Answer:
a) csc∅ = √53/2
b) cot ∅ = 15/√514
Step-by-step explanation:
a) The value of cot ∅ = -7/2
cos ∅ < 0
We note that cos(∅) is less than 0 in Quadrant II and III, and cot(∅) is less than 0 in the Quadrant II, therefore, we have;
∅ is in the Quadrant II
csc∅ = (√((-7)² + 2²))/2 =√53/2 ≈ 3.64
csc∅ = √53/2
b) cos∅ 15/17
∅ is in Quadrant IV
∴ cot ∅ = 15/(√(15² + 17²)) = 15/√514 ≈ 0.662
cot ∅ = 15/√514
In 2 Year 6 classes, 2/5 of the children are girls. There are 39 boys. How many children are there in the class?
Can someone help giving branliest to first correct answer
Given two similar cylinders with a height ratio of 2:3 what is the ratio of their volumes?
Answer:
8 : 27
Step-by-step explanation:
The ratio of the volumes is the ratio of the scale factor cubed
2^3 : 3^3
8 : 27
Answer:
8 : 27
Step-by-step explanation:
Given 2 similar cylinders with height ratio = a : b , then
ratio of volumes = a³ : b³
Here height ratio = 2 : 3
ratio of volumes = 2³ : 3³ = 8 : 27
22 - 8x = -5x - 14
Find x
Please help this is due today
Write the expression as either the sine, cosine, or tangent of a single angle. cos(pi/5) cos(pi/7)+sin(pi/5)sin (pi/7)
Answer:
cos(2π/35)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightPre-Calculus
Sum/Difference Formula [cosine]: [tex]\displaystyle cos(x \pm y) = cos(x)cos(y) \mp sin(x)sin(y)[/tex]Step-by-step explanation:
Step 1: Define
Identify
cos(π/5)cos(π/7) + sin(π/5)sin(π/7)
Step 2: Simplify
Sum/Difference Formula [cosine]: cos(π/5)cos(π/7) + sin(π/5)sin(π/7) = cos(π/5 - π/7)Subtract: cos(π/5 - π/7) = cos(2π/35)What are the possible degrees for the polynomial function?
Answer:
degrees of 5 or greater
Step-by-step explanation:
peaks counted are 5
What are the apparent coordinates of the midpoint of ab
Answer:
A. [tex](-1,-2)[/tex]
Step-by-step explanation:
Hope this helps you.
( -4, 1 ) and ( 2 , -5 )
Now,
mid point = ( 2 - 4 )/2 , ( -5 + 1 )/2
= ( -2 /2 ) , ( -4 /2)
= ( - 1, - 2 )
A ( - 1, - 2 )
I hope it's help you...
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फरक परेछ? A person deposited Rs. 80,000 in bank 'P' for 2 years at the rate of 10% annual compound interest. But after one year bank has changed the policy and decided to pay semi-annual compound interest at the same rate. What is the percentage difference between compound interests of the first year and second year? Give reason with calculation,
Answer:
you nepali me nepali all are nepalese nepalese are only unintelligent
Please help I’ll give brainliest
Answer:
D. 12m^3n^5
Step-by-step explanation:
Answer:
12m³n⁵
Step-by-step explanation:
3 · 4 = 12
m² · m = m³
n³ · n² = n⁵
Therefore, 3m²n³ · 4mn² = 12m³m⁵
A graph of f(x)=acos(bx) is shown, where b is a positive constant. Determine the values of a and b.
Answer:
Option (1)
Step-by-step explanation:
Equation of the given wave function,
f(x) = acos(bx)
Here, a = amplitude of the wave
Period of the wave = [tex]\frac{2\pi }{B}[/tex]
From the graph attached,
Amplitude = [tex]\frac{4-(-4)}{2}[/tex]
= [tex]\frac{4+4}{2}[/tex]
= 4
Period of the wave = π - 0
= π
From the formula of the period,
Period = [tex]\frac{2\pi }{b}[/tex]
[tex]\pi =\frac{2\pi }{b}[/tex]
b = 2
Therefore, a = 4 and b = 2.
Option (1) will be the answer.
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Answer:
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Step-by-step explanation:
Answer:
The radius of the circle is 2 units.
Step-by-step explanation:
The radius is half the diameter, therefor you must divide the diameter (4) by 2, and you get 2 units.
