide both sides by 20 )

x = [tex]\frac{3}{20}[/tex]

x + 3/2 + x - 1 = 4/5

Collect the same terms

x + x + 3/2 - 1 = 4/5

2x + 3/2 - 2/2 = 4/5

2x + (3 - 2)/2 = 4/5

2x + 1/2 = 4/5

2x + 0.5 = 0.8

Subtract both sides 0.5

2x + 0.5 - 0.5 = 0.8 - 0.5

2x + 0 = 0.3

2x = 3/10

Divide both sides by 2

2x ÷ 2 = ( 3/10 ) ÷ 2

x = 3/10 × 1/2

x = 3/20

_________________________________

3/20 + 3/2 + ( 3/20 - 1 ) = 4/5

3/20 + 30/20 + ( 3/20 - 20/20 ) = 4/5

(3 + 30)/20 + (3 - 20)/20 = 4/5

33/20 - 17/20 = 4/5

(33 - 17)/20 = 4/5

16/20 = 4/5

4 × 4 / 4 × 5 = 4/5

4/5 = 4/5

Thus we found the correct value of x .

And we're done...

Given:

The exponential function is:

[tex]R(x)=(5.3)^x[/tex]

To find:

The domain of the given exponential function.

Solution:

We know that the general form of an exponential function is:

[tex]f(x)=ab^x[/tex]

Where, a is the initial value and b is growth/decay factor.

This function is defined for all real values of x, so the domain of these type of functions is the set of all real number.

We have,

[tex]R(x)=(5.3)^x[/tex]

Here, a is 1 and b is 5.3. This function is defined for all real values of x

Therefore, the domain of these type of functions is the set of all real number or it can be written as [tex](-\infty,\infty)[/tex].

Answer:

23

4* 4  = 16

cir = 2[tex]\pi[/tex]r = 2[tex]\pi[/tex](1.2) = 2.4[tex]\pi[/tex]

16 + 2.4[tex]\pi[/tex] = 23.53

Step-by-step explanation:

Answer:

1cm divided by 17 = 32 then subtract the 32 into 17

Answer:

Step-by-step explanation:

As,

1/4 = (1×2)/(4×2) = 4/8

4/8 = (4×1)/(8×1) = 4/8

In both case,

The denominator 8 is least common multiple

Answer:

600g of Flour

Step-by-step explanation:

According to the question every 15 biscuits is 50g it need 50g of sugar and flour is 3 times the amount it needs for 15 biscuits so 50*3=150 now we know 15 biscuits need 150g of flour so 30 requires 300 and 300g +300g is equal to 600g of flour.

Answer:

600 g of flour.

Step-by-step explanation:

If Deon needs 50 g of sugar to make 15 biscuits, and she is going to make 60 biscuits, then she will need 200 g of sugar, since 60/15 is 4.

If the amount of flour she needs is equal to the amount of sugar multiplied by three, or 3x, if x is the amount of sugar, then she will need 200 x 3 g of flour.

Therefore, she will need 600 g of flour.

Answer:

The value of x is 18°

Step-by-step explanation:

Sum of the angles are 180°

3x+126=180

3x=180-126

3x=54

x=18

Answered by GAUTHMATH

Answer:

using the pythagoras theorem

Step-by-step explanation:

[tex] \sqrt{4 {}^{2} - ( \sqrt{7}) {}^{2} } = 3[/tex]

Answer:

I think the answer is 9

=====================================================

Work Shown:

f(x) = x-7

f(4) = 4-7

f(4) = -3

We can see that f(4) and -3 are the same number. Because of this, we can replace f(4) with -3

This will have us go from g( f(4) ) to g( -3 )

Then we plug x = -3 into the g(x) function

g(x) = x^2

g(-3) = (-3)^2

g(-3) = 9 is the final answer

Again, since -3 and f(4) are the same thing, we can replace that '-3' in g(-3) to get

g( -3 ) = 9

g( f(4) ) = 9

-------------------

An alternative route:

g(x) = x^2

g( f(x) ) = ( f(x) )^2 .... replace every x with f(x)

g( f(x) ) = ( x-7 )^2 .... plug in f(x) = x-7 for the right hand side only

g( f(4) ) = ( 4-7 )^2 ... plug in x = 4

g( f(4) ) = (-3)^2

g( f(4) ) = 9

Answer:

Yeah, so that is right, just put it into a formula.

[tex]9.07*10x^{-2}[/tex]

Answer:

12x36

Step-by-step explanation:

Answer:

36*12 = 432

Step-by-step explanation:

Answer: [tex]y=\sqrt{x+12}[/tex]

Step-by-step explanation:

I hope you mean y = x² - 12 and not y = 2x - 12.

You switch the y and x variables:

x = y² - 12

And solve for y:

x + 12 = y²

[tex]y=\sqrt{x+12}[/tex]

Answer:

???

Step-by-step explanation:

Answer:

-9

Step-by-step explanation:

{-2*-1^-2/-2-1*-1-3}3

= -9

Answered by GAUTHMATH

Answer:

12y² + 9y + 7

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

4y² + 5y + 2 + 8y² + 4y + 5

Step 2: Simplify

Answer:

12y² + 9y + 7

Step-by-step explanation:

4y² + 5y + 2 + 8y² + 4y + 5

Simplify :-

4y² + 5y + 2 + 8y² + 4y + 5

4y² + 8y² + 5y + 4y + 2 + 5

12y² + 9y + 7

Answer:

3/2 liters/minute

Step-by-step explanation:

Divide 11/15 liters by 22/45 minutes:

 11

------

 15

-----------

 22

-----

 45

This is equivalent to:

11      45

----- * -----  =  3/2 (liters/min)

15      22

The flow rate of the pipe is 3/2 (or 1.5) litres per minute.

To calculate the flow rate of the pipe, we divide the volume of water (in litres) by the time taken (in minutes).

Given:

Volume of water = 11/15 liters

Time taken = 22/45 minutes

Flow rate = Volume / Time

Flow rate = (11/15) liters / (22/45) minutes

To divide by a fraction, we multiply by its reciprocal:

Flow rate = (11/15) x (45/22) liters/minutes

Simplifying the expression:

Flow rate = 495/330 litres/minutes

The fraction can be simplified further by dividing both the numerator and denominator by their greatest common divisor (GCD), which is 165 in this case:

Flow rate = (495/165) / (330/165) litres/minutes

Flow rate = 3/2 liters/minutes

Therefore, the flow rate of the pipe is 3/2 (or 1.5) litres per minute.

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