A five-question multiple-choice quiz has five choices for each answer. Use the random number table provided, with O's representing Incorrect answers
and 1's representing correct answers, to answer the following question:
What is the probability of correctly guessing at random exactly one correct answer? Round to the nearest whole number.

Answer:

.40 is the greatest .350 is the second greatest and last but not least .3456 is the lowest

Step-by-step explanation:

Answer:

volume=length×width×height

v=15×20×20

v=6000

Answer:

$10

Step-by-step explanation:

5 toys = $1

Zach wants 50 of these

50 ÷ 5 = 10

10 x 1 = 10

= $10

Answer:

10 dollars

Step-by-step explanation:

We can use a ratio to solve

5 rings     50 rings

----------  = --------------

1 dollar         x dollars

Using cross products

5*x = 1 * 50

5x = 50

Divide by 5

5x/5 = 50/5

x = 10

Answer:

15×115+3{0÷3}5-3×(-6)

15×115+3of 0 of 5-3×(-6)

15×115+0 of 5-3×(-6)

15×115+0+18

1725+0+18

1743

9514 1404 393

Answer:

  50π cm²

Step-by-step explanation:

The radius of the larger circle is 10 cm, so its area is ...

  A = πr² = π(10 cm)² = 100π cm²

The area of each smaller circle is ...

  A = π(5 cm)² = 25π cm²

Then the shaded area is ...

  shaded = large circle - 2 × small circle

  shaded = 100π cm² - 2(25π cm²) = 50π cm²

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that [tex]P(A) = 0.8[/tex]

If you have passed subject A, the probability of passing subject B is 0.8.

This means that [tex]P(B|A) = 0.8[/tex]

Find the probability that the student passes both subjects?

This is [tex]P(A \cap B)[/tex]. So

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

[tex]P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64[/tex]

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

[tex]p = P(A) + P(B) - P(A \cap B)[/tex]

Considering [tex]P(B) = 0.7[/tex], we have that:

[tex]p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86[/tex]

0.86 = 86% probability that the student passes at least one of the two subjects

Answer:

{f, a}

Step-by-step explanation:

Given the sets:

X = {d, c, f, a}

Y = {d, e, c}

Z ={e, c, b, f, g}

U = {a, b, c, d, e, f, g}

To obtain the set X n (X - Y)

We first obtain :

(X - Y) :

The elements in X that are not in Y

(X - Y) = {f, a}

X n (X - Y) :

X = {d, c, f, a} intersection

(X - Y) = {f, a}

X n (X - Y) = elements in X and (X - Y)

X n (X - Y) = {f, a}

9514 1404 393

Answer:

  2

Step-by-step explanation:

In this expression, the terms are the parts of the sum. They are 3x and 4. There are 2 terms.

Answer:

your selected answer is right

Answer: The line starts at 1 positive, then from there go -4 (so go to the left) then 1 down from that point.

Step-by-step explanation: the problem is supposed to have been Y= -4/1 +1

Answer:

If rounded to the nearest 10 bacteria, then it would be 500 bacteria.

Step-by-step explanation:

First multiply 150 by two in order to get 300, that leaves 4 hours to figure out. From there you can figure out the rest by seeing that 4 is 2/3 of 6. I converted it into the decimal number .66. Multiply 300 by .66 to get 198 and then add it to 300 to get 498. Then just round it up to the nearest 10 bacteria which leaves you with the final answer of 500 bacteria.

Answer:

a=1, b=9, c=-2, d=4

Step-by-step explanation:

Answer:

The solution to the equation  log3(x+2)=1 is given by x=1

Step-by-step explanation:

We are given that

[tex]log_3(x+2)=1[/tex]

We have to find the graph which shows the  solution to the equation log3(x+2)=1.

[tex]log_3(x+2)=1[/tex]

[tex]x+2=3^1[/tex]

Using the formula

[tex]lnx=y\implies x=e^y[/tex]

[tex]x+2=3[/tex]

[tex]x=3-2[/tex]

[tex]x=1[/tex]

Answer:

6/11, 11/2, 5.77, 5.772

Step-by-step explanation:

Answer:

[tex]b=h=\sqrt{6}[/tex] m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=[tex]2b^2+4bh[/tex]

[tex]2b^2+4bh=36[/tex]

[tex]b^2+2bh=18[/tex]

[tex]2bh=18-b^2[/tex]

[tex]h=\frac{18-b^2}{2b}[/tex]

Volume of box, V=[tex]b^2h[/tex]