Which sequence is geometric?
Answer:
4th option
Step-by-step explanation:
in geometric sequences the number is multiplied or divided by same number continuously
in the 4th option we can see that the number 1 is multiplied by 4 continuously so the correct answer would be that.
When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a ____________of the given expression.
[tex] \huge\boxed{\mathfrak{Answer}}[/tex]
=> Factor.
When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a factor of the given expression.
[tex] \sf \: It's \: called \: a \: \boxed{\underline{\bf \: factor}}[/tex]
When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a [tex]\boxed{\underline{\bf \: factor}}[/tex]of the given expression.
Solve for x. Round to the nearest tenth, if
necessary.
I hope this is help full to u
thank you
Answer:
x = 3.8
Step-by-step explanation:
take 53 degree as reference angle
using cos rule
cos 53 = adjacent/hypotenuse
0.60 = x /6.3
0.60*6.3 = x
3.78 = x
3.8 = x ( after converting the answer to nearest tenth)
In the diagram below, AJKL is an equilateral triangle and KM I JL.
к
3
2
Which statement must be true?
O A. JK = KM
B. AJKM is a 30-60-90 triangle.
O C. KM = 2 .JM
D. AJKM is a 45-45-90 triangle.
Answer : B
Step-by-step explanation:
Ape
The statement which is true is KM = 2 .JM, the correct option is C.
What is the right triangle?A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse. The angle of a right angle is always 90 degrees.
We are given that;
AJKL is an equilateral triangle
Now,
Using these properties, we can eliminate some of the options.
Option A is false because JK and KM are not equal. JK is half of JL, which is one side of the equilateral triangle AJKL, while KM is a perpendicular bisector of JL.
Option B is false because AJKM is not a right triangle. The angle JAK is 60 degrees, not 90 degrees.
Option D is false because AJKM is not a right triangle. The angle JAK is 60 degrees, not 45 degrees.
Option C must be true because KM bisects JL into two equal parts JM and ML. Since JL is one side of the equilateral triangle AJKL, we have JL = AK = AL. Therefore, JM = ML = JL/2 = AK/2 = AL/2. By Pythagoras’ theorem, we have:
KM^2 = AK^2 - AM^2
KM^2 = (AK/2)^2 - (AL/4)^2
KM^2 = (AK/4)^2 + (AL/4)^2
KM^2 = ((AK + AL)/4)^2
Since AK + AL = 2 * JL,
KM^2 = (JL/4)^2 * 4
KM^2 = (JL/4)^2 * 4
KM = JL/4 * 2
KM = JL/2
Therefore, the answer of the triangle will be KM = 2 * JM.
Learn more about a right triangle;
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Jade has seven cards. Each card is labeled with a letter. A B C D E F G H J Jade picks one of her cards at random. Find the probability that the card she picks is a) labelled F, b) labelled with a letter in her name JADE c) labelled with a letter that has at least one line of symmetry
Answer:
(a) [tex]\frac{1}{7}[/tex]
(b) [tex]\frac{4}{7}[/tex]
(c) [tex]\frac{5}{7}[/tex]
Step-by-step explanation:
Probability (P) of an event is the likelihood that the event will occur. It is given by;
P = number of favourable outcomes ÷ total number of events in the sample space.
Given letters of cards:
A B C D E F G H J
∴ Total number of events in sample space is actually the number of cards which is 7
If a card is picked at random;
(a) the probability P(F), that it is labelled F is given by;
P(F) = number of favourable outcomes ÷ total number of events in the sample space.
The number of favourable outcomes for picking an F = 1 since there is only one card labelled with F.
