A distressed car is rolling backward, downhill at 3.0 m/s when its driver finally manages to
get the engine started. What velocity will the car have 6.0 s later if it can accelerate at
3.0 m/s??

Answer:

55

Explanation:95-40=55

i hope i did the math right if i didnt please tell me

By the work-energy theorem, the total work done on the mass as it swings is

W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J

No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.

If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.

Now, if w is the amount of work done by friction/air resistance, then

(176.4 N) h - w = 153 J

If you know the starting height h, then you can solve for w.

For saving lives  the most important safety feature on a car is B. Safety Belt

Safety features of  a car is a feature of a product designed to ensure or increase safety.

Air bag and Anti-lock brakes are the supplemental protection and designed to work best with combination with seat bells.

Air bag reduce the chance that upper body or head will strike the vehicle's interior during a crash alongside with belt that will  also hold your upper body

so, the primary safety feature is seat belt and Air bag and Anti-lock brakes  comes in secondary safety feature  as they increases the safety and risk of getting an injury during any accident

correct answer is B. Safety Belt

learn more about Safety features

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Answer:

The answer should be: 1.20 A

Explanation:

Answer:

a)  [tex]F_{net}=0[/tex]

b)  [tex]T=0[/tex]

Explanation:

From the question we are told that:

Dimensions:

[tex]L*B=22.0*35.0cm[/tex]

Current [tex]I=1.40A[/tex]

Magnetic field [tex]B=1.40[/tex]

Therefore

[tex]Area=L*B[/tex]

[tex]A=22.0*35.0cm[/tex]

[tex]A=770cm=>770*0^{-4}[/tex]

a)

Generally Force on Looping gives

[tex]F_1-F_2[/tex]

[tex]F_3=F_4[/tex]

Therefore

[tex]F_{net}=0[/tex]

b)

Generally the equation for Torque is mathematically given by

[tex]T=i*Asin \theta[/tex]

Since A and B are on opposite direction

[tex]\theta=180[/tex]

Therefore

[tex]T=1.40*770*10^{-4}sin 180[/tex]

[tex]T=0[/tex]

Explanation:

The square meter is the SI-derived unit of area. It has a symbol m² (33A1 in Unicode). It is defined as the area of a square whose sides measure exactly one metre.

Answer:

6.9 m/s

Explanation:

1000m = 1km

3600s = 1hr

25000m/3600s

6.9m/s

Answer:

B

Explanation:

BECAUSE TO DO THE TESTS YOU NEED TO DO THE SCIENTIFIC METHOD.

FOR EXAMPLE: OBSERVATIONS AND EXPERIMENTS TO OBTAIN RESULTS.

ANYWAY I LEAVE YOU THE LINK:

https://gscourses.thinkific.com

Answer:

D. Fats

Explanation:

they are the long term energy storing nutrient carbohydrates are a quick way for energy minerals dont contain any energy and neither do proteins

fats

Explanation:

it is nutrient kept in the body

Answer:

Evaluate the solution.

Explanation:

A technological design is designed as the design and study of a solution that can be provided from the solution by identifying the root cause or problem and trying to solve by various means.

A good technological design requires the minimum effort and resources while meeting the requirement of the problem.

The steps involved in the technological design are :

1. search and identify the problem or need.

2. design a solution

3. Implement a solution.

4. Evaluate the solution.

Therefore, the final step or the fourth step in the process of a technological design is " evaluating or communicating the final design solution".

Answer:

Explained below

Explanation:

Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.

Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.

Answer:

Explanation:

The formula for this, the easy one, is

[tex]N=N_0(\frac{1}{2})^{\frac{t}{H}[/tex] where No is the initial amount of the element, t is the time in years, and H is the half life. Filling in:

[tex]N=48.0(\frac{1}{2})^{\frac{49.2}{12.3}[/tex] and simplifying a bit:

[tex]N=48.0(.5)^4[/tex] and

N = 48.0(.0625) so

N = 3 mg left after 12.3 years

How many half-lifes is 49.2 years ?

(49.2 years) / (12.3 years per half-life)  =  4 half-lifes.

In 4 half-lifes, (1/2) · (1/2) · (1/2) · (1/2) of the original sample remains.