Substitute the values

[tex]V=b^2\times \frac{18-b^2}{2b}[/tex]

[tex]V=\frac{1}{2}(18b-b^3)[/tex]

Differentiate w. r.t b

[tex]\frac{dV}{db}=\frac{1}{2}(18-3b^2)[/tex]

[tex]\frac{dV}{db}=0[/tex]

[tex]\frac{1}{2}(18-3b^2)=0[/tex]

[tex]\implies 18-3b^2=0[/tex]

[tex]\implies 3b^2=18[/tex]

[tex]b^2=6[/tex]

[tex]b=\pm \sqrt{6}[/tex]

[tex]b=\sqrt{6}[/tex]

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

[tex]\frac{d^2V}{db^2}=-3b[/tex]

At  [tex]b=\sqrt{6}[/tex]

[tex]\frac{d^2V}{db^2}=-3\sqrt{6}<0[/tex]

Hence, the volume of box is maximum at [tex]b=\sqrt{6}[/tex].

[tex]h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}[/tex]

[tex]h=\frac{18-6}{2\sqrt{6}}[/tex]

[tex]h=\frac{12}{2\sqrt{6}}[/tex]

[tex]h=\sqrt{6}[/tex]

[tex]b=h=\sqrt{6}[/tex] m

Answer:

Sum = 19,662

Step-by-step explanation:

Given that this is a finite geometric series (meaning it stops at a specific term or in this case -24,576), we can use this formula:  

[tex]\frac{a(1-r^n)}{1-r}[/tex], where a is the first term, r is the common ratio, and n is the number of terms.

Substituting for everything and simplifying gives us:

[tex]\frac{6(1-(-4)^7)}{1-(-4)} \\\\\frac{6(16385}{5}\\ \\\frac{98310}{5}\\ \\19662[/tex]

Answer:

sensory measurement are lower after hypnotism

Step-by-step explanation:

Given the data :

Before 6.6 6.5 9.0 10.3 11.3 8.1 6.3 11.6

After 6.8 2.4 7.4 8.5 8.1 6.1 3.4 2.0

The difference ;

After - Before, d = 0.2, - 4.1, - 1.6, - 1.8, - 3.2, - 2, - 2.9, - 9.6

Hypothesis :

H0 : μd = 0

H0 : μ < 0

The test statistic ;

T = μd / sd/√n

Where, xd = mean of difference

sd = standard deviation of difference

n = sample size

Mean of difference, μd = Σx/n = - 3.13

Standard deviation of difference, sd = 2.91

T = - 3.13 / 2.91/√8

T = - 3.13 / 1.0288403

T = - 3.042

α = 0.01

The Pvalue using a Pvalue calculator ;

Degree of freedom, df = n - 1 ; 8-1 = 7

Pvalue(-3.042, 7) = 0.00939

Pvalue < α ; we reject the null and conclude that sensory measurement are lower after hypnotism

Answer:

b= 5i square root of 3

b = -5i square root of 3

Step-by-step explanation:

4b^2+300=0

4b^2 = -300

b^2 = -75

b = square root of -75

b = -75^1/2

^1/2 means square root

b = 25^1/2 * 3^1/2 * i

b= 5i square root of 3

b = -5i square root of 3

Answer:

[tex]y = - \frac{1}{3}x + 5[/tex]

Step-by-step explanation:

Consider two points through which the line passes.

Let it be ( 0 , 5 ) and ( 6 , 3 )

Step 1 : Find slope

    [tex]Slope, m = \frac{y_2 - y_ 1 }{x_2 - x_1}[/tex]

                 [tex]= \frac{3-5}{6-0} \\\\=\frac{-2}{6}\\\\= -\frac{1}{3}[/tex]

Step 2 : Find the equation of the line passing through the points.

       [tex]( y - y_1) = m (x - x_1)\\\\(y - 5) = -\frac{1}{3} ( x - 0) \\\\y = -\frac{1}{3}x + 5[/tex]

Answer:

The right answer is "[tex]x\simeq 254[/tex]".

Step-by-step explanation:

Let the number of earlier case will be "x".