∴ P(F) = 1 ÷ 7
=> P(F) = [tex]\frac{1}{7}[/tex]
(b) the probability P(N), that it is labelled with a letter in her name JADE is given by;
P(N) = P(J) + P(A) + P(D) + P(E)
Where;
P(J) = Probability that it is labelled J
P(A) = Probability that it is labelled A
P(D) = Probability that it is labelled D
P(E) = Probability that it is labelled E
P(J) = [tex]\frac{1}{7}[/tex]
P(A) = [tex]\frac{1}{7}[/tex]
P(D) = [tex]\frac{1}{7}[/tex]
P(E) = [tex]\frac{1}{7}[/tex]
∴ P(N) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]
∴ P(N) = [tex]\frac{4}{7}[/tex]
(c) the probability P(S), that it is labelled with a letter that has at least one line of symmetry is;
P(S) = P(A) + P(B) + P(C) + P(D) + P(E) + P(H)
Where;
P(A) = Probability that it is labelled A
P(B) = Probability that it is labelled B
P(C) = Probability that it is labelled C
P(D) = Probability that it is labelled D
P(E) = Probability that it is labelled E
P(H) = Probability that it is labelled H
Cards with letters A, B, C, D, E and H are selected because these letters have at least one line of symmetry. A line of symmetry is a line that cuts an object into two identical halves. Letters A, B, C, D, E and H can each be cut into two identical halves.
P(A) = [tex]\frac{1}{7}[/tex]
P(B) = [tex]\frac{1}{7}[/tex]
P(C) = [tex]\frac{1}{7}[/tex]
P(D) = [tex]\frac{1}{7}[/tex]
P(E) = [tex]\frac{1}{7}[/tex]
P(H) = [tex]\frac{1}{7}[/tex]
∴ P(S) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]
∴ P(S) = [tex]\frac{5}{7}[/tex]
A passenger traveling by air is allowed a maximum of 20kg luggage. A man has 4 bags weighing 3.5kg , 15kg, 2kg, 1.5kg. Find the excess weight of the luggage. Express the excess weight as a percentage of the maximum weight
Answer:
The passenger's luggage has an excess weight of 2 kg, which is 10% of the maximum weight.
Step-by-step explanation:
First, we need to find the weight (W) of the 4 bags:
[tex] W = 3.5 kg + 15 kg + 2 kg + 1.5 kg = 22 kg [/tex]
Now, knowing that the maximum allowed (M) is 20 kg the excess weight of the luggage is:
[tex] W_{e} = W - M = 22 kg - 20 kg = 2 kg [/tex]
We can express the excess weight in percentage as follows:
[tex] \% W_{e} = \frac{W_{e}}{M} \times 100 = \frac{2 kg}{20 kg}\times 100 = 10 \% [/tex]
Therefore, the passenger's luggage has an excess weight of 2 kg, which is 10% of the maximum weight.
I hope it helps you!
Help me please
How many solutions does the equation
x -4 = 12 - 2x have? Explain.
- ? .
Answer: one solution.
Step-by-step explanation:
[tex]\dfrac{2}{3} x-4=12-2x\\\\\dfrac{2}{3} x+2x=12+4\\\\2\dfrac{2}{3} x=16\\\\\dfrac{8}{3} x=16\\\\8x=16 \cdot 3\\\\8x=48\\\\x=\dfrac{48}{8} =6[/tex]
This equation has one solution: x = 6.
Determine whether the triangles are congruent. Explain your reasoning .
SAS (Side, Angle, Side) or ASA (Angle, Side, Angle)
Answer:
Ty
Step-by-step explanation:
What is the general equation for direct
variation?
Answer:
☆ y=kx
Example: if we have x= 3 and y= 15
Find y?
y= kx
*We know that y= 15 and x= 3
So,
15=k(3)
15=3k
*divide 3 from both sides
K=5
y=5x
y=5(5)=25
☆▪☆▪☆▪☆▪☆
Hope it helps..
Have a great day!!
A shoe repairman is working with his assistant, who takes 1.5 times as long to repair a pair of shoes.
Together they can fix 10 pairs of shoes in six hours. How long does it take the repairman to fix one pair
of shoes by himself?
Answer:
1/2 or 0.5 hours
Step-by-step explanation:
r = time for repairman to fix one pair of shoes.
a = time for assistant to fix one pair of shoes.
a = r×1.5
x×r + y×a = 6
x = number of pairs of shoes repaired by repairman.
y = number of pairs of shoes repaired by assistant.
x+y = 10
y = 10-x
x = y×1.5 (based on the a/r ratio : as the assistant needs 1.5 times longer, the repairman will have repaired 1.5 times more pair of shoes in the same time)
y = 10 - y×1.5
y + y×1.5 = 10
2.5×y = 10
y = 4
=> x = 6
6×r + 4×r×1.5 = 6
6×r + 6×r = 6
12×r = 6
r = 6/12 = 1/2 or 0.5 hours
what is the common difference for this arthimitic sequence? -8, -13, -18, -23
a. 5
b. -5
c. -28
d. -21
could anyone help me with this?