That's (1/2⁴) or (1/16) of the original.

(1/16) of 48.0 mg  =  3 mg .

=======================

Step-by-step:

== Start with 48 mg .

== After one half-life, 24 mg remains.

== Then, after the second half-life, 12 mg remains.

== Then, after the third half-life, 6 mg remains.

== Then, after the fourth half-life, 3 mg remains.

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, [tex]P_{headlight}[/tex] = 38 W

The power at which the kick starter operates in parallel, [tex]P_{kick \ starter}[/tex] = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/[tex]P_{headlight}[/tex]  = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/[tex]P_{kick \ starter}[/tex] = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

[tex]P_{headlight}[/tex] = I² × R₁

∴ [tex]P_{headlight}[/tex] = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, [tex]P_{headlight, S}[/tex] ≈ 0.134 W

[tex]P_{kick \ starter}[/tex] = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, [tex]P_{kick \ starter, S}[/tex] ≈ 2.123 W

The total power they will consume, [tex]P_{Total}[/tex] = [tex]P_{headlight, S}[/tex] + [tex]P_{kick \ starter, S}[/tex]

Therefore;

[tex]P_{Total}[/tex] ≈ 0.134 W + 2.123 W = 2.257 W

Answer:

A flower emits only visible light

A flower reflects much of the light that hits it

Answer:

80 °C

Explanation:

The heat transfer parameters for the water and copper container are;

Mass of the copper container, m₁ = 84 g

Mass of the water in the container, m₂ = 84 g

Initial temperature of the water in the container, T₂ = 20°C

Mass of the hot water added, m₃ = 46 g

Initial temperature of the hot water, T₃ = 200°C

Specific heat capacity of water, c₂ = 4,200 J·kg⁻¹·°C⁻¹

Specific heat capacity of copper, c₁ = 400 J·kg⁻¹·C⁻¹

The formula for the specific heat, ΔQ = m·c·ΔT

The heat lost by the hot water = The heat gained by the container the and the cold water

The formula for the specific heat of the mixture is presented as follows;

m₃ × c₃ × (T₃ - T)  = m₁ × c₁ × (T - T₁) + m₂ × c₂ × (T - T₂)

Where T represents the final temperature of the water

Therefore, by plugging in the values, we get;

46 × 4200 × (200 - T) = 84 × 400 × (T - 20) + 84 × 4200 × (T - 20)

38640000 - 193200·T = 386400·T - 7728000

38640000 + 7728000 = 46368000 = 386400·T + 193200·T = 579,600·T

∴ T = 46368000/579,600 = 80

The final temperature of the water, T = 80°C

Answer:

The maximum height reached is 413.27 m.

Explanation:

How long will it take for a body to reach its maximum height, knowing that it was thrown, vertically upwards, with a velocity whose value was 90 m / s?

initial velocity , u = 90 m/s

gravity, g = 9.8 m/s^2

Let the maximum height is h.

At maximum height the velocity v = 0

Use third equation of motion

[tex]v^2 = u^2 - 2 gh\\\\0 = 90\times 90 - 2 \times 9.8 \times h\\\\h = 413.27 m[/tex]

Answer:

It increases twice the original

Answer: 8000N

Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort

Answer:

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

Explanation:

Although The Photon ( sunshine from the sun's surface ) heating up the student standing on the Earth's surface and the neutrinos discovered by the other student inside the gold mine are both formed in the Sun's core.

The difference between both are

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

a. cool air warms as it mixes with denser air

Explanation:

c. warm air is displaced by cooler denser air

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Answer:

C. 14.93 m

Explanation:

The given frequency of the wave, f = 100 Hz

The given equation for the wave speed, v, is presented as follows;

v = f × λ

The speed of sound in water, v = 1,493 m/s

Therefore, we get;

The wavelength, λ = v/f

∴ λ = 1,493 m/s/(100 Hz) = 14.93 m

The wavelength, λ = 14.93 m.