Now,

⇒ [tex]x+x\times \frac{26.3}{100}=321[/tex]

or,

⇒ [tex]x+x\times 0.263=321[/tex]

By taking "x" common, we get

⇒   [tex]x(1+0.263)=321[/tex]

⇒                    [tex]x=\frac{321}{1.263}[/tex]

⇒                       [tex]=254.15[/tex]

or,

⇒                    [tex]x\simeq 254[/tex]

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) [tex]\lim_{x\rightarrow 2^{-}}f(x)=3[/tex]

(b) [tex]\lim_{x\rightarrow 2^{+}}f(x)=1[/tex]

(c) [tex]\lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq \lim_{x\rightarrow 2^{+}}f(x) \right.[/tex]

(d) [tex]f(2)=3[/tex]

(e) [tex]\lim_{x\rightarrow 4}f(x) = 4[/tex]

(f) [tex]f(4)= DNE.[/tex]{ Hole in graph}

Hence solved.

Answer:

See attachment showing the rise and run

Slope = 1

Step-by-step explanation:

In the diagram attached below, the rise is represented by the blue line, while the run is represented by the red line.

Rise = 4 units

Run = 4 units

It's a positive slope because the line slopes upwards from left to right

Slope = rise/run = 4/4

Slope = 1

Answer:

The  weight that separate the top 8% by 5.2605 and the weight that separate bottom 8% by 5.1195.

Step-by-step explanation:

We are given that

Mean,[tex]\mu=5.19[/tex]

Standard deviation,[tex]\sigma=0.05[/tex]

We have to find the two weights that separate the top 8% and the bottom 8%.

Let x1 and x2 the two weights that separate the top 8% and the bottom 8%.

Z-value for p-value =0.08 =[tex]-1.41[/tex]

For 8% bottom

[tex]Z=\frac{x_1-\mu}{\sigma}=-1.41[/tex]

[tex]\frac{x_1-5.19}{0.05}=-1.41[/tex]

[tex]x_1-5.19=-1.41\times 0.05[/tex]

[tex]x_1=-1.41\times 0.05+5.19[/tex]

[tex]x_1=5.1195[/tex]

For 8% top

p-Value=1-0.08=0.92

Z- value=1.41

Now,

[tex]\frac{x_2-5.19}{0.05}=1.41[/tex]

[tex]x_2-5.19=1.41\times 0.05[/tex]

[tex]x_2=1.41\times 0.05+5.19[/tex]

[tex]x_2=5.2605[/tex]

(x1,x2)=(5.1195,5.2605)

9514 1404 393

Answer:

  (c)

Step-by-step explanation:

  [tex]\displaystyle\sqrt[3]{xy^5}\sqrt[3]{x^7y^{17}}=\sqrt[3]{x^{1+7}y^{5+17}}=\sqrt[3]{x^6x^2y^{21}y}=\sqrt[3]{x^6y^{21}}\sqrt[3]{x^2y}\\\\=\boxed{x^2y^7\sqrt[3]{x^2y}}[/tex]

Answer:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]

[tex]P(x < 70) = 0.225[/tex]

Step-by-step explanation:

Given

[tex]Lower = 30[/tex]

[tex]Width = 10[/tex]

Solving (a): The relative frequency table

First, we construct the frequency table using the given parameters.

[tex]\begin{array}{cc}{Class} & {Frequency} &{30-39} & {1} & {40-49} & {1} & {50 - 59} & {2} & {60 - 69} & {5} & {70 - 79} & {13} & {80 - 89} & {10} & {90 - 99} & {8} & {Total} & {40}\ \end{array}[/tex]

The relative frequency (RF) is calculated as:

[tex]RF = \frac{Frequency}{Total}[/tex]

Using the above formula to calculate the relative frequency, the relative frequency table is:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]

Solving (b): [tex]P(x < 70)[/tex]

To do this, we add up the relative frequencies of classes less than 70.

i.e.

[tex]P(x < 70) = [30 - 39] + [40 - 49] + [50 - 59] + [60 - 69][/tex]

So, we have:

[tex]P(x < 70) = 0.025 + 0.025 + 0.050 + 0.125[/tex]

[tex]P(x < 70) = 0.225[/tex]

Answer:

(-6,-12)

Step-by-step explanation:

A dilation makes a figure gets bigger so just multiply 3 to point N to find N prime.

[tex] - 2 \times 3 = - 6[/tex]

[tex] - 4 \times 3 = - 12[/tex]

So our new coordinates is

(-6,-12)

Answer:

(-6,-12)

Step-by-step explanation:

A dilation makes a figure gets bigger so just multiply 3 to point N to find N prime.

So our new coordinates is

(-6,-12)

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

y-1=10

Any figure that crosses equal sign, the operational sign changes.

y=10+1

y= 11

Answer:

5^2×5

=25×5

=125

hope this will help you

Answer:

125

Step-by-step explanation:

hope this helps you

=25×5

=125