Answer:
93.4 cm²
Step-by-step explanation:
Area of the shaded region = area of the square - area of half of the circle
Area of the shaded region = s² + ½(πr²)
Where,
r = 6.2 cm
s = length of square = diameter of circle = 2*r = 2*6.2
s = 12.4 cm
Plug in the values
Area of the shaded region = 12.4² - ½(π × 6.2²)
= 153.76 - 60.381411
= 93.378589
≈ 93.4 cm² (nearest tenth)
The locksmith is 82.9 miles west of the bakery. The pet store is 44.5 miles west of the bakery. The toy store is 38.6 miles east of the bakery. The coffee shop is 71.5 miles east of the bakery. The library is 57.0 miles south of the bakery. The magic shop is 75.7 miles south of the bakery. How far apart are the toy store and the locksmith?
Answer:
82.9+38.6=121.5 miles far away.
Help
Will give
Brainlist
Answer
Answer:
the answer for this one is 39.2f. me being a Canadian and knowing that 0c is 32 Celsius it had to be larger and putting 4 Celsius thru a converter gives you 39.2
Step-by-step explanation:
The bus ride was 35 minutes long. If the ride ended at 12:05 a.m., what time did the ride begin?
Answer:
11:30 A.M.
Step-by-step explanation:
Answer:
11:30
Step-by-step explanation:
12.05- 35 min and its 11:30
hope that helps bby<3
(Find m∠IGH) m∠IGH=
Answer:
angle IGH = 50 degree
Step-by-step explanation:
triangle GHI is an isosceles triangle because it's two sides are equal.
if angle I is 50 degree then angle G is also 50 degree becasue in isosceles triangle the base angles are equal.
Find all solutions to the equation in the interval [0, 2pie]. Enter the solutions in increasing order. cos 2x = sin x
Answer:
cos2x=sinx
<=> 1-2sin^{2}x =sinx
solve and we have x=3pie/2, x=pie/6,x= 5pie/6
Step-by-step explanation:
What is the product?
(5r − 4)(r2 − 6r + 4)
5r3 − 34r2 + 44r − 16
5r3 − 4r2 + 14r − 16
5r3 − 6r − 16
5r3 + 10r − 16
Answer:
5r³ - 34r² + 44r - 16
Step-by-step explanation:
[tex] \small \sf \: (5r − 4)(r² − 6r + 4)[/tex]
use the distributive property
5r × (r² − 6r + 4) - 4× (r² − 6r + 4)
5r³ - 30r² + 20r - 4r² + 24r - 16
combine like terms
5r³ - 30r² - 4r² + 20r + 24r - 16
5r³ - 34r² + 44r - 16
The product of the expressions is 5r^3 - 34r^2 + 44r - 16
What is a product?The product of two expression is done by multiplying the expressions
The product expression is given as:
[tex](5r - 4)(r^2 - 6r + 4)[/tex]
Expand the expression
[tex]5r^3 - 30r^2 + 20r - 4r^2 + 24r - 16[/tex]
Collect like terms
[tex]5r^3 - 30r^2 - 4r^2 + 20r + 24r - 16[/tex]
Evaluate the like terms
[tex]5r^3 - 34r^2 + 44r - 16[/tex]
Hence, the product of the expressions is 5r^3 - 34r^2 + 44r - 16
Read more about product at:
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please i have 15 minutes
Answer:
[tex] x = \dfrac{-\log 7}{\log 7 - \log 2} [/tex]
Step-by-step explanation:
[tex] 2^x = 7^{x + 1} [/tex]
Take the log of both sides.
[tex] \log 2^x = \log 7^{x + 1} [/tex]
Use properties of log.
[tex] x \log 2 = (x + 1) \log 7 [/tex]
[tex] x \log 2 = x \log 7 + \log 7 [/tex]
[tex] x \log 2 - x \log 7 = \log 7 [/tex]
[tex] x(\log 2 - \log 7) = \log 7 [/tex]
[tex] x = \dfrac{\log 7}{\log 2 - \log 7} [/tex]
[tex] x = \dfrac{\log 7}{-(\log 7 - \log 2)} [/tex]
[tex] x = \dfrac{-\log 7}{\log 7 - \log 2} [/tex]