Answer:

2. 8.62×10² Nm

3. 2.30×10² Nm

4. 6.32×10² Nm

Explanation:

2. Determination of the work done by the applied force.

Force (F) = 225 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fd × Cos θ

Wd = 225 × 5 × Cos 40

Wd = 8.62×10² Nm

3. Determination of the work done by the frictional force.

Frictional Force (Fբ) = 60 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fբd × Cos θ

Wd = 60 × 5 × Cos 40

Wd = 2.30×10² Nm

4. Determination of the net work done.

We'll begin by calculating the net force acting on the crate

Force applied (F) = 225 N

Frictional Force (Fբ) = 60 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 225 – 60

Fₙ = 165 N

Finally, we shall determine the net Workdone. This can be obtained as follow:

Net force (Fₙ) = 165 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fₙd × Cos θ

Wd = 165 × 5 × Cos 40

Wd = 6.32×10² Nm

Answer:

5.66 m

Explanation:

From online sources, the speed in item 3 being referred to was discovered to be 7.62 m/s

Now, let's get the time of flight from one of Newton's equation of motion;

S = ut + ½gt²

Considering the vertical component, we have u = 0 m/s.

Thus;.

S = ½gt²

Plugging in the relevant values;

2.7 = ½ × 9.8 × t²

t² = 2.7/4.9

t = √(2.7/4.9)

t = 0.7423 s

Now, when we consider the horizontal component of the motion, we have;

S = vt

Where;

S is the distance the fish will travel horizontally before hitting the water.

v = 7.62 m/s

t = 0.7423

Thus

s = 7.62 × 0.7423

s ≈ 5.66 m

Answer:

A is the answer!

Explanation:

Edge 2021

Answer:

A

Explanation:

Edge

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[tex]\sf{\qquad{\qquad{\underline{\underline{ Projectile~motion }}}}}[/tex]

If an object is given an initial velocity in any direction and then allowed to travel freely under gravity only, it is called a projectile motion.

It is basically 3 types

The path followed by a projectile is called its trajectory.

Projectile motion is when an object moves in a bilaterally symmetrical, parabolic path.

The path that the object follows is called its trajectory.

Projectile motion only occurs when there is one force applied at the beginning, after which the only influence on the trajectory is that of gravity

Answer:

a. i. 35.96 μC  b. i. 11.98 μC ii. 24.04 μC

Explanation:

We need to find the total capacitance of the system C.

The total capacitance of the parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is C' = 1.47 μF + 2.95 μF = 4.42 μF.

C' = 4.42 μF is in series with the 4.89 μF capacitor and for a series combination of capacitors, we have the total capacitance, C from

1/C = 1/4.42 μF + 1/4.89 μF

1/C = (4.42 μF + 4.89 μF)/(4.42 μF × 4.89 μF)

1/C = 9.31 μF/21.6138 μF²

C = 21.6138/9.31 μF

C = 2.32 μF

So, the total charge in the circuit Q = CV where C = total capacitance = 2.32 μF and v = voltage = 15.5 V

So, Q = CV

Q = 2.32 μF × 15.5 V

Q = 35.96 μC

i. The charge on the 4.89 μF capacitor

Since the 4.89 μF is in series with C', the total charge flowing i the circuit is the total charge in the 4.89 μF capacitor. So, its charge Q = 35.96 μC

b. The charge in the 1.47 μF and 2.95 μF capacitors.

To find the charge in the 4.89 μF and 2.95 μF capacitors, we need to find the voltage across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor. The voltage, V' across the 4.89 μF capacitor, since Q = CV', V' = Q/C = 35.96 μC/4.89 μF = 7.35 V

So, the voltage V" across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor, C' is V" = 15.5 V - V' (since V' + V" = 15.5 V).

So, V" = 15.5 V - V'

V" = 15.5 V - 7.35 V

V" = 8.15 V

i. The charge on the 1.47 μF capacitor

Using Q' = CV" where Q' = charge across capacitor, C = 1.47 μF and V" = 8.15 V.

So, Q' = CV"

Q' = 1.47 μF × 8.15 V

Q' = 11.98 μC

ii. The charge on the 2.95 μF capacitor

Using Q" = CV" where Q' = charge across capacitor, C = 2.95 μF and V" = 8.15 V.

So, Q" = CV"

Q" = 2.95 μF × 8.15 V

Q" = 24.04 μC